How to convert binary floating point to decimal scientific notation?
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Let me be clear, by this I don't just mean convert 1.01 * 2 ^ 010 to "5". I'm talking about the exponent as well. This is the true challenge. The mantissa is fairly easy to convert, just find the trailing bit and then pass it through a basic Binary to BCD converter. That would be it for the mantissa, but I don't want that. I want to convert the exponent as well.
People told me to just pass it through a binary to BCD decoder, but this makes no sense, because if we literally translated 1.01 * 2 ^ 010 to 5 * 2 ^ 2, that would be incorrect. 2 ^ 0 is 8, and 5 * 8 is 40. I am talking about real base conversion here. I want to turn 1.01 * 2 ^ 010 into 5 * 10 ^ 0. But how? I am required to do this in order to replicate the Versuchsmodell 1. Please, I need this. Thank you very much.
Sorry the edit is because I messed up the shifts. I meant to type 010, not 011. That would be 10, sorry
computer-science
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up vote
0
down vote
favorite
Let me be clear, by this I don't just mean convert 1.01 * 2 ^ 010 to "5". I'm talking about the exponent as well. This is the true challenge. The mantissa is fairly easy to convert, just find the trailing bit and then pass it through a basic Binary to BCD converter. That would be it for the mantissa, but I don't want that. I want to convert the exponent as well.
People told me to just pass it through a binary to BCD decoder, but this makes no sense, because if we literally translated 1.01 * 2 ^ 010 to 5 * 2 ^ 2, that would be incorrect. 2 ^ 0 is 8, and 5 * 8 is 40. I am talking about real base conversion here. I want to turn 1.01 * 2 ^ 010 into 5 * 10 ^ 0. But how? I am required to do this in order to replicate the Versuchsmodell 1. Please, I need this. Thank you very much.
Sorry the edit is because I messed up the shifts. I meant to type 010, not 011. That would be 10, sorry
computer-science
Could you include MathJax formatting? It makes your question more readable.
– AryanSonwatikar
Nov 17 at 16:24
What do you mean by1.01 * 2 ^ 011
if not $(1+0times 1/2+1/4)times 2^3?$ Why do you think it s $5?$
– gammatester
Nov 17 at 16:24
gammatester. 1.01 shifted left 3 times. That is what the exponent means, how many times to shift the number. I only place the 2 because it is the base and it is ignored in the actual machine
– Konrad Zuse
Nov 17 at 16:28
@AryanSonwatikar what is mathjax?
– Konrad Zuse
Nov 17 at 16:28
@gammatester actually sorry lmao I messed up with the shifts. That would be 1010, or 10. I meant to type the exponent to be 10
– Konrad Zuse
Nov 17 at 16:30
|
show 10 more comments
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Let me be clear, by this I don't just mean convert 1.01 * 2 ^ 010 to "5". I'm talking about the exponent as well. This is the true challenge. The mantissa is fairly easy to convert, just find the trailing bit and then pass it through a basic Binary to BCD converter. That would be it for the mantissa, but I don't want that. I want to convert the exponent as well.
People told me to just pass it through a binary to BCD decoder, but this makes no sense, because if we literally translated 1.01 * 2 ^ 010 to 5 * 2 ^ 2, that would be incorrect. 2 ^ 0 is 8, and 5 * 8 is 40. I am talking about real base conversion here. I want to turn 1.01 * 2 ^ 010 into 5 * 10 ^ 0. But how? I am required to do this in order to replicate the Versuchsmodell 1. Please, I need this. Thank you very much.
Sorry the edit is because I messed up the shifts. I meant to type 010, not 011. That would be 10, sorry
computer-science
Let me be clear, by this I don't just mean convert 1.01 * 2 ^ 010 to "5". I'm talking about the exponent as well. This is the true challenge. The mantissa is fairly easy to convert, just find the trailing bit and then pass it through a basic Binary to BCD converter. That would be it for the mantissa, but I don't want that. I want to convert the exponent as well.
People told me to just pass it through a binary to BCD decoder, but this makes no sense, because if we literally translated 1.01 * 2 ^ 010 to 5 * 2 ^ 2, that would be incorrect. 2 ^ 0 is 8, and 5 * 8 is 40. I am talking about real base conversion here. I want to turn 1.01 * 2 ^ 010 into 5 * 10 ^ 0. But how? I am required to do this in order to replicate the Versuchsmodell 1. Please, I need this. Thank you very much.
Sorry the edit is because I messed up the shifts. I meant to type 010, not 011. That would be 10, sorry
computer-science
computer-science
edited Nov 17 at 16:32
asked Nov 17 at 16:18
Konrad Zuse
11
11
Could you include MathJax formatting? It makes your question more readable.
– AryanSonwatikar
Nov 17 at 16:24
What do you mean by1.01 * 2 ^ 011
if not $(1+0times 1/2+1/4)times 2^3?$ Why do you think it s $5?$
– gammatester
Nov 17 at 16:24
gammatester. 1.01 shifted left 3 times. That is what the exponent means, how many times to shift the number. I only place the 2 because it is the base and it is ignored in the actual machine
– Konrad Zuse
Nov 17 at 16:28
@AryanSonwatikar what is mathjax?
– Konrad Zuse
Nov 17 at 16:28
@gammatester actually sorry lmao I messed up with the shifts. That would be 1010, or 10. I meant to type the exponent to be 10
– Konrad Zuse
Nov 17 at 16:30
|
show 10 more comments
Could you include MathJax formatting? It makes your question more readable.
– AryanSonwatikar
Nov 17 at 16:24
What do you mean by1.01 * 2 ^ 011
if not $(1+0times 1/2+1/4)times 2^3?$ Why do you think it s $5?$
– gammatester
Nov 17 at 16:24
gammatester. 1.01 shifted left 3 times. That is what the exponent means, how many times to shift the number. I only place the 2 because it is the base and it is ignored in the actual machine
– Konrad Zuse
Nov 17 at 16:28
@AryanSonwatikar what is mathjax?
– Konrad Zuse
Nov 17 at 16:28
@gammatester actually sorry lmao I messed up with the shifts. That would be 1010, or 10. I meant to type the exponent to be 10
– Konrad Zuse
Nov 17 at 16:30
Could you include MathJax formatting? It makes your question more readable.
– AryanSonwatikar
Nov 17 at 16:24
Could you include MathJax formatting? It makes your question more readable.
– AryanSonwatikar
Nov 17 at 16:24
What do you mean by
1.01 * 2 ^ 011
if not $(1+0times 1/2+1/4)times 2^3?$ Why do you think it s $5?$– gammatester
Nov 17 at 16:24
What do you mean by
1.01 * 2 ^ 011
if not $(1+0times 1/2+1/4)times 2^3?$ Why do you think it s $5?$– gammatester
Nov 17 at 16:24
gammatester. 1.01 shifted left 3 times. That is what the exponent means, how many times to shift the number. I only place the 2 because it is the base and it is ignored in the actual machine
– Konrad Zuse
Nov 17 at 16:28
gammatester. 1.01 shifted left 3 times. That is what the exponent means, how many times to shift the number. I only place the 2 because it is the base and it is ignored in the actual machine
– Konrad Zuse
Nov 17 at 16:28
@AryanSonwatikar what is mathjax?
– Konrad Zuse
Nov 17 at 16:28
@AryanSonwatikar what is mathjax?
– Konrad Zuse
Nov 17 at 16:28
@gammatester actually sorry lmao I messed up with the shifts. That would be 1010, or 10. I meant to type the exponent to be 10
– Konrad Zuse
Nov 17 at 16:30
@gammatester actually sorry lmao I messed up with the shifts. That would be 1010, or 10. I meant to type the exponent to be 10
– Konrad Zuse
Nov 17 at 16:30
|
show 10 more comments
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Could you include MathJax formatting? It makes your question more readable.
– AryanSonwatikar
Nov 17 at 16:24
What do you mean by
1.01 * 2 ^ 011
if not $(1+0times 1/2+1/4)times 2^3?$ Why do you think it s $5?$– gammatester
Nov 17 at 16:24
gammatester. 1.01 shifted left 3 times. That is what the exponent means, how many times to shift the number. I only place the 2 because it is the base and it is ignored in the actual machine
– Konrad Zuse
Nov 17 at 16:28
@AryanSonwatikar what is mathjax?
– Konrad Zuse
Nov 17 at 16:28
@gammatester actually sorry lmao I messed up with the shifts. That would be 1010, or 10. I meant to type the exponent to be 10
– Konrad Zuse
Nov 17 at 16:30