Finding position at given distance in a GeoPath
up vote
8
down vote
favorite
Is there a way to find the geoposition of a given distance from start in a GeoPath
? I want to mark equidistant positions along a track, for example, a mark every 500 km along the path given by
path=GeoGraphics[
GeoPath[{
Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
}, "Rhumb"]
]
Is there a way to find the pos that gives GeoDistance[Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],pos]==500 km
along the path?
geographics
New contributor
add a comment |
up vote
8
down vote
favorite
Is there a way to find the geoposition of a given distance from start in a GeoPath
? I want to mark equidistant positions along a track, for example, a mark every 500 km along the path given by
path=GeoGraphics[
GeoPath[{
Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
}, "Rhumb"]
]
Is there a way to find the pos that gives GeoDistance[Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],pos]==500 km
along the path?
geographics
New contributor
add a comment |
up vote
8
down vote
favorite
up vote
8
down vote
favorite
Is there a way to find the geoposition of a given distance from start in a GeoPath
? I want to mark equidistant positions along a track, for example, a mark every 500 km along the path given by
path=GeoGraphics[
GeoPath[{
Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
}, "Rhumb"]
]
Is there a way to find the pos that gives GeoDistance[Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],pos]==500 km
along the path?
geographics
New contributor
Is there a way to find the geoposition of a given distance from start in a GeoPath
? I want to mark equidistant positions along a track, for example, a mark every 500 km along the path given by
path=GeoGraphics[
GeoPath[{
Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
}, "Rhumb"]
]
Is there a way to find the pos that gives GeoDistance[Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],pos]==500 km
along the path?
geographics
geographics
New contributor
New contributor
edited Nov 28 at 13:10
Kuba♦
103k12200511
103k12200511
New contributor
asked Nov 28 at 12:57
Gunnar
412
412
New contributor
New contributor
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
6
down vote
Here's my attempt to parametrize the path by arclength, where here arclength is GeoLength
.
First I build up a function that can be used on many values:
ParametrizeGeoPath[g_GeoPath, t_] := ParametrizeGeoPath[g][t]
ParametrizeGeoPath[GeoPath[locs_, args___]] :=
Block[{line, nodes, lens, acc, nf, n1, n2, solver},
line = GeoGraphics`GeoEvaluate[GeoPath[locs, args]];
nodes = GeoPosition /@ Reverse[line[[1]], {2}];
lens = QuantityMagnitude[UnitConvert[GeoLength[GeoPath[#, args]]& /@ Partition[nodes, 2, 1], "Kilometers"]];
acc = Accumulate[lens];
nf = Nearest[acc -> {"Index", "Element"}];
GeoPathParametricFunction[acc, nodes, nf, args]
]
Given a target distance, we can invert GeoLength
with FindRoot
:
GeoPathParametricFunction[_, nodes_, __][d_] /; d == 0 := First[nodes]
GeoPathParametricFunction[acc_, nodes_, __][d_] /; d == Last[acc] := Last[nodes]
GeoPathParametricFunction[acc_, nodes_, nf_, args___][d_] /; 0 < d < Last[acc] :=
Block[{i, v, s, n1, n2, dist, root, t = Unique["t"]},
{i, v} = First[nf[d]];
If[v > d, i--];
s = If[i == 0, 0, acc[[i]]];
n1 = nodes[[i+1, 1]];
n2 = nodes[[i+2, 1]];
dist[t_?NumericQ] := s + QuantityMagnitude[UnitConvert[GeoLength[GeoPath[{GeoPosition[n1], GeoPosition[(1-t)n1 + t n2]}, args]], "Kilometers"]];
root = Quiet@FindRoot[dist[t] == d, {t, .5, 0, 1}];
(
GeoPosition[(1-t)n1 + t n2] /. root
) /; MatchQ[root, {t -> _Real}]
]
GeoPathParametricFunction[___][d_?NumericQ] = Indeterminate;
GeoPathParametricFunction /: MakeBoxes[expr:GeoPathParametricFunction[__], _] := InterpretationBox[RowBox[{"GeoPathParametricFunction", "[", ""[Ellipsis]"", "]"}], expr]
Your example:
path = GeoPath[{
Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
}, "Rhumb"];
gpf = ParametrizeGeoPath[path];
gpf[500]
GeoPosition[{43.0932, -77.0359}]
Manipulate[GeoGraphics[{
path,
GeoMarker[gpf[d]]
},
PlotLabel -> Row[{"Distance: ", Quantity[d, "Kilometers"]}]],
{d, 0, gpf[[1, -1]]}
]
The points returned are very close to the initial path:
ListLinePlot[
GeoDistance[path, g /@ Range[0, 1300, 100]],
TargetUnits -> "Meters",
AxesLabel -> Automatic,
DataRange -> {0, 1300}
]
Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
– kickert
Nov 28 at 16:01
add a comment |
up vote
4
down vote
Here is a function for finding GeoPositions between 2 cities with certain step
city1 = Entity["City", {"Boston", "Massachusetts", "UnitedStates"}];
city2 = Entity["City", {"Rochester", "NewYork", "UnitedStates"}];
city3 = Entity["City", {"Chicago", "Illinois", "UnitedStates"}];
geopath[c1_, c2_, step_] := Module[{s = First@GeoDistance[c1, c2],
a = GeoDirection[c1, c2]},
GeoPath[NestList[GeoDestination[#,{1000 step,a}]&,c1,Floor[s/step]],"Rhumb"]]
Now if you want to find positions from city1 to city2 every 100 km, type
geopath[city1, city2, 100]
and you will get the positions
GeoPath[{Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
GeoPosition[{42.5124, -72.2106}], GeoPosition[{42.6928, -73.4044}],
GeoPosition[{42.8732, -74.6017}], GeoPosition[{43.0535, -75.8026}],
GeoPosition[{43.2338, -77.0069}]}, "Rhumb"]
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
6
down vote
Here's my attempt to parametrize the path by arclength, where here arclength is GeoLength
.
First I build up a function that can be used on many values:
ParametrizeGeoPath[g_GeoPath, t_] := ParametrizeGeoPath[g][t]
ParametrizeGeoPath[GeoPath[locs_, args___]] :=
Block[{line, nodes, lens, acc, nf, n1, n2, solver},
line = GeoGraphics`GeoEvaluate[GeoPath[locs, args]];
nodes = GeoPosition /@ Reverse[line[[1]], {2}];
lens = QuantityMagnitude[UnitConvert[GeoLength[GeoPath[#, args]]& /@ Partition[nodes, 2, 1], "Kilometers"]];
acc = Accumulate[lens];
nf = Nearest[acc -> {"Index", "Element"}];
GeoPathParametricFunction[acc, nodes, nf, args]
]
Given a target distance, we can invert GeoLength
with FindRoot
:
GeoPathParametricFunction[_, nodes_, __][d_] /; d == 0 := First[nodes]
GeoPathParametricFunction[acc_, nodes_, __][d_] /; d == Last[acc] := Last[nodes]
GeoPathParametricFunction[acc_, nodes_, nf_, args___][d_] /; 0 < d < Last[acc] :=
Block[{i, v, s, n1, n2, dist, root, t = Unique["t"]},
{i, v} = First[nf[d]];
If[v > d, i--];
s = If[i == 0, 0, acc[[i]]];
n1 = nodes[[i+1, 1]];
n2 = nodes[[i+2, 1]];
dist[t_?NumericQ] := s + QuantityMagnitude[UnitConvert[GeoLength[GeoPath[{GeoPosition[n1], GeoPosition[(1-t)n1 + t n2]}, args]], "Kilometers"]];
root = Quiet@FindRoot[dist[t] == d, {t, .5, 0, 1}];
(
GeoPosition[(1-t)n1 + t n2] /. root
) /; MatchQ[root, {t -> _Real}]
]
GeoPathParametricFunction[___][d_?NumericQ] = Indeterminate;
GeoPathParametricFunction /: MakeBoxes[expr:GeoPathParametricFunction[__], _] := InterpretationBox[RowBox[{"GeoPathParametricFunction", "[", ""[Ellipsis]"", "]"}], expr]
Your example:
path = GeoPath[{
Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
}, "Rhumb"];
gpf = ParametrizeGeoPath[path];
gpf[500]
GeoPosition[{43.0932, -77.0359}]
Manipulate[GeoGraphics[{
path,
GeoMarker[gpf[d]]
},
PlotLabel -> Row[{"Distance: ", Quantity[d, "Kilometers"]}]],
{d, 0, gpf[[1, -1]]}
]
The points returned are very close to the initial path:
ListLinePlot[
GeoDistance[path, g /@ Range[0, 1300, 100]],
TargetUnits -> "Meters",
AxesLabel -> Automatic,
DataRange -> {0, 1300}
]
Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
– kickert
Nov 28 at 16:01
add a comment |
up vote
6
down vote
Here's my attempt to parametrize the path by arclength, where here arclength is GeoLength
.
First I build up a function that can be used on many values:
ParametrizeGeoPath[g_GeoPath, t_] := ParametrizeGeoPath[g][t]
ParametrizeGeoPath[GeoPath[locs_, args___]] :=
Block[{line, nodes, lens, acc, nf, n1, n2, solver},
line = GeoGraphics`GeoEvaluate[GeoPath[locs, args]];
nodes = GeoPosition /@ Reverse[line[[1]], {2}];
lens = QuantityMagnitude[UnitConvert[GeoLength[GeoPath[#, args]]& /@ Partition[nodes, 2, 1], "Kilometers"]];
acc = Accumulate[lens];
nf = Nearest[acc -> {"Index", "Element"}];
GeoPathParametricFunction[acc, nodes, nf, args]
]
Given a target distance, we can invert GeoLength
with FindRoot
:
GeoPathParametricFunction[_, nodes_, __][d_] /; d == 0 := First[nodes]
GeoPathParametricFunction[acc_, nodes_, __][d_] /; d == Last[acc] := Last[nodes]
GeoPathParametricFunction[acc_, nodes_, nf_, args___][d_] /; 0 < d < Last[acc] :=
Block[{i, v, s, n1, n2, dist, root, t = Unique["t"]},
{i, v} = First[nf[d]];
If[v > d, i--];
s = If[i == 0, 0, acc[[i]]];
n1 = nodes[[i+1, 1]];
n2 = nodes[[i+2, 1]];
dist[t_?NumericQ] := s + QuantityMagnitude[UnitConvert[GeoLength[GeoPath[{GeoPosition[n1], GeoPosition[(1-t)n1 + t n2]}, args]], "Kilometers"]];
root = Quiet@FindRoot[dist[t] == d, {t, .5, 0, 1}];
(
GeoPosition[(1-t)n1 + t n2] /. root
) /; MatchQ[root, {t -> _Real}]
]
GeoPathParametricFunction[___][d_?NumericQ] = Indeterminate;
GeoPathParametricFunction /: MakeBoxes[expr:GeoPathParametricFunction[__], _] := InterpretationBox[RowBox[{"GeoPathParametricFunction", "[", ""[Ellipsis]"", "]"}], expr]
Your example:
path = GeoPath[{
Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
}, "Rhumb"];
gpf = ParametrizeGeoPath[path];
gpf[500]
GeoPosition[{43.0932, -77.0359}]
Manipulate[GeoGraphics[{
path,
GeoMarker[gpf[d]]
},
PlotLabel -> Row[{"Distance: ", Quantity[d, "Kilometers"]}]],
{d, 0, gpf[[1, -1]]}
]
The points returned are very close to the initial path:
ListLinePlot[
GeoDistance[path, g /@ Range[0, 1300, 100]],
TargetUnits -> "Meters",
AxesLabel -> Automatic,
DataRange -> {0, 1300}
]
Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
– kickert
Nov 28 at 16:01
add a comment |
up vote
6
down vote
up vote
6
down vote
Here's my attempt to parametrize the path by arclength, where here arclength is GeoLength
.
First I build up a function that can be used on many values:
ParametrizeGeoPath[g_GeoPath, t_] := ParametrizeGeoPath[g][t]
ParametrizeGeoPath[GeoPath[locs_, args___]] :=
Block[{line, nodes, lens, acc, nf, n1, n2, solver},
line = GeoGraphics`GeoEvaluate[GeoPath[locs, args]];
nodes = GeoPosition /@ Reverse[line[[1]], {2}];
lens = QuantityMagnitude[UnitConvert[GeoLength[GeoPath[#, args]]& /@ Partition[nodes, 2, 1], "Kilometers"]];
acc = Accumulate[lens];
nf = Nearest[acc -> {"Index", "Element"}];
GeoPathParametricFunction[acc, nodes, nf, args]
]
Given a target distance, we can invert GeoLength
with FindRoot
:
GeoPathParametricFunction[_, nodes_, __][d_] /; d == 0 := First[nodes]
GeoPathParametricFunction[acc_, nodes_, __][d_] /; d == Last[acc] := Last[nodes]
GeoPathParametricFunction[acc_, nodes_, nf_, args___][d_] /; 0 < d < Last[acc] :=
Block[{i, v, s, n1, n2, dist, root, t = Unique["t"]},
{i, v} = First[nf[d]];
If[v > d, i--];
s = If[i == 0, 0, acc[[i]]];
n1 = nodes[[i+1, 1]];
n2 = nodes[[i+2, 1]];
dist[t_?NumericQ] := s + QuantityMagnitude[UnitConvert[GeoLength[GeoPath[{GeoPosition[n1], GeoPosition[(1-t)n1 + t n2]}, args]], "Kilometers"]];
root = Quiet@FindRoot[dist[t] == d, {t, .5, 0, 1}];
(
GeoPosition[(1-t)n1 + t n2] /. root
) /; MatchQ[root, {t -> _Real}]
]
GeoPathParametricFunction[___][d_?NumericQ] = Indeterminate;
GeoPathParametricFunction /: MakeBoxes[expr:GeoPathParametricFunction[__], _] := InterpretationBox[RowBox[{"GeoPathParametricFunction", "[", ""[Ellipsis]"", "]"}], expr]
Your example:
path = GeoPath[{
Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
}, "Rhumb"];
gpf = ParametrizeGeoPath[path];
gpf[500]
GeoPosition[{43.0932, -77.0359}]
Manipulate[GeoGraphics[{
path,
GeoMarker[gpf[d]]
},
PlotLabel -> Row[{"Distance: ", Quantity[d, "Kilometers"]}]],
{d, 0, gpf[[1, -1]]}
]
The points returned are very close to the initial path:
ListLinePlot[
GeoDistance[path, g /@ Range[0, 1300, 100]],
TargetUnits -> "Meters",
AxesLabel -> Automatic,
DataRange -> {0, 1300}
]
Here's my attempt to parametrize the path by arclength, where here arclength is GeoLength
.
First I build up a function that can be used on many values:
ParametrizeGeoPath[g_GeoPath, t_] := ParametrizeGeoPath[g][t]
ParametrizeGeoPath[GeoPath[locs_, args___]] :=
Block[{line, nodes, lens, acc, nf, n1, n2, solver},
line = GeoGraphics`GeoEvaluate[GeoPath[locs, args]];
nodes = GeoPosition /@ Reverse[line[[1]], {2}];
lens = QuantityMagnitude[UnitConvert[GeoLength[GeoPath[#, args]]& /@ Partition[nodes, 2, 1], "Kilometers"]];
acc = Accumulate[lens];
nf = Nearest[acc -> {"Index", "Element"}];
GeoPathParametricFunction[acc, nodes, nf, args]
]
Given a target distance, we can invert GeoLength
with FindRoot
:
GeoPathParametricFunction[_, nodes_, __][d_] /; d == 0 := First[nodes]
GeoPathParametricFunction[acc_, nodes_, __][d_] /; d == Last[acc] := Last[nodes]
GeoPathParametricFunction[acc_, nodes_, nf_, args___][d_] /; 0 < d < Last[acc] :=
Block[{i, v, s, n1, n2, dist, root, t = Unique["t"]},
{i, v} = First[nf[d]];
If[v > d, i--];
s = If[i == 0, 0, acc[[i]]];
n1 = nodes[[i+1, 1]];
n2 = nodes[[i+2, 1]];
dist[t_?NumericQ] := s + QuantityMagnitude[UnitConvert[GeoLength[GeoPath[{GeoPosition[n1], GeoPosition[(1-t)n1 + t n2]}, args]], "Kilometers"]];
root = Quiet@FindRoot[dist[t] == d, {t, .5, 0, 1}];
(
GeoPosition[(1-t)n1 + t n2] /. root
) /; MatchQ[root, {t -> _Real}]
]
GeoPathParametricFunction[___][d_?NumericQ] = Indeterminate;
GeoPathParametricFunction /: MakeBoxes[expr:GeoPathParametricFunction[__], _] := InterpretationBox[RowBox[{"GeoPathParametricFunction", "[", ""[Ellipsis]"", "]"}], expr]
Your example:
path = GeoPath[{
Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
Entity["City", {"Rochester", "NewYork", "UnitedStates"}],
Entity["City", {"Chicago", "Illinois", "UnitedStates"}]
}, "Rhumb"];
gpf = ParametrizeGeoPath[path];
gpf[500]
GeoPosition[{43.0932, -77.0359}]
Manipulate[GeoGraphics[{
path,
GeoMarker[gpf[d]]
},
PlotLabel -> Row[{"Distance: ", Quantity[d, "Kilometers"]}]],
{d, 0, gpf[[1, -1]]}
]
The points returned are very close to the initial path:
ListLinePlot[
GeoDistance[path, g /@ Range[0, 1300, 100]],
TargetUnits -> "Meters",
AxesLabel -> Automatic,
DataRange -> {0, 1300}
]
edited Nov 28 at 18:54
answered Nov 28 at 15:52
Chip Hurst
20k15686
20k15686
Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
– kickert
Nov 28 at 16:01
add a comment |
Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
– kickert
Nov 28 at 16:01
Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
– kickert
Nov 28 at 16:01
Excellent work. I will certainly be using some aspects of your answer in other geo data related work I have been doing.
– kickert
Nov 28 at 16:01
add a comment |
up vote
4
down vote
Here is a function for finding GeoPositions between 2 cities with certain step
city1 = Entity["City", {"Boston", "Massachusetts", "UnitedStates"}];
city2 = Entity["City", {"Rochester", "NewYork", "UnitedStates"}];
city3 = Entity["City", {"Chicago", "Illinois", "UnitedStates"}];
geopath[c1_, c2_, step_] := Module[{s = First@GeoDistance[c1, c2],
a = GeoDirection[c1, c2]},
GeoPath[NestList[GeoDestination[#,{1000 step,a}]&,c1,Floor[s/step]],"Rhumb"]]
Now if you want to find positions from city1 to city2 every 100 km, type
geopath[city1, city2, 100]
and you will get the positions
GeoPath[{Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
GeoPosition[{42.5124, -72.2106}], GeoPosition[{42.6928, -73.4044}],
GeoPosition[{42.8732, -74.6017}], GeoPosition[{43.0535, -75.8026}],
GeoPosition[{43.2338, -77.0069}]}, "Rhumb"]
add a comment |
up vote
4
down vote
Here is a function for finding GeoPositions between 2 cities with certain step
city1 = Entity["City", {"Boston", "Massachusetts", "UnitedStates"}];
city2 = Entity["City", {"Rochester", "NewYork", "UnitedStates"}];
city3 = Entity["City", {"Chicago", "Illinois", "UnitedStates"}];
geopath[c1_, c2_, step_] := Module[{s = First@GeoDistance[c1, c2],
a = GeoDirection[c1, c2]},
GeoPath[NestList[GeoDestination[#,{1000 step,a}]&,c1,Floor[s/step]],"Rhumb"]]
Now if you want to find positions from city1 to city2 every 100 km, type
geopath[city1, city2, 100]
and you will get the positions
GeoPath[{Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
GeoPosition[{42.5124, -72.2106}], GeoPosition[{42.6928, -73.4044}],
GeoPosition[{42.8732, -74.6017}], GeoPosition[{43.0535, -75.8026}],
GeoPosition[{43.2338, -77.0069}]}, "Rhumb"]
add a comment |
up vote
4
down vote
up vote
4
down vote
Here is a function for finding GeoPositions between 2 cities with certain step
city1 = Entity["City", {"Boston", "Massachusetts", "UnitedStates"}];
city2 = Entity["City", {"Rochester", "NewYork", "UnitedStates"}];
city3 = Entity["City", {"Chicago", "Illinois", "UnitedStates"}];
geopath[c1_, c2_, step_] := Module[{s = First@GeoDistance[c1, c2],
a = GeoDirection[c1, c2]},
GeoPath[NestList[GeoDestination[#,{1000 step,a}]&,c1,Floor[s/step]],"Rhumb"]]
Now if you want to find positions from city1 to city2 every 100 km, type
geopath[city1, city2, 100]
and you will get the positions
GeoPath[{Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
GeoPosition[{42.5124, -72.2106}], GeoPosition[{42.6928, -73.4044}],
GeoPosition[{42.8732, -74.6017}], GeoPosition[{43.0535, -75.8026}],
GeoPosition[{43.2338, -77.0069}]}, "Rhumb"]
Here is a function for finding GeoPositions between 2 cities with certain step
city1 = Entity["City", {"Boston", "Massachusetts", "UnitedStates"}];
city2 = Entity["City", {"Rochester", "NewYork", "UnitedStates"}];
city3 = Entity["City", {"Chicago", "Illinois", "UnitedStates"}];
geopath[c1_, c2_, step_] := Module[{s = First@GeoDistance[c1, c2],
a = GeoDirection[c1, c2]},
GeoPath[NestList[GeoDestination[#,{1000 step,a}]&,c1,Floor[s/step]],"Rhumb"]]
Now if you want to find positions from city1 to city2 every 100 km, type
geopath[city1, city2, 100]
and you will get the positions
GeoPath[{Entity["City", {"Boston", "Massachusetts", "UnitedStates"}],
GeoPosition[{42.5124, -72.2106}], GeoPosition[{42.6928, -73.4044}],
GeoPosition[{42.8732, -74.6017}], GeoPosition[{43.0535, -75.8026}],
GeoPosition[{43.2338, -77.0069}]}, "Rhumb"]
edited Nov 28 at 15:40
answered Nov 28 at 13:37
J42161217
3,492220
3,492220
add a comment |
add a comment |
Gunnar is a new contributor. Be nice, and check out our Code of Conduct.
Gunnar is a new contributor. Be nice, and check out our Code of Conduct.
Gunnar is a new contributor. Be nice, and check out our Code of Conduct.
Gunnar is a new contributor. Be nice, and check out our Code of Conduct.
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Post as a guest
Required, but never shown
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StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown