Powershell: compare and match specific part of filename











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0
down vote

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I have something want to use Powershell to write. Could anyone know it? Thanks.
I use powershell to create a list.
e.g.



$SUID = @("0011", "0012", "0013", "0014", "0015")



I have a folder containing log files:



0010Log201811151440.log

0012Log201811151440.log

0013Log201811151440.log

0017Log201811151440.log

0015Log201811151440.log


I want to use Powershell to determine SUID and files matching. Such as:



0011 = file is missing

0012 = 0012Log201811151440.log

0013 = 0013Log201811151440.log

0014 = file is missing

0015 = 0015Log201811151440.log





powershell script







share|improve this question




























    up vote
    0
    down vote

    favorite












    I have something want to use Powershell to write. Could anyone know it? Thanks.
    I use powershell to create a list.
    e.g.



    $SUID = @("0011", "0012", "0013", "0014", "0015")



    I have a folder containing log files:



    0010Log201811151440.log
    
0012Log201811151440.log
    
0013Log201811151440.log
    
0017Log201811151440.log
    
0015Log201811151440.log


    I want to use Powershell to determine SUID and files matching. Such as:



    0011 = file is missing
    
0012 = 0012Log201811151440.log
    
0013 = 0013Log201811151440.log
    
0014 = file is missing
    
0015 = 0015Log201811151440.log





    powershell script







    share|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have something want to use Powershell to write. Could anyone know it? Thanks.
      I use powershell to create a list.
      e.g.



      $SUID = @("0011", "0012", "0013", "0014", "0015")



      I have a folder containing log files:



      0010Log201811151440.log
      
0012Log201811151440.log
      
0013Log201811151440.log
      
0017Log201811151440.log
      
0015Log201811151440.log


      I want to use Powershell to determine SUID and files matching. Such as:



      0011 = file is missing
      
0012 = 0012Log201811151440.log
      
0013 = 0013Log201811151440.log
      
0014 = file is missing
      
0015 = 0015Log201811151440.log





      powershell script







      share|improve this question















      I have something want to use Powershell to write. Could anyone know it? Thanks.
      I use powershell to create a list.
      e.g.



      $SUID = @("0011", "0012", "0013", "0014", "0015")



      I have a folder containing log files:



      0010Log201811151440.log
      
0012Log201811151440.log
      
0013Log201811151440.log
      
0017Log201811151440.log
      
0015Log201811151440.log


      I want to use Powershell to determine SUID and files matching. Such as:



      0011 = file is missing
      
0012 = 0012Log201811151440.log
      
0013 = 0013Log201811151440.log
      
0014 = file is missing
      
0015 = 0015Log201811151440.log





      powershell script




      powershell script






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 22 at 7:06









      Aulis Ronkainen

      6051614




      6051614










      asked Nov 22 at 6:35









      user966127

      31




      31






















          1 Answer
          1






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          oldest

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          up vote
          0
          down vote



          accepted










          You can use a split method to get the first part of the name:



          $filename = "0010Log201811151440.log"
          
$separator = "Log"
          
$first = ($filename -split $separator)[0]
          
$first





          share|improve this answer





















          • Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
            – user966127
            Nov 23 at 3:30













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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          0
          down vote



          accepted










          You can use a split method to get the first part of the name:



          $filename = "0010Log201811151440.log"
          
$separator = "Log"
          
$first = ($filename -split $separator)[0]
          
$first





          share|improve this answer





















          • Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
            – user966127
            Nov 23 at 3:30

















          up vote
          0
          down vote



          accepted










          You can use a split method to get the first part of the name:



          $filename = "0010Log201811151440.log"
          
$separator = "Log"
          
$first = ($filename -split $separator)[0]
          
$first





          share|improve this answer





















          • Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
            – user966127
            Nov 23 at 3:30















          up vote
          0
          down vote



          accepted







          up vote
          0
          down vote



          accepted






          You can use a split method to get the first part of the name:



          $filename = "0010Log201811151440.log"
          
$separator = "Log"
          
$first = ($filename -split $separator)[0]
          
$first





          share|improve this answer












          You can use a split method to get the first part of the name:



          $filename = "0010Log201811151440.log"
          
$separator = "Log"
          
$first = ($filename -split $separator)[0]
          
$first






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 22 at 10:03









          Xaero Walk

          16




          16












          • Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
            – user966127
            Nov 23 at 3:30




















          • Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
            – user966127
            Nov 23 at 3:30


















          Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
          – user966127
          Nov 23 at 3:30






          Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
          – user966127
          Nov 23 at 3:30




















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