What is the probability of getting 1 winner from each group?
There are three groups (A, B, C) . group A and B have 4 people and group c has 3 making a total of 11 people.three people are going to be chosen from the total of 11 to win a prize, what is the probability that 1 person from each group will win?
assuming that order doesn't matter, the total number of outcomes is 165 and the total number of ways 1 person from each group can be selected is 4x4x3=48. so the probability should be 48/165. is this correct?
and how would you calculate the probability that 2 of the winners will be from group A and the other one will be from group C?
probability
asked Nov 18 at 15:26
NoLifeKing
1
add a comment |
There are three groups (A, B, C) . group A and B have 4 people and group c has 3 making a total of 11 people.three people are going to be chosen from the total of 11 to win a prize, what is the probability that 1 person from each group will win?
assuming that order doesn't matter, the total number of outcomes is 165 and the total number of ways 1 person from each group can be selected is 4x4x3=48. so the probability should be 48/165. is this correct?
and how would you calculate the probability that 2 of the winners will be from group A and the other one will be from group C?
probability
asked Nov 18 at 15:26
NoLifeKing
1
2
Yes that is correct. To your second question: the same methodology works in this case.
– lulu
Nov 18 at 15:45
add a comment |
There are three groups (A, B, C) . group A and B have 4 people and group c has 3 making a total of 11 people.three people are going to be chosen from the total of 11 to win a prize, what is the probability that 1 person from each group will win?
assuming that order doesn't matter, the total number of outcomes is 165 and the total number of ways 1 person from each group can be selected is 4x4x3=48. so the probability should be 48/165. is this correct?
and how would you calculate the probability that 2 of the winners will be from group A and the other one will be from group C?
probability
asked Nov 18 at 15:26
NoLifeKing
1
There are three groups (A, B, C) . group A and B have 4 people and group c has 3 making a total of 11 people.three people are going to be chosen from the total of 11 to win a prize, what is the probability that 1 person from each group will win?
assuming that order doesn't matter, the total number of outcomes is 165 and the total number of ways 1 person from each group can be selected is 4x4x3=48. so the probability should be 48/165. is this correct?
and how would you calculate the probability that 2 of the winners will be from group A and the other one will be from group C?
probability
probability
asked Nov 18 at 15:26
NoLifeKing
1
asked Nov 18 at 15:26
NoLifeKing
1
asked Nov 18 at 15:26
NoLifeKing
1
asked Nov 18 at 15:26
NoLifeKing
1
asked Nov 18 at 15:26
NoLifeKing
1
1
2
Yes that is correct. To your second question: the same methodology works in this case.
– lulu
Nov 18 at 15:45
add a comment |
2
Yes that is correct. To your second question: the same methodology works in this case.
– lulu
Nov 18 at 15:45
2
2
Yes that is correct. To your second question: the same methodology works in this case.
– lulu
Nov 18 at 15:45
Yes that is correct. To your second question: the same methodology works in this case.
– lulu
Nov 18 at 15:45
add a comment |
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Yes that is correct. To your second question: the same methodology works in this case.
– lulu
Nov 18 at 15:45