Why the empty function is a local isomorphism?
In a study conserning finite model theory, it says that when the two models are purely relational (namely, they contain only predicate symbols and not function as well as constant symbols), the empty function is a local isomorphism. Why this is the case?
group-isomorphism
asked Nov 18 at 15:28
Athanasios Margaris
1213
add a comment |
In a study conserning finite model theory, it says that when the two models are purely relational (namely, they contain only predicate symbols and not function as well as constant symbols), the empty function is a local isomorphism. Why this is the case?
group-isomorphism
asked Nov 18 at 15:28
Athanasios Margaris
1213
add a comment |
In a study conserning finite model theory, it says that when the two models are purely relational (namely, they contain only predicate symbols and not function as well as constant symbols), the empty function is a local isomorphism. Why this is the case?
group-isomorphism
asked Nov 18 at 15:28
Athanasios Margaris
1213
In a study conserning finite model theory, it says that when the two models are purely relational (namely, they contain only predicate symbols and not function as well as constant symbols), the empty function is a local isomorphism. Why this is the case?
group-isomorphism
group-isomorphism
asked Nov 18 at 15:28
Athanasios Margaris
1213
asked Nov 18 at 15:28
Athanasios Margaris
1213
asked Nov 18 at 15:28
Athanasios Margaris
1213
asked Nov 18 at 15:28
Athanasios Margaris
1213
asked Nov 18 at 15:28
Athanasios Margaris
1213
1213
add a comment |
add a comment |
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