Create executable and shared library with one makefile
Using makefiles is new to me. My first tests with the simplest approach worked very well so far. But now I got stuck writing a makefile that creates a executable file and a shared library. As I said I'm new to makefiles. Here is my simple approach:
exe.a: main.c func.c
gcc main.c func.c -o exe.a
lib.so: func.c
gcc func.c -o lib.so -fPIC -shared
When the makefile is executed only the executable will be compiled. Is it even possible to create two objects with one makefile? What is the best approach to create these files?
compiling make executable shared-library
edited Nov 24 '18 at 1:25
Peter Mortensen
1,03821016
asked Nov 23 '18 at 8:37
Olupo
235
add a comment |
Using makefiles is new to me. My first tests with the simplest approach worked very well so far. But now I got stuck writing a makefile that creates a executable file and a shared library. As I said I'm new to makefiles. Here is my simple approach:
exe.a: main.c func.c
gcc main.c func.c -o exe.a
lib.so: func.c
gcc func.c -o lib.so -fPIC -shared
When the makefile is executed only the executable will be compiled. Is it even possible to create two objects with one makefile? What is the best approach to create these files?
compiling make executable shared-library
edited Nov 24 '18 at 1:25
Peter Mortensen
1,03821016
asked Nov 23 '18 at 8:37
Olupo
235
add a comment |
Using makefiles is new to me. My first tests with the simplest approach worked very well so far. But now I got stuck writing a makefile that creates a executable file and a shared library. As I said I'm new to makefiles. Here is my simple approach:
exe.a: main.c func.c
gcc main.c func.c -o exe.a
lib.so: func.c
gcc func.c -o lib.so -fPIC -shared
When the makefile is executed only the executable will be compiled. Is it even possible to create two objects with one makefile? What is the best approach to create these files?
compiling make executable shared-library
edited Nov 24 '18 at 1:25
Peter Mortensen
1,03821016
asked Nov 23 '18 at 8:37
Olupo
235
Using makefiles is new to me. My first tests with the simplest approach worked very well so far. But now I got stuck writing a makefile that creates a executable file and a shared library. As I said I'm new to makefiles. Here is my simple approach:
exe.a: main.c func.c
gcc main.c func.c -o exe.a
lib.so: func.c
gcc func.c -o lib.so -fPIC -shared
When the makefile is executed only the executable will be compiled. Is it even possible to create two objects with one makefile? What is the best approach to create these files?
compiling make executable shared-library
compiling make executable shared-library
edited Nov 24 '18 at 1:25
Peter Mortensen
1,03821016
asked Nov 23 '18 at 8:37
Olupo
235
edited Nov 24 '18 at 1:25
Peter Mortensen
1,03821016
asked Nov 23 '18 at 8:37
Olupo
235
edited Nov 24 '18 at 1:25
Peter Mortensen
1,03821016
edited Nov 24 '18 at 1:25
Peter Mortensen
1,03821016
edited Nov 24 '18 at 1:25
Peter Mortensen
1,03821016
1,03821016
asked Nov 23 '18 at 8:37
Olupo
235
asked Nov 23 '18 at 8:37
Olupo
235
asked Nov 23 '18 at 8:37
Olupo
235
235
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
By default make will build only the first target in a Makefile
which is exe.a in your case. You can either tell make to create
another target:
make lib.so
or both targets:
make lib.so exe.a
or (preferred) introduce a new first target which is usually named
all:
all: exe.a lib.so
exe.a: main.c func.c
gcc main.c func.c -o exe.a
lib.so: func.c
gcc func.c -o lib.so -fPIC -shared
Now a simple make will build the (pseudo-) target all which in turn
depends on exe.a and lib.so, so they get built first. Note that you
must not have a file called all in your directory in this case because
then make gets confused.
answered Nov 23 '18 at 9:39
PerlDuck
5,36911231
Thank you. The option with the new first target is exactly what I was looking for.
– Olupo
Nov 23 '18 at 9:49
@Olupo You are welcome. When you study other Makefiles you'll encounter thisalltarget very often.
– PerlDuck
Nov 23 '18 at 9:51
I've read some other makefiles, but most of them were to advanced for my current skill level.
– Olupo
Nov 23 '18 at 9:53
2
I know exactly what you mean :-) My skills aren't very good either and when it comes to more complicated Makefiles I usually think of them as rocket science.
– PerlDuck
Nov 23 '18 at 10:04
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
By default make will build only the first target in a Makefile
which is exe.a in your case. You can either tell make to create
another target:
make lib.so
or both targets:
make lib.so exe.a
or (preferred) introduce a new first target which is usually named
all:
all: exe.a lib.so
exe.a: main.c func.c
gcc main.c func.c -o exe.a
lib.so: func.c
gcc func.c -o lib.so -fPIC -shared
Now a simple make will build the (pseudo-) target all which in turn
depends on exe.a and lib.so, so they get built first. Note that you
must not have a file called all in your directory in this case because
then make gets confused.
answered Nov 23 '18 at 9:39
PerlDuck
5,36911231
Thank you. The option with the new first target is exactly what I was looking for.
– Olupo
Nov 23 '18 at 9:49
@Olupo You are welcome. When you study other Makefiles you'll encounter thisalltarget very often.
– PerlDuck
Nov 23 '18 at 9:51
I've read some other makefiles, but most of them were to advanced for my current skill level.
– Olupo
Nov 23 '18 at 9:53
2
I know exactly what you mean :-) My skills aren't very good either and when it comes to more complicated Makefiles I usually think of them as rocket science.
– PerlDuck
Nov 23 '18 at 10:04
add a comment |
By default make will build only the first target in a Makefile
which is exe.a in your case. You can either tell make to create
another target:
make lib.so
or both targets:
make lib.so exe.a
or (preferred) introduce a new first target which is usually named
all:
all: exe.a lib.so
exe.a: main.c func.c
gcc main.c func.c -o exe.a
lib.so: func.c
gcc func.c -o lib.so -fPIC -shared
Now a simple make will build the (pseudo-) target all which in turn
depends on exe.a and lib.so, so they get built first. Note that you
must not have a file called all in your directory in this case because
then make gets confused.
answered Nov 23 '18 at 9:39
PerlDuck
5,36911231
Thank you. The option with the new first target is exactly what I was looking for.
– Olupo
Nov 23 '18 at 9:49
@Olupo You are welcome. When you study other Makefiles you'll encounter thisalltarget very often.
– PerlDuck
Nov 23 '18 at 9:51
I've read some other makefiles, but most of them were to advanced for my current skill level.
– Olupo
Nov 23 '18 at 9:53
2
I know exactly what you mean :-) My skills aren't very good either and when it comes to more complicated Makefiles I usually think of them as rocket science.
– PerlDuck
Nov 23 '18 at 10:04
add a comment |
By default make will build only the first target in a Makefile
which is exe.a in your case. You can either tell make to create
another target:
make lib.so
or both targets:
make lib.so exe.a
or (preferred) introduce a new first target which is usually named
all:
all: exe.a lib.so
exe.a: main.c func.c
gcc main.c func.c -o exe.a
lib.so: func.c
gcc func.c -o lib.so -fPIC -shared
Now a simple make will build the (pseudo-) target all which in turn
depends on exe.a and lib.so, so they get built first. Note that you
must not have a file called all in your directory in this case because
then make gets confused.
answered Nov 23 '18 at 9:39
PerlDuck
5,36911231
By default make will build only the first target in a Makefile
which is exe.a in your case. You can either tell make to create
another target:
make lib.so
or both targets:
make lib.so exe.a
or (preferred) introduce a new first target which is usually named
all:
all: exe.a lib.so
exe.a: main.c func.c
gcc main.c func.c -o exe.a
lib.so: func.c
gcc func.c -o lib.so -fPIC -shared
Now a simple make will build the (pseudo-) target all which in turn
depends on exe.a and lib.so, so they get built first. Note that you
must not have a file called all in your directory in this case because
then make gets confused.
answered Nov 23 '18 at 9:39
PerlDuck
5,36911231
answered Nov 23 '18 at 9:39
PerlDuck
5,36911231
answered Nov 23 '18 at 9:39
PerlDuck
5,36911231
answered Nov 23 '18 at 9:39
PerlDuck
5,36911231
5,36911231
Thank you. The option with the new first target is exactly what I was looking for.
– Olupo
Nov 23 '18 at 9:49
@Olupo You are welcome. When you study other Makefiles you'll encounter thisalltarget very often.
– PerlDuck
Nov 23 '18 at 9:51
I've read some other makefiles, but most of them were to advanced for my current skill level.
– Olupo
Nov 23 '18 at 9:53
2
I know exactly what you mean :-) My skills aren't very good either and when it comes to more complicated Makefiles I usually think of them as rocket science.
– PerlDuck
Nov 23 '18 at 10:04
add a comment |
Thank you. The option with the new first target is exactly what I was looking for.
– Olupo
Nov 23 '18 at 9:49
@Olupo You are welcome. When you study other Makefiles you'll encounter thisalltarget very often.
– PerlDuck
Nov 23 '18 at 9:51
I've read some other makefiles, but most of them were to advanced for my current skill level.
– Olupo
Nov 23 '18 at 9:53
2
I know exactly what you mean :-) My skills aren't very good either and when it comes to more complicated Makefiles I usually think of them as rocket science.
– PerlDuck
Nov 23 '18 at 10:04
Thank you. The option with the new first target is exactly what I was looking for.
– Olupo
Nov 23 '18 at 9:49
Thank you. The option with the new first target is exactly what I was looking for.
– Olupo
Nov 23 '18 at 9:49
@Olupo You are welcome. When you study other Makefiles you'll encounter this
all target very often.– PerlDuck
Nov 23 '18 at 9:51
@Olupo You are welcome. When you study other Makefiles you'll encounter this
all target very often.– PerlDuck
Nov 23 '18 at 9:51
I've read some other makefiles, but most of them were to advanced for my current skill level.
– Olupo
Nov 23 '18 at 9:53
I've read some other makefiles, but most of them were to advanced for my current skill level.
– Olupo
Nov 23 '18 at 9:53
2
2
I know exactly what you mean :-) My skills aren't very good either and when it comes to more complicated Makefiles I usually think of them as rocket science.
– PerlDuck
Nov 23 '18 at 10:04
I know exactly what you mean :-) My skills aren't very good either and when it comes to more complicated Makefiles I usually think of them as rocket science.
– PerlDuck
Nov 23 '18 at 10:04
add a comment |
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