Reversing conditional probability
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0
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If
$$
P(B|A)=frac{P(A cap B)}{P(A)}
$$
then can the conditional probability be reversed ?
So that :
$$
P(A|B)=frac{P(B cap A)}{P(A)}
$$
probability conditional-probability
asked Nov 17 at 14:06
blue-sky
96511222
add a comment |
up vote
0
down vote
favorite
If
$$
P(B|A)=frac{P(A cap B)}{P(A)}
$$
then can the conditional probability be reversed ?
So that :
$$
P(A|B)=frac{P(B cap A)}{P(A)}
$$
probability conditional-probability
asked Nov 17 at 14:06
blue-sky
96511222
1
Just change the $P(A)$ in the denominator to $P(B)$, too.
– Parcly Taxel
Nov 17 at 14:11
Your "If" condition is always true and, of course, by symmetry, it can be reversed.
– Arnaud Mégret
Nov 17 at 15:18
Both equations are true only if $P(A)=P(B)neq 0$
– callculus
Nov 17 at 17:39
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
If
$$
P(B|A)=frac{P(A cap B)}{P(A)}
$$
then can the conditional probability be reversed ?
So that :
$$
P(A|B)=frac{P(B cap A)}{P(A)}
$$
probability conditional-probability
asked Nov 17 at 14:06
blue-sky
96511222
If
$$
P(B|A)=frac{P(A cap B)}{P(A)}
$$
then can the conditional probability be reversed ?
So that :
$$
P(A|B)=frac{P(B cap A)}{P(A)}
$$
probability conditional-probability
probability conditional-probability
asked Nov 17 at 14:06
blue-sky
96511222
asked Nov 17 at 14:06
blue-sky
96511222
asked Nov 17 at 14:06
blue-sky
96511222
asked Nov 17 at 14:06
blue-sky
96511222
asked Nov 17 at 14:06
blue-sky
96511222
96511222
1
Just change the $P(A)$ in the denominator to $P(B)$, too.
– Parcly Taxel
Nov 17 at 14:11
Your "If" condition is always true and, of course, by symmetry, it can be reversed.
– Arnaud Mégret
Nov 17 at 15:18
Both equations are true only if $P(A)=P(B)neq 0$
– callculus
Nov 17 at 17:39
add a comment |
1
Just change the $P(A)$ in the denominator to $P(B)$, too.
– Parcly Taxel
Nov 17 at 14:11
Your "If" condition is always true and, of course, by symmetry, it can be reversed.
– Arnaud Mégret
Nov 17 at 15:18
Both equations are true only if $P(A)=P(B)neq 0$
– callculus
Nov 17 at 17:39
1
1
Just change the $P(A)$ in the denominator to $P(B)$, too.
– Parcly Taxel
Nov 17 at 14:11
Just change the $P(A)$ in the denominator to $P(B)$, too.
– Parcly Taxel
Nov 17 at 14:11
Your "If" condition is always true and, of course, by symmetry, it can be reversed.
– Arnaud Mégret
Nov 17 at 15:18
Your "If" condition is always true and, of course, by symmetry, it can be reversed.
– Arnaud Mégret
Nov 17 at 15:18
Both equations are true only if $P(A)=P(B)neq 0$
– callculus
Nov 17 at 17:39
Both equations are true only if $P(A)=P(B)neq 0$
– callculus
Nov 17 at 17:39
add a comment |
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Just change the $P(A)$ in the denominator to $P(B)$, too.
– Parcly Taxel
Nov 17 at 14:11
Your "If" condition is always true and, of course, by symmetry, it can be reversed.
– Arnaud Mégret
Nov 17 at 15:18
Both equations are true only if $P(A)=P(B)neq 0$
– callculus
Nov 17 at 17:39