Determine measure unit.
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Determine a measuring unit of $B$ and $k$ if $T$ is a temperature in Kelvins, $t$ is time in seconds and $L$ is the length in meters.
$$T(t)=T - (1 - e^{-kt})(1 - B - L^2)$$
unit-of-measure
edited Nov 18 at 2:16
hanszimmer
195
asked Nov 18 at 0:48
Lind
266
add a comment |
up vote
1
down vote
favorite
Determine a measuring unit of $B$ and $k$ if $T$ is a temperature in Kelvins, $t$ is time in seconds and $L$ is the length in meters.
$$T(t)=T - (1 - e^{-kt})(1 - B - L^2)$$
unit-of-measure
edited Nov 18 at 2:16
hanszimmer
195
asked Nov 18 at 0:48
Lind
266
I assume that measuring unit for k is just $s^{-1}$ but I have no idea how to find an answer for B.
– Lind
Nov 18 at 0:55
If $L$ is length in meters then $L^2$ is meters squared, but $1$ is dimensionless so this formula literally doesn't add up. Are you sure that's exactly what it said?
– David K
Nov 18 at 2:26
I am sure, but it is probably incorrect.
– Lind
Nov 18 at 18:10
1
An error in the problem statement does appear to be likely.
– David K
Nov 18 at 19:40
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Determine a measuring unit of $B$ and $k$ if $T$ is a temperature in Kelvins, $t$ is time in seconds and $L$ is the length in meters.
$$T(t)=T - (1 - e^{-kt})(1 - B - L^2)$$
unit-of-measure
edited Nov 18 at 2:16
hanszimmer
195
asked Nov 18 at 0:48
Lind
266
Determine a measuring unit of $B$ and $k$ if $T$ is a temperature in Kelvins, $t$ is time in seconds and $L$ is the length in meters.
$$T(t)=T - (1 - e^{-kt})(1 - B - L^2)$$
unit-of-measure
unit-of-measure
edited Nov 18 at 2:16
hanszimmer
195
asked Nov 18 at 0:48
Lind
266
edited Nov 18 at 2:16
hanszimmer
195
asked Nov 18 at 0:48
Lind
266
edited Nov 18 at 2:16
hanszimmer
195
edited Nov 18 at 2:16
hanszimmer
195
edited Nov 18 at 2:16
hanszimmer
195
195
asked Nov 18 at 0:48
Lind
266
asked Nov 18 at 0:48
Lind
266
asked Nov 18 at 0:48
Lind
266
266
I assume that measuring unit for k is just $s^{-1}$ but I have no idea how to find an answer for B.
– Lind
Nov 18 at 0:55
If $L$ is length in meters then $L^2$ is meters squared, but $1$ is dimensionless so this formula literally doesn't add up. Are you sure that's exactly what it said?
– David K
Nov 18 at 2:26
I am sure, but it is probably incorrect.
– Lind
Nov 18 at 18:10
1
An error in the problem statement does appear to be likely.
– David K
Nov 18 at 19:40
add a comment |
I assume that measuring unit for k is just $s^{-1}$ but I have no idea how to find an answer for B.
– Lind
Nov 18 at 0:55
If $L$ is length in meters then $L^2$ is meters squared, but $1$ is dimensionless so this formula literally doesn't add up. Are you sure that's exactly what it said?
– David K
Nov 18 at 2:26
I am sure, but it is probably incorrect.
– Lind
Nov 18 at 18:10
1
An error in the problem statement does appear to be likely.
– David K
Nov 18 at 19:40
I assume that measuring unit for k is just $s^{-1}$ but I have no idea how to find an answer for B.
– Lind
Nov 18 at 0:55
I assume that measuring unit for k is just $s^{-1}$ but I have no idea how to find an answer for B.
– Lind
Nov 18 at 0:55
If $L$ is length in meters then $L^2$ is meters squared, but $1$ is dimensionless so this formula literally doesn't add up. Are you sure that's exactly what it said?
– David K
Nov 18 at 2:26
If $L$ is length in meters then $L^2$ is meters squared, but $1$ is dimensionless so this formula literally doesn't add up. Are you sure that's exactly what it said?
– David K
Nov 18 at 2:26
I am sure, but it is probably incorrect.
– Lind
Nov 18 at 18:10
I am sure, but it is probably incorrect.
– Lind
Nov 18 at 18:10
1
1
An error in the problem statement does appear to be likely.
– David K
Nov 18 at 19:40
An error in the problem statement does appear to be likely.
– David K
Nov 18 at 19:40
add a comment |
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I assume that measuring unit for k is just $s^{-1}$ but I have no idea how to find an answer for B.
– Lind
Nov 18 at 0:55
If $L$ is length in meters then $L^2$ is meters squared, but $1$ is dimensionless so this formula literally doesn't add up. Are you sure that's exactly what it said?
– David K
Nov 18 at 2:26
I am sure, but it is probably incorrect.
– Lind
Nov 18 at 18:10
1
An error in the problem statement does appear to be likely.
– David K
Nov 18 at 19:40