Find coordinate on circumference [closed]
Consider a body starts moving in a circular motion with linear velocity 0.02 m/s and angular velocity 0.3 rads/s. If it's initial coordinates on Cartesian plane are x=5 and y=5, where would the body be after 5 seconds in terms of coordinates?
trigonometry
closed as off-topic by Jyrki Lahtonen, Saad, Lee David Chung Lin, Gibbs, ancientmathematician Nov 22 '18 at 12:28
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Jyrki Lahtonen, Saad, Lee David Chung Lin, Gibbs, ancientmathematician
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
Consider a body starts moving in a circular motion with linear velocity 0.02 m/s and angular velocity 0.3 rads/s. If it's initial coordinates on Cartesian plane are x=5 and y=5, where would the body be after 5 seconds in terms of coordinates?
trigonometry
closed as off-topic by Jyrki Lahtonen, Saad, Lee David Chung Lin, Gibbs, ancientmathematician Nov 22 '18 at 12:28
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Jyrki Lahtonen, Saad, Lee David Chung Lin, Gibbs, ancientmathematician
If this question can be reworded to fit the rules in the help center, please edit the question.
Without an initial direction there are infinitely many solutions to this question which form a circle. Do you look for the radius of this circle or is something missing in the problem description?
– maxmilgram
Nov 19 '18 at 6:15
The body is moving in linear motion from origin (0,0) till (5,5). After (5,5) it takes a right turn
– user617365
Nov 19 '18 at 6:25
The angular velocity $omega$ and the velocity $v$ are linked via the formula $omegacdot r=v$. Using this you can calculate the radius. Let me know if you need further help.
– maxmilgram
Nov 19 '18 at 6:46
About what point is the angular velocity?
– Matti P.
Nov 19 '18 at 6:47
@maxmilgram I want to know the location of the body after 5 seconds
– user617365
Nov 19 '18 at 6:51
add a comment |
Consider a body starts moving in a circular motion with linear velocity 0.02 m/s and angular velocity 0.3 rads/s. If it's initial coordinates on Cartesian plane are x=5 and y=5, where would the body be after 5 seconds in terms of coordinates?
trigonometry
Consider a body starts moving in a circular motion with linear velocity 0.02 m/s and angular velocity 0.3 rads/s. If it's initial coordinates on Cartesian plane are x=5 and y=5, where would the body be after 5 seconds in terms of coordinates?
trigonometry
trigonometry
asked Nov 19 '18 at 5:50
user617365
41
41
closed as off-topic by Jyrki Lahtonen, Saad, Lee David Chung Lin, Gibbs, ancientmathematician Nov 22 '18 at 12:28
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Jyrki Lahtonen, Saad, Lee David Chung Lin, Gibbs, ancientmathematician
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Jyrki Lahtonen, Saad, Lee David Chung Lin, Gibbs, ancientmathematician Nov 22 '18 at 12:28
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Jyrki Lahtonen, Saad, Lee David Chung Lin, Gibbs, ancientmathematician
If this question can be reworded to fit the rules in the help center, please edit the question.
Without an initial direction there are infinitely many solutions to this question which form a circle. Do you look for the radius of this circle or is something missing in the problem description?
– maxmilgram
Nov 19 '18 at 6:15
The body is moving in linear motion from origin (0,0) till (5,5). After (5,5) it takes a right turn
– user617365
Nov 19 '18 at 6:25
The angular velocity $omega$ and the velocity $v$ are linked via the formula $omegacdot r=v$. Using this you can calculate the radius. Let me know if you need further help.
– maxmilgram
Nov 19 '18 at 6:46
About what point is the angular velocity?
– Matti P.
Nov 19 '18 at 6:47
@maxmilgram I want to know the location of the body after 5 seconds
– user617365
Nov 19 '18 at 6:51
add a comment |
Without an initial direction there are infinitely many solutions to this question which form a circle. Do you look for the radius of this circle or is something missing in the problem description?
– maxmilgram
Nov 19 '18 at 6:15
The body is moving in linear motion from origin (0,0) till (5,5). After (5,5) it takes a right turn
– user617365
Nov 19 '18 at 6:25
The angular velocity $omega$ and the velocity $v$ are linked via the formula $omegacdot r=v$. Using this you can calculate the radius. Let me know if you need further help.
– maxmilgram
Nov 19 '18 at 6:46
About what point is the angular velocity?
– Matti P.
Nov 19 '18 at 6:47
@maxmilgram I want to know the location of the body after 5 seconds
– user617365
Nov 19 '18 at 6:51
Without an initial direction there are infinitely many solutions to this question which form a circle. Do you look for the radius of this circle or is something missing in the problem description?
– maxmilgram
Nov 19 '18 at 6:15
Without an initial direction there are infinitely many solutions to this question which form a circle. Do you look for the radius of this circle or is something missing in the problem description?
– maxmilgram
Nov 19 '18 at 6:15
The body is moving in linear motion from origin (0,0) till (5,5). After (5,5) it takes a right turn
– user617365
Nov 19 '18 at 6:25
The body is moving in linear motion from origin (0,0) till (5,5). After (5,5) it takes a right turn
– user617365
Nov 19 '18 at 6:25
The angular velocity $omega$ and the velocity $v$ are linked via the formula $omegacdot r=v$. Using this you can calculate the radius. Let me know if you need further help.
– maxmilgram
Nov 19 '18 at 6:46
The angular velocity $omega$ and the velocity $v$ are linked via the formula $omegacdot r=v$. Using this you can calculate the radius. Let me know if you need further help.
– maxmilgram
Nov 19 '18 at 6:46
About what point is the angular velocity?
– Matti P.
Nov 19 '18 at 6:47
About what point is the angular velocity?
– Matti P.
Nov 19 '18 at 6:47
@maxmilgram I want to know the location of the body after 5 seconds
– user617365
Nov 19 '18 at 6:51
@maxmilgram I want to know the location of the body after 5 seconds
– user617365
Nov 19 '18 at 6:51
add a comment |
2 Answers
2
active
oldest
votes
With the additional information from the comments the problem can be solved in the following way:
Calculate the radius $r$ of the circular motion by using $omegacdot r = v$. Here, $omega$ is the angular velocity and $v$ is the velocity.
Calculate the center point of the circular motion.
Calculate the total angle covered in 5 seconds: $varphi=omegacdot5$.
Use trigonometric functions or vector algebra to deduce the endpoint of the motion after 5 seconds.
Hope that helps! :-)
Thank you very much for the quick solution. How to find out the center point of the circular motion?
– user617365
Nov 19 '18 at 7:06
You know the radius and you know that the mid point is orthogonal to the current direction of movement (at point $(5,5)$).
– maxmilgram
Nov 19 '18 at 7:24
add a comment |
Assuming the motion in clockwise direction, we have
- $x-x_0=Rcos (omega cdot t)$
- $y-y_0=-Rsin (omega cdot t)$
with
$omega=0.3$ rad/s
$v=omegacdot R=0.02$ m/s $implies R=frac {2}{30}$m
where $(x_0,y_0)$ are the coordinates of the center of motion lying on the line $y=x$ such that the distance form $(5,5)$ is equal to $R$.
Note that assuming the motion couterclock wise we can fine another valid solution.
The OP added some information in the comments below his post.
– maxmilgram
Nov 19 '18 at 7:21
@maxmilgram Thanks, I see that now, then it seems moving clockwise!
– gimusi
Nov 19 '18 at 7:23
from what I understood the center of motion is not at the origin. However the problem is very vaguely posed so I might be wrong. :-D
– maxmilgram
Nov 19 '18 at 7:25
@maxmilgram Yes I think you are right! We can find the center of motion from the given conditions.
– gimusi
Nov 19 '18 at 7:27
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
With the additional information from the comments the problem can be solved in the following way:
Calculate the radius $r$ of the circular motion by using $omegacdot r = v$. Here, $omega$ is the angular velocity and $v$ is the velocity.
Calculate the center point of the circular motion.
Calculate the total angle covered in 5 seconds: $varphi=omegacdot5$.
Use trigonometric functions or vector algebra to deduce the endpoint of the motion after 5 seconds.
Hope that helps! :-)
Thank you very much for the quick solution. How to find out the center point of the circular motion?
– user617365
Nov 19 '18 at 7:06
You know the radius and you know that the mid point is orthogonal to the current direction of movement (at point $(5,5)$).
– maxmilgram
Nov 19 '18 at 7:24
add a comment |
With the additional information from the comments the problem can be solved in the following way:
Calculate the radius $r$ of the circular motion by using $omegacdot r = v$. Here, $omega$ is the angular velocity and $v$ is the velocity.
Calculate the center point of the circular motion.
Calculate the total angle covered in 5 seconds: $varphi=omegacdot5$.
Use trigonometric functions or vector algebra to deduce the endpoint of the motion after 5 seconds.
Hope that helps! :-)
Thank you very much for the quick solution. How to find out the center point of the circular motion?
– user617365
Nov 19 '18 at 7:06
You know the radius and you know that the mid point is orthogonal to the current direction of movement (at point $(5,5)$).
– maxmilgram
Nov 19 '18 at 7:24
add a comment |
With the additional information from the comments the problem can be solved in the following way:
Calculate the radius $r$ of the circular motion by using $omegacdot r = v$. Here, $omega$ is the angular velocity and $v$ is the velocity.
Calculate the center point of the circular motion.
Calculate the total angle covered in 5 seconds: $varphi=omegacdot5$.
Use trigonometric functions or vector algebra to deduce the endpoint of the motion after 5 seconds.
Hope that helps! :-)
With the additional information from the comments the problem can be solved in the following way:
Calculate the radius $r$ of the circular motion by using $omegacdot r = v$. Here, $omega$ is the angular velocity and $v$ is the velocity.
Calculate the center point of the circular motion.
Calculate the total angle covered in 5 seconds: $varphi=omegacdot5$.
Use trigonometric functions or vector algebra to deduce the endpoint of the motion after 5 seconds.
Hope that helps! :-)
edited Nov 19 '18 at 7:21
answered Nov 19 '18 at 7:01
maxmilgram
4327
4327
Thank you very much for the quick solution. How to find out the center point of the circular motion?
– user617365
Nov 19 '18 at 7:06
You know the radius and you know that the mid point is orthogonal to the current direction of movement (at point $(5,5)$).
– maxmilgram
Nov 19 '18 at 7:24
add a comment |
Thank you very much for the quick solution. How to find out the center point of the circular motion?
– user617365
Nov 19 '18 at 7:06
You know the radius and you know that the mid point is orthogonal to the current direction of movement (at point $(5,5)$).
– maxmilgram
Nov 19 '18 at 7:24
Thank you very much for the quick solution. How to find out the center point of the circular motion?
– user617365
Nov 19 '18 at 7:06
Thank you very much for the quick solution. How to find out the center point of the circular motion?
– user617365
Nov 19 '18 at 7:06
You know the radius and you know that the mid point is orthogonal to the current direction of movement (at point $(5,5)$).
– maxmilgram
Nov 19 '18 at 7:24
You know the radius and you know that the mid point is orthogonal to the current direction of movement (at point $(5,5)$).
– maxmilgram
Nov 19 '18 at 7:24
add a comment |
Assuming the motion in clockwise direction, we have
- $x-x_0=Rcos (omega cdot t)$
- $y-y_0=-Rsin (omega cdot t)$
with
$omega=0.3$ rad/s
$v=omegacdot R=0.02$ m/s $implies R=frac {2}{30}$m
where $(x_0,y_0)$ are the coordinates of the center of motion lying on the line $y=x$ such that the distance form $(5,5)$ is equal to $R$.
Note that assuming the motion couterclock wise we can fine another valid solution.
The OP added some information in the comments below his post.
– maxmilgram
Nov 19 '18 at 7:21
@maxmilgram Thanks, I see that now, then it seems moving clockwise!
– gimusi
Nov 19 '18 at 7:23
from what I understood the center of motion is not at the origin. However the problem is very vaguely posed so I might be wrong. :-D
– maxmilgram
Nov 19 '18 at 7:25
@maxmilgram Yes I think you are right! We can find the center of motion from the given conditions.
– gimusi
Nov 19 '18 at 7:27
add a comment |
Assuming the motion in clockwise direction, we have
- $x-x_0=Rcos (omega cdot t)$
- $y-y_0=-Rsin (omega cdot t)$
with
$omega=0.3$ rad/s
$v=omegacdot R=0.02$ m/s $implies R=frac {2}{30}$m
where $(x_0,y_0)$ are the coordinates of the center of motion lying on the line $y=x$ such that the distance form $(5,5)$ is equal to $R$.
Note that assuming the motion couterclock wise we can fine another valid solution.
The OP added some information in the comments below his post.
– maxmilgram
Nov 19 '18 at 7:21
@maxmilgram Thanks, I see that now, then it seems moving clockwise!
– gimusi
Nov 19 '18 at 7:23
from what I understood the center of motion is not at the origin. However the problem is very vaguely posed so I might be wrong. :-D
– maxmilgram
Nov 19 '18 at 7:25
@maxmilgram Yes I think you are right! We can find the center of motion from the given conditions.
– gimusi
Nov 19 '18 at 7:27
add a comment |
Assuming the motion in clockwise direction, we have
- $x-x_0=Rcos (omega cdot t)$
- $y-y_0=-Rsin (omega cdot t)$
with
$omega=0.3$ rad/s
$v=omegacdot R=0.02$ m/s $implies R=frac {2}{30}$m
where $(x_0,y_0)$ are the coordinates of the center of motion lying on the line $y=x$ such that the distance form $(5,5)$ is equal to $R$.
Note that assuming the motion couterclock wise we can fine another valid solution.
Assuming the motion in clockwise direction, we have
- $x-x_0=Rcos (omega cdot t)$
- $y-y_0=-Rsin (omega cdot t)$
with
$omega=0.3$ rad/s
$v=omegacdot R=0.02$ m/s $implies R=frac {2}{30}$m
where $(x_0,y_0)$ are the coordinates of the center of motion lying on the line $y=x$ such that the distance form $(5,5)$ is equal to $R$.
Note that assuming the motion couterclock wise we can fine another valid solution.
edited Nov 19 '18 at 7:32
answered Nov 19 '18 at 7:16
gimusi
1
1
The OP added some information in the comments below his post.
– maxmilgram
Nov 19 '18 at 7:21
@maxmilgram Thanks, I see that now, then it seems moving clockwise!
– gimusi
Nov 19 '18 at 7:23
from what I understood the center of motion is not at the origin. However the problem is very vaguely posed so I might be wrong. :-D
– maxmilgram
Nov 19 '18 at 7:25
@maxmilgram Yes I think you are right! We can find the center of motion from the given conditions.
– gimusi
Nov 19 '18 at 7:27
add a comment |
The OP added some information in the comments below his post.
– maxmilgram
Nov 19 '18 at 7:21
@maxmilgram Thanks, I see that now, then it seems moving clockwise!
– gimusi
Nov 19 '18 at 7:23
from what I understood the center of motion is not at the origin. However the problem is very vaguely posed so I might be wrong. :-D
– maxmilgram
Nov 19 '18 at 7:25
@maxmilgram Yes I think you are right! We can find the center of motion from the given conditions.
– gimusi
Nov 19 '18 at 7:27
The OP added some information in the comments below his post.
– maxmilgram
Nov 19 '18 at 7:21
The OP added some information in the comments below his post.
– maxmilgram
Nov 19 '18 at 7:21
@maxmilgram Thanks, I see that now, then it seems moving clockwise!
– gimusi
Nov 19 '18 at 7:23
@maxmilgram Thanks, I see that now, then it seems moving clockwise!
– gimusi
Nov 19 '18 at 7:23
from what I understood the center of motion is not at the origin. However the problem is very vaguely posed so I might be wrong. :-D
– maxmilgram
Nov 19 '18 at 7:25
from what I understood the center of motion is not at the origin. However the problem is very vaguely posed so I might be wrong. :-D
– maxmilgram
Nov 19 '18 at 7:25
@maxmilgram Yes I think you are right! We can find the center of motion from the given conditions.
– gimusi
Nov 19 '18 at 7:27
@maxmilgram Yes I think you are right! We can find the center of motion from the given conditions.
– gimusi
Nov 19 '18 at 7:27
add a comment |
Without an initial direction there are infinitely many solutions to this question which form a circle. Do you look for the radius of this circle or is something missing in the problem description?
– maxmilgram
Nov 19 '18 at 6:15
The body is moving in linear motion from origin (0,0) till (5,5). After (5,5) it takes a right turn
– user617365
Nov 19 '18 at 6:25
The angular velocity $omega$ and the velocity $v$ are linked via the formula $omegacdot r=v$. Using this you can calculate the radius. Let me know if you need further help.
– maxmilgram
Nov 19 '18 at 6:46
About what point is the angular velocity?
– Matti P.
Nov 19 '18 at 6:47
@maxmilgram I want to know the location of the body after 5 seconds
– user617365
Nov 19 '18 at 6:51