Given a random sample size 40 from a binomial population, where p = 0.25 calculate the probability that the...
Given a random sample size 40 from a binomial population, where p = 0.25 calculate the probability that the sample ratio is between 0.20 and 0.30.
I don't have a clear idea of how solve this exercise:
Can someone help me?
probability
asked Nov 19 '18 at 2:17
Bvss12
1,744617
add a comment |
Given a random sample size 40 from a binomial population, where p = 0.25 calculate the probability that the sample ratio is between 0.20 and 0.30.
I don't have a clear idea of how solve this exercise:
Can someone help me?
probability
asked Nov 19 '18 at 2:17
Bvss12
1,744617
add a comment |
Given a random sample size 40 from a binomial population, where p = 0.25 calculate the probability that the sample ratio is between 0.20 and 0.30.
I don't have a clear idea of how solve this exercise:
Can someone help me?
probability
asked Nov 19 '18 at 2:17
Bvss12
1,744617
Given a random sample size 40 from a binomial population, where p = 0.25 calculate the probability that the sample ratio is between 0.20 and 0.30.
I don't have a clear idea of how solve this exercise:
Can someone help me?
probability
probability
asked Nov 19 '18 at 2:17
Bvss12
1,744617
asked Nov 19 '18 at 2:17
Bvss12
1,744617
asked Nov 19 '18 at 2:17
Bvss12
1,744617
asked Nov 19 '18 at 2:17
Bvss12
1,744617
asked Nov 19 '18 at 2:17
Bvss12
1,744617
1,744617
add a comment |
add a comment |
1 Answer
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It looks like you need to use the binomial distribution. The specific answer is $sum_{k=8}^{12}binom{40}{k}.25^k.75^{40-k}$. $k=8$ to $ 12$ comes from $.20,.30$ times $40$.
answered Nov 19 '18 at 2:31
herb steinberg
2,4982310
add a comment |
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1 Answer
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1 Answer
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It looks like you need to use the binomial distribution. The specific answer is $sum_{k=8}^{12}binom{40}{k}.25^k.75^{40-k}$. $k=8$ to $ 12$ comes from $.20,.30$ times $40$.
answered Nov 19 '18 at 2:31
herb steinberg
2,4982310
add a comment |
It looks like you need to use the binomial distribution. The specific answer is $sum_{k=8}^{12}binom{40}{k}.25^k.75^{40-k}$. $k=8$ to $ 12$ comes from $.20,.30$ times $40$.
answered Nov 19 '18 at 2:31
herb steinberg
2,4982310
add a comment |
It looks like you need to use the binomial distribution. The specific answer is $sum_{k=8}^{12}binom{40}{k}.25^k.75^{40-k}$. $k=8$ to $ 12$ comes from $.20,.30$ times $40$.
answered Nov 19 '18 at 2:31
herb steinberg
2,4982310
It looks like you need to use the binomial distribution. The specific answer is $sum_{k=8}^{12}binom{40}{k}.25^k.75^{40-k}$. $k=8$ to $ 12$ comes from $.20,.30$ times $40$.
answered Nov 19 '18 at 2:31
herb steinberg
2,4982310
answered Nov 19 '18 at 2:31
herb steinberg
2,4982310
answered Nov 19 '18 at 2:31
herb steinberg
2,4982310
answered Nov 19 '18 at 2:31
herb steinberg
2,4982310
2,4982310
add a comment |
add a comment |
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