Known conditions to make $A otimes B$ be pos.def., even if $A$ is not pos.def.?











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Are there conditions that I should demand to be sure that $A otimes B$ is positive definite, even when allowing $A$ not being positive definite, while $B$ is positive definite?










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    I suppose $A$ and $B$ could both be negative definite.
    – Lord Shark the Unknown
    Nov 17 at 17:12










  • @LordSharktheUnknown Thanks for the comment. I forgot the $B$ matrix must be pos.def. , and edited the question accordingly. I'm sorry for my error,.
    – An old man in the sea.
    Nov 17 at 17:14








  • 1




    In this context, does positive definite mean symmetric?
    – Omnomnomnom
    Nov 17 at 23:45










  • Assuming positive definite means symmetric here: If $B$ is positive definite, then $A otimes B$ will be positive definite if and only if $A$ is also positive definite.
    – Omnomnomnom
    Nov 17 at 23:47















up vote
0
down vote

favorite












Are there conditions that I should demand to be sure that $A otimes B$ is positive definite, even when allowing $A$ not being positive definite, while $B$ is positive definite?










share|cite|improve this question




















  • 1




    I suppose $A$ and $B$ could both be negative definite.
    – Lord Shark the Unknown
    Nov 17 at 17:12










  • @LordSharktheUnknown Thanks for the comment. I forgot the $B$ matrix must be pos.def. , and edited the question accordingly. I'm sorry for my error,.
    – An old man in the sea.
    Nov 17 at 17:14








  • 1




    In this context, does positive definite mean symmetric?
    – Omnomnomnom
    Nov 17 at 23:45










  • Assuming positive definite means symmetric here: If $B$ is positive definite, then $A otimes B$ will be positive definite if and only if $A$ is also positive definite.
    – Omnomnomnom
    Nov 17 at 23:47













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Are there conditions that I should demand to be sure that $A otimes B$ is positive definite, even when allowing $A$ not being positive definite, while $B$ is positive definite?










share|cite|improve this question















Are there conditions that I should demand to be sure that $A otimes B$ is positive definite, even when allowing $A$ not being positive definite, while $B$ is positive definite?







linear-algebra matrices tensor-products positive-definite






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share|cite|improve this question













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edited Nov 17 at 17:13

























asked Nov 17 at 16:54









An old man in the sea.

1,60411031




1,60411031








  • 1




    I suppose $A$ and $B$ could both be negative definite.
    – Lord Shark the Unknown
    Nov 17 at 17:12










  • @LordSharktheUnknown Thanks for the comment. I forgot the $B$ matrix must be pos.def. , and edited the question accordingly. I'm sorry for my error,.
    – An old man in the sea.
    Nov 17 at 17:14








  • 1




    In this context, does positive definite mean symmetric?
    – Omnomnomnom
    Nov 17 at 23:45










  • Assuming positive definite means symmetric here: If $B$ is positive definite, then $A otimes B$ will be positive definite if and only if $A$ is also positive definite.
    – Omnomnomnom
    Nov 17 at 23:47














  • 1




    I suppose $A$ and $B$ could both be negative definite.
    – Lord Shark the Unknown
    Nov 17 at 17:12










  • @LordSharktheUnknown Thanks for the comment. I forgot the $B$ matrix must be pos.def. , and edited the question accordingly. I'm sorry for my error,.
    – An old man in the sea.
    Nov 17 at 17:14








  • 1




    In this context, does positive definite mean symmetric?
    – Omnomnomnom
    Nov 17 at 23:45










  • Assuming positive definite means symmetric here: If $B$ is positive definite, then $A otimes B$ will be positive definite if and only if $A$ is also positive definite.
    – Omnomnomnom
    Nov 17 at 23:47








1




1




I suppose $A$ and $B$ could both be negative definite.
– Lord Shark the Unknown
Nov 17 at 17:12




I suppose $A$ and $B$ could both be negative definite.
– Lord Shark the Unknown
Nov 17 at 17:12












@LordSharktheUnknown Thanks for the comment. I forgot the $B$ matrix must be pos.def. , and edited the question accordingly. I'm sorry for my error,.
– An old man in the sea.
Nov 17 at 17:14






@LordSharktheUnknown Thanks for the comment. I forgot the $B$ matrix must be pos.def. , and edited the question accordingly. I'm sorry for my error,.
– An old man in the sea.
Nov 17 at 17:14






1




1




In this context, does positive definite mean symmetric?
– Omnomnomnom
Nov 17 at 23:45




In this context, does positive definite mean symmetric?
– Omnomnomnom
Nov 17 at 23:45












Assuming positive definite means symmetric here: If $B$ is positive definite, then $A otimes B$ will be positive definite if and only if $A$ is also positive definite.
– Omnomnomnom
Nov 17 at 23:47




Assuming positive definite means symmetric here: If $B$ is positive definite, then $A otimes B$ will be positive definite if and only if $A$ is also positive definite.
– Omnomnomnom
Nov 17 at 23:47















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