Back propagation equation proof











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I am trying to prove this equation (from the backpropagation equations in AI).



$$frac{partial C}{partial b_j^l} = delta_j^l$$



C is the cost function: $C = frac{1}{2}||y - a^L||^2$



Where the output of layer l and neuron j is express like so $a^l_j=σ(∑_kw^l_{jk}a^{l−1}_k+b^l_j)$



I am suppose to use this assertion to do the demonstration: $delta_j^L = frac{partial C}{partial z_j^L}$



So far, here is what I have tried:



$$frac{partial C}{partial z_j^L} = sum_k frac{partial C}{partial z_j^L} frac{partial b_j^l}{partial b_j^L} $$ (I am using the chain rule to have a sum)



<=> $$frac{partial C}{partial z_j^L} = sum_k frac{partial C}{partial b_j^l} frac{partial b_j^l}{partial z_j^L} $$



So I guess I have to prove, that $frac{partial b_j^l}{partial z_j^L}$ equals 1.



But I don't have any ideas how to prove it.



Thanks for your help



N.B
I am following this course => http://neuralnetworksanddeeplearning.com/chap2.html where the first two equations of the BackPropagation equations are already proved, and the 2 others should be proved the same way (using the chain rule)










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    up vote
    0
    down vote

    favorite












    I am trying to prove this equation (from the backpropagation equations in AI).



    $$frac{partial C}{partial b_j^l} = delta_j^l$$



    C is the cost function: $C = frac{1}{2}||y - a^L||^2$



    Where the output of layer l and neuron j is express like so $a^l_j=σ(∑_kw^l_{jk}a^{l−1}_k+b^l_j)$



    I am suppose to use this assertion to do the demonstration: $delta_j^L = frac{partial C}{partial z_j^L}$



    So far, here is what I have tried:



    $$frac{partial C}{partial z_j^L} = sum_k frac{partial C}{partial z_j^L} frac{partial b_j^l}{partial b_j^L} $$ (I am using the chain rule to have a sum)



    <=> $$frac{partial C}{partial z_j^L} = sum_k frac{partial C}{partial b_j^l} frac{partial b_j^l}{partial z_j^L} $$



    So I guess I have to prove, that $frac{partial b_j^l}{partial z_j^L}$ equals 1.



    But I don't have any ideas how to prove it.



    Thanks for your help



    N.B
    I am following this course => http://neuralnetworksanddeeplearning.com/chap2.html where the first two equations of the BackPropagation equations are already proved, and the 2 others should be proved the same way (using the chain rule)










    share|cite|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I am trying to prove this equation (from the backpropagation equations in AI).



      $$frac{partial C}{partial b_j^l} = delta_j^l$$



      C is the cost function: $C = frac{1}{2}||y - a^L||^2$



      Where the output of layer l and neuron j is express like so $a^l_j=σ(∑_kw^l_{jk}a^{l−1}_k+b^l_j)$



      I am suppose to use this assertion to do the demonstration: $delta_j^L = frac{partial C}{partial z_j^L}$



      So far, here is what I have tried:



      $$frac{partial C}{partial z_j^L} = sum_k frac{partial C}{partial z_j^L} frac{partial b_j^l}{partial b_j^L} $$ (I am using the chain rule to have a sum)



      <=> $$frac{partial C}{partial z_j^L} = sum_k frac{partial C}{partial b_j^l} frac{partial b_j^l}{partial z_j^L} $$



      So I guess I have to prove, that $frac{partial b_j^l}{partial z_j^L}$ equals 1.



      But I don't have any ideas how to prove it.



      Thanks for your help



      N.B
      I am following this course => http://neuralnetworksanddeeplearning.com/chap2.html where the first two equations of the BackPropagation equations are already proved, and the 2 others should be proved the same way (using the chain rule)










      share|cite|improve this question













      I am trying to prove this equation (from the backpropagation equations in AI).



      $$frac{partial C}{partial b_j^l} = delta_j^l$$



      C is the cost function: $C = frac{1}{2}||y - a^L||^2$



      Where the output of layer l and neuron j is express like so $a^l_j=σ(∑_kw^l_{jk}a^{l−1}_k+b^l_j)$



      I am suppose to use this assertion to do the demonstration: $delta_j^L = frac{partial C}{partial z_j^L}$



      So far, here is what I have tried:



      $$frac{partial C}{partial z_j^L} = sum_k frac{partial C}{partial z_j^L} frac{partial b_j^l}{partial b_j^L} $$ (I am using the chain rule to have a sum)



      <=> $$frac{partial C}{partial z_j^L} = sum_k frac{partial C}{partial b_j^l} frac{partial b_j^l}{partial z_j^L} $$



      So I guess I have to prove, that $frac{partial b_j^l}{partial z_j^L}$ equals 1.



      But I don't have any ideas how to prove it.



      Thanks for your help



      N.B
      I am following this course => http://neuralnetworksanddeeplearning.com/chap2.html where the first two equations of the BackPropagation equations are already proved, and the 2 others should be proved the same way (using the chain rule)







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      asked Nov 18 at 13:41









      Unepierre

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