functional calculus for non-unital $C^*$ algebras
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If $A$ is a non-unital $C^*$ algebra,$a$ is a normal element of $A$, there is a $*$ isometric isomorphism from $C_0(sigma_{A}(a))$ to $C^*(a)$.
I have a question:what is the set of $C_0(sigma_{A}(a))$?Is it the set of all continuous functions $f$ defined on $sigma_{A}(a) $ which vanish at infinity? or besides, we need $f(0)=0$? see continuous functional calculus for nonunital $c^*$-algebras
operator-theory operator-algebras c-star-algebras von-neumann-algebras
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If $A$ is a non-unital $C^*$ algebra,$a$ is a normal element of $A$, there is a $*$ isometric isomorphism from $C_0(sigma_{A}(a))$ to $C^*(a)$.
I have a question:what is the set of $C_0(sigma_{A}(a))$?Is it the set of all continuous functions $f$ defined on $sigma_{A}(a) $ which vanish at infinity? or besides, we need $f(0)=0$? see continuous functional calculus for nonunital $c^*$-algebras
operator-theory operator-algebras c-star-algebras von-neumann-algebras
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
If $A$ is a non-unital $C^*$ algebra,$a$ is a normal element of $A$, there is a $*$ isometric isomorphism from $C_0(sigma_{A}(a))$ to $C^*(a)$.
I have a question:what is the set of $C_0(sigma_{A}(a))$?Is it the set of all continuous functions $f$ defined on $sigma_{A}(a) $ which vanish at infinity? or besides, we need $f(0)=0$? see continuous functional calculus for nonunital $c^*$-algebras
operator-theory operator-algebras c-star-algebras von-neumann-algebras
If $A$ is a non-unital $C^*$ algebra,$a$ is a normal element of $A$, there is a $*$ isometric isomorphism from $C_0(sigma_{A}(a))$ to $C^*(a)$.
I have a question:what is the set of $C_0(sigma_{A}(a))$?Is it the set of all continuous functions $f$ defined on $sigma_{A}(a) $ which vanish at infinity? or besides, we need $f(0)=0$? see continuous functional calculus for nonunital $c^*$-algebras
operator-theory operator-algebras c-star-algebras von-neumann-algebras
operator-theory operator-algebras c-star-algebras von-neumann-algebras
asked Nov 18 at 11:20
mathrookie
722512
722512
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No, it's just bad notation. When $A$ is not unital and you consider the C$^*$-algebra generated by $a$ in $A$, it cannot contain the unit of $A$. So when $a$ is normal C$^*(a)$ is the closure of the span of the words in $a$ and $a^*$, without constants.
The spectrum $sigma(A)$ is compact, so $C(sigma(A)$ is unital. For the identification $C^*(a)simeq C_0(sigma(a))$, one is taking the continuous functions where $f(0)=0$. That's what the subscript means. It's bad notation because it is not the set of functions that vanish at infinity.
So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
– mathrookie
Nov 18 at 12:26
Not usually, but it is in what you wrote. It's a really bad choice of notation.
– Martin Argerami
Nov 18 at 12:54
what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
– mathrookie
Nov 18 at 13:05
Standard notation for what ?
– André S.
Nov 18 at 15:19
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
No, it's just bad notation. When $A$ is not unital and you consider the C$^*$-algebra generated by $a$ in $A$, it cannot contain the unit of $A$. So when $a$ is normal C$^*(a)$ is the closure of the span of the words in $a$ and $a^*$, without constants.
The spectrum $sigma(A)$ is compact, so $C(sigma(A)$ is unital. For the identification $C^*(a)simeq C_0(sigma(a))$, one is taking the continuous functions where $f(0)=0$. That's what the subscript means. It's bad notation because it is not the set of functions that vanish at infinity.
So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
– mathrookie
Nov 18 at 12:26
Not usually, but it is in what you wrote. It's a really bad choice of notation.
– Martin Argerami
Nov 18 at 12:54
what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
– mathrookie
Nov 18 at 13:05
Standard notation for what ?
– André S.
Nov 18 at 15:19
add a comment |
up vote
1
down vote
accepted
No, it's just bad notation. When $A$ is not unital and you consider the C$^*$-algebra generated by $a$ in $A$, it cannot contain the unit of $A$. So when $a$ is normal C$^*(a)$ is the closure of the span of the words in $a$ and $a^*$, without constants.
The spectrum $sigma(A)$ is compact, so $C(sigma(A)$ is unital. For the identification $C^*(a)simeq C_0(sigma(a))$, one is taking the continuous functions where $f(0)=0$. That's what the subscript means. It's bad notation because it is not the set of functions that vanish at infinity.
So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
– mathrookie
Nov 18 at 12:26
Not usually, but it is in what you wrote. It's a really bad choice of notation.
– Martin Argerami
Nov 18 at 12:54
what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
– mathrookie
Nov 18 at 13:05
Standard notation for what ?
– André S.
Nov 18 at 15:19
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
No, it's just bad notation. When $A$ is not unital and you consider the C$^*$-algebra generated by $a$ in $A$, it cannot contain the unit of $A$. So when $a$ is normal C$^*(a)$ is the closure of the span of the words in $a$ and $a^*$, without constants.
The spectrum $sigma(A)$ is compact, so $C(sigma(A)$ is unital. For the identification $C^*(a)simeq C_0(sigma(a))$, one is taking the continuous functions where $f(0)=0$. That's what the subscript means. It's bad notation because it is not the set of functions that vanish at infinity.
No, it's just bad notation. When $A$ is not unital and you consider the C$^*$-algebra generated by $a$ in $A$, it cannot contain the unit of $A$. So when $a$ is normal C$^*(a)$ is the closure of the span of the words in $a$ and $a^*$, without constants.
The spectrum $sigma(A)$ is compact, so $C(sigma(A)$ is unital. For the identification $C^*(a)simeq C_0(sigma(a))$, one is taking the continuous functions where $f(0)=0$. That's what the subscript means. It's bad notation because it is not the set of functions that vanish at infinity.
answered Nov 18 at 12:09
Martin Argerami
122k1174172
122k1174172
So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
– mathrookie
Nov 18 at 12:26
Not usually, but it is in what you wrote. It's a really bad choice of notation.
– Martin Argerami
Nov 18 at 12:54
what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
– mathrookie
Nov 18 at 13:05
Standard notation for what ?
– André S.
Nov 18 at 15:19
add a comment |
So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
– mathrookie
Nov 18 at 12:26
Not usually, but it is in what you wrote. It's a really bad choice of notation.
– Martin Argerami
Nov 18 at 12:54
what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
– mathrookie
Nov 18 at 13:05
Standard notation for what ?
– André S.
Nov 18 at 15:19
So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
– mathrookie
Nov 18 at 12:26
So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
– mathrookie
Nov 18 at 12:26
Not usually, but it is in what you wrote. It's a really bad choice of notation.
– Martin Argerami
Nov 18 at 12:54
Not usually, but it is in what you wrote. It's a really bad choice of notation.
– Martin Argerami
Nov 18 at 12:54
what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
– mathrookie
Nov 18 at 13:05
what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
– mathrookie
Nov 18 at 13:05
Standard notation for what ?
– André S.
Nov 18 at 15:19
Standard notation for what ?
– André S.
Nov 18 at 15:19
add a comment |
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