functional calculus for non-unital $C^*$ algebras











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If $A$ is a non-unital $C^*$ algebra,$a$ is a normal element of $A$, there is a $*$ isometric isomorphism from $C_0(sigma_{A}(a))$ to $C^*(a)$.



I have a question:what is the set of $C_0(sigma_{A}(a))$?Is it the set of all continuous functions $f$ defined on $sigma_{A}(a) $ which vanish at infinity? or besides, we need $f(0)=0$? see continuous functional calculus for nonunital $c^*$-algebras










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    up vote
    1
    down vote

    favorite












    If $A$ is a non-unital $C^*$ algebra,$a$ is a normal element of $A$, there is a $*$ isometric isomorphism from $C_0(sigma_{A}(a))$ to $C^*(a)$.



    I have a question:what is the set of $C_0(sigma_{A}(a))$?Is it the set of all continuous functions $f$ defined on $sigma_{A}(a) $ which vanish at infinity? or besides, we need $f(0)=0$? see continuous functional calculus for nonunital $c^*$-algebras










    share|cite|improve this question
























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      If $A$ is a non-unital $C^*$ algebra,$a$ is a normal element of $A$, there is a $*$ isometric isomorphism from $C_0(sigma_{A}(a))$ to $C^*(a)$.



      I have a question:what is the set of $C_0(sigma_{A}(a))$?Is it the set of all continuous functions $f$ defined on $sigma_{A}(a) $ which vanish at infinity? or besides, we need $f(0)=0$? see continuous functional calculus for nonunital $c^*$-algebras










      share|cite|improve this question













      If $A$ is a non-unital $C^*$ algebra,$a$ is a normal element of $A$, there is a $*$ isometric isomorphism from $C_0(sigma_{A}(a))$ to $C^*(a)$.



      I have a question:what is the set of $C_0(sigma_{A}(a))$?Is it the set of all continuous functions $f$ defined on $sigma_{A}(a) $ which vanish at infinity? or besides, we need $f(0)=0$? see continuous functional calculus for nonunital $c^*$-algebras







      operator-theory operator-algebras c-star-algebras von-neumann-algebras






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      asked Nov 18 at 11:20









      mathrookie

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          No, it's just bad notation. When $A$ is not unital and you consider the C$^*$-algebra generated by $a$ in $A$, it cannot contain the unit of $A$. So when $a$ is normal C$^*(a)$ is the closure of the span of the words in $a$ and $a^*$, without constants.



          The spectrum $sigma(A)$ is compact, so $C(sigma(A)$ is unital. For the identification $C^*(a)simeq C_0(sigma(a))$, one is taking the continuous functions where $f(0)=0$. That's what the subscript means. It's bad notation because it is not the set of functions that vanish at infinity.






          share|cite|improve this answer





















          • So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
            – mathrookie
            Nov 18 at 12:26










          • Not usually, but it is in what you wrote. It's a really bad choice of notation.
            – Martin Argerami
            Nov 18 at 12:54










          • what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
            – mathrookie
            Nov 18 at 13:05












          • Standard notation for what ?
            – André S.
            Nov 18 at 15:19











          Your Answer





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          up vote
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          down vote



          accepted










          No, it's just bad notation. When $A$ is not unital and you consider the C$^*$-algebra generated by $a$ in $A$, it cannot contain the unit of $A$. So when $a$ is normal C$^*(a)$ is the closure of the span of the words in $a$ and $a^*$, without constants.



          The spectrum $sigma(A)$ is compact, so $C(sigma(A)$ is unital. For the identification $C^*(a)simeq C_0(sigma(a))$, one is taking the continuous functions where $f(0)=0$. That's what the subscript means. It's bad notation because it is not the set of functions that vanish at infinity.






          share|cite|improve this answer





















          • So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
            – mathrookie
            Nov 18 at 12:26










          • Not usually, but it is in what you wrote. It's a really bad choice of notation.
            – Martin Argerami
            Nov 18 at 12:54










          • what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
            – mathrookie
            Nov 18 at 13:05












          • Standard notation for what ?
            – André S.
            Nov 18 at 15:19















          up vote
          1
          down vote



          accepted










          No, it's just bad notation. When $A$ is not unital and you consider the C$^*$-algebra generated by $a$ in $A$, it cannot contain the unit of $A$. So when $a$ is normal C$^*(a)$ is the closure of the span of the words in $a$ and $a^*$, without constants.



          The spectrum $sigma(A)$ is compact, so $C(sigma(A)$ is unital. For the identification $C^*(a)simeq C_0(sigma(a))$, one is taking the continuous functions where $f(0)=0$. That's what the subscript means. It's bad notation because it is not the set of functions that vanish at infinity.






          share|cite|improve this answer





















          • So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
            – mathrookie
            Nov 18 at 12:26










          • Not usually, but it is in what you wrote. It's a really bad choice of notation.
            – Martin Argerami
            Nov 18 at 12:54










          • what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
            – mathrookie
            Nov 18 at 13:05












          • Standard notation for what ?
            – André S.
            Nov 18 at 15:19













          up vote
          1
          down vote



          accepted







          up vote
          1
          down vote



          accepted






          No, it's just bad notation. When $A$ is not unital and you consider the C$^*$-algebra generated by $a$ in $A$, it cannot contain the unit of $A$. So when $a$ is normal C$^*(a)$ is the closure of the span of the words in $a$ and $a^*$, without constants.



          The spectrum $sigma(A)$ is compact, so $C(sigma(A)$ is unital. For the identification $C^*(a)simeq C_0(sigma(a))$, one is taking the continuous functions where $f(0)=0$. That's what the subscript means. It's bad notation because it is not the set of functions that vanish at infinity.






          share|cite|improve this answer












          No, it's just bad notation. When $A$ is not unital and you consider the C$^*$-algebra generated by $a$ in $A$, it cannot contain the unit of $A$. So when $a$ is normal C$^*(a)$ is the closure of the span of the words in $a$ and $a^*$, without constants.



          The spectrum $sigma(A)$ is compact, so $C(sigma(A)$ is unital. For the identification $C^*(a)simeq C_0(sigma(a))$, one is taking the continuous functions where $f(0)=0$. That's what the subscript means. It's bad notation because it is not the set of functions that vanish at infinity.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 18 at 12:09









          Martin Argerami

          122k1174172




          122k1174172












          • So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
            – mathrookie
            Nov 18 at 12:26










          • Not usually, but it is in what you wrote. It's a really bad choice of notation.
            – Martin Argerami
            Nov 18 at 12:54










          • what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
            – mathrookie
            Nov 18 at 13:05












          • Standard notation for what ?
            – André S.
            Nov 18 at 15:19


















          • So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
            – mathrookie
            Nov 18 at 12:26










          • Not usually, but it is in what you wrote. It's a really bad choice of notation.
            – Martin Argerami
            Nov 18 at 12:54










          • what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
            – mathrookie
            Nov 18 at 13:05












          • Standard notation for what ?
            – André S.
            Nov 18 at 15:19
















          So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
          – mathrookie
          Nov 18 at 12:26




          So $C_0(sigma(a))$ is the set of continuous functions $f$ defined on $sigma(a)$ such that $f(0)=0$?
          – mathrookie
          Nov 18 at 12:26












          Not usually, but it is in what you wrote. It's a really bad choice of notation.
          – Martin Argerami
          Nov 18 at 12:54




          Not usually, but it is in what you wrote. It's a really bad choice of notation.
          – Martin Argerami
          Nov 18 at 12:54












          what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
          – mathrookie
          Nov 18 at 13:05






          what is the standard notaion when we talk about the functional calculus for the non-unital $C^*$ algebras?
          – mathrookie
          Nov 18 at 13:05














          Standard notation for what ?
          – André S.
          Nov 18 at 15:19




          Standard notation for what ?
          – André S.
          Nov 18 at 15:19


















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