sketch graph of function
Sketch a possible graph of a function that satisfies the given conditions.
𝑓(0)=−2,𝑓(2)=4
𝑓′(2)=0,𝑓′(1) is not defined
𝑓′(𝑥)<0 on (−∞,1) and (2,∞)
𝑓′′(𝑥𝑥)>0 on (−∞,1)
𝑓′′(𝑥𝑥)<0 on (1,∞)
graphing-functions
asked Nov 18 at 23:12
saba
2
add a comment |
Sketch a possible graph of a function that satisfies the given conditions.
𝑓(0)=−2,𝑓(2)=4
𝑓′(2)=0,𝑓′(1) is not defined
𝑓′(𝑥)<0 on (−∞,1) and (2,∞)
𝑓′′(𝑥𝑥)>0 on (−∞,1)
𝑓′′(𝑥𝑥)<0 on (1,∞)
graphing-functions
asked Nov 18 at 23:12
saba
2
add a comment |
Sketch a possible graph of a function that satisfies the given conditions.
𝑓(0)=−2,𝑓(2)=4
𝑓′(2)=0,𝑓′(1) is not defined
𝑓′(𝑥)<0 on (−∞,1) and (2,∞)
𝑓′′(𝑥𝑥)>0 on (−∞,1)
𝑓′′(𝑥𝑥)<0 on (1,∞)
graphing-functions
asked Nov 18 at 23:12
saba
2
Sketch a possible graph of a function that satisfies the given conditions.
𝑓(0)=−2,𝑓(2)=4
𝑓′(2)=0,𝑓′(1) is not defined
𝑓′(𝑥)<0 on (−∞,1) and (2,∞)
𝑓′′(𝑥𝑥)>0 on (−∞,1)
𝑓′′(𝑥𝑥)<0 on (1,∞)
graphing-functions
graphing-functions
asked Nov 18 at 23:12
saba
2
asked Nov 18 at 23:12
saba
2
asked Nov 18 at 23:12
saba
2
asked Nov 18 at 23:12
saba
2
asked Nov 18 at 23:12
saba
2
2
add a comment |
add a comment |
1 Answer
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Lets try and write examine these special conditions. Firstly
Look at gradients. It is negative everywhere except on[1,2] and 0 at 2.
Then we see that if it isnt a line what kind of convex it will be. We use the 2nd derivative to find this. Finally we move the graphs till they satisfy the conditions, also, but having a discontinuity at 1, prevents f '(x) being defined there
Click here to see a graph which satisfies the conditions you stated. I leave it to you to check them.
answered Nov 19 at 0:09
anuj1610
12
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Lets try and write examine these special conditions. Firstly
Look at gradients. It is negative everywhere except on[1,2] and 0 at 2.
Then we see that if it isnt a line what kind of convex it will be. We use the 2nd derivative to find this. Finally we move the graphs till they satisfy the conditions, also, but having a discontinuity at 1, prevents f '(x) being defined there
Click here to see a graph which satisfies the conditions you stated. I leave it to you to check them.
answered Nov 19 at 0:09
anuj1610
12
add a comment |
Lets try and write examine these special conditions. Firstly
Look at gradients. It is negative everywhere except on[1,2] and 0 at 2.
Then we see that if it isnt a line what kind of convex it will be. We use the 2nd derivative to find this. Finally we move the graphs till they satisfy the conditions, also, but having a discontinuity at 1, prevents f '(x) being defined there
Click here to see a graph which satisfies the conditions you stated. I leave it to you to check them.
answered Nov 19 at 0:09
anuj1610
12
add a comment |
Lets try and write examine these special conditions. Firstly
Look at gradients. It is negative everywhere except on[1,2] and 0 at 2.
Then we see that if it isnt a line what kind of convex it will be. We use the 2nd derivative to find this. Finally we move the graphs till they satisfy the conditions, also, but having a discontinuity at 1, prevents f '(x) being defined there
Click here to see a graph which satisfies the conditions you stated. I leave it to you to check them.
answered Nov 19 at 0:09
anuj1610
12
Lets try and write examine these special conditions. Firstly
Look at gradients. It is negative everywhere except on[1,2] and 0 at 2.
Then we see that if it isnt a line what kind of convex it will be. We use the 2nd derivative to find this. Finally we move the graphs till they satisfy the conditions, also, but having a discontinuity at 1, prevents f '(x) being defined there
Click here to see a graph which satisfies the conditions you stated. I leave it to you to check them.
answered Nov 19 at 0:09
anuj1610
12
answered Nov 19 at 0:09
anuj1610
12
answered Nov 19 at 0:09
anuj1610
12
answered Nov 19 at 0:09
anuj1610
12
12
add a comment |
add a comment |
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