Does relation S is transitive
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0
down vote
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Let S be relation whose representing matrix
$$
begin{bmatrix}
0 & 0 & 1 \
1 & 0 & 1 \
1 & 0 & 1 \
end{bmatrix}
$$
Does relation S is transitive?
I write down relation S: $$S = {(1, 3), (2, 1), (2, 3), (3, 1), (3, 3)}$$
I have:$$(2, 1), (1, 3)∈ SquadAndquad(2, 3)∈ S$$
$$(2, 3), (3, 1)∈ SquadAndquad(2, 1)∈ S$$
So it should be transitive, but the answer is not. Where did i miss?
discrete-mathematics relations
asked Nov 15 at 15:57
Doan Van Thang
32
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Doan Van Thang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
up vote
0
down vote
favorite
Let S be relation whose representing matrix
$$
begin{bmatrix}
0 & 0 & 1 \
1 & 0 & 1 \
1 & 0 & 1 \
end{bmatrix}
$$
Does relation S is transitive?
I write down relation S: $$S = {(1, 3), (2, 1), (2, 3), (3, 1), (3, 3)}$$
I have:$$(2, 1), (1, 3)∈ SquadAndquad(2, 3)∈ S$$
$$(2, 3), (3, 1)∈ SquadAndquad(2, 1)∈ S$$
So it should be transitive, but the answer is not. Where did i miss?
discrete-mathematics relations
asked Nov 15 at 15:57
Doan Van Thang
32
New contributor
Doan Van Thang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$(1,3),(3,1)in S$ but $(1,1)notin S$
– saulspatz
Nov 15 at 16:01
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Let S be relation whose representing matrix
$$
begin{bmatrix}
0 & 0 & 1 \
1 & 0 & 1 \
1 & 0 & 1 \
end{bmatrix}
$$
Does relation S is transitive?
I write down relation S: $$S = {(1, 3), (2, 1), (2, 3), (3, 1), (3, 3)}$$
I have:$$(2, 1), (1, 3)∈ SquadAndquad(2, 3)∈ S$$
$$(2, 3), (3, 1)∈ SquadAndquad(2, 1)∈ S$$
So it should be transitive, but the answer is not. Where did i miss?
discrete-mathematics relations
asked Nov 15 at 15:57
Doan Van Thang
32
New contributor
Doan Van Thang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Let S be relation whose representing matrix
$$
begin{bmatrix}
0 & 0 & 1 \
1 & 0 & 1 \
1 & 0 & 1 \
end{bmatrix}
$$
Does relation S is transitive?
I write down relation S: $$S = {(1, 3), (2, 1), (2, 3), (3, 1), (3, 3)}$$
I have:$$(2, 1), (1, 3)∈ SquadAndquad(2, 3)∈ S$$
$$(2, 3), (3, 1)∈ SquadAndquad(2, 1)∈ S$$
So it should be transitive, but the answer is not. Where did i miss?
discrete-mathematics relations
discrete-mathematics relations
asked Nov 15 at 15:57
Doan Van Thang
32
New contributor
Doan Van Thang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 15 at 15:57
Doan Van Thang
32
New contributor
Doan Van Thang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 15 at 15:57
Doan Van Thang
32
New contributor
Doan Van Thang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 15 at 15:57
Doan Van Thang
32
asked Nov 15 at 15:57
Doan Van Thang
32
32
New contributor
Doan Van Thang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Doan Van Thang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Doan Van Thang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$(1,3),(3,1)in S$ but $(1,1)notin S$
– saulspatz
Nov 15 at 16:01
add a comment |
$(1,3),(3,1)in S$ but $(1,1)notin S$
– saulspatz
Nov 15 at 16:01
$(1,3),(3,1)in S$ but $(1,1)notin S$
– saulspatz
Nov 15 at 16:01
$(1,3),(3,1)in S$ but $(1,1)notin S$
– saulspatz
Nov 15 at 16:01
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
We have $(1,3),(3,1) in S$, but $(1,1)notin S$. You need to check all possible pairs.
answered Nov 15 at 15:59
user3482749
1,001411
add a comment |
up vote
0
down vote
You missed that $(1,3),(3,1)in S$, but $(1,1)notin S$.
answered Nov 15 at 16:00
José Carlos Santos
140k18111204
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
We have $(1,3),(3,1) in S$, but $(1,1)notin S$. You need to check all possible pairs.
answered Nov 15 at 15:59
user3482749
1,001411
add a comment |
up vote
1
down vote
accepted
We have $(1,3),(3,1) in S$, but $(1,1)notin S$. You need to check all possible pairs.
answered Nov 15 at 15:59
user3482749
1,001411
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
We have $(1,3),(3,1) in S$, but $(1,1)notin S$. You need to check all possible pairs.
answered Nov 15 at 15:59
user3482749
1,001411
We have $(1,3),(3,1) in S$, but $(1,1)notin S$. You need to check all possible pairs.
answered Nov 15 at 15:59
user3482749
1,001411
answered Nov 15 at 15:59
user3482749
1,001411
answered Nov 15 at 15:59
user3482749
1,001411
answered Nov 15 at 15:59
user3482749
1,001411
1,001411
add a comment |
add a comment |
up vote
0
down vote
You missed that $(1,3),(3,1)in S$, but $(1,1)notin S$.
answered Nov 15 at 16:00
José Carlos Santos
140k18111204
add a comment |
up vote
0
down vote
You missed that $(1,3),(3,1)in S$, but $(1,1)notin S$.
answered Nov 15 at 16:00
José Carlos Santos
140k18111204
add a comment |
up vote
0
down vote
up vote
0
down vote
You missed that $(1,3),(3,1)in S$, but $(1,1)notin S$.
answered Nov 15 at 16:00
José Carlos Santos
140k18111204
You missed that $(1,3),(3,1)in S$, but $(1,1)notin S$.
answered Nov 15 at 16:00
José Carlos Santos
140k18111204
answered Nov 15 at 16:00
José Carlos Santos
140k18111204
answered Nov 15 at 16:00
José Carlos Santos
140k18111204
answered Nov 15 at 16:00
José Carlos Santos
140k18111204
140k18111204
add a comment |
add a comment |
Doan Van Thang is a new contributor. Be nice, and check out our Code of Conduct.
Doan Van Thang is a new contributor. Be nice, and check out our Code of Conduct.
Doan Van Thang is a new contributor. Be nice, and check out our Code of Conduct.
Doan Van Thang is a new contributor. Be nice, and check out our Code of Conduct.
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$(1,3),(3,1)in S$ but $(1,1)notin S$
– saulspatz
Nov 15 at 16:01