If Φ⊢¬(ϕ→ψ) , show that Φ,¬ϕ and Φ, ψ are both inconsistent.











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So far I have shown that Φ, ψ is inconsistent:



If Φ⊢¬(ϕ→ψ) then Φ, ψ⊢¬(ϕ→ψ)



By the axiom ψ→ϕ→ψ and Modus Ponens, Φ, ψ⊢ϕ→ψ.



So Φ, ψ is inconsistent.



Could anyone help me to prove that Φ,¬ϕ is inconsistent?










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  • I do not get the gist of your question: what is $Phi$, $phi$ and $psi$? Which conditions hold for them? $Phi,psivdashlnot(phitopsi)$ is the only condition you have assumed?
    – Hanul Jeon
    Nov 18 at 8:06










  • I missed a step here. If Φ⊢¬(ϕ→ψ) then Φ, ψ⊢¬(ϕ→ψ).
    – mdryizk
    Nov 18 at 8:25










  • Hint: $Phivdash philand lnotpsi$.
    – Hanul Jeon
    Nov 18 at 8:26










  • Thank you for the hint. I think i know what you are trying to tell me. But i'm looking for a proof using only ¬ and →.
    – mdryizk
    Nov 18 at 8:30








  • 1




    @mdryizk If you're looking for a proof in a particular formal system you should indicate this in your question.
    – spaceisdarkgreen
    Nov 18 at 8:48

















up vote
-1
down vote

favorite












So far I have shown that Φ, ψ is inconsistent:



If Φ⊢¬(ϕ→ψ) then Φ, ψ⊢¬(ϕ→ψ)



By the axiom ψ→ϕ→ψ and Modus Ponens, Φ, ψ⊢ϕ→ψ.



So Φ, ψ is inconsistent.



Could anyone help me to prove that Φ,¬ϕ is inconsistent?










share|cite|improve this question
























  • I do not get the gist of your question: what is $Phi$, $phi$ and $psi$? Which conditions hold for them? $Phi,psivdashlnot(phitopsi)$ is the only condition you have assumed?
    – Hanul Jeon
    Nov 18 at 8:06










  • I missed a step here. If Φ⊢¬(ϕ→ψ) then Φ, ψ⊢¬(ϕ→ψ).
    – mdryizk
    Nov 18 at 8:25










  • Hint: $Phivdash philand lnotpsi$.
    – Hanul Jeon
    Nov 18 at 8:26










  • Thank you for the hint. I think i know what you are trying to tell me. But i'm looking for a proof using only ¬ and →.
    – mdryizk
    Nov 18 at 8:30








  • 1




    @mdryizk If you're looking for a proof in a particular formal system you should indicate this in your question.
    – spaceisdarkgreen
    Nov 18 at 8:48















up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











So far I have shown that Φ, ψ is inconsistent:



If Φ⊢¬(ϕ→ψ) then Φ, ψ⊢¬(ϕ→ψ)



By the axiom ψ→ϕ→ψ and Modus Ponens, Φ, ψ⊢ϕ→ψ.



So Φ, ψ is inconsistent.



Could anyone help me to prove that Φ,¬ϕ is inconsistent?










share|cite|improve this question















So far I have shown that Φ, ψ is inconsistent:



If Φ⊢¬(ϕ→ψ) then Φ, ψ⊢¬(ϕ→ψ)



By the axiom ψ→ϕ→ψ and Modus Ponens, Φ, ψ⊢ϕ→ψ.



So Φ, ψ is inconsistent.



Could anyone help me to prove that Φ,¬ϕ is inconsistent?







propositional-calculus






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edited Nov 18 at 9:11

























asked Nov 18 at 8:03









mdryizk

153




153












  • I do not get the gist of your question: what is $Phi$, $phi$ and $psi$? Which conditions hold for them? $Phi,psivdashlnot(phitopsi)$ is the only condition you have assumed?
    – Hanul Jeon
    Nov 18 at 8:06










  • I missed a step here. If Φ⊢¬(ϕ→ψ) then Φ, ψ⊢¬(ϕ→ψ).
    – mdryizk
    Nov 18 at 8:25










  • Hint: $Phivdash philand lnotpsi$.
    – Hanul Jeon
    Nov 18 at 8:26










  • Thank you for the hint. I think i know what you are trying to tell me. But i'm looking for a proof using only ¬ and →.
    – mdryizk
    Nov 18 at 8:30








  • 1




    @mdryizk If you're looking for a proof in a particular formal system you should indicate this in your question.
    – spaceisdarkgreen
    Nov 18 at 8:48




















  • I do not get the gist of your question: what is $Phi$, $phi$ and $psi$? Which conditions hold for them? $Phi,psivdashlnot(phitopsi)$ is the only condition you have assumed?
    – Hanul Jeon
    Nov 18 at 8:06










  • I missed a step here. If Φ⊢¬(ϕ→ψ) then Φ, ψ⊢¬(ϕ→ψ).
    – mdryizk
    Nov 18 at 8:25










  • Hint: $Phivdash philand lnotpsi$.
    – Hanul Jeon
    Nov 18 at 8:26










  • Thank you for the hint. I think i know what you are trying to tell me. But i'm looking for a proof using only ¬ and →.
    – mdryizk
    Nov 18 at 8:30








  • 1




    @mdryizk If you're looking for a proof in a particular formal system you should indicate this in your question.
    – spaceisdarkgreen
    Nov 18 at 8:48


















I do not get the gist of your question: what is $Phi$, $phi$ and $psi$? Which conditions hold for them? $Phi,psivdashlnot(phitopsi)$ is the only condition you have assumed?
– Hanul Jeon
Nov 18 at 8:06




I do not get the gist of your question: what is $Phi$, $phi$ and $psi$? Which conditions hold for them? $Phi,psivdashlnot(phitopsi)$ is the only condition you have assumed?
– Hanul Jeon
Nov 18 at 8:06












I missed a step here. If Φ⊢¬(ϕ→ψ) then Φ, ψ⊢¬(ϕ→ψ).
– mdryizk
Nov 18 at 8:25




I missed a step here. If Φ⊢¬(ϕ→ψ) then Φ, ψ⊢¬(ϕ→ψ).
– mdryizk
Nov 18 at 8:25












Hint: $Phivdash philand lnotpsi$.
– Hanul Jeon
Nov 18 at 8:26




Hint: $Phivdash philand lnotpsi$.
– Hanul Jeon
Nov 18 at 8:26












Thank you for the hint. I think i know what you are trying to tell me. But i'm looking for a proof using only ¬ and →.
– mdryizk
Nov 18 at 8:30






Thank you for the hint. I think i know what you are trying to tell me. But i'm looking for a proof using only ¬ and →.
– mdryizk
Nov 18 at 8:30






1




1




@mdryizk If you're looking for a proof in a particular formal system you should indicate this in your question.
– spaceisdarkgreen
Nov 18 at 8:48






@mdryizk If you're looking for a proof in a particular formal system you should indicate this in your question.
– spaceisdarkgreen
Nov 18 at 8:48












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From the same reasoning you used for the first part, $$ Phi,lnotphi vdash lnot psi to lnot phi.$$ By the contrapositive axiom (theorem? you haven't told us which system you are using... it seems clear that it's Hilbert style from context, but there are several commonly used versions of Axiom 3), $$ Phi,lnot phivdash (lnotpsito lnot phi)to(phito psi), $$ so by MP $$Phi,lnot phivdash phitopsi $$






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    From the same reasoning you used for the first part, $$ Phi,lnotphi vdash lnot psi to lnot phi.$$ By the contrapositive axiom (theorem? you haven't told us which system you are using... it seems clear that it's Hilbert style from context, but there are several commonly used versions of Axiom 3), $$ Phi,lnot phivdash (lnotpsito lnot phi)to(phito psi), $$ so by MP $$Phi,lnot phivdash phitopsi $$






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      up vote
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      From the same reasoning you used for the first part, $$ Phi,lnotphi vdash lnot psi to lnot phi.$$ By the contrapositive axiom (theorem? you haven't told us which system you are using... it seems clear that it's Hilbert style from context, but there are several commonly used versions of Axiom 3), $$ Phi,lnot phivdash (lnotpsito lnot phi)to(phito psi), $$ so by MP $$Phi,lnot phivdash phitopsi $$






      share|cite|improve this answer























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        down vote



        accepted







        up vote
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        From the same reasoning you used for the first part, $$ Phi,lnotphi vdash lnot psi to lnot phi.$$ By the contrapositive axiom (theorem? you haven't told us which system you are using... it seems clear that it's Hilbert style from context, but there are several commonly used versions of Axiom 3), $$ Phi,lnot phivdash (lnotpsito lnot phi)to(phito psi), $$ so by MP $$Phi,lnot phivdash phitopsi $$






        share|cite|improve this answer












        From the same reasoning you used for the first part, $$ Phi,lnotphi vdash lnot psi to lnot phi.$$ By the contrapositive axiom (theorem? you haven't told us which system you are using... it seems clear that it's Hilbert style from context, but there are several commonly used versions of Axiom 3), $$ Phi,lnot phivdash (lnotpsito lnot phi)to(phito psi), $$ so by MP $$Phi,lnot phivdash phitopsi $$







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        answered Nov 18 at 9:01









        spaceisdarkgreen

        31.7k21552




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