Standard name for the computation of Lagrange multipliers iteratively by fixing other multipliers?











up vote
0
down vote

favorite
2












Dear Optimization Experts,



Background:



I have a convex optimization problem on hand that can be shown in general form as given below
begin{equation}
begin{aligned}
& underset{x in mathbb{R}^N}{text{minimize}}
& & f(x) \
& text{subject to}
& & g_i(x) - alpha_i leq 0 forall i = 1,cdots,K ; ,
end{aligned}
end{equation}

where both functions $g_i: mathbb{R}^N rightarrowmathbb{R}$ and $f: mathbb{R}^N rightarrowmathbb{R}$ are convex, and $alpha_i in mathbb{R}$ is given.



The Lagrangian is:
begin{align}
Lleft(x, left{lambda_iright}right)
&= f(x) + sum limits_{i=1}^{K} lambda_i left(g_i(x) - alpha_i right) ; .
end{align}



Question:



If $K=1$ then I can obtain the closed-form solution $x$ (and analytical solution of the Lagrange multiplier $lambda_1$) by following the KKT conditions.



Now, the question arises when $K > 1$ then I can't obtain the closed-form solution, but I can compute $x$ analytically which is dependent on all the $lambda_i$. So, to compute the Lagrange multiplier say $lambda_i$, I resort to iterative solution where I fix other Lagrange multipliers ($lambda_j forall j = 1,cdots,K$ except $i$). Then repeat the above process for other Lagrange multipliers iteratively.




  • do you have any standard name for such scheme to compute Lagrange multipliers cyclically?

  • If not, can I say that this cyclic/iterative scheme is nothing but Coordinate Descent (or like)?


Thank you so much for your time in advance.










share|cite|improve this question




















  • 1




    Depending on how you select $lambda$, this may be coordinate descent in the dual problem.
    – LinAlg
    Nov 18 at 13:53










  • thank you LinAlg!
    – user550103
    Nov 18 at 15:51















up vote
0
down vote

favorite
2












Dear Optimization Experts,



Background:



I have a convex optimization problem on hand that can be shown in general form as given below
begin{equation}
begin{aligned}
& underset{x in mathbb{R}^N}{text{minimize}}
& & f(x) \
& text{subject to}
& & g_i(x) - alpha_i leq 0 forall i = 1,cdots,K ; ,
end{aligned}
end{equation}

where both functions $g_i: mathbb{R}^N rightarrowmathbb{R}$ and $f: mathbb{R}^N rightarrowmathbb{R}$ are convex, and $alpha_i in mathbb{R}$ is given.



The Lagrangian is:
begin{align}
Lleft(x, left{lambda_iright}right)
&= f(x) + sum limits_{i=1}^{K} lambda_i left(g_i(x) - alpha_i right) ; .
end{align}



Question:



If $K=1$ then I can obtain the closed-form solution $x$ (and analytical solution of the Lagrange multiplier $lambda_1$) by following the KKT conditions.



Now, the question arises when $K > 1$ then I can't obtain the closed-form solution, but I can compute $x$ analytically which is dependent on all the $lambda_i$. So, to compute the Lagrange multiplier say $lambda_i$, I resort to iterative solution where I fix other Lagrange multipliers ($lambda_j forall j = 1,cdots,K$ except $i$). Then repeat the above process for other Lagrange multipliers iteratively.




  • do you have any standard name for such scheme to compute Lagrange multipliers cyclically?

  • If not, can I say that this cyclic/iterative scheme is nothing but Coordinate Descent (or like)?


Thank you so much for your time in advance.










share|cite|improve this question




















  • 1




    Depending on how you select $lambda$, this may be coordinate descent in the dual problem.
    – LinAlg
    Nov 18 at 13:53










  • thank you LinAlg!
    – user550103
    Nov 18 at 15:51













up vote
0
down vote

favorite
2









up vote
0
down vote

favorite
2






2





Dear Optimization Experts,



Background:



I have a convex optimization problem on hand that can be shown in general form as given below
begin{equation}
begin{aligned}
& underset{x in mathbb{R}^N}{text{minimize}}
& & f(x) \
& text{subject to}
& & g_i(x) - alpha_i leq 0 forall i = 1,cdots,K ; ,
end{aligned}
end{equation}

where both functions $g_i: mathbb{R}^N rightarrowmathbb{R}$ and $f: mathbb{R}^N rightarrowmathbb{R}$ are convex, and $alpha_i in mathbb{R}$ is given.



The Lagrangian is:
begin{align}
Lleft(x, left{lambda_iright}right)
&= f(x) + sum limits_{i=1}^{K} lambda_i left(g_i(x) - alpha_i right) ; .
end{align}



Question:



If $K=1$ then I can obtain the closed-form solution $x$ (and analytical solution of the Lagrange multiplier $lambda_1$) by following the KKT conditions.



Now, the question arises when $K > 1$ then I can't obtain the closed-form solution, but I can compute $x$ analytically which is dependent on all the $lambda_i$. So, to compute the Lagrange multiplier say $lambda_i$, I resort to iterative solution where I fix other Lagrange multipliers ($lambda_j forall j = 1,cdots,K$ except $i$). Then repeat the above process for other Lagrange multipliers iteratively.




  • do you have any standard name for such scheme to compute Lagrange multipliers cyclically?

  • If not, can I say that this cyclic/iterative scheme is nothing but Coordinate Descent (or like)?


Thank you so much for your time in advance.










share|cite|improve this question















Dear Optimization Experts,



Background:



I have a convex optimization problem on hand that can be shown in general form as given below
begin{equation}
begin{aligned}
& underset{x in mathbb{R}^N}{text{minimize}}
& & f(x) \
& text{subject to}
& & g_i(x) - alpha_i leq 0 forall i = 1,cdots,K ; ,
end{aligned}
end{equation}

where both functions $g_i: mathbb{R}^N rightarrowmathbb{R}$ and $f: mathbb{R}^N rightarrowmathbb{R}$ are convex, and $alpha_i in mathbb{R}$ is given.



The Lagrangian is:
begin{align}
Lleft(x, left{lambda_iright}right)
&= f(x) + sum limits_{i=1}^{K} lambda_i left(g_i(x) - alpha_i right) ; .
end{align}



Question:



If $K=1$ then I can obtain the closed-form solution $x$ (and analytical solution of the Lagrange multiplier $lambda_1$) by following the KKT conditions.



Now, the question arises when $K > 1$ then I can't obtain the closed-form solution, but I can compute $x$ analytically which is dependent on all the $lambda_i$. So, to compute the Lagrange multiplier say $lambda_i$, I resort to iterative solution where I fix other Lagrange multipliers ($lambda_j forall j = 1,cdots,K$ except $i$). Then repeat the above process for other Lagrange multipliers iteratively.




  • do you have any standard name for such scheme to compute Lagrange multipliers cyclically?

  • If not, can I say that this cyclic/iterative scheme is nothing but Coordinate Descent (or like)?


Thank you so much for your time in advance.







optimization convex-optimization numerical-optimization






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 18 at 8:27

























asked Nov 18 at 8:12









user550103

8911315




8911315








  • 1




    Depending on how you select $lambda$, this may be coordinate descent in the dual problem.
    – LinAlg
    Nov 18 at 13:53










  • thank you LinAlg!
    – user550103
    Nov 18 at 15:51














  • 1




    Depending on how you select $lambda$, this may be coordinate descent in the dual problem.
    – LinAlg
    Nov 18 at 13:53










  • thank you LinAlg!
    – user550103
    Nov 18 at 15:51








1




1




Depending on how you select $lambda$, this may be coordinate descent in the dual problem.
– LinAlg
Nov 18 at 13:53




Depending on how you select $lambda$, this may be coordinate descent in the dual problem.
– LinAlg
Nov 18 at 13:53












thank you LinAlg!
– user550103
Nov 18 at 15:51




thank you LinAlg!
– user550103
Nov 18 at 15:51















active

oldest

votes











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3003249%2fstandard-name-for-the-computation-of-lagrange-multipliers-iteratively-by-fixing%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown






























active

oldest

votes













active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.





Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


Please pay close attention to the following guidance:


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3003249%2fstandard-name-for-the-computation-of-lagrange-multipliers-iteratively-by-fixing%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Актюбинская область

QoS: MAC-Priority for clients behind a repeater

AnyDesk - Fatal Program Failure