Tribute to Stan Lee











up vote
34
down vote

favorite
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Unfortunately one of the greatest comic book writers passed away yesterday afternoon. Lots of Hollywood stars, musicians, actors, and many other people are paying tribute to this awesome writer, so we must do something as well.



Challenge



Print The Avengers Logo



Note: You may use any other character in place of # other than a space character; while you must use a space character for the space



enter image description here



In ASCII-art



              ######       
###############
##### ##########
#### ####### ####
### #### ### ###
### #### ### ###
### #### ### ###
### #### ### ###
### #### ### ###
### #### ### ###
### ########### ###
### ########### ###
### #### ### ###
### ### ### ###
#### #### ####
######## ######
#################
###


Optional



Who was (in your opinion) his greatest hero and villain in the entire marvel universe?





Standard code-golf rules apply










share|improve this question




















  • 3




    What happened to the → in Ⓐ?
    – Adám
    yesterday






  • 3




    @Adám 2 Reasons. I believe that the arrow means the continuation of the series (in this case the comics about avengers). Since Stan passed away there wont be a continuation of it (In my opinion, it is not the same without Stan). That is one of the reasons
    – Luis felipe De jesus Munoz
    yesterday






  • 33




    The second one is that I didnt know how to draw it :c
    – Luis felipe De jesus Munoz
    yesterday










  • Can we use other characters instead of # and space?
    – Jo King
    yesterday










  • @JoKing you can use a different char instead # but not the space.
    – Luis felipe De jesus Munoz
    yesterday















up vote
34
down vote

favorite
6












Unfortunately one of the greatest comic book writers passed away yesterday afternoon. Lots of Hollywood stars, musicians, actors, and many other people are paying tribute to this awesome writer, so we must do something as well.



Challenge



Print The Avengers Logo



Note: You may use any other character in place of # other than a space character; while you must use a space character for the space



enter image description here



In ASCII-art



              ######       
###############
##### ##########
#### ####### ####
### #### ### ###
### #### ### ###
### #### ### ###
### #### ### ###
### #### ### ###
### #### ### ###
### ########### ###
### ########### ###
### #### ### ###
### ### ### ###
#### #### ####
######## ######
#################
###


Optional



Who was (in your opinion) his greatest hero and villain in the entire marvel universe?





Standard code-golf rules apply










share|improve this question




















  • 3




    What happened to the → in Ⓐ?
    – Adám
    yesterday






  • 3




    @Adám 2 Reasons. I believe that the arrow means the continuation of the series (in this case the comics about avengers). Since Stan passed away there wont be a continuation of it (In my opinion, it is not the same without Stan). That is one of the reasons
    – Luis felipe De jesus Munoz
    yesterday






  • 33




    The second one is that I didnt know how to draw it :c
    – Luis felipe De jesus Munoz
    yesterday










  • Can we use other characters instead of # and space?
    – Jo King
    yesterday










  • @JoKing you can use a different char instead # but not the space.
    – Luis felipe De jesus Munoz
    yesterday













up vote
34
down vote

favorite
6









up vote
34
down vote

favorite
6






6





Unfortunately one of the greatest comic book writers passed away yesterday afternoon. Lots of Hollywood stars, musicians, actors, and many other people are paying tribute to this awesome writer, so we must do something as well.



Challenge



Print The Avengers Logo



Note: You may use any other character in place of # other than a space character; while you must use a space character for the space



enter image description here



In ASCII-art



              ######       
###############
##### ##########
#### ####### ####
### #### ### ###
### #### ### ###
### #### ### ###
### #### ### ###
### #### ### ###
### #### ### ###
### ########### ###
### ########### ###
### #### ### ###
### ### ### ###
#### #### ####
######## ######
#################
###


Optional



Who was (in your opinion) his greatest hero and villain in the entire marvel universe?





Standard code-golf rules apply










share|improve this question















Unfortunately one of the greatest comic book writers passed away yesterday afternoon. Lots of Hollywood stars, musicians, actors, and many other people are paying tribute to this awesome writer, so we must do something as well.



Challenge



Print The Avengers Logo



Note: You may use any other character in place of # other than a space character; while you must use a space character for the space



enter image description here



In ASCII-art



              ######       
###############
##### ##########
#### ####### ####
### #### ### ###
### #### ### ###
### #### ### ###
### #### ### ###
### #### ### ###
### #### ### ###
### ########### ###
### ########### ###
### #### ### ###
### ### ### ###
#### #### ####
######## ######
#################
###


Optional



Who was (in your opinion) his greatest hero and villain in the entire marvel universe?





Standard code-golf rules apply







code-golf ascii-art kolmogorov-complexity






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 22 hours ago

























asked 2 days ago









Luis felipe De jesus Munoz

3,95411253




3,95411253








  • 3




    What happened to the → in Ⓐ?
    – Adám
    yesterday






  • 3




    @Adám 2 Reasons. I believe that the arrow means the continuation of the series (in this case the comics about avengers). Since Stan passed away there wont be a continuation of it (In my opinion, it is not the same without Stan). That is one of the reasons
    – Luis felipe De jesus Munoz
    yesterday






  • 33




    The second one is that I didnt know how to draw it :c
    – Luis felipe De jesus Munoz
    yesterday










  • Can we use other characters instead of # and space?
    – Jo King
    yesterday










  • @JoKing you can use a different char instead # but not the space.
    – Luis felipe De jesus Munoz
    yesterday














  • 3




    What happened to the → in Ⓐ?
    – Adám
    yesterday






  • 3




    @Adám 2 Reasons. I believe that the arrow means the continuation of the series (in this case the comics about avengers). Since Stan passed away there wont be a continuation of it (In my opinion, it is not the same without Stan). That is one of the reasons
    – Luis felipe De jesus Munoz
    yesterday






  • 33




    The second one is that I didnt know how to draw it :c
    – Luis felipe De jesus Munoz
    yesterday










  • Can we use other characters instead of # and space?
    – Jo King
    yesterday










  • @JoKing you can use a different char instead # but not the space.
    – Luis felipe De jesus Munoz
    yesterday








3




3




What happened to the → in Ⓐ?
– Adám
yesterday




What happened to the → in Ⓐ?
– Adám
yesterday




3




3




@Adám 2 Reasons. I believe that the arrow means the continuation of the series (in this case the comics about avengers). Since Stan passed away there wont be a continuation of it (In my opinion, it is not the same without Stan). That is one of the reasons
– Luis felipe De jesus Munoz
yesterday




@Adám 2 Reasons. I believe that the arrow means the continuation of the series (in this case the comics about avengers). Since Stan passed away there wont be a continuation of it (In my opinion, it is not the same without Stan). That is one of the reasons
– Luis felipe De jesus Munoz
yesterday




33




33




The second one is that I didnt know how to draw it :c
– Luis felipe De jesus Munoz
yesterday




The second one is that I didnt know how to draw it :c
– Luis felipe De jesus Munoz
yesterday












Can we use other characters instead of # and space?
– Jo King
yesterday




Can we use other characters instead of # and space?
– Jo King
yesterday












@JoKing you can use a different char instead # but not the space.
– Luis felipe De jesus Munoz
yesterday




@JoKing you can use a different char instead # but not the space.
– Luis felipe De jesus Munoz
yesterday










21 Answers
21






active

oldest

votes

















up vote
19
down vote














Jelly, 62 59 58 bytes



“ḢE{ɠs{Ƒ0Ṇṁỵ8ỊṢṂƊeLṫfIWẈḞ'ʠJ£ṗɱçoȧ?ƒnØẆƥṂ⁷ɱ’b12ĖŒṙḂa⁶s27Y


Thanks to @JonathanAllan for golfing off 1 byte!



Try it online!



How it works



“ḢE{ɠs{Ƒ0Ṇṁỵ8ỊṢṂƊeLṫfIWẈḞ'ʠJ£ṗɱçoȧ?ƒnØẆƥṂ⁷ɱ’


is a bijective base-250 integer literal, which uses the characters in Jelly's code page as digits.



The literal encodes the integer $scriptsize 10250938842396786963034911279002199266186481794751691439873548591280332406943905758890346943197901909163$, which b12 converts to duodecimal, yielding $scriptsize 30b620b40ba54a64771433841333139413468423468423467433467433466b466b465453465363431424b43896860ba3_{12}$.



There are some zeroes, because 14 spaces (e.g.) are encoded as 3 spaces, 0 hashes, and 11 spaces. This maintains the base small (the largest run consists of 17 hashes), without adding any additional logic to the decoder.



Ė (enumerate) prefixes every base-12 digit by its 1-based index, then Œṙ performs run-length decoding.



Now, for each integer in the resulting array, extracts the least significant bit, then a⁶ (AND space) replaces ones with spaces, while leaving zeroes unchanged.



Finally, s27 splits the unformatted character array into chunks of length 27, which Y separates by linefeeds.






share|improve this answer






























    up vote
    13
    down vote














    R, 198, 173, 163, 157, 144, 142 bytes





    write(rep(rep(c(' ',4),44),utf8ToInt("NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJC")-64),1,27,,'')


    Try it online!



    Also R honors to the great Stan.



    Notes :




    • instead of the character # we've used the character 4 because saves 2 bytes and :


      • it's a reference to the Fantastic Four and/or the next Avengers 4 movie

      • it like we're repeating the logo inside the logo (since 4 seems a mini "slanted" A)



    • -15 bytes thanks to @Giuseppe


    Explanation :



    Applying a Run Length Encoding (rle function) on the characters of the string (excluding 'n') returns 88 repetitions of the alternating <space>,<hash>,<space>,<hash>,<space>,<hash>....



    The 88 repetitions are all values in the range [1,17] hence, summing 64 we get the code points of the letters [A...Q] obtaining the string : "NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJC"



    Hence the code basically does the opposite operations :



    v <- utf8ToInt("NFMOJEDJFDGGADC...")-64  # convert the string back to [1...17] vector

    e <- rep(rep(c(' ',4),44),v) # perform the inverse of rle function obtaining an
    # expanded vector of <space>'s and <four>'s

    write(e,1,27,,'') # write the vector to stdout arranging it
    # in rows of maximum 27 characters





    share|improve this answer



















    • 1




      Your solution is nicer, but your own gzip 2-parter gives 89+47 = 136 bytes.
      – J.Doe
      23 hours ago












    • @J.Doe : ahah I even forgot to have used that approach! please post it as your own answer :)
      – digEmAll
      23 hours ago












    • Since we can use any character for #, using 0 in place of "#" should save 2 more bytes. @J.Doe that may work better for your gzip as well.
      – Giuseppe
      22 hours ago


















    up vote
    9
    down vote














    C (gcc), 244 243 bytes





    #define z <<10|117441415
    x={8064,2097088,8142832,31473596,58751886,30 z,60 z,60 z,120 z,120 z,255 z,255 z,480 z,448 z,63897630,33423612,2097136,1835008};b(_,i){i&&b(_/2,i-1),putchar(" #"[_%2]);}main(_){_<19&&b(x[_-1],27)&puts("")&main(_+1);}


    Try it online!



    -1 Thanks to Peter Cordes



    Uses bit compression.



    Explanation:



    The goal is to print a set of numbers in binary using space and # as digits which represent the logo. A bit of bash magic converts the logo to binary masks:



    echo "ibase=2;$(<code which echoes the logo [see my bash solution for example]> | tr ' #' 01)" | bc


    This results in the binary 'numbers' being:



    8064,2097088,8142832,31473596,58751886,117472135,117502855,117502855,117564295,117564295,117702535,117702535,117932935,117900167,63897630,33423612,2097136,1835008


    There is an obvious pattern in the middle where every line contains ### ### ###



    We can save some space by compressing that middle section based on saving that pattern and OR-ing against it. In addition, all of those lines merely add some stuff to the left of the middle section, so we make the z macro which takes ?????????????? and converts it into ###??????????????### ###. This involves bitshifting left by 10 and OR-ing with the binary of that pattern, which is 117441415.



    Now we can more easily understand the code:



    #define z <<10|117441415 // Define z to be the compression defined above
    x={ // Define x to be an array storing each line's number
    8064,2097088,8142832, // The first 5 lines are uncompressed
    31473596,58751886,
    30 z,60 z,60 z,120 z, // The middle 9 lines are z-compressed
    120 z,255 z,255 z,480 z,
    448 z,
    63897630,33423612, // The last 4 lines are uncompressed
    2097136,1835008};
    b(_,i){ // we also need a function to print n-bit binary numbers
    i&& // i is the bit counter, we recurse until its zero
    b(_/2,i-1), // each recursive call halves the input and decrements i
    putchar(" #"[_%2]);} // this just prints the correct character
    main(_){ // this is the main function, called as ./? will have 1 in _ (argc)
    _<19? // if _ is less than 19 then...
    b(x[_-1],27), // print the binary expansion of x[_-1]
    puts(""), // print a new line
    main(_+1) // recurse with _++
    :0;}





    share|improve this answer























    • Can x?y:0 be replaced with x&&y, or does operator precedence not work? Maybe with & instead of , separating the 3 function calls because & has higher precedence than && or , (en.cppreference.com/w/c/language/operator_precedence). Or not because only , provides a sequence point for the printing vs. recursion to avoid undefined behaviour.
      – Peter Cordes
      yesterday












    • It doesn't work with && indeed because of the precedence, while & doesn't short-circuit. As of yet I haven't found a shorter alternative, though I wouldn't rule one out.
      – LambdaBeta
      yesterday










    • I meant with & or | or ^ replacing , (because they don't short-circuit) and && replacing ? (because it does). Like _<19 && b() & puts() & main(_+1); (spaces added for readability). The order of evaluation is undefined, which may actually undefined behaviour because of unsequenced side-effects on stdout en.cppreference.com/w/c/language/eval_order, but in practice any given compiler will pick some order for a given set of target + options.
      – Peter Cordes
      yesterday








    • 1




      Ahh, I see what you mean. You're right - that does work! -1 byte.
      – LambdaBeta
      yesterday


















    up vote
    8
    down vote














    Canvas, 74 73 71 bytes



    qc2-Az↓n⁴╫m┬ff╷\_↘Tt)%⁵6>Yy7pQ∔I%SIŗ+T^≤?↔↖¶8^`O‾+O│≤n≡j↶82„2┬{ #@]∑‾+n


    Try it here!






    share|improve this answer






























      up vote
      8
      down vote













      T-SQL, 341 338 bytes



      DECLARE @ CHAR(2000)=REPLACE(REPLACE(REPLACE(
      'PRINT SPACE(14*6&$6*15&$4*5$4*10&$2*4$7*7$1*4&$1*3$8*4$1*3$3*3&*3$9*4$1*3$4
      *3&*3$8*4$2*3$4*3&*3$8*4$2*3$4*3&*3$7*4$3*3$4*3&*3$7*4$3*3$4*3&*3$6*11$4*3&
      *3$6*11$4*3&*3$5*4$5*3$4*3&*3$5*3$6*3$4*3&$1*4$2*4$11*4&$2*8$9*6&$6*17&$6*3)'
      ,'*',')+REPLICATE(''#'','),'$',')+SPACE('),'&',')+(''
      ''')EXEC(@)


      The first 4 line breaks are for readability only, the final line break is part of a string literal.



      Similar to my Adam West tribute, I've manually encoded a long string, and made the following replacements:





      • *7 gets replaced by +REPLICATE('#',7)


      • $4 gets replaced by +SPACE(4)


      • & gets replaced by a line break inside quotes


      This results in a massive SQL command string:



      PRINT SPACE(14)+REPLICATE('#',6)+('
      ')+SPACE(6)+REPLICATE('#',15)+('
      ')+SPACE(4)+REPLICATE('#',5)+SPACE(4)+REPLICATE('#',10)+('
      ')+SPACE(2)+REPLICATE('#',4)+SPACE(7)+REPLICATE('#',7)+SPACE(1)+REPLICATE('#',4)+('
      ')+SPACE(1)+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(1)+REPLICATE('#',3)+SPACE(3)+REPLICATE('#',3)+('
      ')+REPLICATE('#',3)+SPACE(9)+REPLICATE('#',4)+SPACE(1)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
      ')+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
      ')+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
      ')+REPLICATE('#',3)+SPACE(7)+REPLICATE('#',4)+SPACE(3)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
      ')+REPLICATE('#',3)+SPACE(7)+REPLICATE('#',4)+SPACE(3)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
      ')+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',11)+SPACE(4)+REPLICATE('#',3)+('
      ')+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',11)+SPACE(4)+REPLICATE('#',3)+('
      ')+REPLICATE('#',3)+SPACE(5)+REPLICATE('#',4)+SPACE(5)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
      ')+REPLICATE('#',3)+SPACE(5)+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
      ')+SPACE(1)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',4)+SPACE(11)+REPLICATE('#',4)+('
      ')+SPACE(2)+REPLICATE('#',8)+SPACE(9)+REPLICATE('#',6)+('
      ')+SPACE(6)+REPLICATE('#',17)+('
      ')+SPACE(6)+REPLICATE('#',3)


      Which, when run, produces the necessary output.



      Long, but still better than my best set-based solution (463 bytes):



      SELECT SPACE(a)+REPLICATE('#',b)+SPACE(c)+REPLICATE('#',d)
      +SPACE(e)+REPLICATE('#',f)+SPACE(g)+REPLICATE('#',h)
      FROM(VALUES(7,0,7,6,0,0,0,0),(6,8,0,7,0,0,0,0),(4,5,4,5,0,5,0,0),(2,4,7,7,1,4,0,0),
      (1,3,8,4,1,3,3,3),(0,3,9,4,1,3,4,3),(0,3,8,4,2,3,4,3),(0,3,8,4,2,3,4,3),
      (0,3,7,4,3,3,4,3),(0,3,7,4,3,3,4,3),(0,3,6,6,0,5,4,3),(0,3,6,6,0,5,4,3),
      (0,3,5,4,5,3,4,3),(0,3,5,3,6,3,4,3),(1,4,2,4,5,0,6,4),(2,8,9,6,0,0,0,0),
      (6,9,0,8,0,0,0,0),(6,3,0,0,0,0,0,0))t(a,b,c,d,e,f,g,h)





      share|improve this answer























      • can drop 2 chars using CHAR(8000) instead of VARCHAR(max) (the huge command is 1453 bytes)
        – Shameen
        yesterday






      • 1




        Thanks, @Shameen. I tried to save one more and use CHAR(2E3) but it didn't seem to like that. I also saved a byte by using a line break literal instead of CHAR(13).
        – BradC
        yesterday




















      up vote
      8
      down vote














      Bubblegum, 71 66 65 64 bytes



      0000000: 95 91 21 12 00 20 08 c0 3a af 90 ff 7f 52 4e 58  ..!.. ..:....RNX
      0000010: 58 93 25 d8 8a 27 47 e4 23 66 01 2c ce b1 3c 12 X.%..'G.#f.,..<.
      0000020: 5f 5b 17 7c 81 ed 31 28 4e 6e a4 6d 23 ad 5b c2 _[.|..1(Nn.m#.[.
      0000030: ae 25 83 9a 94 1a 2f 6f 05 fc e5 f0 73 13 f9 0b .%..../o....s...


      Thanks to @ovs for golfing off 1 byte!



      Try it online!






      share|improve this answer























      • 65 bytes. (zopfli with 120000 iterations)
        – ovs
        21 hours ago










      • @ovs Thanks! I had never tried so many iterations before.
        – Dennis
        20 hours ago


















      up vote
      7
      down vote














      ///, 170 bytes



      /+/////*/  +)/'$# +(/"$!+'/" +&/!#+%/"!
      !+$/*!+"/**+!/###/""('*
      (!!!'
      "&#"!!&"
      $#'$& &*
      !""& ! $
      !"'& !%""&$%""&$%)$%)$%(&#%(&#%'&'!%'!"$"!
      &$#")
      $&#"'!!*
      (!!&#"
      "$


      Try it online!






      share|improve this answer




























        up vote
        7
        down vote













        JavaScript (ES6), 173 170 bytes





        _=>`tc
        du
        9a9k
        58fe38
        36h83676
        6j83!h85!h85!f87!f87!dm96
        6dm96
        6b8b!b6d696
        3858n8
        5gjc
        dy
        d6`.split`!`.join`696
        6`.replace(/./g,c=>'# '[(k=parseInt(c,36))&1].repeat(k/2))


        Try it online!






        Node.js, 163 bytes



        Provided that an array of strings is a valid output:





        _=>Buffer(`.&-/*%$*&$''!$##($!###!#)$!#$&($"#$&($"#$&'$##$&'$##$&&+$&&+$&%$%#$&%#&#$#!$"$+$#()&(1*#2`).map(c=>s+='# '[x^=1].repeat(c-32),s=x='')&&s.match(/.{27}/g)


        Try it online!






        share|improve this answer






























          up vote
          7
          down vote














          Charcoal, 71 bytes



          P⁸↓P-³↙←⁴↓P³↙G→³↓⁹←³#↘P⁴↘P⁶↘‖OM←←¹⁷↘F⁹«P⁺³›ι³↑P⁴↗¿⁼ι²B⁸±²»↘→UO³¦¹⁴UMKA#


          Try it online! Link is to verbose version of code. Explanation:



          P⁸↓P-³↙←⁴↓P³↙G→³↓⁹←³#↘P⁴↘P⁶


          Output half of the circle.



          ↘‖OM←←¹⁷↘


          Reflect it and draw in the bottom.



          F⁹«P⁺³›ι³↑P⁴↗¿⁼ι²B⁸±²»


          Draw the left arm and crossbar of the A.



          ↘→UO³¦¹⁴


          Draw the right arm of the A.



          UMKA#


          Change all the characters to #s.






          share|improve this answer




























            up vote
            7
            down vote














            C (gcc), 174 168 164 bytes



            -6 bytes thanks to Dennis.





            i,j=88;main(l){while(j--)for(i="CJQHFIHCDKDBDACDCFCEFDCEDEFDKFFDKFFDCCDGFDCCDGFDCBDHFDCBDHFDCADICACCCADHCCDAGGDFJDEJOMFN"[j]-64;i;)putchar(l++%28?--i,35-j%2*3:10);}


            Try it online!






            share|improve this answer






























              up vote
              7
              down vote













              Python 2, 129 bytes





              00000000: 2363 6f64 696e 673a 4c31 0a70 7269 6e74  #coding:L1.print
              00000010: 2778 da95 9141 0e5c 3021 0803 ef7d 4593 'x...A.!...}E.
              00000020: feff 8f9b 5d14 5c6e f1b0 f622 7422 2890 ....].n..."t"(.
              00000030: 2e7d 5a09 dc4b 19cb bc53 84d1 4a6a 5960 .}Z..K...S..JjY`
              00000040: 116e 3f42 c290 b3f7 c0bc 76cf 549d 6ed8 .n?B......v.T.n.
              00000050: f8fa 5f26 0b0e 8c93 d5cb 35f6 b1e7 a939 .._&......5....9
              00000060: 9e98 e769 47b9 87d6 cdf5 5c30 3030 32c0 ...iG.....002.
              00000070: 4029 272e 6465 636f 6465 2827 7a69 7027 @)'.decode('zip'
              00000080: 29 )


              Try it online!






              share|improve this answer























              • 129 bytes, I removed the trailing n from the compressed string.
                – ovs
                22 hours ago


















              up vote
              6
              down vote













              Haskell, 170 163 bytes



              Edit: -7 bytes thanks to @Ørjan Johansen



              m=<<"Mc Ul WeWg YdTgZa ZcSdZcX cRdZcW cSdYcW cSdYcW cTdXcW cTdXcW cUkW cUkW cVdVcW cVcUcW ZdYdPa YhRc Un U "
              m ' '="###n"
              m c=(' '<$['Z','Y'..c])++('#'<$['a'..c])


              Try it online!



              Spaces are encoded as uppercase characters (length: Z down to char), hash signs as lowercase characters (length: a to char) and the last three # of each line plus newline as a space. Function m decodes it.






              share|improve this answer



















              • 1




                I think you can save some by letting space encode "###n".
                – Ørjan Johansen
                yesterday


















              up vote
              6
              down vote














              05AB1E, 101 88 64 bytes



              „# •∍ΔÎë,½=bOÅ.âαUΔ'òõƶαÔγλ#xÆ]~”FbćÁ˜Ð”wнQ_wā©•12вεN>yи}˜èJ27ô»


              -24 bytes by creating a port of @Dennis♦' Jelly answer.



              Try it online.



              Explanation:





              „#                     # Push string "# "
              •∍ΔÎë,½=bOÅ.âαUΔ'òõƶαÔγλ#xÆ]~”FbćÁ˜Ð”wнQ_wā©•
              '# Push compressed integer 10250938842396786963034911279002199266186481794751691439873548591280332406943905758890346943197901909163
              12в # Convert to Base-12 as list: [3,0,11,6,2,0,11,4,0,11,10,5,4,10,6,4,7,7,1,4,3,3,8,4,1,3,3,3,1,3,9,4,1,3,4,6,8,4,2,3,4,6,8,4,2,3,4,6,7,4,3,3,4,6,7,4,3,3,4,6,6,11,4,6,6,11,4,6,5,4,5,3,4,6,5,3,6,3,4,3,1,4,2,4,11,4,3,8,9,6,8,6,0,11,10,3]
              ε } # Map each `y` to:
              N> # The index+1
              yи # Repeated `y` amount of times
              ˜ # Flatten the list
              è # Index each in the string "# " (with automatic wraparound)
              J # Join everything together
              27ô # Split into parts of length 27
              » # And join by newlines


              See this 05AB1E tip of mine (sections How to compress large integers? and How to compress integer lists?) to understand how the compression of the integer and list works.






              share|improve this answer






























                up vote
                6
                down vote














                Bash, 192 176 bytes





                dc<<<"16i2o81C0000 81FFFF0 9FE00FC BCF001E F070387 F078387 F03FF87 F03FF87 F01E387 F01E387 F00F387 F00F387 F007B87 B807B8E 9E03FBC 87C3FF0 81FFFC0 8001F80f"|tr 01 ' #'|cut -c2-


                Try it online!



                -16 thanks to manatwork



                This is similar to my C answer, except it just uses a raw base-16 compression and passes it through bc, then uses tr to convert 1 to # and 0 to space. Each row has 1 appended to it and stripped off of it to maintain alignment.



                Unfortunately dc is shorter than bc.






                share|improve this answer























                • No need for ^. But even better, use cut -c2- instead of the sed part.
                  – manatwork
                  yesterday












                • And also shorter with here-string instead of echo and even shorter with dc instead of bc: Try it online!
                  – manatwork
                  yesterday






                • 2




                  I'll give you the echo, but come on - dc for Stan Lee... you must be joking ;)
                  – LambdaBeta
                  yesterday






                • 1




                  134 bytes
                  – Dennis
                  yesterday


















                up vote
                5
                down vote














                J, 130 128 bytes



                echo' #'{~18 27$;(_243{.2#.inv 92x#._32+a.i.])&>'!TYPW.ajz i8hIhXl''3lOH8GvV.C2Z{r/=,G';'"a*2ZDxRplkh2tzRakz.?ZwVmeOT6L^lFB^eyT'


                Try it online!



                Initial solution




                J, 164 bytes



                echo' #'{~18 27$,#:849239965469633263905532594449192007713271791872263657753301928240007 12380965417202148347902847903517734495157419855048834759608223758433386496x


                Try it online!






                share|improve this answer






























                  up vote
                  4
                  down vote














                  Perl 5, 181 bytes





                  say+(sprintf"%28b",oct"0x$_")=~y/10/# /r for"0003f0003fff800f87fe03c07f78700f71ce00f70ee01e70ee01e70ee03c70ee03c70ee07ff0ee07ff0ee0f070ee0e070e79e003c3fc01f803fffe00380000"=~/.{7}/g


                  Try it online!






                  share|improve this answer




























                    up vote
                    4
                    down vote














                    Perl 6, 136 116 bytes





                    :100['>	b3V$^%&!U3X/_9-D>Z(+, OD_=D,-:&3S>#OL
                    8C"> c H'.ords].base(2)~~TR/1/ /.comb(27)>>.say


                    Try it online!



                    Parses a base 100 number from the ordinal values of the string, converts to base 2 and replaces the 1s with spaces. This uses zeroes as the main character.



                    Explanation:



                    :100['...'.ords]   # Convert the bytes of the string to base 100
                    .base(2) # Convert to base 2
                    ~~TR/1/ / # Translate 1s to spaces
                    # Alternatively, this could be .split(1)
                    .comb(27) # Split to strings of length 27
                    >>.say # Print each on a newline





                    share|improve this answer






























                      up vote
                      3
                      down vote













                      MATLAB : 144 Bytes



                      reshape(repelem([repmat(' #',1,44),' '],'NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJCR'-64),27,)'


                      Try it online! (Technically in Octave)



                      Explanation:



                      This uses the same strategy as digEmAll in R, just with MATLAB syntax. The main difference is that MATLAB has automatic conversion from characters to integers.






                      share|improve this answer










                      New contributor




                      Nicky Mattsson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.

























                        up vote
                        2
                        down vote














                        C# (.NET Core), 199 bytes





                        _=>{var r="";for(int i=0,j,k=0;i<88;i++)for(j=0;j++<"0(/1,'&,(&))#&%%*&#%%%#%+&#%&(*&$%&(*&$%&()&%%&()&%%&((-&((-&('&'%&('%(%&%#&$&-&%*+(*3,%"[i]-34;){r+=i%2<1?' ':'#';if(++k%27<1)r+='n';}return r;}


                        Try it online!



                        Uses the same approach as my solution to the tribute to Adam West.






                        share|improve this answer




























                          up vote
                          1
                          down vote














                          PHP, 286 bytes





                          <?=preg_replace_callback('~(d*)(D)~',function($m){return str_repeat($m[2],$m[1]?:1);},str_replace(["
                          ",'~','^',';'],["^
                          ",'^4 ','3#','4#'],"14 ^
                          6 12#
                          4 5#4 7#
                          2 ; 6 7# #
                          ^8 ; ^3
                          ^9 ; ~
                          ^8 ;2 ~
                          ^8 ;2 ~
                          ^7 ;3 ~
                          ^7 ;3 ~
                          ^6 11#4
                          ^6 11#4
                          ^5 ;5 ~
                          ^5 ^6 ~
                          ;2 ;11 #
                          2 8#9 ^
                          6 1;
                          6 ^"));


                          Try it online!






                          share|improve this answer




























                            up vote
                            -1
                            down vote













                            deflate, 79 bytes



                            eJyVkcsJADAIQ++ZIpD9dyxUqrGUgjlpHvglXdqCJymk1yEiaRXEIOXzuBHCiKObReUxUzYaMdt2wmTBg/FmNXndgLRbNvL7ifsLfMw6iQ==






                            share|improve this answer








                            New contributor




                            Whale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.














                            • 5




                              You appear to have posted two answers in the same language. If you make an improvement to your submission it is better to edit your existing answer. Additionally, could you provide a link to the deflate language, as this just looks like a base64 string
                              – Jo King
                              yesterday








                            • 3




                              I don't think deflate counts as a programming language (although I could be wrong as I don't participate on PPCG).
                              – NobodyNada
                              yesterday






                            • 2




                              This is not DEFLATE, but zlib, which is DEFLATE plus a 2 byte header and a 4 byte checksum. By stripping those, you can use the Bubblegum interpreter.
                              – Dennis
                              yesterday












                            • @NobodyNada deflate is not a programming language but we do not require that submissions be in programming languages.
                              – Post Left Garf Hunter
                              19 hours ago











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                            up vote
                            19
                            down vote














                            Jelly, 62 59 58 bytes



                            “ḢE{ɠs{Ƒ0Ṇṁỵ8ỊṢṂƊeLṫfIWẈḞ'ʠJ£ṗɱçoȧ?ƒnØẆƥṂ⁷ɱ’b12ĖŒṙḂa⁶s27Y


                            Thanks to @JonathanAllan for golfing off 1 byte!



                            Try it online!



                            How it works



                            “ḢE{ɠs{Ƒ0Ṇṁỵ8ỊṢṂƊeLṫfIWẈḞ'ʠJ£ṗɱçoȧ?ƒnØẆƥṂ⁷ɱ’


                            is a bijective base-250 integer literal, which uses the characters in Jelly's code page as digits.



                            The literal encodes the integer $scriptsize 10250938842396786963034911279002199266186481794751691439873548591280332406943905758890346943197901909163$, which b12 converts to duodecimal, yielding $scriptsize 30b620b40ba54a64771433841333139413468423468423467433467433466b466b465453465363431424b43896860ba3_{12}$.



                            There are some zeroes, because 14 spaces (e.g.) are encoded as 3 spaces, 0 hashes, and 11 spaces. This maintains the base small (the largest run consists of 17 hashes), without adding any additional logic to the decoder.



                            Ė (enumerate) prefixes every base-12 digit by its 1-based index, then Œṙ performs run-length decoding.



                            Now, for each integer in the resulting array, extracts the least significant bit, then a⁶ (AND space) replaces ones with spaces, while leaving zeroes unchanged.



                            Finally, s27 splits the unformatted character array into chunks of length 27, which Y separates by linefeeds.






                            share|improve this answer



























                              up vote
                              19
                              down vote














                              Jelly, 62 59 58 bytes



                              “ḢE{ɠs{Ƒ0Ṇṁỵ8ỊṢṂƊeLṫfIWẈḞ'ʠJ£ṗɱçoȧ?ƒnØẆƥṂ⁷ɱ’b12ĖŒṙḂa⁶s27Y


                              Thanks to @JonathanAllan for golfing off 1 byte!



                              Try it online!



                              How it works



                              “ḢE{ɠs{Ƒ0Ṇṁỵ8ỊṢṂƊeLṫfIWẈḞ'ʠJ£ṗɱçoȧ?ƒnØẆƥṂ⁷ɱ’


                              is a bijective base-250 integer literal, which uses the characters in Jelly's code page as digits.



                              The literal encodes the integer $scriptsize 10250938842396786963034911279002199266186481794751691439873548591280332406943905758890346943197901909163$, which b12 converts to duodecimal, yielding $scriptsize 30b620b40ba54a64771433841333139413468423468423467433467433466b466b465453465363431424b43896860ba3_{12}$.



                              There are some zeroes, because 14 spaces (e.g.) are encoded as 3 spaces, 0 hashes, and 11 spaces. This maintains the base small (the largest run consists of 17 hashes), without adding any additional logic to the decoder.



                              Ė (enumerate) prefixes every base-12 digit by its 1-based index, then Œṙ performs run-length decoding.



                              Now, for each integer in the resulting array, extracts the least significant bit, then a⁶ (AND space) replaces ones with spaces, while leaving zeroes unchanged.



                              Finally, s27 splits the unformatted character array into chunks of length 27, which Y separates by linefeeds.






                              share|improve this answer

























                                up vote
                                19
                                down vote










                                up vote
                                19
                                down vote










                                Jelly, 62 59 58 bytes



                                “ḢE{ɠs{Ƒ0Ṇṁỵ8ỊṢṂƊeLṫfIWẈḞ'ʠJ£ṗɱçoȧ?ƒnØẆƥṂ⁷ɱ’b12ĖŒṙḂa⁶s27Y


                                Thanks to @JonathanAllan for golfing off 1 byte!



                                Try it online!



                                How it works



                                “ḢE{ɠs{Ƒ0Ṇṁỵ8ỊṢṂƊeLṫfIWẈḞ'ʠJ£ṗɱçoȧ?ƒnØẆƥṂ⁷ɱ’


                                is a bijective base-250 integer literal, which uses the characters in Jelly's code page as digits.



                                The literal encodes the integer $scriptsize 10250938842396786963034911279002199266186481794751691439873548591280332406943905758890346943197901909163$, which b12 converts to duodecimal, yielding $scriptsize 30b620b40ba54a64771433841333139413468423468423467433467433466b466b465453465363431424b43896860ba3_{12}$.



                                There are some zeroes, because 14 spaces (e.g.) are encoded as 3 spaces, 0 hashes, and 11 spaces. This maintains the base small (the largest run consists of 17 hashes), without adding any additional logic to the decoder.



                                Ė (enumerate) prefixes every base-12 digit by its 1-based index, then Œṙ performs run-length decoding.



                                Now, for each integer in the resulting array, extracts the least significant bit, then a⁶ (AND space) replaces ones with spaces, while leaving zeroes unchanged.



                                Finally, s27 splits the unformatted character array into chunks of length 27, which Y separates by linefeeds.






                                share|improve this answer















                                Jelly, 62 59 58 bytes



                                “ḢE{ɠs{Ƒ0Ṇṁỵ8ỊṢṂƊeLṫfIWẈḞ'ʠJ£ṗɱçoȧ?ƒnØẆƥṂ⁷ɱ’b12ĖŒṙḂa⁶s27Y


                                Thanks to @JonathanAllan for golfing off 1 byte!



                                Try it online!



                                How it works



                                “ḢE{ɠs{Ƒ0Ṇṁỵ8ỊṢṂƊeLṫfIWẈḞ'ʠJ£ṗɱçoȧ?ƒnØẆƥṂ⁷ɱ’


                                is a bijective base-250 integer literal, which uses the characters in Jelly's code page as digits.



                                The literal encodes the integer $scriptsize 10250938842396786963034911279002199266186481794751691439873548591280332406943905758890346943197901909163$, which b12 converts to duodecimal, yielding $scriptsize 30b620b40ba54a64771433841333139413468423468423467433467433466b466b465453465363431424b43896860ba3_{12}$.



                                There are some zeroes, because 14 spaces (e.g.) are encoded as 3 spaces, 0 hashes, and 11 spaces. This maintains the base small (the largest run consists of 17 hashes), without adding any additional logic to the decoder.



                                Ė (enumerate) prefixes every base-12 digit by its 1-based index, then Œṙ performs run-length decoding.



                                Now, for each integer in the resulting array, extracts the least significant bit, then a⁶ (AND space) replaces ones with spaces, while leaving zeroes unchanged.



                                Finally, s27 splits the unformatted character array into chunks of length 27, which Y separates by linefeeds.







                                share|improve this answer














                                share|improve this answer



                                share|improve this answer








                                edited 22 hours ago

























                                answered yesterday









                                Dennis

                                184k32293728




                                184k32293728






















                                    up vote
                                    13
                                    down vote














                                    R, 198, 173, 163, 157, 144, 142 bytes





                                    write(rep(rep(c(' ',4),44),utf8ToInt("NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJC")-64),1,27,,'')


                                    Try it online!



                                    Also R honors to the great Stan.



                                    Notes :




                                    • instead of the character # we've used the character 4 because saves 2 bytes and :


                                      • it's a reference to the Fantastic Four and/or the next Avengers 4 movie

                                      • it like we're repeating the logo inside the logo (since 4 seems a mini "slanted" A)



                                    • -15 bytes thanks to @Giuseppe


                                    Explanation :



                                    Applying a Run Length Encoding (rle function) on the characters of the string (excluding 'n') returns 88 repetitions of the alternating <space>,<hash>,<space>,<hash>,<space>,<hash>....



                                    The 88 repetitions are all values in the range [1,17] hence, summing 64 we get the code points of the letters [A...Q] obtaining the string : "NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJC"



                                    Hence the code basically does the opposite operations :



                                    v <- utf8ToInt("NFMOJEDJFDGGADC...")-64  # convert the string back to [1...17] vector

                                    e <- rep(rep(c(' ',4),44),v) # perform the inverse of rle function obtaining an
                                    # expanded vector of <space>'s and <four>'s

                                    write(e,1,27,,'') # write the vector to stdout arranging it
                                    # in rows of maximum 27 characters





                                    share|improve this answer



















                                    • 1




                                      Your solution is nicer, but your own gzip 2-parter gives 89+47 = 136 bytes.
                                      – J.Doe
                                      23 hours ago












                                    • @J.Doe : ahah I even forgot to have used that approach! please post it as your own answer :)
                                      – digEmAll
                                      23 hours ago












                                    • Since we can use any character for #, using 0 in place of "#" should save 2 more bytes. @J.Doe that may work better for your gzip as well.
                                      – Giuseppe
                                      22 hours ago















                                    up vote
                                    13
                                    down vote














                                    R, 198, 173, 163, 157, 144, 142 bytes





                                    write(rep(rep(c(' ',4),44),utf8ToInt("NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJC")-64),1,27,,'')


                                    Try it online!



                                    Also R honors to the great Stan.



                                    Notes :




                                    • instead of the character # we've used the character 4 because saves 2 bytes and :


                                      • it's a reference to the Fantastic Four and/or the next Avengers 4 movie

                                      • it like we're repeating the logo inside the logo (since 4 seems a mini "slanted" A)



                                    • -15 bytes thanks to @Giuseppe


                                    Explanation :



                                    Applying a Run Length Encoding (rle function) on the characters of the string (excluding 'n') returns 88 repetitions of the alternating <space>,<hash>,<space>,<hash>,<space>,<hash>....



                                    The 88 repetitions are all values in the range [1,17] hence, summing 64 we get the code points of the letters [A...Q] obtaining the string : "NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJC"



                                    Hence the code basically does the opposite operations :



                                    v <- utf8ToInt("NFMOJEDJFDGGADC...")-64  # convert the string back to [1...17] vector

                                    e <- rep(rep(c(' ',4),44),v) # perform the inverse of rle function obtaining an
                                    # expanded vector of <space>'s and <four>'s

                                    write(e,1,27,,'') # write the vector to stdout arranging it
                                    # in rows of maximum 27 characters





                                    share|improve this answer



















                                    • 1




                                      Your solution is nicer, but your own gzip 2-parter gives 89+47 = 136 bytes.
                                      – J.Doe
                                      23 hours ago












                                    • @J.Doe : ahah I even forgot to have used that approach! please post it as your own answer :)
                                      – digEmAll
                                      23 hours ago












                                    • Since we can use any character for #, using 0 in place of "#" should save 2 more bytes. @J.Doe that may work better for your gzip as well.
                                      – Giuseppe
                                      22 hours ago













                                    up vote
                                    13
                                    down vote










                                    up vote
                                    13
                                    down vote










                                    R, 198, 173, 163, 157, 144, 142 bytes





                                    write(rep(rep(c(' ',4),44),utf8ToInt("NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJC")-64),1,27,,'')


                                    Try it online!



                                    Also R honors to the great Stan.



                                    Notes :




                                    • instead of the character # we've used the character 4 because saves 2 bytes and :


                                      • it's a reference to the Fantastic Four and/or the next Avengers 4 movie

                                      • it like we're repeating the logo inside the logo (since 4 seems a mini "slanted" A)



                                    • -15 bytes thanks to @Giuseppe


                                    Explanation :



                                    Applying a Run Length Encoding (rle function) on the characters of the string (excluding 'n') returns 88 repetitions of the alternating <space>,<hash>,<space>,<hash>,<space>,<hash>....



                                    The 88 repetitions are all values in the range [1,17] hence, summing 64 we get the code points of the letters [A...Q] obtaining the string : "NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJC"



                                    Hence the code basically does the opposite operations :



                                    v <- utf8ToInt("NFMOJEDJFDGGADC...")-64  # convert the string back to [1...17] vector

                                    e <- rep(rep(c(' ',4),44),v) # perform the inverse of rle function obtaining an
                                    # expanded vector of <space>'s and <four>'s

                                    write(e,1,27,,'') # write the vector to stdout arranging it
                                    # in rows of maximum 27 characters





                                    share|improve this answer















                                    R, 198, 173, 163, 157, 144, 142 bytes





                                    write(rep(rep(c(' ',4),44),utf8ToInt("NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJC")-64),1,27,,'')


                                    Try it online!



                                    Also R honors to the great Stan.



                                    Notes :




                                    • instead of the character # we've used the character 4 because saves 2 bytes and :


                                      • it's a reference to the Fantastic Four and/or the next Avengers 4 movie

                                      • it like we're repeating the logo inside the logo (since 4 seems a mini "slanted" A)



                                    • -15 bytes thanks to @Giuseppe


                                    Explanation :



                                    Applying a Run Length Encoding (rle function) on the characters of the string (excluding 'n') returns 88 repetitions of the alternating <space>,<hash>,<space>,<hash>,<space>,<hash>....



                                    The 88 repetitions are all values in the range [1,17] hence, summing 64 we get the code points of the letters [A...Q] obtaining the string : "NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJC"



                                    Hence the code basically does the opposite operations :



                                    v <- utf8ToInt("NFMOJEDJFDGGADC...")-64  # convert the string back to [1...17] vector

                                    e <- rep(rep(c(' ',4),44),v) # perform the inverse of rle function obtaining an
                                    # expanded vector of <space>'s and <four>'s

                                    write(e,1,27,,'') # write the vector to stdout arranging it
                                    # in rows of maximum 27 characters






                                    share|improve this answer














                                    share|improve this answer



                                    share|improve this answer








                                    edited 11 hours ago

























                                    answered 2 days ago









                                    digEmAll

                                    2,18148




                                    2,18148








                                    • 1




                                      Your solution is nicer, but your own gzip 2-parter gives 89+47 = 136 bytes.
                                      – J.Doe
                                      23 hours ago












                                    • @J.Doe : ahah I even forgot to have used that approach! please post it as your own answer :)
                                      – digEmAll
                                      23 hours ago












                                    • Since we can use any character for #, using 0 in place of "#" should save 2 more bytes. @J.Doe that may work better for your gzip as well.
                                      – Giuseppe
                                      22 hours ago














                                    • 1




                                      Your solution is nicer, but your own gzip 2-parter gives 89+47 = 136 bytes.
                                      – J.Doe
                                      23 hours ago












                                    • @J.Doe : ahah I even forgot to have used that approach! please post it as your own answer :)
                                      – digEmAll
                                      23 hours ago












                                    • Since we can use any character for #, using 0 in place of "#" should save 2 more bytes. @J.Doe that may work better for your gzip as well.
                                      – Giuseppe
                                      22 hours ago








                                    1




                                    1




                                    Your solution is nicer, but your own gzip 2-parter gives 89+47 = 136 bytes.
                                    – J.Doe
                                    23 hours ago






                                    Your solution is nicer, but your own gzip 2-parter gives 89+47 = 136 bytes.
                                    – J.Doe
                                    23 hours ago














                                    @J.Doe : ahah I even forgot to have used that approach! please post it as your own answer :)
                                    – digEmAll
                                    23 hours ago






                                    @J.Doe : ahah I even forgot to have used that approach! please post it as your own answer :)
                                    – digEmAll
                                    23 hours ago














                                    Since we can use any character for #, using 0 in place of "#" should save 2 more bytes. @J.Doe that may work better for your gzip as well.
                                    – Giuseppe
                                    22 hours ago




                                    Since we can use any character for #, using 0 in place of "#" should save 2 more bytes. @J.Doe that may work better for your gzip as well.
                                    – Giuseppe
                                    22 hours ago










                                    up vote
                                    9
                                    down vote














                                    C (gcc), 244 243 bytes





                                    #define z <<10|117441415
                                    x={8064,2097088,8142832,31473596,58751886,30 z,60 z,60 z,120 z,120 z,255 z,255 z,480 z,448 z,63897630,33423612,2097136,1835008};b(_,i){i&&b(_/2,i-1),putchar(" #"[_%2]);}main(_){_<19&&b(x[_-1],27)&puts("")&main(_+1);}


                                    Try it online!



                                    -1 Thanks to Peter Cordes



                                    Uses bit compression.



                                    Explanation:



                                    The goal is to print a set of numbers in binary using space and # as digits which represent the logo. A bit of bash magic converts the logo to binary masks:



                                    echo "ibase=2;$(<code which echoes the logo [see my bash solution for example]> | tr ' #' 01)" | bc


                                    This results in the binary 'numbers' being:



                                    8064,2097088,8142832,31473596,58751886,117472135,117502855,117502855,117564295,117564295,117702535,117702535,117932935,117900167,63897630,33423612,2097136,1835008


                                    There is an obvious pattern in the middle where every line contains ### ### ###



                                    We can save some space by compressing that middle section based on saving that pattern and OR-ing against it. In addition, all of those lines merely add some stuff to the left of the middle section, so we make the z macro which takes ?????????????? and converts it into ###??????????????### ###. This involves bitshifting left by 10 and OR-ing with the binary of that pattern, which is 117441415.



                                    Now we can more easily understand the code:



                                    #define z <<10|117441415 // Define z to be the compression defined above
                                    x={ // Define x to be an array storing each line's number
                                    8064,2097088,8142832, // The first 5 lines are uncompressed
                                    31473596,58751886,
                                    30 z,60 z,60 z,120 z, // The middle 9 lines are z-compressed
                                    120 z,255 z,255 z,480 z,
                                    448 z,
                                    63897630,33423612, // The last 4 lines are uncompressed
                                    2097136,1835008};
                                    b(_,i){ // we also need a function to print n-bit binary numbers
                                    i&& // i is the bit counter, we recurse until its zero
                                    b(_/2,i-1), // each recursive call halves the input and decrements i
                                    putchar(" #"[_%2]);} // this just prints the correct character
                                    main(_){ // this is the main function, called as ./? will have 1 in _ (argc)
                                    _<19? // if _ is less than 19 then...
                                    b(x[_-1],27), // print the binary expansion of x[_-1]
                                    puts(""), // print a new line
                                    main(_+1) // recurse with _++
                                    :0;}





                                    share|improve this answer























                                    • Can x?y:0 be replaced with x&&y, or does operator precedence not work? Maybe with & instead of , separating the 3 function calls because & has higher precedence than && or , (en.cppreference.com/w/c/language/operator_precedence). Or not because only , provides a sequence point for the printing vs. recursion to avoid undefined behaviour.
                                      – Peter Cordes
                                      yesterday












                                    • It doesn't work with && indeed because of the precedence, while & doesn't short-circuit. As of yet I haven't found a shorter alternative, though I wouldn't rule one out.
                                      – LambdaBeta
                                      yesterday










                                    • I meant with & or | or ^ replacing , (because they don't short-circuit) and && replacing ? (because it does). Like _<19 && b() & puts() & main(_+1); (spaces added for readability). The order of evaluation is undefined, which may actually undefined behaviour because of unsequenced side-effects on stdout en.cppreference.com/w/c/language/eval_order, but in practice any given compiler will pick some order for a given set of target + options.
                                      – Peter Cordes
                                      yesterday








                                    • 1




                                      Ahh, I see what you mean. You're right - that does work! -1 byte.
                                      – LambdaBeta
                                      yesterday















                                    up vote
                                    9
                                    down vote














                                    C (gcc), 244 243 bytes





                                    #define z <<10|117441415
                                    x={8064,2097088,8142832,31473596,58751886,30 z,60 z,60 z,120 z,120 z,255 z,255 z,480 z,448 z,63897630,33423612,2097136,1835008};b(_,i){i&&b(_/2,i-1),putchar(" #"[_%2]);}main(_){_<19&&b(x[_-1],27)&puts("")&main(_+1);}


                                    Try it online!



                                    -1 Thanks to Peter Cordes



                                    Uses bit compression.



                                    Explanation:



                                    The goal is to print a set of numbers in binary using space and # as digits which represent the logo. A bit of bash magic converts the logo to binary masks:



                                    echo "ibase=2;$(<code which echoes the logo [see my bash solution for example]> | tr ' #' 01)" | bc


                                    This results in the binary 'numbers' being:



                                    8064,2097088,8142832,31473596,58751886,117472135,117502855,117502855,117564295,117564295,117702535,117702535,117932935,117900167,63897630,33423612,2097136,1835008


                                    There is an obvious pattern in the middle where every line contains ### ### ###



                                    We can save some space by compressing that middle section based on saving that pattern and OR-ing against it. In addition, all of those lines merely add some stuff to the left of the middle section, so we make the z macro which takes ?????????????? and converts it into ###??????????????### ###. This involves bitshifting left by 10 and OR-ing with the binary of that pattern, which is 117441415.



                                    Now we can more easily understand the code:



                                    #define z <<10|117441415 // Define z to be the compression defined above
                                    x={ // Define x to be an array storing each line's number
                                    8064,2097088,8142832, // The first 5 lines are uncompressed
                                    31473596,58751886,
                                    30 z,60 z,60 z,120 z, // The middle 9 lines are z-compressed
                                    120 z,255 z,255 z,480 z,
                                    448 z,
                                    63897630,33423612, // The last 4 lines are uncompressed
                                    2097136,1835008};
                                    b(_,i){ // we also need a function to print n-bit binary numbers
                                    i&& // i is the bit counter, we recurse until its zero
                                    b(_/2,i-1), // each recursive call halves the input and decrements i
                                    putchar(" #"[_%2]);} // this just prints the correct character
                                    main(_){ // this is the main function, called as ./? will have 1 in _ (argc)
                                    _<19? // if _ is less than 19 then...
                                    b(x[_-1],27), // print the binary expansion of x[_-1]
                                    puts(""), // print a new line
                                    main(_+1) // recurse with _++
                                    :0;}





                                    share|improve this answer























                                    • Can x?y:0 be replaced with x&&y, or does operator precedence not work? Maybe with & instead of , separating the 3 function calls because & has higher precedence than && or , (en.cppreference.com/w/c/language/operator_precedence). Or not because only , provides a sequence point for the printing vs. recursion to avoid undefined behaviour.
                                      – Peter Cordes
                                      yesterday












                                    • It doesn't work with && indeed because of the precedence, while & doesn't short-circuit. As of yet I haven't found a shorter alternative, though I wouldn't rule one out.
                                      – LambdaBeta
                                      yesterday










                                    • I meant with & or | or ^ replacing , (because they don't short-circuit) and && replacing ? (because it does). Like _<19 && b() & puts() & main(_+1); (spaces added for readability). The order of evaluation is undefined, which may actually undefined behaviour because of unsequenced side-effects on stdout en.cppreference.com/w/c/language/eval_order, but in practice any given compiler will pick some order for a given set of target + options.
                                      – Peter Cordes
                                      yesterday








                                    • 1




                                      Ahh, I see what you mean. You're right - that does work! -1 byte.
                                      – LambdaBeta
                                      yesterday













                                    up vote
                                    9
                                    down vote










                                    up vote
                                    9
                                    down vote










                                    C (gcc), 244 243 bytes





                                    #define z <<10|117441415
                                    x={8064,2097088,8142832,31473596,58751886,30 z,60 z,60 z,120 z,120 z,255 z,255 z,480 z,448 z,63897630,33423612,2097136,1835008};b(_,i){i&&b(_/2,i-1),putchar(" #"[_%2]);}main(_){_<19&&b(x[_-1],27)&puts("")&main(_+1);}


                                    Try it online!



                                    -1 Thanks to Peter Cordes



                                    Uses bit compression.



                                    Explanation:



                                    The goal is to print a set of numbers in binary using space and # as digits which represent the logo. A bit of bash magic converts the logo to binary masks:



                                    echo "ibase=2;$(<code which echoes the logo [see my bash solution for example]> | tr ' #' 01)" | bc


                                    This results in the binary 'numbers' being:



                                    8064,2097088,8142832,31473596,58751886,117472135,117502855,117502855,117564295,117564295,117702535,117702535,117932935,117900167,63897630,33423612,2097136,1835008


                                    There is an obvious pattern in the middle where every line contains ### ### ###



                                    We can save some space by compressing that middle section based on saving that pattern and OR-ing against it. In addition, all of those lines merely add some stuff to the left of the middle section, so we make the z macro which takes ?????????????? and converts it into ###??????????????### ###. This involves bitshifting left by 10 and OR-ing with the binary of that pattern, which is 117441415.



                                    Now we can more easily understand the code:



                                    #define z <<10|117441415 // Define z to be the compression defined above
                                    x={ // Define x to be an array storing each line's number
                                    8064,2097088,8142832, // The first 5 lines are uncompressed
                                    31473596,58751886,
                                    30 z,60 z,60 z,120 z, // The middle 9 lines are z-compressed
                                    120 z,255 z,255 z,480 z,
                                    448 z,
                                    63897630,33423612, // The last 4 lines are uncompressed
                                    2097136,1835008};
                                    b(_,i){ // we also need a function to print n-bit binary numbers
                                    i&& // i is the bit counter, we recurse until its zero
                                    b(_/2,i-1), // each recursive call halves the input and decrements i
                                    putchar(" #"[_%2]);} // this just prints the correct character
                                    main(_){ // this is the main function, called as ./? will have 1 in _ (argc)
                                    _<19? // if _ is less than 19 then...
                                    b(x[_-1],27), // print the binary expansion of x[_-1]
                                    puts(""), // print a new line
                                    main(_+1) // recurse with _++
                                    :0;}





                                    share|improve this answer















                                    C (gcc), 244 243 bytes





                                    #define z <<10|117441415
                                    x={8064,2097088,8142832,31473596,58751886,30 z,60 z,60 z,120 z,120 z,255 z,255 z,480 z,448 z,63897630,33423612,2097136,1835008};b(_,i){i&&b(_/2,i-1),putchar(" #"[_%2]);}main(_){_<19&&b(x[_-1],27)&puts("")&main(_+1);}


                                    Try it online!



                                    -1 Thanks to Peter Cordes



                                    Uses bit compression.



                                    Explanation:



                                    The goal is to print a set of numbers in binary using space and # as digits which represent the logo. A bit of bash magic converts the logo to binary masks:



                                    echo "ibase=2;$(<code which echoes the logo [see my bash solution for example]> | tr ' #' 01)" | bc


                                    This results in the binary 'numbers' being:



                                    8064,2097088,8142832,31473596,58751886,117472135,117502855,117502855,117564295,117564295,117702535,117702535,117932935,117900167,63897630,33423612,2097136,1835008


                                    There is an obvious pattern in the middle where every line contains ### ### ###



                                    We can save some space by compressing that middle section based on saving that pattern and OR-ing against it. In addition, all of those lines merely add some stuff to the left of the middle section, so we make the z macro which takes ?????????????? and converts it into ###??????????????### ###. This involves bitshifting left by 10 and OR-ing with the binary of that pattern, which is 117441415.



                                    Now we can more easily understand the code:



                                    #define z <<10|117441415 // Define z to be the compression defined above
                                    x={ // Define x to be an array storing each line's number
                                    8064,2097088,8142832, // The first 5 lines are uncompressed
                                    31473596,58751886,
                                    30 z,60 z,60 z,120 z, // The middle 9 lines are z-compressed
                                    120 z,255 z,255 z,480 z,
                                    448 z,
                                    63897630,33423612, // The last 4 lines are uncompressed
                                    2097136,1835008};
                                    b(_,i){ // we also need a function to print n-bit binary numbers
                                    i&& // i is the bit counter, we recurse until its zero
                                    b(_/2,i-1), // each recursive call halves the input and decrements i
                                    putchar(" #"[_%2]);} // this just prints the correct character
                                    main(_){ // this is the main function, called as ./? will have 1 in _ (argc)
                                    _<19? // if _ is less than 19 then...
                                    b(x[_-1],27), // print the binary expansion of x[_-1]
                                    puts(""), // print a new line
                                    main(_+1) // recurse with _++
                                    :0;}






                                    share|improve this answer














                                    share|improve this answer



                                    share|improve this answer








                                    edited yesterday

























                                    answered yesterday









                                    LambdaBeta

                                    1,989416




                                    1,989416












                                    • Can x?y:0 be replaced with x&&y, or does operator precedence not work? Maybe with & instead of , separating the 3 function calls because & has higher precedence than && or , (en.cppreference.com/w/c/language/operator_precedence). Or not because only , provides a sequence point for the printing vs. recursion to avoid undefined behaviour.
                                      – Peter Cordes
                                      yesterday












                                    • It doesn't work with && indeed because of the precedence, while & doesn't short-circuit. As of yet I haven't found a shorter alternative, though I wouldn't rule one out.
                                      – LambdaBeta
                                      yesterday










                                    • I meant with & or | or ^ replacing , (because they don't short-circuit) and && replacing ? (because it does). Like _<19 && b() & puts() & main(_+1); (spaces added for readability). The order of evaluation is undefined, which may actually undefined behaviour because of unsequenced side-effects on stdout en.cppreference.com/w/c/language/eval_order, but in practice any given compiler will pick some order for a given set of target + options.
                                      – Peter Cordes
                                      yesterday








                                    • 1




                                      Ahh, I see what you mean. You're right - that does work! -1 byte.
                                      – LambdaBeta
                                      yesterday


















                                    • Can x?y:0 be replaced with x&&y, or does operator precedence not work? Maybe with & instead of , separating the 3 function calls because & has higher precedence than && or , (en.cppreference.com/w/c/language/operator_precedence). Or not because only , provides a sequence point for the printing vs. recursion to avoid undefined behaviour.
                                      – Peter Cordes
                                      yesterday












                                    • It doesn't work with && indeed because of the precedence, while & doesn't short-circuit. As of yet I haven't found a shorter alternative, though I wouldn't rule one out.
                                      – LambdaBeta
                                      yesterday










                                    • I meant with & or | or ^ replacing , (because they don't short-circuit) and && replacing ? (because it does). Like _<19 && b() & puts() & main(_+1); (spaces added for readability). The order of evaluation is undefined, which may actually undefined behaviour because of unsequenced side-effects on stdout en.cppreference.com/w/c/language/eval_order, but in practice any given compiler will pick some order for a given set of target + options.
                                      – Peter Cordes
                                      yesterday








                                    • 1




                                      Ahh, I see what you mean. You're right - that does work! -1 byte.
                                      – LambdaBeta
                                      yesterday
















                                    Can x?y:0 be replaced with x&&y, or does operator precedence not work? Maybe with & instead of , separating the 3 function calls because & has higher precedence than && or , (en.cppreference.com/w/c/language/operator_precedence). Or not because only , provides a sequence point for the printing vs. recursion to avoid undefined behaviour.
                                    – Peter Cordes
                                    yesterday






                                    Can x?y:0 be replaced with x&&y, or does operator precedence not work? Maybe with & instead of , separating the 3 function calls because & has higher precedence than && or , (en.cppreference.com/w/c/language/operator_precedence). Or not because only , provides a sequence point for the printing vs. recursion to avoid undefined behaviour.
                                    – Peter Cordes
                                    yesterday














                                    It doesn't work with && indeed because of the precedence, while & doesn't short-circuit. As of yet I haven't found a shorter alternative, though I wouldn't rule one out.
                                    – LambdaBeta
                                    yesterday




                                    It doesn't work with && indeed because of the precedence, while & doesn't short-circuit. As of yet I haven't found a shorter alternative, though I wouldn't rule one out.
                                    – LambdaBeta
                                    yesterday












                                    I meant with & or | or ^ replacing , (because they don't short-circuit) and && replacing ? (because it does). Like _<19 && b() & puts() & main(_+1); (spaces added for readability). The order of evaluation is undefined, which may actually undefined behaviour because of unsequenced side-effects on stdout en.cppreference.com/w/c/language/eval_order, but in practice any given compiler will pick some order for a given set of target + options.
                                    – Peter Cordes
                                    yesterday






                                    I meant with & or | or ^ replacing , (because they don't short-circuit) and && replacing ? (because it does). Like _<19 && b() & puts() & main(_+1); (spaces added for readability). The order of evaluation is undefined, which may actually undefined behaviour because of unsequenced side-effects on stdout en.cppreference.com/w/c/language/eval_order, but in practice any given compiler will pick some order for a given set of target + options.
                                    – Peter Cordes
                                    yesterday






                                    1




                                    1




                                    Ahh, I see what you mean. You're right - that does work! -1 byte.
                                    – LambdaBeta
                                    yesterday




                                    Ahh, I see what you mean. You're right - that does work! -1 byte.
                                    – LambdaBeta
                                    yesterday










                                    up vote
                                    8
                                    down vote














                                    Canvas, 74 73 71 bytes



                                    qc2-Az↓n⁴╫m┬ff╷\_↘Tt)%⁵6>Yy7pQ∔I%SIŗ+T^≤?↔↖¶8^`O‾+O│≤n≡j↶82„2┬{ #@]∑‾+n


                                    Try it here!






                                    share|improve this answer



























                                      up vote
                                      8
                                      down vote














                                      Canvas, 74 73 71 bytes



                                      qc2-Az↓n⁴╫m┬ff╷\_↘Tt)%⁵6>Yy7pQ∔I%SIŗ+T^≤?↔↖¶8^`O‾+O│≤n≡j↶82„2┬{ #@]∑‾+n


                                      Try it here!






                                      share|improve this answer

























                                        up vote
                                        8
                                        down vote










                                        up vote
                                        8
                                        down vote










                                        Canvas, 74 73 71 bytes



                                        qc2-Az↓n⁴╫m┬ff╷\_↘Tt)%⁵6>Yy7pQ∔I%SIŗ+T^≤?↔↖¶8^`O‾+O│≤n≡j↶82„2┬{ #@]∑‾+n


                                        Try it here!






                                        share|improve this answer















                                        Canvas, 74 73 71 bytes



                                        qc2-Az↓n⁴╫m┬ff╷\_↘Tt)%⁵6>Yy7pQ∔I%SIŗ+T^≤?↔↖¶8^`O‾+O│≤n≡j↶82„2┬{ #@]∑‾+n


                                        Try it here!







                                        share|improve this answer














                                        share|improve this answer



                                        share|improve this answer








                                        edited 2 days ago

























                                        answered 2 days ago









                                        dzaima

                                        14k21653




                                        14k21653






















                                            up vote
                                            8
                                            down vote













                                            T-SQL, 341 338 bytes



                                            DECLARE @ CHAR(2000)=REPLACE(REPLACE(REPLACE(
                                            'PRINT SPACE(14*6&$6*15&$4*5$4*10&$2*4$7*7$1*4&$1*3$8*4$1*3$3*3&*3$9*4$1*3$4
                                            *3&*3$8*4$2*3$4*3&*3$8*4$2*3$4*3&*3$7*4$3*3$4*3&*3$7*4$3*3$4*3&*3$6*11$4*3&
                                            *3$6*11$4*3&*3$5*4$5*3$4*3&*3$5*3$6*3$4*3&$1*4$2*4$11*4&$2*8$9*6&$6*17&$6*3)'
                                            ,'*',')+REPLICATE(''#'','),'$',')+SPACE('),'&',')+(''
                                            ''')EXEC(@)


                                            The first 4 line breaks are for readability only, the final line break is part of a string literal.



                                            Similar to my Adam West tribute, I've manually encoded a long string, and made the following replacements:





                                            • *7 gets replaced by +REPLICATE('#',7)


                                            • $4 gets replaced by +SPACE(4)


                                            • & gets replaced by a line break inside quotes


                                            This results in a massive SQL command string:



                                            PRINT SPACE(14)+REPLICATE('#',6)+('
                                            ')+SPACE(6)+REPLICATE('#',15)+('
                                            ')+SPACE(4)+REPLICATE('#',5)+SPACE(4)+REPLICATE('#',10)+('
                                            ')+SPACE(2)+REPLICATE('#',4)+SPACE(7)+REPLICATE('#',7)+SPACE(1)+REPLICATE('#',4)+('
                                            ')+SPACE(1)+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(1)+REPLICATE('#',3)+SPACE(3)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(9)+REPLICATE('#',4)+SPACE(1)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(7)+REPLICATE('#',4)+SPACE(3)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(7)+REPLICATE('#',4)+SPACE(3)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',11)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',11)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(5)+REPLICATE('#',4)+SPACE(5)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(5)+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+SPACE(1)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',4)+SPACE(11)+REPLICATE('#',4)+('
                                            ')+SPACE(2)+REPLICATE('#',8)+SPACE(9)+REPLICATE('#',6)+('
                                            ')+SPACE(6)+REPLICATE('#',17)+('
                                            ')+SPACE(6)+REPLICATE('#',3)


                                            Which, when run, produces the necessary output.



                                            Long, but still better than my best set-based solution (463 bytes):



                                            SELECT SPACE(a)+REPLICATE('#',b)+SPACE(c)+REPLICATE('#',d)
                                            +SPACE(e)+REPLICATE('#',f)+SPACE(g)+REPLICATE('#',h)
                                            FROM(VALUES(7,0,7,6,0,0,0,0),(6,8,0,7,0,0,0,0),(4,5,4,5,0,5,0,0),(2,4,7,7,1,4,0,0),
                                            (1,3,8,4,1,3,3,3),(0,3,9,4,1,3,4,3),(0,3,8,4,2,3,4,3),(0,3,8,4,2,3,4,3),
                                            (0,3,7,4,3,3,4,3),(0,3,7,4,3,3,4,3),(0,3,6,6,0,5,4,3),(0,3,6,6,0,5,4,3),
                                            (0,3,5,4,5,3,4,3),(0,3,5,3,6,3,4,3),(1,4,2,4,5,0,6,4),(2,8,9,6,0,0,0,0),
                                            (6,9,0,8,0,0,0,0),(6,3,0,0,0,0,0,0))t(a,b,c,d,e,f,g,h)





                                            share|improve this answer























                                            • can drop 2 chars using CHAR(8000) instead of VARCHAR(max) (the huge command is 1453 bytes)
                                              – Shameen
                                              yesterday






                                            • 1




                                              Thanks, @Shameen. I tried to save one more and use CHAR(2E3) but it didn't seem to like that. I also saved a byte by using a line break literal instead of CHAR(13).
                                              – BradC
                                              yesterday

















                                            up vote
                                            8
                                            down vote













                                            T-SQL, 341 338 bytes



                                            DECLARE @ CHAR(2000)=REPLACE(REPLACE(REPLACE(
                                            'PRINT SPACE(14*6&$6*15&$4*5$4*10&$2*4$7*7$1*4&$1*3$8*4$1*3$3*3&*3$9*4$1*3$4
                                            *3&*3$8*4$2*3$4*3&*3$8*4$2*3$4*3&*3$7*4$3*3$4*3&*3$7*4$3*3$4*3&*3$6*11$4*3&
                                            *3$6*11$4*3&*3$5*4$5*3$4*3&*3$5*3$6*3$4*3&$1*4$2*4$11*4&$2*8$9*6&$6*17&$6*3)'
                                            ,'*',')+REPLICATE(''#'','),'$',')+SPACE('),'&',')+(''
                                            ''')EXEC(@)


                                            The first 4 line breaks are for readability only, the final line break is part of a string literal.



                                            Similar to my Adam West tribute, I've manually encoded a long string, and made the following replacements:





                                            • *7 gets replaced by +REPLICATE('#',7)


                                            • $4 gets replaced by +SPACE(4)


                                            • & gets replaced by a line break inside quotes


                                            This results in a massive SQL command string:



                                            PRINT SPACE(14)+REPLICATE('#',6)+('
                                            ')+SPACE(6)+REPLICATE('#',15)+('
                                            ')+SPACE(4)+REPLICATE('#',5)+SPACE(4)+REPLICATE('#',10)+('
                                            ')+SPACE(2)+REPLICATE('#',4)+SPACE(7)+REPLICATE('#',7)+SPACE(1)+REPLICATE('#',4)+('
                                            ')+SPACE(1)+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(1)+REPLICATE('#',3)+SPACE(3)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(9)+REPLICATE('#',4)+SPACE(1)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(7)+REPLICATE('#',4)+SPACE(3)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(7)+REPLICATE('#',4)+SPACE(3)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',11)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',11)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(5)+REPLICATE('#',4)+SPACE(5)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(5)+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+SPACE(1)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',4)+SPACE(11)+REPLICATE('#',4)+('
                                            ')+SPACE(2)+REPLICATE('#',8)+SPACE(9)+REPLICATE('#',6)+('
                                            ')+SPACE(6)+REPLICATE('#',17)+('
                                            ')+SPACE(6)+REPLICATE('#',3)


                                            Which, when run, produces the necessary output.



                                            Long, but still better than my best set-based solution (463 bytes):



                                            SELECT SPACE(a)+REPLICATE('#',b)+SPACE(c)+REPLICATE('#',d)
                                            +SPACE(e)+REPLICATE('#',f)+SPACE(g)+REPLICATE('#',h)
                                            FROM(VALUES(7,0,7,6,0,0,0,0),(6,8,0,7,0,0,0,0),(4,5,4,5,0,5,0,0),(2,4,7,7,1,4,0,0),
                                            (1,3,8,4,1,3,3,3),(0,3,9,4,1,3,4,3),(0,3,8,4,2,3,4,3),(0,3,8,4,2,3,4,3),
                                            (0,3,7,4,3,3,4,3),(0,3,7,4,3,3,4,3),(0,3,6,6,0,5,4,3),(0,3,6,6,0,5,4,3),
                                            (0,3,5,4,5,3,4,3),(0,3,5,3,6,3,4,3),(1,4,2,4,5,0,6,4),(2,8,9,6,0,0,0,0),
                                            (6,9,0,8,0,0,0,0),(6,3,0,0,0,0,0,0))t(a,b,c,d,e,f,g,h)





                                            share|improve this answer























                                            • can drop 2 chars using CHAR(8000) instead of VARCHAR(max) (the huge command is 1453 bytes)
                                              – Shameen
                                              yesterday






                                            • 1




                                              Thanks, @Shameen. I tried to save one more and use CHAR(2E3) but it didn't seem to like that. I also saved a byte by using a line break literal instead of CHAR(13).
                                              – BradC
                                              yesterday















                                            up vote
                                            8
                                            down vote










                                            up vote
                                            8
                                            down vote









                                            T-SQL, 341 338 bytes



                                            DECLARE @ CHAR(2000)=REPLACE(REPLACE(REPLACE(
                                            'PRINT SPACE(14*6&$6*15&$4*5$4*10&$2*4$7*7$1*4&$1*3$8*4$1*3$3*3&*3$9*4$1*3$4
                                            *3&*3$8*4$2*3$4*3&*3$8*4$2*3$4*3&*3$7*4$3*3$4*3&*3$7*4$3*3$4*3&*3$6*11$4*3&
                                            *3$6*11$4*3&*3$5*4$5*3$4*3&*3$5*3$6*3$4*3&$1*4$2*4$11*4&$2*8$9*6&$6*17&$6*3)'
                                            ,'*',')+REPLICATE(''#'','),'$',')+SPACE('),'&',')+(''
                                            ''')EXEC(@)


                                            The first 4 line breaks are for readability only, the final line break is part of a string literal.



                                            Similar to my Adam West tribute, I've manually encoded a long string, and made the following replacements:





                                            • *7 gets replaced by +REPLICATE('#',7)


                                            • $4 gets replaced by +SPACE(4)


                                            • & gets replaced by a line break inside quotes


                                            This results in a massive SQL command string:



                                            PRINT SPACE(14)+REPLICATE('#',6)+('
                                            ')+SPACE(6)+REPLICATE('#',15)+('
                                            ')+SPACE(4)+REPLICATE('#',5)+SPACE(4)+REPLICATE('#',10)+('
                                            ')+SPACE(2)+REPLICATE('#',4)+SPACE(7)+REPLICATE('#',7)+SPACE(1)+REPLICATE('#',4)+('
                                            ')+SPACE(1)+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(1)+REPLICATE('#',3)+SPACE(3)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(9)+REPLICATE('#',4)+SPACE(1)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(7)+REPLICATE('#',4)+SPACE(3)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(7)+REPLICATE('#',4)+SPACE(3)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',11)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',11)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(5)+REPLICATE('#',4)+SPACE(5)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(5)+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+SPACE(1)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',4)+SPACE(11)+REPLICATE('#',4)+('
                                            ')+SPACE(2)+REPLICATE('#',8)+SPACE(9)+REPLICATE('#',6)+('
                                            ')+SPACE(6)+REPLICATE('#',17)+('
                                            ')+SPACE(6)+REPLICATE('#',3)


                                            Which, when run, produces the necessary output.



                                            Long, but still better than my best set-based solution (463 bytes):



                                            SELECT SPACE(a)+REPLICATE('#',b)+SPACE(c)+REPLICATE('#',d)
                                            +SPACE(e)+REPLICATE('#',f)+SPACE(g)+REPLICATE('#',h)
                                            FROM(VALUES(7,0,7,6,0,0,0,0),(6,8,0,7,0,0,0,0),(4,5,4,5,0,5,0,0),(2,4,7,7,1,4,0,0),
                                            (1,3,8,4,1,3,3,3),(0,3,9,4,1,3,4,3),(0,3,8,4,2,3,4,3),(0,3,8,4,2,3,4,3),
                                            (0,3,7,4,3,3,4,3),(0,3,7,4,3,3,4,3),(0,3,6,6,0,5,4,3),(0,3,6,6,0,5,4,3),
                                            (0,3,5,4,5,3,4,3),(0,3,5,3,6,3,4,3),(1,4,2,4,5,0,6,4),(2,8,9,6,0,0,0,0),
                                            (6,9,0,8,0,0,0,0),(6,3,0,0,0,0,0,0))t(a,b,c,d,e,f,g,h)





                                            share|improve this answer














                                            T-SQL, 341 338 bytes



                                            DECLARE @ CHAR(2000)=REPLACE(REPLACE(REPLACE(
                                            'PRINT SPACE(14*6&$6*15&$4*5$4*10&$2*4$7*7$1*4&$1*3$8*4$1*3$3*3&*3$9*4$1*3$4
                                            *3&*3$8*4$2*3$4*3&*3$8*4$2*3$4*3&*3$7*4$3*3$4*3&*3$7*4$3*3$4*3&*3$6*11$4*3&
                                            *3$6*11$4*3&*3$5*4$5*3$4*3&*3$5*3$6*3$4*3&$1*4$2*4$11*4&$2*8$9*6&$6*17&$6*3)'
                                            ,'*',')+REPLICATE(''#'','),'$',')+SPACE('),'&',')+(''
                                            ''')EXEC(@)


                                            The first 4 line breaks are for readability only, the final line break is part of a string literal.



                                            Similar to my Adam West tribute, I've manually encoded a long string, and made the following replacements:





                                            • *7 gets replaced by +REPLICATE('#',7)


                                            • $4 gets replaced by +SPACE(4)


                                            • & gets replaced by a line break inside quotes


                                            This results in a massive SQL command string:



                                            PRINT SPACE(14)+REPLICATE('#',6)+('
                                            ')+SPACE(6)+REPLICATE('#',15)+('
                                            ')+SPACE(4)+REPLICATE('#',5)+SPACE(4)+REPLICATE('#',10)+('
                                            ')+SPACE(2)+REPLICATE('#',4)+SPACE(7)+REPLICATE('#',7)+SPACE(1)+REPLICATE('#',4)+('
                                            ')+SPACE(1)+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(1)+REPLICATE('#',3)+SPACE(3)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(9)+REPLICATE('#',4)+SPACE(1)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(8)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(7)+REPLICATE('#',4)+SPACE(3)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(7)+REPLICATE('#',4)+SPACE(3)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',11)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',11)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(5)+REPLICATE('#',4)+SPACE(5)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+REPLICATE('#',3)+SPACE(5)+REPLICATE('#',3)+SPACE(6)+REPLICATE('#',3)+SPACE(4)+REPLICATE('#',3)+('
                                            ')+SPACE(1)+REPLICATE('#',4)+SPACE(2)+REPLICATE('#',4)+SPACE(11)+REPLICATE('#',4)+('
                                            ')+SPACE(2)+REPLICATE('#',8)+SPACE(9)+REPLICATE('#',6)+('
                                            ')+SPACE(6)+REPLICATE('#',17)+('
                                            ')+SPACE(6)+REPLICATE('#',3)


                                            Which, when run, produces the necessary output.



                                            Long, but still better than my best set-based solution (463 bytes):



                                            SELECT SPACE(a)+REPLICATE('#',b)+SPACE(c)+REPLICATE('#',d)
                                            +SPACE(e)+REPLICATE('#',f)+SPACE(g)+REPLICATE('#',h)
                                            FROM(VALUES(7,0,7,6,0,0,0,0),(6,8,0,7,0,0,0,0),(4,5,4,5,0,5,0,0),(2,4,7,7,1,4,0,0),
                                            (1,3,8,4,1,3,3,3),(0,3,9,4,1,3,4,3),(0,3,8,4,2,3,4,3),(0,3,8,4,2,3,4,3),
                                            (0,3,7,4,3,3,4,3),(0,3,7,4,3,3,4,3),(0,3,6,6,0,5,4,3),(0,3,6,6,0,5,4,3),
                                            (0,3,5,4,5,3,4,3),(0,3,5,3,6,3,4,3),(1,4,2,4,5,0,6,4),(2,8,9,6,0,0,0,0),
                                            (6,9,0,8,0,0,0,0),(6,3,0,0,0,0,0,0))t(a,b,c,d,e,f,g,h)






                                            share|improve this answer














                                            share|improve this answer



                                            share|improve this answer








                                            edited yesterday

























                                            answered yesterday









                                            BradC

                                            3,519521




                                            3,519521












                                            • can drop 2 chars using CHAR(8000) instead of VARCHAR(max) (the huge command is 1453 bytes)
                                              – Shameen
                                              yesterday






                                            • 1




                                              Thanks, @Shameen. I tried to save one more and use CHAR(2E3) but it didn't seem to like that. I also saved a byte by using a line break literal instead of CHAR(13).
                                              – BradC
                                              yesterday




















                                            • can drop 2 chars using CHAR(8000) instead of VARCHAR(max) (the huge command is 1453 bytes)
                                              – Shameen
                                              yesterday






                                            • 1




                                              Thanks, @Shameen. I tried to save one more and use CHAR(2E3) but it didn't seem to like that. I also saved a byte by using a line break literal instead of CHAR(13).
                                              – BradC
                                              yesterday


















                                            can drop 2 chars using CHAR(8000) instead of VARCHAR(max) (the huge command is 1453 bytes)
                                            – Shameen
                                            yesterday




                                            can drop 2 chars using CHAR(8000) instead of VARCHAR(max) (the huge command is 1453 bytes)
                                            – Shameen
                                            yesterday




                                            1




                                            1




                                            Thanks, @Shameen. I tried to save one more and use CHAR(2E3) but it didn't seem to like that. I also saved a byte by using a line break literal instead of CHAR(13).
                                            – BradC
                                            yesterday






                                            Thanks, @Shameen. I tried to save one more and use CHAR(2E3) but it didn't seem to like that. I also saved a byte by using a line break literal instead of CHAR(13).
                                            – BradC
                                            yesterday












                                            up vote
                                            8
                                            down vote














                                            Bubblegum, 71 66 65 64 bytes



                                            0000000: 95 91 21 12 00 20 08 c0 3a af 90 ff 7f 52 4e 58  ..!.. ..:....RNX
                                            0000010: 58 93 25 d8 8a 27 47 e4 23 66 01 2c ce b1 3c 12 X.%..'G.#f.,..<.
                                            0000020: 5f 5b 17 7c 81 ed 31 28 4e 6e a4 6d 23 ad 5b c2 _[.|..1(Nn.m#.[.
                                            0000030: ae 25 83 9a 94 1a 2f 6f 05 fc e5 f0 73 13 f9 0b .%..../o....s...


                                            Thanks to @ovs for golfing off 1 byte!



                                            Try it online!






                                            share|improve this answer























                                            • 65 bytes. (zopfli with 120000 iterations)
                                              – ovs
                                              21 hours ago










                                            • @ovs Thanks! I had never tried so many iterations before.
                                              – Dennis
                                              20 hours ago















                                            up vote
                                            8
                                            down vote














                                            Bubblegum, 71 66 65 64 bytes



                                            0000000: 95 91 21 12 00 20 08 c0 3a af 90 ff 7f 52 4e 58  ..!.. ..:....RNX
                                            0000010: 58 93 25 d8 8a 27 47 e4 23 66 01 2c ce b1 3c 12 X.%..'G.#f.,..<.
                                            0000020: 5f 5b 17 7c 81 ed 31 28 4e 6e a4 6d 23 ad 5b c2 _[.|..1(Nn.m#.[.
                                            0000030: ae 25 83 9a 94 1a 2f 6f 05 fc e5 f0 73 13 f9 0b .%..../o....s...


                                            Thanks to @ovs for golfing off 1 byte!



                                            Try it online!






                                            share|improve this answer























                                            • 65 bytes. (zopfli with 120000 iterations)
                                              – ovs
                                              21 hours ago










                                            • @ovs Thanks! I had never tried so many iterations before.
                                              – Dennis
                                              20 hours ago













                                            up vote
                                            8
                                            down vote










                                            up vote
                                            8
                                            down vote










                                            Bubblegum, 71 66 65 64 bytes



                                            0000000: 95 91 21 12 00 20 08 c0 3a af 90 ff 7f 52 4e 58  ..!.. ..:....RNX
                                            0000010: 58 93 25 d8 8a 27 47 e4 23 66 01 2c ce b1 3c 12 X.%..'G.#f.,..<.
                                            0000020: 5f 5b 17 7c 81 ed 31 28 4e 6e a4 6d 23 ad 5b c2 _[.|..1(Nn.m#.[.
                                            0000030: ae 25 83 9a 94 1a 2f 6f 05 fc e5 f0 73 13 f9 0b .%..../o....s...


                                            Thanks to @ovs for golfing off 1 byte!



                                            Try it online!






                                            share|improve this answer















                                            Bubblegum, 71 66 65 64 bytes



                                            0000000: 95 91 21 12 00 20 08 c0 3a af 90 ff 7f 52 4e 58  ..!.. ..:....RNX
                                            0000010: 58 93 25 d8 8a 27 47 e4 23 66 01 2c ce b1 3c 12 X.%..'G.#f.,..<.
                                            0000020: 5f 5b 17 7c 81 ed 31 28 4e 6e a4 6d 23 ad 5b c2 _[.|..1(Nn.m#.[.
                                            0000030: ae 25 83 9a 94 1a 2f 6f 05 fc e5 f0 73 13 f9 0b .%..../o....s...


                                            Thanks to @ovs for golfing off 1 byte!



                                            Try it online!







                                            share|improve this answer














                                            share|improve this answer



                                            share|improve this answer








                                            edited 20 hours ago

























                                            answered yesterday









                                            Dennis

                                            184k32293728




                                            184k32293728












                                            • 65 bytes. (zopfli with 120000 iterations)
                                              – ovs
                                              21 hours ago










                                            • @ovs Thanks! I had never tried so many iterations before.
                                              – Dennis
                                              20 hours ago


















                                            • 65 bytes. (zopfli with 120000 iterations)
                                              – ovs
                                              21 hours ago










                                            • @ovs Thanks! I had never tried so many iterations before.
                                              – Dennis
                                              20 hours ago
















                                            65 bytes. (zopfli with 120000 iterations)
                                            – ovs
                                            21 hours ago




                                            65 bytes. (zopfli with 120000 iterations)
                                            – ovs
                                            21 hours ago












                                            @ovs Thanks! I had never tried so many iterations before.
                                            – Dennis
                                            20 hours ago




                                            @ovs Thanks! I had never tried so many iterations before.
                                            – Dennis
                                            20 hours ago










                                            up vote
                                            7
                                            down vote














                                            ///, 170 bytes



                                            /+/////*/  +)/'$# +(/"$!+'/" +&/!#+%/"!
                                            !+$/*!+"/**+!/###/""('*
                                            (!!!'
                                            "&#"!!&"
                                            $#'$& &*
                                            !""& ! $
                                            !"'& !%""&$%""&$%)$%)$%(&#%(&#%'&'!%'!"$"!
                                            &$#")
                                            $&#"'!!*
                                            (!!&#"
                                            "$


                                            Try it online!






                                            share|improve this answer

























                                              up vote
                                              7
                                              down vote














                                              ///, 170 bytes



                                              /+/////*/  +)/'$# +(/"$!+'/" +&/!#+%/"!
                                              !+$/*!+"/**+!/###/""('*
                                              (!!!'
                                              "&#"!!&"
                                              $#'$& &*
                                              !""& ! $
                                              !"'& !%""&$%""&$%)$%)$%(&#%(&#%'&'!%'!"$"!
                                              &$#")
                                              $&#"'!!*
                                              (!!&#"
                                              "$


                                              Try it online!






                                              share|improve this answer























                                                up vote
                                                7
                                                down vote










                                                up vote
                                                7
                                                down vote










                                                ///, 170 bytes



                                                /+/////*/  +)/'$# +(/"$!+'/" +&/!#+%/"!
                                                !+$/*!+"/**+!/###/""('*
                                                (!!!'
                                                "&#"!!&"
                                                $#'$& &*
                                                !""& ! $
                                                !"'& !%""&$%""&$%)$%)$%(&#%(&#%'&'!%'!"$"!
                                                &$#")
                                                $&#"'!!*
                                                (!!&#"
                                                "$


                                                Try it online!






                                                share|improve this answer













                                                ///, 170 bytes



                                                /+/////*/  +)/'$# +(/"$!+'/" +&/!#+%/"!
                                                !+$/*!+"/**+!/###/""('*
                                                (!!!'
                                                "&#"!!&"
                                                $#'$& &*
                                                !""& ! $
                                                !"'& !%""&$%""&$%)$%)$%(&#%(&#%'&'!%'!"$"!
                                                &$#")
                                                $&#"'!!*
                                                (!!&#"
                                                "$


                                                Try it online!







                                                share|improve this answer












                                                share|improve this answer



                                                share|improve this answer










                                                answered yesterday









                                                Conor O'Brien

                                                28.8k263160




                                                28.8k263160






















                                                    up vote
                                                    7
                                                    down vote













                                                    JavaScript (ES6), 173 170 bytes





                                                    _=>`tc
                                                    du
                                                    9a9k
                                                    58fe38
                                                    36h83676
                                                    6j83!h85!h85!f87!f87!dm96
                                                    6dm96
                                                    6b8b!b6d696
                                                    3858n8
                                                    5gjc
                                                    dy
                                                    d6`.split`!`.join`696
                                                    6`.replace(/./g,c=>'# '[(k=parseInt(c,36))&1].repeat(k/2))


                                                    Try it online!






                                                    Node.js, 163 bytes



                                                    Provided that an array of strings is a valid output:





                                                    _=>Buffer(`.&-/*%$*&$''!$##($!###!#)$!#$&($"#$&($"#$&'$##$&'$##$&&+$&&+$&%$%#$&%#&#$#!$"$+$#()&(1*#2`).map(c=>s+='# '[x^=1].repeat(c-32),s=x='')&&s.match(/.{27}/g)


                                                    Try it online!






                                                    share|improve this answer



























                                                      up vote
                                                      7
                                                      down vote













                                                      JavaScript (ES6), 173 170 bytes





                                                      _=>`tc
                                                      du
                                                      9a9k
                                                      58fe38
                                                      36h83676
                                                      6j83!h85!h85!f87!f87!dm96
                                                      6dm96
                                                      6b8b!b6d696
                                                      3858n8
                                                      5gjc
                                                      dy
                                                      d6`.split`!`.join`696
                                                      6`.replace(/./g,c=>'# '[(k=parseInt(c,36))&1].repeat(k/2))


                                                      Try it online!






                                                      Node.js, 163 bytes



                                                      Provided that an array of strings is a valid output:





                                                      _=>Buffer(`.&-/*%$*&$''!$##($!###!#)$!#$&($"#$&($"#$&'$##$&'$##$&&+$&&+$&%$%#$&%#&#$#!$"$+$#()&(1*#2`).map(c=>s+='# '[x^=1].repeat(c-32),s=x='')&&s.match(/.{27}/g)


                                                      Try it online!






                                                      share|improve this answer

























                                                        up vote
                                                        7
                                                        down vote










                                                        up vote
                                                        7
                                                        down vote









                                                        JavaScript (ES6), 173 170 bytes





                                                        _=>`tc
                                                        du
                                                        9a9k
                                                        58fe38
                                                        36h83676
                                                        6j83!h85!h85!f87!f87!dm96
                                                        6dm96
                                                        6b8b!b6d696
                                                        3858n8
                                                        5gjc
                                                        dy
                                                        d6`.split`!`.join`696
                                                        6`.replace(/./g,c=>'# '[(k=parseInt(c,36))&1].repeat(k/2))


                                                        Try it online!






                                                        Node.js, 163 bytes



                                                        Provided that an array of strings is a valid output:





                                                        _=>Buffer(`.&-/*%$*&$''!$##($!###!#)$!#$&($"#$&($"#$&'$##$&'$##$&&+$&&+$&%$%#$&%#&#$#!$"$+$#()&(1*#2`).map(c=>s+='# '[x^=1].repeat(c-32),s=x='')&&s.match(/.{27}/g)


                                                        Try it online!






                                                        share|improve this answer














                                                        JavaScript (ES6), 173 170 bytes





                                                        _=>`tc
                                                        du
                                                        9a9k
                                                        58fe38
                                                        36h83676
                                                        6j83!h85!h85!f87!f87!dm96
                                                        6dm96
                                                        6b8b!b6d696
                                                        3858n8
                                                        5gjc
                                                        dy
                                                        d6`.split`!`.join`696
                                                        6`.replace(/./g,c=>'# '[(k=parseInt(c,36))&1].repeat(k/2))


                                                        Try it online!






                                                        Node.js, 163 bytes



                                                        Provided that an array of strings is a valid output:





                                                        _=>Buffer(`.&-/*%$*&$''!$##($!###!#)$!#$&($"#$&($"#$&'$##$&'$##$&&+$&&+$&%$%#$&%#&#$#!$"$+$#()&(1*#2`).map(c=>s+='# '[x^=1].repeat(c-32),s=x='')&&s.match(/.{27}/g)


                                                        Try it online!







                                                        share|improve this answer














                                                        share|improve this answer



                                                        share|improve this answer








                                                        edited yesterday

























                                                        answered 2 days ago









                                                        Arnauld

                                                        68.5k584289




                                                        68.5k584289






















                                                            up vote
                                                            7
                                                            down vote














                                                            Charcoal, 71 bytes



                                                            P⁸↓P-³↙←⁴↓P³↙G→³↓⁹←³#↘P⁴↘P⁶↘‖OM←←¹⁷↘F⁹«P⁺³›ι³↑P⁴↗¿⁼ι²B⁸±²»↘→UO³¦¹⁴UMKA#


                                                            Try it online! Link is to verbose version of code. Explanation:



                                                            P⁸↓P-³↙←⁴↓P³↙G→³↓⁹←³#↘P⁴↘P⁶


                                                            Output half of the circle.



                                                            ↘‖OM←←¹⁷↘


                                                            Reflect it and draw in the bottom.



                                                            F⁹«P⁺³›ι³↑P⁴↗¿⁼ι²B⁸±²»


                                                            Draw the left arm and crossbar of the A.



                                                            ↘→UO³¦¹⁴


                                                            Draw the right arm of the A.



                                                            UMKA#


                                                            Change all the characters to #s.






                                                            share|improve this answer

























                                                              up vote
                                                              7
                                                              down vote














                                                              Charcoal, 71 bytes



                                                              P⁸↓P-³↙←⁴↓P³↙G→³↓⁹←³#↘P⁴↘P⁶↘‖OM←←¹⁷↘F⁹«P⁺³›ι³↑P⁴↗¿⁼ι²B⁸±²»↘→UO³¦¹⁴UMKA#


                                                              Try it online! Link is to verbose version of code. Explanation:



                                                              P⁸↓P-³↙←⁴↓P³↙G→³↓⁹←³#↘P⁴↘P⁶


                                                              Output half of the circle.



                                                              ↘‖OM←←¹⁷↘


                                                              Reflect it and draw in the bottom.



                                                              F⁹«P⁺³›ι³↑P⁴↗¿⁼ι²B⁸±²»


                                                              Draw the left arm and crossbar of the A.



                                                              ↘→UO³¦¹⁴


                                                              Draw the right arm of the A.



                                                              UMKA#


                                                              Change all the characters to #s.






                                                              share|improve this answer























                                                                up vote
                                                                7
                                                                down vote










                                                                up vote
                                                                7
                                                                down vote










                                                                Charcoal, 71 bytes



                                                                P⁸↓P-³↙←⁴↓P³↙G→³↓⁹←³#↘P⁴↘P⁶↘‖OM←←¹⁷↘F⁹«P⁺³›ι³↑P⁴↗¿⁼ι²B⁸±²»↘→UO³¦¹⁴UMKA#


                                                                Try it online! Link is to verbose version of code. Explanation:



                                                                P⁸↓P-³↙←⁴↓P³↙G→³↓⁹←³#↘P⁴↘P⁶


                                                                Output half of the circle.



                                                                ↘‖OM←←¹⁷↘


                                                                Reflect it and draw in the bottom.



                                                                F⁹«P⁺³›ι³↑P⁴↗¿⁼ι²B⁸±²»


                                                                Draw the left arm and crossbar of the A.



                                                                ↘→UO³¦¹⁴


                                                                Draw the right arm of the A.



                                                                UMKA#


                                                                Change all the characters to #s.






                                                                share|improve this answer













                                                                Charcoal, 71 bytes



                                                                P⁸↓P-³↙←⁴↓P³↙G→³↓⁹←³#↘P⁴↘P⁶↘‖OM←←¹⁷↘F⁹«P⁺³›ι³↑P⁴↗¿⁼ι²B⁸±²»↘→UO³¦¹⁴UMKA#


                                                                Try it online! Link is to verbose version of code. Explanation:



                                                                P⁸↓P-³↙←⁴↓P³↙G→³↓⁹←³#↘P⁴↘P⁶


                                                                Output half of the circle.



                                                                ↘‖OM←←¹⁷↘


                                                                Reflect it and draw in the bottom.



                                                                F⁹«P⁺³›ι³↑P⁴↗¿⁼ι²B⁸±²»


                                                                Draw the left arm and crossbar of the A.



                                                                ↘→UO³¦¹⁴


                                                                Draw the right arm of the A.



                                                                UMKA#


                                                                Change all the characters to #s.







                                                                share|improve this answer












                                                                share|improve this answer



                                                                share|improve this answer










                                                                answered yesterday









                                                                Neil

                                                                77.8k744174




                                                                77.8k744174






















                                                                    up vote
                                                                    7
                                                                    down vote














                                                                    C (gcc), 174 168 164 bytes



                                                                    -6 bytes thanks to Dennis.





                                                                    i,j=88;main(l){while(j--)for(i="CJQHFIHCDKDBDACDCFCEFDCEDEFDKFFDKFFDCCDGFDCCDGFDCBDHFDCBDHFDCADICACCCADHCCDAGGDFJDEJOMFN"[j]-64;i;)putchar(l++%28?--i,35-j%2*3:10);}


                                                                    Try it online!






                                                                    share|improve this answer



























                                                                      up vote
                                                                      7
                                                                      down vote














                                                                      C (gcc), 174 168 164 bytes



                                                                      -6 bytes thanks to Dennis.





                                                                      i,j=88;main(l){while(j--)for(i="CJQHFIHCDKDBDACDCFCEFDCEDEFDKFFDKFFDCCDGFDCCDGFDCBDHFDCBDHFDCADICACCCADHCCDAGGDFJDEJOMFN"[j]-64;i;)putchar(l++%28?--i,35-j%2*3:10);}


                                                                      Try it online!






                                                                      share|improve this answer

























                                                                        up vote
                                                                        7
                                                                        down vote










                                                                        up vote
                                                                        7
                                                                        down vote










                                                                        C (gcc), 174 168 164 bytes



                                                                        -6 bytes thanks to Dennis.





                                                                        i,j=88;main(l){while(j--)for(i="CJQHFIHCDKDBDACDCFCEFDCEDEFDKFFDKFFDCCDGFDCCDGFDCBDHFDCBDHFDCADICACCCADHCCDAGGDFJDEJOMFN"[j]-64;i;)putchar(l++%28?--i,35-j%2*3:10);}


                                                                        Try it online!






                                                                        share|improve this answer















                                                                        C (gcc), 174 168 164 bytes



                                                                        -6 bytes thanks to Dennis.





                                                                        i,j=88;main(l){while(j--)for(i="CJQHFIHCDKDBDACDCFCEFDCEDEFDKFFDKFFDCCDGFDCCDGFDCBDHFDCBDHFDCADICACCCADHCCDAGGDFJDEJOMFN"[j]-64;i;)putchar(l++%28?--i,35-j%2*3:10);}


                                                                        Try it online!







                                                                        share|improve this answer














                                                                        share|improve this answer



                                                                        share|improve this answer








                                                                        edited yesterday

























                                                                        answered yesterday









                                                                        gastropner

                                                                        1,7901410




                                                                        1,7901410






















                                                                            up vote
                                                                            7
                                                                            down vote













                                                                            Python 2, 129 bytes





                                                                            00000000: 2363 6f64 696e 673a 4c31 0a70 7269 6e74  #coding:L1.print
                                                                            00000010: 2778 da95 9141 0e5c 3021 0803 ef7d 4593 'x...A.!...}E.
                                                                            00000020: feff 8f9b 5d14 5c6e f1b0 f622 7422 2890 ....].n..."t"(.
                                                                            00000030: 2e7d 5a09 dc4b 19cb bc53 84d1 4a6a 5960 .}Z..K...S..JjY`
                                                                            00000040: 116e 3f42 c290 b3f7 c0bc 76cf 549d 6ed8 .n?B......v.T.n.
                                                                            00000050: f8fa 5f26 0b0e 8c93 d5cb 35f6 b1e7 a939 .._&......5....9
                                                                            00000060: 9e98 e769 47b9 87d6 cdf5 5c30 3030 32c0 ...iG.....002.
                                                                            00000070: 4029 272e 6465 636f 6465 2827 7a69 7027 @)'.decode('zip'
                                                                            00000080: 29 )


                                                                            Try it online!






                                                                            share|improve this answer























                                                                            • 129 bytes, I removed the trailing n from the compressed string.
                                                                              – ovs
                                                                              22 hours ago















                                                                            up vote
                                                                            7
                                                                            down vote













                                                                            Python 2, 129 bytes





                                                                            00000000: 2363 6f64 696e 673a 4c31 0a70 7269 6e74  #coding:L1.print
                                                                            00000010: 2778 da95 9141 0e5c 3021 0803 ef7d 4593 'x...A.!...}E.
                                                                            00000020: feff 8f9b 5d14 5c6e f1b0 f622 7422 2890 ....].n..."t"(.
                                                                            00000030: 2e7d 5a09 dc4b 19cb bc53 84d1 4a6a 5960 .}Z..K...S..JjY`
                                                                            00000040: 116e 3f42 c290 b3f7 c0bc 76cf 549d 6ed8 .n?B......v.T.n.
                                                                            00000050: f8fa 5f26 0b0e 8c93 d5cb 35f6 b1e7 a939 .._&......5....9
                                                                            00000060: 9e98 e769 47b9 87d6 cdf5 5c30 3030 32c0 ...iG.....002.
                                                                            00000070: 4029 272e 6465 636f 6465 2827 7a69 7027 @)'.decode('zip'
                                                                            00000080: 29 )


                                                                            Try it online!






                                                                            share|improve this answer























                                                                            • 129 bytes, I removed the trailing n from the compressed string.
                                                                              – ovs
                                                                              22 hours ago













                                                                            up vote
                                                                            7
                                                                            down vote










                                                                            up vote
                                                                            7
                                                                            down vote









                                                                            Python 2, 129 bytes





                                                                            00000000: 2363 6f64 696e 673a 4c31 0a70 7269 6e74  #coding:L1.print
                                                                            00000010: 2778 da95 9141 0e5c 3021 0803 ef7d 4593 'x...A.!...}E.
                                                                            00000020: feff 8f9b 5d14 5c6e f1b0 f622 7422 2890 ....].n..."t"(.
                                                                            00000030: 2e7d 5a09 dc4b 19cb bc53 84d1 4a6a 5960 .}Z..K...S..JjY`
                                                                            00000040: 116e 3f42 c290 b3f7 c0bc 76cf 549d 6ed8 .n?B......v.T.n.
                                                                            00000050: f8fa 5f26 0b0e 8c93 d5cb 35f6 b1e7 a939 .._&......5....9
                                                                            00000060: 9e98 e769 47b9 87d6 cdf5 5c30 3030 32c0 ...iG.....002.
                                                                            00000070: 4029 272e 6465 636f 6465 2827 7a69 7027 @)'.decode('zip'
                                                                            00000080: 29 )


                                                                            Try it online!






                                                                            share|improve this answer














                                                                            Python 2, 129 bytes





                                                                            00000000: 2363 6f64 696e 673a 4c31 0a70 7269 6e74  #coding:L1.print
                                                                            00000010: 2778 da95 9141 0e5c 3021 0803 ef7d 4593 'x...A.!...}E.
                                                                            00000020: feff 8f9b 5d14 5c6e f1b0 f622 7422 2890 ....].n..."t"(.
                                                                            00000030: 2e7d 5a09 dc4b 19cb bc53 84d1 4a6a 5960 .}Z..K...S..JjY`
                                                                            00000040: 116e 3f42 c290 b3f7 c0bc 76cf 549d 6ed8 .n?B......v.T.n.
                                                                            00000050: f8fa 5f26 0b0e 8c93 d5cb 35f6 b1e7 a939 .._&......5....9
                                                                            00000060: 9e98 e769 47b9 87d6 cdf5 5c30 3030 32c0 ...iG.....002.
                                                                            00000070: 4029 272e 6465 636f 6465 2827 7a69 7027 @)'.decode('zip'
                                                                            00000080: 29 )


                                                                            Try it online!







                                                                            share|improve this answer














                                                                            share|improve this answer



                                                                            share|improve this answer








                                                                            edited 20 hours ago

























                                                                            answered yesterday









                                                                            Lynn

                                                                            49.1k694223




                                                                            49.1k694223












                                                                            • 129 bytes, I removed the trailing n from the compressed string.
                                                                              – ovs
                                                                              22 hours ago


















                                                                            • 129 bytes, I removed the trailing n from the compressed string.
                                                                              – ovs
                                                                              22 hours ago
















                                                                            129 bytes, I removed the trailing n from the compressed string.
                                                                            – ovs
                                                                            22 hours ago




                                                                            129 bytes, I removed the trailing n from the compressed string.
                                                                            – ovs
                                                                            22 hours ago










                                                                            up vote
                                                                            6
                                                                            down vote













                                                                            Haskell, 170 163 bytes



                                                                            Edit: -7 bytes thanks to @Ørjan Johansen



                                                                            m=<<"Mc Ul WeWg YdTgZa ZcSdZcX cRdZcW cSdYcW cSdYcW cTdXcW cTdXcW cUkW cUkW cVdVcW cVcUcW ZdYdPa YhRc Un U "
                                                                            m ' '="###n"
                                                                            m c=(' '<$['Z','Y'..c])++('#'<$['a'..c])


                                                                            Try it online!



                                                                            Spaces are encoded as uppercase characters (length: Z down to char), hash signs as lowercase characters (length: a to char) and the last three # of each line plus newline as a space. Function m decodes it.






                                                                            share|improve this answer



















                                                                            • 1




                                                                              I think you can save some by letting space encode "###n".
                                                                              – Ørjan Johansen
                                                                              yesterday















                                                                            up vote
                                                                            6
                                                                            down vote













                                                                            Haskell, 170 163 bytes



                                                                            Edit: -7 bytes thanks to @Ørjan Johansen



                                                                            m=<<"Mc Ul WeWg YdTgZa ZcSdZcX cRdZcW cSdYcW cSdYcW cTdXcW cTdXcW cUkW cUkW cVdVcW cVcUcW ZdYdPa YhRc Un U "
                                                                            m ' '="###n"
                                                                            m c=(' '<$['Z','Y'..c])++('#'<$['a'..c])


                                                                            Try it online!



                                                                            Spaces are encoded as uppercase characters (length: Z down to char), hash signs as lowercase characters (length: a to char) and the last three # of each line plus newline as a space. Function m decodes it.






                                                                            share|improve this answer



















                                                                            • 1




                                                                              I think you can save some by letting space encode "###n".
                                                                              – Ørjan Johansen
                                                                              yesterday













                                                                            up vote
                                                                            6
                                                                            down vote










                                                                            up vote
                                                                            6
                                                                            down vote









                                                                            Haskell, 170 163 bytes



                                                                            Edit: -7 bytes thanks to @Ørjan Johansen



                                                                            m=<<"Mc Ul WeWg YdTgZa ZcSdZcX cRdZcW cSdYcW cSdYcW cTdXcW cTdXcW cUkW cUkW cVdVcW cVcUcW ZdYdPa YhRc Un U "
                                                                            m ' '="###n"
                                                                            m c=(' '<$['Z','Y'..c])++('#'<$['a'..c])


                                                                            Try it online!



                                                                            Spaces are encoded as uppercase characters (length: Z down to char), hash signs as lowercase characters (length: a to char) and the last three # of each line plus newline as a space. Function m decodes it.






                                                                            share|improve this answer














                                                                            Haskell, 170 163 bytes



                                                                            Edit: -7 bytes thanks to @Ørjan Johansen



                                                                            m=<<"Mc Ul WeWg YdTgZa ZcSdZcX cRdZcW cSdYcW cSdYcW cTdXcW cTdXcW cUkW cUkW cVdVcW cVcUcW ZdYdPa YhRc Un U "
                                                                            m ' '="###n"
                                                                            m c=(' '<$['Z','Y'..c])++('#'<$['a'..c])


                                                                            Try it online!



                                                                            Spaces are encoded as uppercase characters (length: Z down to char), hash signs as lowercase characters (length: a to char) and the last three # of each line plus newline as a space. Function m decodes it.







                                                                            share|improve this answer














                                                                            share|improve this answer



                                                                            share|improve this answer








                                                                            edited yesterday

























                                                                            answered yesterday









                                                                            nimi

                                                                            30.7k31985




                                                                            30.7k31985








                                                                            • 1




                                                                              I think you can save some by letting space encode "###n".
                                                                              – Ørjan Johansen
                                                                              yesterday














                                                                            • 1




                                                                              I think you can save some by letting space encode "###n".
                                                                              – Ørjan Johansen
                                                                              yesterday








                                                                            1




                                                                            1




                                                                            I think you can save some by letting space encode "###n".
                                                                            – Ørjan Johansen
                                                                            yesterday




                                                                            I think you can save some by letting space encode "###n".
                                                                            – Ørjan Johansen
                                                                            yesterday










                                                                            up vote
                                                                            6
                                                                            down vote














                                                                            05AB1E, 101 88 64 bytes



                                                                            „# •∍ΔÎë,½=bOÅ.âαUΔ'òõƶαÔγλ#xÆ]~”FbćÁ˜Ð”wнQ_wā©•12вεN>yи}˜èJ27ô»


                                                                            -24 bytes by creating a port of @Dennis♦' Jelly answer.



                                                                            Try it online.



                                                                            Explanation:





                                                                            „#                     # Push string "# "
                                                                            •∍ΔÎë,½=bOÅ.âαUΔ'òõƶαÔγλ#xÆ]~”FbćÁ˜Ð”wнQ_wā©•
                                                                            '# Push compressed integer 10250938842396786963034911279002199266186481794751691439873548591280332406943905758890346943197901909163
                                                                            12в # Convert to Base-12 as list: [3,0,11,6,2,0,11,4,0,11,10,5,4,10,6,4,7,7,1,4,3,3,8,4,1,3,3,3,1,3,9,4,1,3,4,6,8,4,2,3,4,6,8,4,2,3,4,6,7,4,3,3,4,6,7,4,3,3,4,6,6,11,4,6,6,11,4,6,5,4,5,3,4,6,5,3,6,3,4,3,1,4,2,4,11,4,3,8,9,6,8,6,0,11,10,3]
                                                                            ε } # Map each `y` to:
                                                                            N> # The index+1
                                                                            yи # Repeated `y` amount of times
                                                                            ˜ # Flatten the list
                                                                            è # Index each in the string "# " (with automatic wraparound)
                                                                            J # Join everything together
                                                                            27ô # Split into parts of length 27
                                                                            » # And join by newlines


                                                                            See this 05AB1E tip of mine (sections How to compress large integers? and How to compress integer lists?) to understand how the compression of the integer and list works.






                                                                            share|improve this answer



























                                                                              up vote
                                                                              6
                                                                              down vote














                                                                              05AB1E, 101 88 64 bytes



                                                                              „# •∍ΔÎë,½=bOÅ.âαUΔ'òõƶαÔγλ#xÆ]~”FbćÁ˜Ð”wнQ_wā©•12вεN>yи}˜èJ27ô»


                                                                              -24 bytes by creating a port of @Dennis♦' Jelly answer.



                                                                              Try it online.



                                                                              Explanation:





                                                                              „#                     # Push string "# "
                                                                              •∍ΔÎë,½=bOÅ.âαUΔ'òõƶαÔγλ#xÆ]~”FbćÁ˜Ð”wнQ_wā©•
                                                                              '# Push compressed integer 10250938842396786963034911279002199266186481794751691439873548591280332406943905758890346943197901909163
                                                                              12в # Convert to Base-12 as list: [3,0,11,6,2,0,11,4,0,11,10,5,4,10,6,4,7,7,1,4,3,3,8,4,1,3,3,3,1,3,9,4,1,3,4,6,8,4,2,3,4,6,8,4,2,3,4,6,7,4,3,3,4,6,7,4,3,3,4,6,6,11,4,6,6,11,4,6,5,4,5,3,4,6,5,3,6,3,4,3,1,4,2,4,11,4,3,8,9,6,8,6,0,11,10,3]
                                                                              ε } # Map each `y` to:
                                                                              N> # The index+1
                                                                              yи # Repeated `y` amount of times
                                                                              ˜ # Flatten the list
                                                                              è # Index each in the string "# " (with automatic wraparound)
                                                                              J # Join everything together
                                                                              27ô # Split into parts of length 27
                                                                              » # And join by newlines


                                                                              See this 05AB1E tip of mine (sections How to compress large integers? and How to compress integer lists?) to understand how the compression of the integer and list works.






                                                                              share|improve this answer

























                                                                                up vote
                                                                                6
                                                                                down vote










                                                                                up vote
                                                                                6
                                                                                down vote










                                                                                05AB1E, 101 88 64 bytes



                                                                                „# •∍ΔÎë,½=bOÅ.âαUΔ'òõƶαÔγλ#xÆ]~”FbćÁ˜Ð”wнQ_wā©•12вεN>yи}˜èJ27ô»


                                                                                -24 bytes by creating a port of @Dennis♦' Jelly answer.



                                                                                Try it online.



                                                                                Explanation:





                                                                                „#                     # Push string "# "
                                                                                •∍ΔÎë,½=bOÅ.âαUΔ'òõƶαÔγλ#xÆ]~”FbćÁ˜Ð”wнQ_wā©•
                                                                                '# Push compressed integer 10250938842396786963034911279002199266186481794751691439873548591280332406943905758890346943197901909163
                                                                                12в # Convert to Base-12 as list: [3,0,11,6,2,0,11,4,0,11,10,5,4,10,6,4,7,7,1,4,3,3,8,4,1,3,3,3,1,3,9,4,1,3,4,6,8,4,2,3,4,6,8,4,2,3,4,6,7,4,3,3,4,6,7,4,3,3,4,6,6,11,4,6,6,11,4,6,5,4,5,3,4,6,5,3,6,3,4,3,1,4,2,4,11,4,3,8,9,6,8,6,0,11,10,3]
                                                                                ε } # Map each `y` to:
                                                                                N> # The index+1
                                                                                yи # Repeated `y` amount of times
                                                                                ˜ # Flatten the list
                                                                                è # Index each in the string "# " (with automatic wraparound)
                                                                                J # Join everything together
                                                                                27ô # Split into parts of length 27
                                                                                » # And join by newlines


                                                                                See this 05AB1E tip of mine (sections How to compress large integers? and How to compress integer lists?) to understand how the compression of the integer and list works.






                                                                                share|improve this answer















                                                                                05AB1E, 101 88 64 bytes



                                                                                „# •∍ΔÎë,½=bOÅ.âαUΔ'òõƶαÔγλ#xÆ]~”FbćÁ˜Ð”wнQ_wā©•12вεN>yи}˜èJ27ô»


                                                                                -24 bytes by creating a port of @Dennis♦' Jelly answer.



                                                                                Try it online.



                                                                                Explanation:





                                                                                „#                     # Push string "# "
                                                                                •∍ΔÎë,½=bOÅ.âαUΔ'òõƶαÔγλ#xÆ]~”FbćÁ˜Ð”wнQ_wā©•
                                                                                '# Push compressed integer 10250938842396786963034911279002199266186481794751691439873548591280332406943905758890346943197901909163
                                                                                12в # Convert to Base-12 as list: [3,0,11,6,2,0,11,4,0,11,10,5,4,10,6,4,7,7,1,4,3,3,8,4,1,3,3,3,1,3,9,4,1,3,4,6,8,4,2,3,4,6,8,4,2,3,4,6,7,4,3,3,4,6,7,4,3,3,4,6,6,11,4,6,6,11,4,6,5,4,5,3,4,6,5,3,6,3,4,3,1,4,2,4,11,4,3,8,9,6,8,6,0,11,10,3]
                                                                                ε } # Map each `y` to:
                                                                                N> # The index+1
                                                                                yи # Repeated `y` amount of times
                                                                                ˜ # Flatten the list
                                                                                è # Index each in the string "# " (with automatic wraparound)
                                                                                J # Join everything together
                                                                                27ô # Split into parts of length 27
                                                                                » # And join by newlines


                                                                                See this 05AB1E tip of mine (sections How to compress large integers? and How to compress integer lists?) to understand how the compression of the integer and list works.







                                                                                share|improve this answer














                                                                                share|improve this answer



                                                                                share|improve this answer








                                                                                edited yesterday

























                                                                                answered yesterday









                                                                                Kevin Cruijssen

                                                                                33.8k554180




                                                                                33.8k554180






















                                                                                    up vote
                                                                                    6
                                                                                    down vote














                                                                                    Bash, 192 176 bytes





                                                                                    dc<<<"16i2o81C0000 81FFFF0 9FE00FC BCF001E F070387 F078387 F03FF87 F03FF87 F01E387 F01E387 F00F387 F00F387 F007B87 B807B8E 9E03FBC 87C3FF0 81FFFC0 8001F80f"|tr 01 ' #'|cut -c2-


                                                                                    Try it online!



                                                                                    -16 thanks to manatwork



                                                                                    This is similar to my C answer, except it just uses a raw base-16 compression and passes it through bc, then uses tr to convert 1 to # and 0 to space. Each row has 1 appended to it and stripped off of it to maintain alignment.



                                                                                    Unfortunately dc is shorter than bc.






                                                                                    share|improve this answer























                                                                                    • No need for ^. But even better, use cut -c2- instead of the sed part.
                                                                                      – manatwork
                                                                                      yesterday












                                                                                    • And also shorter with here-string instead of echo and even shorter with dc instead of bc: Try it online!
                                                                                      – manatwork
                                                                                      yesterday






                                                                                    • 2




                                                                                      I'll give you the echo, but come on - dc for Stan Lee... you must be joking ;)
                                                                                      – LambdaBeta
                                                                                      yesterday






                                                                                    • 1




                                                                                      134 bytes
                                                                                      – Dennis
                                                                                      yesterday















                                                                                    up vote
                                                                                    6
                                                                                    down vote














                                                                                    Bash, 192 176 bytes





                                                                                    dc<<<"16i2o81C0000 81FFFF0 9FE00FC BCF001E F070387 F078387 F03FF87 F03FF87 F01E387 F01E387 F00F387 F00F387 F007B87 B807B8E 9E03FBC 87C3FF0 81FFFC0 8001F80f"|tr 01 ' #'|cut -c2-


                                                                                    Try it online!



                                                                                    -16 thanks to manatwork



                                                                                    This is similar to my C answer, except it just uses a raw base-16 compression and passes it through bc, then uses tr to convert 1 to # and 0 to space. Each row has 1 appended to it and stripped off of it to maintain alignment.



                                                                                    Unfortunately dc is shorter than bc.






                                                                                    share|improve this answer























                                                                                    • No need for ^. But even better, use cut -c2- instead of the sed part.
                                                                                      – manatwork
                                                                                      yesterday












                                                                                    • And also shorter with here-string instead of echo and even shorter with dc instead of bc: Try it online!
                                                                                      – manatwork
                                                                                      yesterday






                                                                                    • 2




                                                                                      I'll give you the echo, but come on - dc for Stan Lee... you must be joking ;)
                                                                                      – LambdaBeta
                                                                                      yesterday






                                                                                    • 1




                                                                                      134 bytes
                                                                                      – Dennis
                                                                                      yesterday













                                                                                    up vote
                                                                                    6
                                                                                    down vote










                                                                                    up vote
                                                                                    6
                                                                                    down vote










                                                                                    Bash, 192 176 bytes





                                                                                    dc<<<"16i2o81C0000 81FFFF0 9FE00FC BCF001E F070387 F078387 F03FF87 F03FF87 F01E387 F01E387 F00F387 F00F387 F007B87 B807B8E 9E03FBC 87C3FF0 81FFFC0 8001F80f"|tr 01 ' #'|cut -c2-


                                                                                    Try it online!



                                                                                    -16 thanks to manatwork



                                                                                    This is similar to my C answer, except it just uses a raw base-16 compression and passes it through bc, then uses tr to convert 1 to # and 0 to space. Each row has 1 appended to it and stripped off of it to maintain alignment.



                                                                                    Unfortunately dc is shorter than bc.






                                                                                    share|improve this answer















                                                                                    Bash, 192 176 bytes





                                                                                    dc<<<"16i2o81C0000 81FFFF0 9FE00FC BCF001E F070387 F078387 F03FF87 F03FF87 F01E387 F01E387 F00F387 F00F387 F007B87 B807B8E 9E03FBC 87C3FF0 81FFFC0 8001F80f"|tr 01 ' #'|cut -c2-


                                                                                    Try it online!



                                                                                    -16 thanks to manatwork



                                                                                    This is similar to my C answer, except it just uses a raw base-16 compression and passes it through bc, then uses tr to convert 1 to # and 0 to space. Each row has 1 appended to it and stripped off of it to maintain alignment.



                                                                                    Unfortunately dc is shorter than bc.







                                                                                    share|improve this answer














                                                                                    share|improve this answer



                                                                                    share|improve this answer








                                                                                    edited yesterday

























                                                                                    answered yesterday









                                                                                    LambdaBeta

                                                                                    1,989416




                                                                                    1,989416












                                                                                    • No need for ^. But even better, use cut -c2- instead of the sed part.
                                                                                      – manatwork
                                                                                      yesterday












                                                                                    • And also shorter with here-string instead of echo and even shorter with dc instead of bc: Try it online!
                                                                                      – manatwork
                                                                                      yesterday






                                                                                    • 2




                                                                                      I'll give you the echo, but come on - dc for Stan Lee... you must be joking ;)
                                                                                      – LambdaBeta
                                                                                      yesterday






                                                                                    • 1




                                                                                      134 bytes
                                                                                      – Dennis
                                                                                      yesterday


















                                                                                    • No need for ^. But even better, use cut -c2- instead of the sed part.
                                                                                      – manatwork
                                                                                      yesterday












                                                                                    • And also shorter with here-string instead of echo and even shorter with dc instead of bc: Try it online!
                                                                                      – manatwork
                                                                                      yesterday






                                                                                    • 2




                                                                                      I'll give you the echo, but come on - dc for Stan Lee... you must be joking ;)
                                                                                      – LambdaBeta
                                                                                      yesterday






                                                                                    • 1




                                                                                      134 bytes
                                                                                      – Dennis
                                                                                      yesterday
















                                                                                    No need for ^. But even better, use cut -c2- instead of the sed part.
                                                                                    – manatwork
                                                                                    yesterday






                                                                                    No need for ^. But even better, use cut -c2- instead of the sed part.
                                                                                    – manatwork
                                                                                    yesterday














                                                                                    And also shorter with here-string instead of echo and even shorter with dc instead of bc: Try it online!
                                                                                    – manatwork
                                                                                    yesterday




                                                                                    And also shorter with here-string instead of echo and even shorter with dc instead of bc: Try it online!
                                                                                    – manatwork
                                                                                    yesterday




                                                                                    2




                                                                                    2




                                                                                    I'll give you the echo, but come on - dc for Stan Lee... you must be joking ;)
                                                                                    – LambdaBeta
                                                                                    yesterday




                                                                                    I'll give you the echo, but come on - dc for Stan Lee... you must be joking ;)
                                                                                    – LambdaBeta
                                                                                    yesterday




                                                                                    1




                                                                                    1




                                                                                    134 bytes
                                                                                    – Dennis
                                                                                    yesterday




                                                                                    134 bytes
                                                                                    – Dennis
                                                                                    yesterday










                                                                                    up vote
                                                                                    5
                                                                                    down vote














                                                                                    J, 130 128 bytes



                                                                                    echo' #'{~18 27$;(_243{.2#.inv 92x#._32+a.i.])&>'!TYPW.ajz i8hIhXl''3lOH8GvV.C2Z{r/=,G';'"a*2ZDxRplkh2tzRakz.?ZwVmeOT6L^lFB^eyT'


                                                                                    Try it online!



                                                                                    Initial solution




                                                                                    J, 164 bytes



                                                                                    echo' #'{~18 27$,#:849239965469633263905532594449192007713271791872263657753301928240007 12380965417202148347902847903517734495157419855048834759608223758433386496x


                                                                                    Try it online!






                                                                                    share|improve this answer



























                                                                                      up vote
                                                                                      5
                                                                                      down vote














                                                                                      J, 130 128 bytes



                                                                                      echo' #'{~18 27$;(_243{.2#.inv 92x#._32+a.i.])&>'!TYPW.ajz i8hIhXl''3lOH8GvV.C2Z{r/=,G';'"a*2ZDxRplkh2tzRakz.?ZwVmeOT6L^lFB^eyT'


                                                                                      Try it online!



                                                                                      Initial solution




                                                                                      J, 164 bytes



                                                                                      echo' #'{~18 27$,#:849239965469633263905532594449192007713271791872263657753301928240007 12380965417202148347902847903517734495157419855048834759608223758433386496x


                                                                                      Try it online!






                                                                                      share|improve this answer

























                                                                                        up vote
                                                                                        5
                                                                                        down vote










                                                                                        up vote
                                                                                        5
                                                                                        down vote










                                                                                        J, 130 128 bytes



                                                                                        echo' #'{~18 27$;(_243{.2#.inv 92x#._32+a.i.])&>'!TYPW.ajz i8hIhXl''3lOH8GvV.C2Z{r/=,G';'"a*2ZDxRplkh2tzRakz.?ZwVmeOT6L^lFB^eyT'


                                                                                        Try it online!



                                                                                        Initial solution




                                                                                        J, 164 bytes



                                                                                        echo' #'{~18 27$,#:849239965469633263905532594449192007713271791872263657753301928240007 12380965417202148347902847903517734495157419855048834759608223758433386496x


                                                                                        Try it online!






                                                                                        share|improve this answer















                                                                                        J, 130 128 bytes



                                                                                        echo' #'{~18 27$;(_243{.2#.inv 92x#._32+a.i.])&>'!TYPW.ajz i8hIhXl''3lOH8GvV.C2Z{r/=,G';'"a*2ZDxRplkh2tzRakz.?ZwVmeOT6L^lFB^eyT'


                                                                                        Try it online!



                                                                                        Initial solution




                                                                                        J, 164 bytes



                                                                                        echo' #'{~18 27$,#:849239965469633263905532594449192007713271791872263657753301928240007 12380965417202148347902847903517734495157419855048834759608223758433386496x


                                                                                        Try it online!







                                                                                        share|improve this answer














                                                                                        share|improve this answer



                                                                                        share|improve this answer








                                                                                        edited yesterday

























                                                                                        answered yesterday









                                                                                        Galen Ivanov

                                                                                        5,87711032




                                                                                        5,87711032






















                                                                                            up vote
                                                                                            4
                                                                                            down vote














                                                                                            Perl 5, 181 bytes





                                                                                            say+(sprintf"%28b",oct"0x$_")=~y/10/# /r for"0003f0003fff800f87fe03c07f78700f71ce00f70ee01e70ee01e70ee03c70ee03c70ee07ff0ee07ff0ee0f070ee0e070e79e003c3fc01f803fffe00380000"=~/.{7}/g


                                                                                            Try it online!






                                                                                            share|improve this answer

























                                                                                              up vote
                                                                                              4
                                                                                              down vote














                                                                                              Perl 5, 181 bytes





                                                                                              say+(sprintf"%28b",oct"0x$_")=~y/10/# /r for"0003f0003fff800f87fe03c07f78700f71ce00f70ee01e70ee01e70ee03c70ee03c70ee07ff0ee07ff0ee0f070ee0e070e79e003c3fc01f803fffe00380000"=~/.{7}/g


                                                                                              Try it online!






                                                                                              share|improve this answer























                                                                                                up vote
                                                                                                4
                                                                                                down vote










                                                                                                up vote
                                                                                                4
                                                                                                down vote










                                                                                                Perl 5, 181 bytes





                                                                                                say+(sprintf"%28b",oct"0x$_")=~y/10/# /r for"0003f0003fff800f87fe03c07f78700f71ce00f70ee01e70ee01e70ee03c70ee03c70ee07ff0ee07ff0ee0f070ee0e070e79e003c3fc01f803fffe00380000"=~/.{7}/g


                                                                                                Try it online!






                                                                                                share|improve this answer













                                                                                                Perl 5, 181 bytes





                                                                                                say+(sprintf"%28b",oct"0x$_")=~y/10/# /r for"0003f0003fff800f87fe03c07f78700f71ce00f70ee01e70ee01e70ee03c70ee03c70ee07ff0ee07ff0ee0f070ee0e070e79e003c3fc01f803fffe00380000"=~/.{7}/g


                                                                                                Try it online!







                                                                                                share|improve this answer












                                                                                                share|improve this answer



                                                                                                share|improve this answer










                                                                                                answered yesterday









                                                                                                Xcali

                                                                                                4,960520




                                                                                                4,960520






















                                                                                                    up vote
                                                                                                    4
                                                                                                    down vote














                                                                                                    Perl 6, 136 116 bytes





                                                                                                    :100['>	b3V$^%&!U3X/_9-D>Z(+, OD_=D,-:&3S>#OL
                                                                                                    8C"> c H'.ords].base(2)~~TR/1/ /.comb(27)>>.say


                                                                                                    Try it online!



                                                                                                    Parses a base 100 number from the ordinal values of the string, converts to base 2 and replaces the 1s with spaces. This uses zeroes as the main character.



                                                                                                    Explanation:



                                                                                                    :100['...'.ords]   # Convert the bytes of the string to base 100
                                                                                                    .base(2) # Convert to base 2
                                                                                                    ~~TR/1/ / # Translate 1s to spaces
                                                                                                    # Alternatively, this could be .split(1)
                                                                                                    .comb(27) # Split to strings of length 27
                                                                                                    >>.say # Print each on a newline





                                                                                                    share|improve this answer



























                                                                                                      up vote
                                                                                                      4
                                                                                                      down vote














                                                                                                      Perl 6, 136 116 bytes





                                                                                                      :100['>	b3V$^%&!U3X/_9-D>Z(+, OD_=D,-:&3S>#OL
                                                                                                      8C"> c H'.ords].base(2)~~TR/1/ /.comb(27)>>.say


                                                                                                      Try it online!



                                                                                                      Parses a base 100 number from the ordinal values of the string, converts to base 2 and replaces the 1s with spaces. This uses zeroes as the main character.



                                                                                                      Explanation:



                                                                                                      :100['...'.ords]   # Convert the bytes of the string to base 100
                                                                                                      .base(2) # Convert to base 2
                                                                                                      ~~TR/1/ / # Translate 1s to spaces
                                                                                                      # Alternatively, this could be .split(1)
                                                                                                      .comb(27) # Split to strings of length 27
                                                                                                      >>.say # Print each on a newline





                                                                                                      share|improve this answer

























                                                                                                        up vote
                                                                                                        4
                                                                                                        down vote










                                                                                                        up vote
                                                                                                        4
                                                                                                        down vote










                                                                                                        Perl 6, 136 116 bytes





                                                                                                        :100['>	b3V$^%&!U3X/_9-D>Z(+, OD_=D,-:&3S>#OL
                                                                                                        8C"> c H'.ords].base(2)~~TR/1/ /.comb(27)>>.say


                                                                                                        Try it online!



                                                                                                        Parses a base 100 number from the ordinal values of the string, converts to base 2 and replaces the 1s with spaces. This uses zeroes as the main character.



                                                                                                        Explanation:



                                                                                                        :100['...'.ords]   # Convert the bytes of the string to base 100
                                                                                                        .base(2) # Convert to base 2
                                                                                                        ~~TR/1/ / # Translate 1s to spaces
                                                                                                        # Alternatively, this could be .split(1)
                                                                                                        .comb(27) # Split to strings of length 27
                                                                                                        >>.say # Print each on a newline





                                                                                                        share|improve this answer















                                                                                                        Perl 6, 136 116 bytes





                                                                                                        :100['>	b3V$^%&!U3X/_9-D>Z(+, OD_=D,-:&3S>#OL
                                                                                                        8C"> c H'.ords].base(2)~~TR/1/ /.comb(27)>>.say


                                                                                                        Try it online!



                                                                                                        Parses a base 100 number from the ordinal values of the string, converts to base 2 and replaces the 1s with spaces. This uses zeroes as the main character.



                                                                                                        Explanation:



                                                                                                        :100['...'.ords]   # Convert the bytes of the string to base 100
                                                                                                        .base(2) # Convert to base 2
                                                                                                        ~~TR/1/ / # Translate 1s to spaces
                                                                                                        # Alternatively, this could be .split(1)
                                                                                                        .comb(27) # Split to strings of length 27
                                                                                                        >>.say # Print each on a newline






                                                                                                        share|improve this answer














                                                                                                        share|improve this answer



                                                                                                        share|improve this answer








                                                                                                        edited yesterday

























                                                                                                        answered yesterday









                                                                                                        Jo King

                                                                                                        19k242101




                                                                                                        19k242101






















                                                                                                            up vote
                                                                                                            3
                                                                                                            down vote













                                                                                                            MATLAB : 144 Bytes



                                                                                                            reshape(repelem([repmat(' #',1,44),' '],'NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJCR'-64),27,)'


                                                                                                            Try it online! (Technically in Octave)



                                                                                                            Explanation:



                                                                                                            This uses the same strategy as digEmAll in R, just with MATLAB syntax. The main difference is that MATLAB has automatic conversion from characters to integers.






                                                                                                            share|improve this answer










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                                                                                                              up vote
                                                                                                              3
                                                                                                              down vote













                                                                                                              MATLAB : 144 Bytes



                                                                                                              reshape(repelem([repmat(' #',1,44),' '],'NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJCR'-64),27,)'


                                                                                                              Try it online! (Technically in Octave)



                                                                                                              Explanation:



                                                                                                              This uses the same strategy as digEmAll in R, just with MATLAB syntax. The main difference is that MATLAB has automatic conversion from characters to integers.






                                                                                                              share|improve this answer










                                                                                                              New contributor




                                                                                                              Nicky Mattsson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                                                                                                                up vote
                                                                                                                3
                                                                                                                down vote










                                                                                                                up vote
                                                                                                                3
                                                                                                                down vote









                                                                                                                MATLAB : 144 Bytes



                                                                                                                reshape(repelem([repmat(' #',1,44),' '],'NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJCR'-64),27,)'


                                                                                                                Try it online! (Technically in Octave)



                                                                                                                Explanation:



                                                                                                                This uses the same strategy as digEmAll in R, just with MATLAB syntax. The main difference is that MATLAB has automatic conversion from characters to integers.






                                                                                                                share|improve this answer










                                                                                                                New contributor




                                                                                                                Nicky Mattsson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                Check out our Code of Conduct.









                                                                                                                MATLAB : 144 Bytes



                                                                                                                reshape(repelem([repmat(' #',1,44),' '],'NFMOJEDJFDGGADCCHDACCCACIDACDFHDBCDFHDBCDFGDCCDFGDCCDFFKDFFKDFEDECDFECFCDCADBDKDCHIFHQJCR'-64),27,)'


                                                                                                                Try it online! (Technically in Octave)



                                                                                                                Explanation:



                                                                                                                This uses the same strategy as digEmAll in R, just with MATLAB syntax. The main difference is that MATLAB has automatic conversion from characters to integers.







                                                                                                                share|improve this answer










                                                                                                                New contributor




                                                                                                                Nicky Mattsson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                Check out our Code of Conduct.









                                                                                                                share|improve this answer



                                                                                                                share|improve this answer








                                                                                                                edited 23 hours ago





















                                                                                                                New contributor




                                                                                                                Nicky Mattsson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                                                                                                                answered yesterday









                                                                                                                Nicky Mattsson

                                                                                                                1314




                                                                                                                1314




                                                                                                                New contributor




                                                                                                                Nicky Mattsson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                Check out our Code of Conduct.





                                                                                                                New contributor





                                                                                                                Nicky Mattsson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                Check out our Code of Conduct.






                                                                                                                Nicky Mattsson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                Check out our Code of Conduct.






















                                                                                                                    up vote
                                                                                                                    2
                                                                                                                    down vote














                                                                                                                    C# (.NET Core), 199 bytes





                                                                                                                    _=>{var r="";for(int i=0,j,k=0;i<88;i++)for(j=0;j++<"0(/1,'&,(&))#&%%*&#%%%#%+&#%&(*&$%&(*&$%&()&%%&()&%%&((-&((-&('&'%&('%(%&%#&$&-&%*+(*3,%"[i]-34;){r+=i%2<1?' ':'#';if(++k%27<1)r+='n';}return r;}


                                                                                                                    Try it online!



                                                                                                                    Uses the same approach as my solution to the tribute to Adam West.






                                                                                                                    share|improve this answer

























                                                                                                                      up vote
                                                                                                                      2
                                                                                                                      down vote














                                                                                                                      C# (.NET Core), 199 bytes





                                                                                                                      _=>{var r="";for(int i=0,j,k=0;i<88;i++)for(j=0;j++<"0(/1,'&,(&))#&%%*&#%%%#%+&#%&(*&$%&(*&$%&()&%%&()&%%&((-&((-&('&'%&('%(%&%#&$&-&%*+(*3,%"[i]-34;){r+=i%2<1?' ':'#';if(++k%27<1)r+='n';}return r;}


                                                                                                                      Try it online!



                                                                                                                      Uses the same approach as my solution to the tribute to Adam West.






                                                                                                                      share|improve this answer























                                                                                                                        up vote
                                                                                                                        2
                                                                                                                        down vote










                                                                                                                        up vote
                                                                                                                        2
                                                                                                                        down vote










                                                                                                                        C# (.NET Core), 199 bytes





                                                                                                                        _=>{var r="";for(int i=0,j,k=0;i<88;i++)for(j=0;j++<"0(/1,'&,(&))#&%%*&#%%%#%+&#%&(*&$%&(*&$%&()&%%&()&%%&((-&((-&('&'%&('%(%&%#&$&-&%*+(*3,%"[i]-34;){r+=i%2<1?' ':'#';if(++k%27<1)r+='n';}return r;}


                                                                                                                        Try it online!



                                                                                                                        Uses the same approach as my solution to the tribute to Adam West.






                                                                                                                        share|improve this answer













                                                                                                                        C# (.NET Core), 199 bytes





                                                                                                                        _=>{var r="";for(int i=0,j,k=0;i<88;i++)for(j=0;j++<"0(/1,'&,(&))#&%%*&#%%%#%+&#%&(*&$%&(*&$%&()&%%&()&%%&((-&((-&('&'%&('%(%&%#&$&-&%*+(*3,%"[i]-34;){r+=i%2<1?' ':'#';if(++k%27<1)r+='n';}return r;}


                                                                                                                        Try it online!



                                                                                                                        Uses the same approach as my solution to the tribute to Adam West.







                                                                                                                        share|improve this answer












                                                                                                                        share|improve this answer



                                                                                                                        share|improve this answer










                                                                                                                        answered yesterday









                                                                                                                        Charlie

                                                                                                                        7,2782388




                                                                                                                        7,2782388






















                                                                                                                            up vote
                                                                                                                            1
                                                                                                                            down vote














                                                                                                                            PHP, 286 bytes





                                                                                                                            <?=preg_replace_callback('~(d*)(D)~',function($m){return str_repeat($m[2],$m[1]?:1);},str_replace(["
                                                                                                                            ",'~','^',';'],["^
                                                                                                                            ",'^4 ','3#','4#'],"14 ^
                                                                                                                            6 12#
                                                                                                                            4 5#4 7#
                                                                                                                            2 ; 6 7# #
                                                                                                                            ^8 ; ^3
                                                                                                                            ^9 ; ~
                                                                                                                            ^8 ;2 ~
                                                                                                                            ^8 ;2 ~
                                                                                                                            ^7 ;3 ~
                                                                                                                            ^7 ;3 ~
                                                                                                                            ^6 11#4
                                                                                                                            ^6 11#4
                                                                                                                            ^5 ;5 ~
                                                                                                                            ^5 ^6 ~
                                                                                                                            ;2 ;11 #
                                                                                                                            2 8#9 ^
                                                                                                                            6 1;
                                                                                                                            6 ^"));


                                                                                                                            Try it online!






                                                                                                                            share|improve this answer

























                                                                                                                              up vote
                                                                                                                              1
                                                                                                                              down vote














                                                                                                                              PHP, 286 bytes





                                                                                                                              <?=preg_replace_callback('~(d*)(D)~',function($m){return str_repeat($m[2],$m[1]?:1);},str_replace(["
                                                                                                                              ",'~','^',';'],["^
                                                                                                                              ",'^4 ','3#','4#'],"14 ^
                                                                                                                              6 12#
                                                                                                                              4 5#4 7#
                                                                                                                              2 ; 6 7# #
                                                                                                                              ^8 ; ^3
                                                                                                                              ^9 ; ~
                                                                                                                              ^8 ;2 ~
                                                                                                                              ^8 ;2 ~
                                                                                                                              ^7 ;3 ~
                                                                                                                              ^7 ;3 ~
                                                                                                                              ^6 11#4
                                                                                                                              ^6 11#4
                                                                                                                              ^5 ;5 ~
                                                                                                                              ^5 ^6 ~
                                                                                                                              ;2 ;11 #
                                                                                                                              2 8#9 ^
                                                                                                                              6 1;
                                                                                                                              6 ^"));


                                                                                                                              Try it online!






                                                                                                                              share|improve this answer























                                                                                                                                up vote
                                                                                                                                1
                                                                                                                                down vote










                                                                                                                                up vote
                                                                                                                                1
                                                                                                                                down vote










                                                                                                                                PHP, 286 bytes





                                                                                                                                <?=preg_replace_callback('~(d*)(D)~',function($m){return str_repeat($m[2],$m[1]?:1);},str_replace(["
                                                                                                                                ",'~','^',';'],["^
                                                                                                                                ",'^4 ','3#','4#'],"14 ^
                                                                                                                                6 12#
                                                                                                                                4 5#4 7#
                                                                                                                                2 ; 6 7# #
                                                                                                                                ^8 ; ^3
                                                                                                                                ^9 ; ~
                                                                                                                                ^8 ;2 ~
                                                                                                                                ^8 ;2 ~
                                                                                                                                ^7 ;3 ~
                                                                                                                                ^7 ;3 ~
                                                                                                                                ^6 11#4
                                                                                                                                ^6 11#4
                                                                                                                                ^5 ;5 ~
                                                                                                                                ^5 ^6 ~
                                                                                                                                ;2 ;11 #
                                                                                                                                2 8#9 ^
                                                                                                                                6 1;
                                                                                                                                6 ^"));


                                                                                                                                Try it online!






                                                                                                                                share|improve this answer













                                                                                                                                PHP, 286 bytes





                                                                                                                                <?=preg_replace_callback('~(d*)(D)~',function($m){return str_repeat($m[2],$m[1]?:1);},str_replace(["
                                                                                                                                ",'~','^',';'],["^
                                                                                                                                ",'^4 ','3#','4#'],"14 ^
                                                                                                                                6 12#
                                                                                                                                4 5#4 7#
                                                                                                                                2 ; 6 7# #
                                                                                                                                ^8 ; ^3
                                                                                                                                ^9 ; ~
                                                                                                                                ^8 ;2 ~
                                                                                                                                ^8 ;2 ~
                                                                                                                                ^7 ;3 ~
                                                                                                                                ^7 ;3 ~
                                                                                                                                ^6 11#4
                                                                                                                                ^6 11#4
                                                                                                                                ^5 ;5 ~
                                                                                                                                ^5 ^6 ~
                                                                                                                                ;2 ;11 #
                                                                                                                                2 8#9 ^
                                                                                                                                6 1;
                                                                                                                                6 ^"));


                                                                                                                                Try it online!







                                                                                                                                share|improve this answer












                                                                                                                                share|improve this answer



                                                                                                                                share|improve this answer










                                                                                                                                answered yesterday









                                                                                                                                Scoots

                                                                                                                                354311




                                                                                                                                354311






















                                                                                                                                    up vote
                                                                                                                                    -1
                                                                                                                                    down vote













                                                                                                                                    deflate, 79 bytes



                                                                                                                                    eJyVkcsJADAIQ++ZIpD9dyxUqrGUgjlpHvglXdqCJymk1yEiaRXEIOXzuBHCiKObReUxUzYaMdt2wmTBg/FmNXndgLRbNvL7ifsLfMw6iQ==






                                                                                                                                    share|improve this answer








                                                                                                                                    New contributor




                                                                                                                                    Whale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                    Check out our Code of Conduct.














                                                                                                                                    • 5




                                                                                                                                      You appear to have posted two answers in the same language. If you make an improvement to your submission it is better to edit your existing answer. Additionally, could you provide a link to the deflate language, as this just looks like a base64 string
                                                                                                                                      – Jo King
                                                                                                                                      yesterday








                                                                                                                                    • 3




                                                                                                                                      I don't think deflate counts as a programming language (although I could be wrong as I don't participate on PPCG).
                                                                                                                                      – NobodyNada
                                                                                                                                      yesterday






                                                                                                                                    • 2




                                                                                                                                      This is not DEFLATE, but zlib, which is DEFLATE plus a 2 byte header and a 4 byte checksum. By stripping those, you can use the Bubblegum interpreter.
                                                                                                                                      – Dennis
                                                                                                                                      yesterday












                                                                                                                                    • @NobodyNada deflate is not a programming language but we do not require that submissions be in programming languages.
                                                                                                                                      – Post Left Garf Hunter
                                                                                                                                      19 hours ago















                                                                                                                                    up vote
                                                                                                                                    -1
                                                                                                                                    down vote













                                                                                                                                    deflate, 79 bytes



                                                                                                                                    eJyVkcsJADAIQ++ZIpD9dyxUqrGUgjlpHvglXdqCJymk1yEiaRXEIOXzuBHCiKObReUxUzYaMdt2wmTBg/FmNXndgLRbNvL7ifsLfMw6iQ==






                                                                                                                                    share|improve this answer








                                                                                                                                    New contributor




                                                                                                                                    Whale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                    Check out our Code of Conduct.














                                                                                                                                    • 5




                                                                                                                                      You appear to have posted two answers in the same language. If you make an improvement to your submission it is better to edit your existing answer. Additionally, could you provide a link to the deflate language, as this just looks like a base64 string
                                                                                                                                      – Jo King
                                                                                                                                      yesterday








                                                                                                                                    • 3




                                                                                                                                      I don't think deflate counts as a programming language (although I could be wrong as I don't participate on PPCG).
                                                                                                                                      – NobodyNada
                                                                                                                                      yesterday






                                                                                                                                    • 2




                                                                                                                                      This is not DEFLATE, but zlib, which is DEFLATE plus a 2 byte header and a 4 byte checksum. By stripping those, you can use the Bubblegum interpreter.
                                                                                                                                      – Dennis
                                                                                                                                      yesterday












                                                                                                                                    • @NobodyNada deflate is not a programming language but we do not require that submissions be in programming languages.
                                                                                                                                      – Post Left Garf Hunter
                                                                                                                                      19 hours ago













                                                                                                                                    up vote
                                                                                                                                    -1
                                                                                                                                    down vote










                                                                                                                                    up vote
                                                                                                                                    -1
                                                                                                                                    down vote









                                                                                                                                    deflate, 79 bytes



                                                                                                                                    eJyVkcsJADAIQ++ZIpD9dyxUqrGUgjlpHvglXdqCJymk1yEiaRXEIOXzuBHCiKObReUxUzYaMdt2wmTBg/FmNXndgLRbNvL7ifsLfMw6iQ==






                                                                                                                                    share|improve this answer








                                                                                                                                    New contributor




                                                                                                                                    Whale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                    Check out our Code of Conduct.









                                                                                                                                    deflate, 79 bytes



                                                                                                                                    eJyVkcsJADAIQ++ZIpD9dyxUqrGUgjlpHvglXdqCJymk1yEiaRXEIOXzuBHCiKObReUxUzYaMdt2wmTBg/FmNXndgLRbNvL7ifsLfMw6iQ==







                                                                                                                                    share|improve this answer








                                                                                                                                    New contributor




                                                                                                                                    Whale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                    Check out our Code of Conduct.









                                                                                                                                    share|improve this answer



                                                                                                                                    share|improve this answer






                                                                                                                                    New contributor




                                                                                                                                    Whale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                    Check out our Code of Conduct.









                                                                                                                                    answered yesterday









                                                                                                                                    Whale

                                                                                                                                    1




                                                                                                                                    1




                                                                                                                                    New contributor




                                                                                                                                    Whale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                    Check out our Code of Conduct.





                                                                                                                                    New contributor





                                                                                                                                    Whale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                    Check out our Code of Conduct.






                                                                                                                                    Whale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                    Check out our Code of Conduct.








                                                                                                                                    • 5




                                                                                                                                      You appear to have posted two answers in the same language. If you make an improvement to your submission it is better to edit your existing answer. Additionally, could you provide a link to the deflate language, as this just looks like a base64 string
                                                                                                                                      – Jo King
                                                                                                                                      yesterday








                                                                                                                                    • 3




                                                                                                                                      I don't think deflate counts as a programming language (although I could be wrong as I don't participate on PPCG).
                                                                                                                                      – NobodyNada
                                                                                                                                      yesterday






                                                                                                                                    • 2




                                                                                                                                      This is not DEFLATE, but zlib, which is DEFLATE plus a 2 byte header and a 4 byte checksum. By stripping those, you can use the Bubblegum interpreter.
                                                                                                                                      – Dennis
                                                                                                                                      yesterday












                                                                                                                                    • @NobodyNada deflate is not a programming language but we do not require that submissions be in programming languages.
                                                                                                                                      – Post Left Garf Hunter
                                                                                                                                      19 hours ago














                                                                                                                                    • 5




                                                                                                                                      You appear to have posted two answers in the same language. If you make an improvement to your submission it is better to edit your existing answer. Additionally, could you provide a link to the deflate language, as this just looks like a base64 string
                                                                                                                                      – Jo King
                                                                                                                                      yesterday








                                                                                                                                    • 3




                                                                                                                                      I don't think deflate counts as a programming language (although I could be wrong as I don't participate on PPCG).
                                                                                                                                      – NobodyNada
                                                                                                                                      yesterday






                                                                                                                                    • 2




                                                                                                                                      This is not DEFLATE, but zlib, which is DEFLATE plus a 2 byte header and a 4 byte checksum. By stripping those, you can use the Bubblegum interpreter.
                                                                                                                                      – Dennis
                                                                                                                                      yesterday












                                                                                                                                    • @NobodyNada deflate is not a programming language but we do not require that submissions be in programming languages.
                                                                                                                                      – Post Left Garf Hunter
                                                                                                                                      19 hours ago








                                                                                                                                    5




                                                                                                                                    5




                                                                                                                                    You appear to have posted two answers in the same language. If you make an improvement to your submission it is better to edit your existing answer. Additionally, could you provide a link to the deflate language, as this just looks like a base64 string
                                                                                                                                    – Jo King
                                                                                                                                    yesterday






                                                                                                                                    You appear to have posted two answers in the same language. If you make an improvement to your submission it is better to edit your existing answer. Additionally, could you provide a link to the deflate language, as this just looks like a base64 string
                                                                                                                                    – Jo King
                                                                                                                                    yesterday






                                                                                                                                    3




                                                                                                                                    3




                                                                                                                                    I don't think deflate counts as a programming language (although I could be wrong as I don't participate on PPCG).
                                                                                                                                    – NobodyNada
                                                                                                                                    yesterday




                                                                                                                                    I don't think deflate counts as a programming language (although I could be wrong as I don't participate on PPCG).
                                                                                                                                    – NobodyNada
                                                                                                                                    yesterday




                                                                                                                                    2




                                                                                                                                    2




                                                                                                                                    This is not DEFLATE, but zlib, which is DEFLATE plus a 2 byte header and a 4 byte checksum. By stripping those, you can use the Bubblegum interpreter.
                                                                                                                                    – Dennis
                                                                                                                                    yesterday






                                                                                                                                    This is not DEFLATE, but zlib, which is DEFLATE plus a 2 byte header and a 4 byte checksum. By stripping those, you can use the Bubblegum interpreter.
                                                                                                                                    – Dennis
                                                                                                                                    yesterday














                                                                                                                                    @NobodyNada deflate is not a programming language but we do not require that submissions be in programming languages.
                                                                                                                                    – Post Left Garf Hunter
                                                                                                                                    19 hours ago




                                                                                                                                    @NobodyNada deflate is not a programming language but we do not require that submissions be in programming languages.
                                                                                                                                    – Post Left Garf Hunter
                                                                                                                                    19 hours ago


















                                                                                                                                     

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