Let $S$ be a simple Module, prove $S^{(I)} cong S^{(I)}$ iff $|I|=|J|$











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Im looking for I proof on this Theorem since my lecture demonstration was kind of redundant.The proof $|I|=|J|$ implies $S^{(I)} cong S^{(I)}$ its quite easy, im more interested in the other implication






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    Im looking for I proof on this Theorem since my lecture demonstration was kind of redundant.The proof $|I|=|J|$ implies $S^{(I)} cong S^{(I)}$ its quite easy, im more interested in the other implication






    modules







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      Im looking for I proof on this Theorem since my lecture demonstration was kind of redundant.The proof $|I|=|J|$ implies $S^{(I)} cong S^{(I)}$ its quite easy, im more interested in the other implication






      modules







      share|cite|improve this question













      Im looking for I proof on this Theorem since my lecture demonstration was kind of redundant.The proof $|I|=|J|$ implies $S^{(I)} cong S^{(I)}$ its quite easy, im more interested in the other implication






      modules




      modules






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      share|cite|improve this question











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      asked 19 hours ago









      Marcos Martínez Wagner

      726




      726



























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