How to exclude a circle from a rectangle when drawing a contour figure?

up vote
3
down vote

favorite

I need to draw a contour figure defined by coordinate x and y. The domain is a rectangle (-100<=x<=100,-100<=y<=100) excluding a circle (center at the origin, and radius of 5). The object function is 'z=x+y'.

What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?

asked yesterday

Robin_Lyn

816

add a comment |

up vote
3
down vote

favorite

What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?

asked yesterday

Robin_Lyn

816

add a comment |

up vote
3
down vote

favorite

What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?

asked yesterday

Robin_Lyn

816

What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?

plotting

asked yesterday

Robin_Lyn

816

asked yesterday

Robin_Lyn

816

asked yesterday

Robin_Lyn

816

asked yesterday

Robin_Lyn

816

asked yesterday

Robin_Lyn

816

add a comment |

2 Answers
2

active

oldest

votes

up vote
2
down vote

accepted

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered 22 hours ago

kglr

171k8193399

add a comment |

up vote
6
down vote

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited 11 hours ago

answered yesterday

Okkes Dulgerci

3,5511716

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
21 hours ago

add a comment |

Your Answer

StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\$","\$"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f186014%2fhow-to-exclude-a-circle-from-a-rectangle-when-drawing-a-contour-figure%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
2
down vote

accepted

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered 22 hours ago

kglr

171k8193399

add a comment |

up vote
2
down vote

accepted

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered 22 hours ago

kglr

171k8193399

add a comment |

up vote
2
down vote

accepted

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered 22 hours ago

kglr

171k8193399

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered 22 hours ago

kglr

171k8193399

answered 22 hours ago

kglr

171k8193399

answered 22 hours ago

kglr

171k8193399

answered 22 hours ago

kglr

171k8193399

add a comment |

up vote
6
down vote

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited 11 hours ago

answered yesterday

Okkes Dulgerci

3,5511716

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
21 hours ago

add a comment |

up vote
6
down vote

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited 11 hours ago

answered yesterday

Okkes Dulgerci

3,5511716

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
21 hours ago

add a comment |

up vote
6
down vote

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited 11 hours ago

answered yesterday

Okkes Dulgerci

3,5511716

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited 11 hours ago

answered yesterday

Okkes Dulgerci

3,5511716

edited 11 hours ago

answered yesterday

Okkes Dulgerci

3,5511716

answered yesterday

Okkes Dulgerci

3,5511716

answered yesterday

Okkes Dulgerci

3,5511716

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
21 hours ago

add a comment |

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
21 hours ago

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
21 hours ago

add a comment |

draft saved

draft discarded

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Vrftjkry