Upward and onward to greater glory!











up vote
14
down vote

favorite
2












May this challenge serve as (another) tribute to Stan Lee, who passed away aged 95.



Stan Lee has left us an invaluable legacy and a peculiar catch word: Excelsior. So here's a small challenge based on what he said it was its meaning:




Finally, what does “Excelsior” mean? “Upward and onward to greater glory!” That’s what I wish you whenever I finish tweeting! Excelsior!




Challenge



Given a series of non-negative integers, output a line with Excelsior! every time an integer is greater than the previous one.



Rules




  • Input will be an array of non-negative integers.

  • Output will consist of lines with the word Excelsior (case does matter) followed by as many ! as the length of the current run of increasingly greater numbers. You can also return an array of strings.

  • Input and output formats are flexible according to the site rules, so feel free to adapt them to your language formats. You can also add spaces at the end of the lines, or even extra new lines after or before the text if you need.


Examples



Input             Output
-----------------------------------
[3,2,1,0,5] Excelsior! // Excelsior because 5 > 0

[1,2,3,4,5] Excelsior! // Excelsior because 2 > 1
Excelsior!! // Excelsior because 3 > 2 (run length: 2)
Excelsior!!! // Excelsior because 4 > 3 (run length: 3)
Excelsior!!!! // Excelsior because 5 > 4 (run length: 4)

<Nothing>

[42] <Nothing>

[1,2,1,3,4,1,5] Excelsior! // Excelsior because 2 > 1
Excelsior! // Excelsior because 3 > 1
Excelsior!! // Excelsior because 4 > 3 (run length: 2)
Excelsior! // Excelsior because 5 > 1

[3,3,3,3,4,3] Excelsior! // Excelsior because 4 > 3


This is code-golf, so may the shortest code for each language win!










share|improve this question






















  • ouflak assumes integers are 1 digit long, is that ok
    – ASCII-only
    2 days ago






  • 1




    @ASCII-only not really. I don't know if LUA has a limitation with that, but if that's not the case ouflak should parse integers of any length.
    – Charlie
    2 days ago










  • @Charlie I don't know Lua, but although it's verbose, it is possible to take for example a space-delimited input and split like this.
    – Kevin Cruijssen
    2 days ago












  • I'm looking at it. The trick is to be able to handle both scenarios.
    – ouflak
    2 days ago










  • FWIW languages like C or Javascript will only handle integers within its precision (9/16 digits) anyway.
    – user202729
    2 days ago















up vote
14
down vote

favorite
2












May this challenge serve as (another) tribute to Stan Lee, who passed away aged 95.



Stan Lee has left us an invaluable legacy and a peculiar catch word: Excelsior. So here's a small challenge based on what he said it was its meaning:




Finally, what does “Excelsior” mean? “Upward and onward to greater glory!” That’s what I wish you whenever I finish tweeting! Excelsior!




Challenge



Given a series of non-negative integers, output a line with Excelsior! every time an integer is greater than the previous one.



Rules




  • Input will be an array of non-negative integers.

  • Output will consist of lines with the word Excelsior (case does matter) followed by as many ! as the length of the current run of increasingly greater numbers. You can also return an array of strings.

  • Input and output formats are flexible according to the site rules, so feel free to adapt them to your language formats. You can also add spaces at the end of the lines, or even extra new lines after or before the text if you need.


Examples



Input             Output
-----------------------------------
[3,2,1,0,5] Excelsior! // Excelsior because 5 > 0

[1,2,3,4,5] Excelsior! // Excelsior because 2 > 1
Excelsior!! // Excelsior because 3 > 2 (run length: 2)
Excelsior!!! // Excelsior because 4 > 3 (run length: 3)
Excelsior!!!! // Excelsior because 5 > 4 (run length: 4)

<Nothing>

[42] <Nothing>

[1,2,1,3,4,1,5] Excelsior! // Excelsior because 2 > 1
Excelsior! // Excelsior because 3 > 1
Excelsior!! // Excelsior because 4 > 3 (run length: 2)
Excelsior! // Excelsior because 5 > 1

[3,3,3,3,4,3] Excelsior! // Excelsior because 4 > 3


This is code-golf, so may the shortest code for each language win!










share|improve this question






















  • ouflak assumes integers are 1 digit long, is that ok
    – ASCII-only
    2 days ago






  • 1




    @ASCII-only not really. I don't know if LUA has a limitation with that, but if that's not the case ouflak should parse integers of any length.
    – Charlie
    2 days ago










  • @Charlie I don't know Lua, but although it's verbose, it is possible to take for example a space-delimited input and split like this.
    – Kevin Cruijssen
    2 days ago












  • I'm looking at it. The trick is to be able to handle both scenarios.
    – ouflak
    2 days ago










  • FWIW languages like C or Javascript will only handle integers within its precision (9/16 digits) anyway.
    – user202729
    2 days ago













up vote
14
down vote

favorite
2









up vote
14
down vote

favorite
2






2





May this challenge serve as (another) tribute to Stan Lee, who passed away aged 95.



Stan Lee has left us an invaluable legacy and a peculiar catch word: Excelsior. So here's a small challenge based on what he said it was its meaning:




Finally, what does “Excelsior” mean? “Upward and onward to greater glory!” That’s what I wish you whenever I finish tweeting! Excelsior!




Challenge



Given a series of non-negative integers, output a line with Excelsior! every time an integer is greater than the previous one.



Rules




  • Input will be an array of non-negative integers.

  • Output will consist of lines with the word Excelsior (case does matter) followed by as many ! as the length of the current run of increasingly greater numbers. You can also return an array of strings.

  • Input and output formats are flexible according to the site rules, so feel free to adapt them to your language formats. You can also add spaces at the end of the lines, or even extra new lines after or before the text if you need.


Examples



Input             Output
-----------------------------------
[3,2,1,0,5] Excelsior! // Excelsior because 5 > 0

[1,2,3,4,5] Excelsior! // Excelsior because 2 > 1
Excelsior!! // Excelsior because 3 > 2 (run length: 2)
Excelsior!!! // Excelsior because 4 > 3 (run length: 3)
Excelsior!!!! // Excelsior because 5 > 4 (run length: 4)

<Nothing>

[42] <Nothing>

[1,2,1,3,4,1,5] Excelsior! // Excelsior because 2 > 1
Excelsior! // Excelsior because 3 > 1
Excelsior!! // Excelsior because 4 > 3 (run length: 2)
Excelsior! // Excelsior because 5 > 1

[3,3,3,3,4,3] Excelsior! // Excelsior because 4 > 3


This is code-golf, so may the shortest code for each language win!










share|improve this question













May this challenge serve as (another) tribute to Stan Lee, who passed away aged 95.



Stan Lee has left us an invaluable legacy and a peculiar catch word: Excelsior. So here's a small challenge based on what he said it was its meaning:




Finally, what does “Excelsior” mean? “Upward and onward to greater glory!” That’s what I wish you whenever I finish tweeting! Excelsior!




Challenge



Given a series of non-negative integers, output a line with Excelsior! every time an integer is greater than the previous one.



Rules




  • Input will be an array of non-negative integers.

  • Output will consist of lines with the word Excelsior (case does matter) followed by as many ! as the length of the current run of increasingly greater numbers. You can also return an array of strings.

  • Input and output formats are flexible according to the site rules, so feel free to adapt them to your language formats. You can also add spaces at the end of the lines, or even extra new lines after or before the text if you need.


Examples



Input             Output
-----------------------------------
[3,2,1,0,5] Excelsior! // Excelsior because 5 > 0

[1,2,3,4,5] Excelsior! // Excelsior because 2 > 1
Excelsior!! // Excelsior because 3 > 2 (run length: 2)
Excelsior!!! // Excelsior because 4 > 3 (run length: 3)
Excelsior!!!! // Excelsior because 5 > 4 (run length: 4)

<Nothing>

[42] <Nothing>

[1,2,1,3,4,1,5] Excelsior! // Excelsior because 2 > 1
Excelsior! // Excelsior because 3 > 1
Excelsior!! // Excelsior because 4 > 3 (run length: 2)
Excelsior! // Excelsior because 5 > 1

[3,3,3,3,4,3] Excelsior! // Excelsior because 4 > 3


This is code-golf, so may the shortest code for each language win!







code-golf string number






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 14 at 7:42









Charlie

7,2812388




7,2812388












  • ouflak assumes integers are 1 digit long, is that ok
    – ASCII-only
    2 days ago






  • 1




    @ASCII-only not really. I don't know if LUA has a limitation with that, but if that's not the case ouflak should parse integers of any length.
    – Charlie
    2 days ago










  • @Charlie I don't know Lua, but although it's verbose, it is possible to take for example a space-delimited input and split like this.
    – Kevin Cruijssen
    2 days ago












  • I'm looking at it. The trick is to be able to handle both scenarios.
    – ouflak
    2 days ago










  • FWIW languages like C or Javascript will only handle integers within its precision (9/16 digits) anyway.
    – user202729
    2 days ago


















  • ouflak assumes integers are 1 digit long, is that ok
    – ASCII-only
    2 days ago






  • 1




    @ASCII-only not really. I don't know if LUA has a limitation with that, but if that's not the case ouflak should parse integers of any length.
    – Charlie
    2 days ago










  • @Charlie I don't know Lua, but although it's verbose, it is possible to take for example a space-delimited input and split like this.
    – Kevin Cruijssen
    2 days ago












  • I'm looking at it. The trick is to be able to handle both scenarios.
    – ouflak
    2 days ago










  • FWIW languages like C or Javascript will only handle integers within its precision (9/16 digits) anyway.
    – user202729
    2 days ago
















ouflak assumes integers are 1 digit long, is that ok
– ASCII-only
2 days ago




ouflak assumes integers are 1 digit long, is that ok
– ASCII-only
2 days ago




1




1




@ASCII-only not really. I don't know if LUA has a limitation with that, but if that's not the case ouflak should parse integers of any length.
– Charlie
2 days ago




@ASCII-only not really. I don't know if LUA has a limitation with that, but if that's not the case ouflak should parse integers of any length.
– Charlie
2 days ago












@Charlie I don't know Lua, but although it's verbose, it is possible to take for example a space-delimited input and split like this.
– Kevin Cruijssen
2 days ago






@Charlie I don't know Lua, but although it's verbose, it is possible to take for example a space-delimited input and split like this.
– Kevin Cruijssen
2 days ago














I'm looking at it. The trick is to be able to handle both scenarios.
– ouflak
2 days ago




I'm looking at it. The trick is to be able to handle both scenarios.
– ouflak
2 days ago












FWIW languages like C or Javascript will only handle integers within its precision (9/16 digits) anyway.
– user202729
2 days ago




FWIW languages like C or Javascript will only handle integers within its precision (9/16 digits) anyway.
– user202729
2 days ago










31 Answers
31






active

oldest

votes













1 2
next











up vote
9
down vote













JavaScript (ES6), 58 54 bytes





a=>a.map(c=>a<(a=c)?`Excelsior${s+='!'}
`:s='').join``


Try it online!



Commented



a =>                           // a = input array, also used to store the previous value
a.map(c => // for each value c in a:
a < // compare the previous value
(a = c) // with the current one; update a to c
// this test is always falsy on the 1st iteration
? // if a is less than c:
`Excelsior${s += '!'}n` // add a '!' to s and yield 'Excelsior' + s + linefeed
: // else:
s = '' // reset s to an empty string and yield an empty string
).join`` // end of map(); join everything


Why re-using a[ ] to store the previous value is safe



There are three possible cases:




  • If $a[text{ }]$ is empty, the callback function of .map() is not invoked at all and we just get an empty array, yielding an empty string.

  • If $a[text{ }]$ contains exactly one element $x$, it is coerced to that element during the first (and unique) test a < (a = c). So, we're testing $x < x$, which is falsy. We get an array containing an empty string, yielding again an empty string.

  • If $a[text{ }]$ contains several elements, it is coerced to NaN during the first test a < (a = c). Therefore, the result is falsy and what's executed is the initialization of $s$ to an empty string -- which is what we want. The first meaningful comparison occurs at the 2nd iteration.






share|improve this answer






























    up vote
    5
    down vote














    Python 2, 84 83 81 70 68 bytes





    a=n=''
    for b in input():
    n+='!';n*=a<b;a=b
    if n:print'Excelsior'+n


    Try it online!



    -2 bytes, thanks to ASCII-only






    share|improve this answer























    • 68?
      – ASCII-only
      Nov 14 at 9:31










    • @ASCII-only Thanks :)
      – TFeld
      Nov 14 at 9:34










    • functions are too long :(
      – ASCII-only
      Nov 14 at 9:46










    • well, recursive approaches at least
      – ASCII-only
      Nov 14 at 9:48










    • same with zip
      – ASCII-only
      Nov 14 at 9:50


















    up vote
    5
    down vote














    05AB1E, 26 24 23 bytes



    ü‹γvyOE.•1Š¥èò²•™N'!׫,


    -2 bytes thanks to @Kroppeb.



    Try it online or verify all test cases.



    Explanation:





    ü                        # Loop over the (implicit) input as pairs
    ‹ # And check for each pair [a,b] if a<b is truthy
    # i.e. [1,2,1,3,4,1,5,7,20,25,3,17]
    # → [1,0,1,1,0,1,1,1,1,0,1]
    γ # Split it into chunks of equal elements
    # i.e. [1,0,1,1,0,1,1,1,1,0,1]
    # → [[1],[0],[1,1],[0],[1,1,1,1],[0],[1]]
    vy # Foreach `y` over them
    O # Take the sum of that inner list
    # i.e. [1,1,1,1] → 4
    # i.e. [0] → 0
    E # Inner loop `N` in the range [1, length]:
    .•1Š¥èò²• # Push string "excelsior"
    ™ # Titlecase it: "Excelsior"
    N'!׫ '# Append `N` amount of "!"
    # i.e. N=3 → "Excelsior!!!"
    , # Output with a trailing newline


    See this 05AB1E tip of mine (section How to compress strings not part of the dictionary?) to understand why .•1Š¥èò²• is "excelsior".






    share|improve this answer



















    • 2




      I don't really know 05AB1E but can't you exchange the 0Kg with O?
      – Kroppeb
      2 days ago












    • @Kroppeb Ah, completely missed that, but yes, I indeed can. Thanks! :)
      – Kevin Cruijssen
      2 days ago


















    up vote
    5
    down vote














    Perl 6, 60 58 57 bytes



    -1 byte thanks to nwellnhof





    {"Excelsior"X~("!"Xx grep +*,[[&(-+^*×*)]] .skip Z>$_)}


    Try it online!



    Anonymous code block that returns a list of Excelsiors!






    share|improve this answer






























      up vote
      4
      down vote














      Java-8 118 113 Bytes



      n->{String e="";for(int i=0;i<n.length-1;)System.out.print(""==(n[i+1]>n[i++]?e+="!":(e=""))?e:"Excelsior"+e+"n");}


      Easy to read :



      private static void lee(int num) {
      String exclamation = "";
      for (int i = 0; i < num.length - 1;) {
      exclamation = num[i + 1] > num[i++] ? exclamation += "!" : "";
      System.out.print("".equals(exclamation) ? "" : "Excelsior" + exclamation + "n");
      }
      }





      share|improve this answer



















      • 2




        Here some golfs to save 10 bytes: n->{var e="";for(int i=0;i<n.length-1;System.out.print(""==e?e:"Excelsior"+e+"n"))e=n[i++]<n[i]?e+="!":"";}. Try it online (108 bytes). (Java 10+)
        – Kevin Cruijssen
        2 days ago










      • @KevinCruijssen Thanks!
        – coder-croc
        2 days ago






      • 2




        n->{for(int e=0,i=0;i<n.length-1;)if(n[i++]<n[i])System.out.println("Excelsior"+"!".repeat(e++));else e=0;} (107 bytes)
        – Olivier Grégoire
        2 days ago










      • Fixing my issue: ++e instead of e++ so that there is at least one ! to be printed.
        – Olivier Grégoire
        yesterday


















      up vote
      4
      down vote














      R, 86 bytes



      Half of this answer is @Giuseppe's. RIP Stan Lee.





      function(a)for(i in diff(a))"if"(i>0,cat("Excelsior",rep("!",F<-F+1),"
      ",sep=""),F<-0)


      Try it online!






      share|improve this answer




























        up vote
        4
        down vote














        05AB1E, 20 19 bytes



        ü‹0¡€ƶ˜ε'!×”¸Îsiorÿ


        Try it online!



        Explanation



        ü‹                    # pair-wise comparison, less-than
        0¡ # split at zeroes
        €ƶ # lift each, multiplying by its 1-based index
        ˜ # flatten
        ε # apply to each
        '!× # repeat "!" that many times
        ÿ # and interpolate it at the end of
        ”¸Îsior # the compressed word "Excel" followed by the string "sior"





        share|improve this answer






























          up vote
          4
          down vote













          C (gcc/clang), 106 99 97 bytes





          f(a,n)int*a;{int r=0,s[n];for(memset(s,33,n);n-->1;)r*=*a<*++a&&printf("Excelsior%.*sn",++r,s);}


          Thanks to gastropner for golfing 2 bytes.



          Try it online here.



          Ungolfed:



          f(a, n) // function taking a pointer to the first integer and the length of the array
          int *a; { // a is of type pointer to int, n is of type int

          int r = 0, // length of the current run
          i = 0, // loop variable
          s[n]; // buffer for exclamation marks; we will never need more than n-1 of those (we are declaring an array of int, but really we will treat it as an array of char)

          for(memset(s, 33, n); // fill the buffer with n exclamation marks (ASCII code 33)
          n -- > 1; ) // loop over the array

          r *= *a < *(++ a) // if the current element is less than the next:
          && printf("Excelsior%.*sn", // print (on their own line) "Excelsior", followed by ...
          ++ r, // ... r (incremented) of the ...
          s) // ... n exclamation marks in the buffer s
          ; // else r is reset to 0

          }





          share|improve this answer























          • I started making a solution, but ended up so close to yours that posting mine as a separate answer felt a bit silly. Still, the few differences there are can save you a few bytes.
            – gastropner
            yesterday










          • @gastropner Thanks for sharing your version. I have incorporated your improvements and golfed it further to 99 bytes. If only we didn't need to handle the empty array – otherwise it would be 97 bytes, using your style of loop.
            – O.O.Balance
            20 hours ago


















          up vote
          4
          down vote













          Japt -R, 25 22 bytes



          ò¨ ËÅ£`Ex­lÐâ`ú'!Y+A
          c


          Try it



          3 bytes saved thanks to Kamil



          ò¨                      :Partition at items that are greater than or equal to the previous item
          Ë :Map
          Å : Slice off the first element
          £ : Map each element at 0-based index Y
          `Ex­lÐâ` : Compressed string "Excelsior"
          ú'! : Right pad with exclamation marks
          Y+A : To length Y+10
          c :Flatten
          :Implicitly join with newlines & output





          share|improve this answer























          • Another 25 bytes
            – Luis felipe De jesus Munoz
            2 days ago










          • The -R flag isn't actually necessary, the challenge says you can output an array of strings.
            – Kamil Drakari
            2 days ago










          • Nice one, thanks, @KamilDrakari. I tried a solution using slice on my first pass but dismissed it when it worked out too long. Coming back to it now, with your prompting, I guess I should have stuck with it 'cause I got it down to 22 too.
            – Shaggy
            17 hours ago


















          up vote
          3
          down vote













          Common Lisp, 111 bytes



          (setq i 0)(loop for(a b)on(read)do(incf i(if(and b(> b a))1(- i)))(format(> i 0)"Excelsior~v@{~a~:*~}~%"i #!))


          Try it online!






          share|improve this answer




























            up vote
            3
            down vote













            Java 8, 106 bytes





            n->{String s="",z=s;for(int i=0;i<n.length-1;)z+=n[i++]<n[i]?"Excelsior"+(s+="!")+"n":(s="")+s;return z;}


            Try it online!



            (those reassignments of s...yikes)






            share|improve this answer





















            • You can golf two more bytes by replacing (s="")+s => (s="")
              – O.O.Balance
              yesterday






            • 1




              n->{String s="",z=s;for(int i=0;i<n.length-1;)z+=n[i++]>=n[i]?s="":"Excelsior"+(s+="!")+"n";return z;} (103 bytes) Move the s="" to spare bytes.
              – Olivier Grégoire
              yesterday


















            up vote
            3
            down vote














            Stax, 17 bytes



            Θx7├╖&σ '@7g┼┘Ñ«═


            Run and debug it






            share|improve this answer




























              up vote
              3
              down vote














              R, 111 bytes





              function(a,r=rle(sign(diff(a))),v=r$l[r$v>0])write(paste0(rep("Excelsior",sum(v)),strrep("!",sequence(v))),1,1)


              Try it online!



              A far better R tribute can be found here -- I was too fixated on sequence and rle.






              share|improve this answer























              • This doesn't give some blank lines, but 86 bytes?
                – J.Doe
                2 days ago






              • 2




                @J.Doe dang, that's way better. I'd post that myself if I were you.
                – Giuseppe
                2 days ago


















              up vote
              3
              down vote














              Jelly, 16 bytes



              <Ɲṣ0ÄẎ”!ẋ“Ø6ḥ»;Ɱ


              A monadic Link yielding a list of lists of characters.



              Try it online! (footer joins with newlines)



              How?



              <Ɲṣ0ÄẎ”!ẋ“Ø6ḥ»;Ɱ - Link: list of integers     e.g. [1,1,4,2,1,1,3,4]
              Ɲ - for each pair of integers: [1,1] [1,4] [4,2] [2,1] [1,1] [1,3] [3,4]
              < - less than? [ 0, 1, 0, 0, 0, 1, 1]
              ṣ0 - split at zeros [, [1], , , [1, 1]]
              Ä - cumulative sums [, [1], , , [1, 2]]
              Ẏ - tighten [1,1,2]
              ”! - literal '!' character '!'
              ẋ - repeat (vectorises) [['!'],['!'],['!','!']]
              “Ø6ḥ» - dictionary lookup ['E','x','c','e','l','s','i','o','r']
              Ɱ - map with:
              ; - concatenate [['E','x','c','e','l','s','i','o','r','!'],['E','x','c','e','l','s','i','o','r','!'],['E','x','c','e','l','s','i','o','r','!','!']]





              share|improve this answer




























                up vote
                3
                down vote














                Perl 5 -n, 41 bytes





                $_>$l&&$l?say$c.='!':($c=Excelsior);$l=$_


                Try it online!



                Takes its input on separate lines.






                share|improve this answer




























                  up vote
                  3
                  down vote














                  Japt, 22 bytes



                  ò¨ ®£`Ex­lÐâ`+'!pYÃÅÃc


                  Try it online!



                  Explanation, with simplified example:



                  ò¨                       :Split whenever the sequence does not increase
                  e.g. [2,1,1,3] -> [[2],[1],[1,3]]
                  ® Ã :For each sub-array:
                  £ Ã : For each item in that sub-array:
                  `Ex­lÐâ` : Compressed "Excelsior"
                  + : Concat with
                  '!pY : a number of "!" equal to the index
                  e.g. [1,3] -> ["Excelsior","Excelsior!"]
                  Å : Remove the first item of each sub-array
                  e.g. [[Excelsior],[Excelsior],[Excelsior,Excelsior!]]->[,,[Excelsior!]]
                  c :Flatten
                  e.g. [,,[Excelsior!]] -> [Excelsior!]





                  share|improve this answer




























                    up vote
                    2
                    down vote














                    Retina, 55 bytes



                    d+
                    *
                    L$rv`(_*,(?<!(?(1)1|2,)))+(_+)b
                    Excelsior$#1*!


                    Try it online! Link includes test cases. Explanation:



                    d+
                    *


                    Convert to unary.



                    rv`(_*,(?<!(?(1)1|2,)))+(_+)b


                    Process overlapping matches from right to left (although the matches are then listed from left to right). This means that we can match every number in a run, and the match extends to the start of the run. Each match is further constrained that each additional matched number must be less than the previously matched additional number, or the first number if no additional numbers have been matched yet.



                    L$...
                    Excelsior$#1*!


                    For each match, output Excelsior with the number of additional numbers in the run as desired.






                    share|improve this answer




























                      up vote
                      2
                      down vote













                      Pyth, 32 bytes



                      j+L"Excelsior"*L!fT.u*hN<0Y.+Q0


                      Try it online here, or verify all the test cases at once here.



                      j+L"Excelsior"*L!fT.u*hN<0Y.+Q0   Implicit: Q=eval(input())
                      .+Q Get forward difference between consecutive elements of Q
                      .u 0 Reduce the above, returning all steps, with current value N starting at 0, next element as Y, using:
                      hN N+1
                      * Multiplied by
                      <0Y 1 if 0<Y, 0 otherwise
                      fT Filter to remove 0s
                      *L! Repeat "!" each element number of times
                      +L"Excelsior" Prepend "Excelsior" to each
                      j Join on newlines, implicit print





                      share|improve this answer




























                        up vote
                        2
                        down vote














                        Jelly, 18 bytes



                        <Ɲ‘×¥ḟ0”!ẋ“Ø6ḥ»;Ɱ


                        Try it online!



                        Output prettified over TIO.






                        share|improve this answer






























                          up vote
                          2
                          down vote














                          Lua, 88 87 83 82 96 95 113 bytes



                          Thanks @Kevin Cruijssen for update adhering to spirit of original question.





                          s=io.read()n=9 e="Excelsior!"f=e
                          for c in s.gmatch(s,"%S+")do if n<c+0then print(e)e=e..'!'else e=f end n=c+0 end


                          Try it online!






                          share|improve this answer



















                          • 1




                            Sorry but you need to print the exclamation mark according to the rules (one exclamation mark per length of the current run of increasingly greater numbers).
                            – Charlie
                            Nov 14 at 9:49










                          • No problem. Think I've done as much as I can do here unless someone else sees something...
                            – ouflak
                            Nov 14 at 9:56






                          • 1




                            I don't know Lua too well, but here is a fix for your code so it runs all test cases correctly Currently you just print an "!" more every time a number is higher than the previous, but you don't reset it back to 1 when that isn't the case. More can probably be golfed, but since I've never golfed in Lua I focused on fixing it with only minor golfs. PS: Not sure if assuming the input are always single digits is correct..
                            – Kevin Cruijssen
                            2 days ago








                          • 2




                            Since @Charlie mentioned in a comment below the challenge description that it should be possible to take multi-digits numbers as input, here a possible fix by taking a space-delimited input and split on it.
                            – Kevin Cruijssen
                            2 days ago












                          • I decided that Kevin Cruijssen modifications are more inline with the OP's expectation. Thanks!
                            – ouflak
                            2 days ago


















                          up vote
                          2
                          down vote













                          C++ 14 (g++), 123 118 bytes





                          (auto a){for(int n=0,i=0;++i<a.size();)a[i]>a[i-1]?puts(&("Excelsior"+std::string(++n,33))[0]):n=0;}


                          Fortunately std::string has a constructor that repeats a char. Try it online here.



                          Thanks to gastropner for saving 5 bytes.



                          Ungolfed:



                           (auto a) { // void lambda taking a std::array of integer

                          for(int n = 0, // length of the current run
                          i = 0; // loop variable
                          ++ i < a.size(); ) // start with the second element and loop to the last
                          a[i] > a[i - 1] // if the current element is greater than the previous ...
                          ? puts( // ... print a new line:
                          &("Excelsior" + // "Excelsior, followed by ...
                          std::string(++ n, 33)) // ... the appropriate number of exclamation marks (33 is ASCII code for '!'); increment the run length
                          [0]) // puts() takes a C string
                          : n = 0; // else reset run length

                          }





                          share|improve this answer























                          • You can shave off another 5 bytes
                            – gastropner
                            2 days ago


















                          up vote
                          2
                          down vote














                          C# (.NET Core), 115 107 105 bytes





                          a=>{var b="";for(int i=0;++i<a.Length;)if(a[i]>a[i-1])Console.WriteLine("Excelsior"+(b+="!"));else b="";}


                          Try it online!



                          -8 bytes: changed b to a string holding "!"s from an int counter
                          -2 bytes: set b+="!" as an inline function (thanks to Zac Faragher)



                          Uses an Action delegate to pull in the input and not require a return.



                          Ungolfed:



                          a => {
                          var b = ""; // initialize the '!' string (b)
                          for(int i = 0; ++i < a.Length;) // from index 1 until the end of a
                          if(a[i] > a[i - 1]) // if the current index is greater than the previous index
                          Console.WriteLine("Excelsior" + // on a new line, print "Excelsior"
                          (b += "!")); // add a "!" to b, and print the string
                          else // if the current index is not greater than the previous index
                          b = ""; // reset b
                          }





                          share|improve this answer



















                          • 1




                            you can save 2 bytes by making the b+="!" inline with the Excelsior if(a[i]>a[i-1])Console.WriteLine("Excelsior"+(b+="!")); Try it online!
                            – Zac Faragher
                            yesterday


















                          up vote
                          2
                          down vote














                          PHP, 117 109 bytes





                          <?php do{$i=next($argv);if($p!==null&&$p<$i){$e.='!';echo "
                          Excelsior$e";}else$e='';$p=$i;}while($i!==false);


                          Try it online!






                          share|improve this answer






























                            up vote
                            2
                            down vote














                            PowerShell, 88 87 bytes





                            param($n)for(;++$i-lt$n.count){if($n[$i]-gt$n[$i-1]){"Excelsior"+"!"*(++$c)}else{$c=0}}


                            Try it online!



                            There's probably a restructuring hiding in there, most likely in the if-else, but overall pretty alright. Uses the ol' "Un-instantiated variable defaults to 0" trick for both making the index and the !.






                            share|improve this answer






























                              up vote
                              1
                              down vote













                              Java, 113 bytes



                              String i="";for(int a=0;a<s.length-1;a++){if(s[a+1]>s[a]){i+="!";System.out.println("Excelsior"+i);}else{i="";}}





                              share|improve this answer










                              New contributor




                              isaace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.

























                                up vote
                                1
                                down vote













                                VBA, 114 bytes



                                For i=0 To UBound(a)-LBound(a)-1 If a(i+1)>a(i)Then s=s&"!" Debug.Print("Excelsior"&s&"") Else s="" End If Next i





                                share|improve this answer








                                New contributor




                                isaace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                Check out our Code of Conduct.

























                                  up vote
                                  1
                                  down vote













                                  Python 3, 87 bytes



                                  c='!'
                                  for i in range(1,len(n)):
                                  if n[i]>n[i-1]:print('Excelsior'+c);c+='!'
                                  else:c='!'


                                  Or 97 with the following:



                                  c='!';n=input()
                                  for i in range(1,len(n)):
                                  if n[i]>n[i-1]:print('Excelsior'+c);c+='!'
                                  else:c='!'


                                  This assumes inputs will be in the format:



                                  32105
                                  12345
                                  <null input>
                                  1
                                  1213415
                                  333343





                                  share|improve this answer










                                  New contributor




                                  Henry T is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                  Check out our Code of Conduct.


















                                  • Your first program is invalid as it takes input through a predefined variable. The second is invalud as it can't distinguish between numbers with multiple digits. Why not use Python 2 or turn it into a function instead?
                                    – Jo King
                                    12 hours ago


















                                  up vote
                                  1
                                  down vote













                                  J, 50 bytes



                                  'Excelsior',"1'!'#"0~[:;@(([:<+/);._1)0,2</ ::0]


                                  Try it online!



                                  ungolfed



                                  'Excelsior' ,"1 '!' #"0~ [: ;@(([: < +/);._1) 0 , 2 </ ::0 ]





                                  share|improve this answer




























                                    up vote
                                    1
                                    down vote













                                    Powershell, 69 bytes





                                    $args|%{if($o-ne$e-and$_-gt$o){'Excelsior'+'!'*++$c}else{$c=0}$o=$_}


                                    Less golfed test script:



                                    $f = {

                                    $args|%{
                                    if($old-ne$empty-and$_-gt$old){
                                    'Excelsior'+'!'*++$c
                                    }else{
                                    $c=0
                                    }
                                    $old=$_
                                    }

                                    }

                                    @(
                                    ,( (3,2,1,0,5), 'Excelsior!') # Excelsior because 5 > 0

                                    ,( (1,2,3,4,5), 'Excelsior!', # Excelsior because 2 > 1
                                    'Excelsior!!', # Excelsior because 3 > 2 (run length: 2)
                                    'Excelsior!!!', # Excelsior because 4 > 3 (run length: 3)
                                    'Excelsior!!!!') # Excelsior because 5 > 4 (run length: 4)

                                    ,( $null, '') # <Nothing>

                                    ,( (42), '') # <Nothing>

                                    ,( (1,2,1,3,4,1,5), 'Excelsior!', # Excelsior because 2 > 1
                                    'Excelsior!', # Excelsior because 3 > 1
                                    'Excelsior!!', # Excelsior because 4 > 3 (run length: 2)
                                    'Excelsior!') # Excelsior because 5 > 1

                                    ,( (3,3,3,3,4,3), 'Excelsior!') # Excelsior because 4 > 3
                                    ) | % {
                                    $a,$expected = $_
                                    $result = &$f @a
                                    "$result"-eq"$expected"
                                    $result
                                    }


                                    Output:



                                    True
                                    Excelsior!
                                    True
                                    Excelsior!
                                    Excelsior!!
                                    Excelsior!!!
                                    Excelsior!!!!
                                    True
                                    True
                                    True
                                    Excelsior!
                                    Excelsior!
                                    Excelsior!!
                                    Excelsior!
                                    True
                                    Excelsior!





                                    share|improve this answer




























                                      up vote
                                      0
                                      down vote














                                      Japt, 25 bytes



                                      ä< ®?`Ex­lÐâ`+'!p°T:T=0
                                      f


                                      Try it online!






                                      share|improve this answer

























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                                        up vote
                                        9
                                        down vote













                                        JavaScript (ES6), 58 54 bytes





                                        a=>a.map(c=>a<(a=c)?`Excelsior${s+='!'}
                                        `:s='').join``


                                        Try it online!



                                        Commented



                                        a =>                           // a = input array, also used to store the previous value
                                        a.map(c => // for each value c in a:
                                        a < // compare the previous value
                                        (a = c) // with the current one; update a to c
                                        // this test is always falsy on the 1st iteration
                                        ? // if a is less than c:
                                        `Excelsior${s += '!'}n` // add a '!' to s and yield 'Excelsior' + s + linefeed
                                        : // else:
                                        s = '' // reset s to an empty string and yield an empty string
                                        ).join`` // end of map(); join everything


                                        Why re-using a[ ] to store the previous value is safe



                                        There are three possible cases:




                                        • If $a[text{ }]$ is empty, the callback function of .map() is not invoked at all and we just get an empty array, yielding an empty string.

                                        • If $a[text{ }]$ contains exactly one element $x$, it is coerced to that element during the first (and unique) test a < (a = c). So, we're testing $x < x$, which is falsy. We get an array containing an empty string, yielding again an empty string.

                                        • If $a[text{ }]$ contains several elements, it is coerced to NaN during the first test a < (a = c). Therefore, the result is falsy and what's executed is the initialization of $s$ to an empty string -- which is what we want. The first meaningful comparison occurs at the 2nd iteration.






                                        share|improve this answer



























                                          up vote
                                          9
                                          down vote













                                          JavaScript (ES6), 58 54 bytes





                                          a=>a.map(c=>a<(a=c)?`Excelsior${s+='!'}
                                          `:s='').join``


                                          Try it online!



                                          Commented



                                          a =>                           // a = input array, also used to store the previous value
                                          a.map(c => // for each value c in a:
                                          a < // compare the previous value
                                          (a = c) // with the current one; update a to c
                                          // this test is always falsy on the 1st iteration
                                          ? // if a is less than c:
                                          `Excelsior${s += '!'}n` // add a '!' to s and yield 'Excelsior' + s + linefeed
                                          : // else:
                                          s = '' // reset s to an empty string and yield an empty string
                                          ).join`` // end of map(); join everything


                                          Why re-using a[ ] to store the previous value is safe



                                          There are three possible cases:




                                          • If $a[text{ }]$ is empty, the callback function of .map() is not invoked at all and we just get an empty array, yielding an empty string.

                                          • If $a[text{ }]$ contains exactly one element $x$, it is coerced to that element during the first (and unique) test a < (a = c). So, we're testing $x < x$, which is falsy. We get an array containing an empty string, yielding again an empty string.

                                          • If $a[text{ }]$ contains several elements, it is coerced to NaN during the first test a < (a = c). Therefore, the result is falsy and what's executed is the initialization of $s$ to an empty string -- which is what we want. The first meaningful comparison occurs at the 2nd iteration.






                                          share|improve this answer

























                                            up vote
                                            9
                                            down vote










                                            up vote
                                            9
                                            down vote









                                            JavaScript (ES6), 58 54 bytes





                                            a=>a.map(c=>a<(a=c)?`Excelsior${s+='!'}
                                            `:s='').join``


                                            Try it online!



                                            Commented



                                            a =>                           // a = input array, also used to store the previous value
                                            a.map(c => // for each value c in a:
                                            a < // compare the previous value
                                            (a = c) // with the current one; update a to c
                                            // this test is always falsy on the 1st iteration
                                            ? // if a is less than c:
                                            `Excelsior${s += '!'}n` // add a '!' to s and yield 'Excelsior' + s + linefeed
                                            : // else:
                                            s = '' // reset s to an empty string and yield an empty string
                                            ).join`` // end of map(); join everything


                                            Why re-using a[ ] to store the previous value is safe



                                            There are three possible cases:




                                            • If $a[text{ }]$ is empty, the callback function of .map() is not invoked at all and we just get an empty array, yielding an empty string.

                                            • If $a[text{ }]$ contains exactly one element $x$, it is coerced to that element during the first (and unique) test a < (a = c). So, we're testing $x < x$, which is falsy. We get an array containing an empty string, yielding again an empty string.

                                            • If $a[text{ }]$ contains several elements, it is coerced to NaN during the first test a < (a = c). Therefore, the result is falsy and what's executed is the initialization of $s$ to an empty string -- which is what we want. The first meaningful comparison occurs at the 2nd iteration.






                                            share|improve this answer














                                            JavaScript (ES6), 58 54 bytes





                                            a=>a.map(c=>a<(a=c)?`Excelsior${s+='!'}
                                            `:s='').join``


                                            Try it online!



                                            Commented



                                            a =>                           // a = input array, also used to store the previous value
                                            a.map(c => // for each value c in a:
                                            a < // compare the previous value
                                            (a = c) // with the current one; update a to c
                                            // this test is always falsy on the 1st iteration
                                            ? // if a is less than c:
                                            `Excelsior${s += '!'}n` // add a '!' to s and yield 'Excelsior' + s + linefeed
                                            : // else:
                                            s = '' // reset s to an empty string and yield an empty string
                                            ).join`` // end of map(); join everything


                                            Why re-using a[ ] to store the previous value is safe



                                            There are three possible cases:




                                            • If $a[text{ }]$ is empty, the callback function of .map() is not invoked at all and we just get an empty array, yielding an empty string.

                                            • If $a[text{ }]$ contains exactly one element $x$, it is coerced to that element during the first (and unique) test a < (a = c). So, we're testing $x < x$, which is falsy. We get an array containing an empty string, yielding again an empty string.

                                            • If $a[text{ }]$ contains several elements, it is coerced to NaN during the first test a < (a = c). Therefore, the result is falsy and what's executed is the initialization of $s$ to an empty string -- which is what we want. The first meaningful comparison occurs at the 2nd iteration.







                                            share|improve this answer














                                            share|improve this answer



                                            share|improve this answer








                                            edited 2 days ago

























                                            answered 2 days ago









                                            Arnauld

                                            68.6k584289




                                            68.6k584289






















                                                up vote
                                                5
                                                down vote














                                                Python 2, 84 83 81 70 68 bytes





                                                a=n=''
                                                for b in input():
                                                n+='!';n*=a<b;a=b
                                                if n:print'Excelsior'+n


                                                Try it online!



                                                -2 bytes, thanks to ASCII-only






                                                share|improve this answer























                                                • 68?
                                                  – ASCII-only
                                                  Nov 14 at 9:31










                                                • @ASCII-only Thanks :)
                                                  – TFeld
                                                  Nov 14 at 9:34










                                                • functions are too long :(
                                                  – ASCII-only
                                                  Nov 14 at 9:46










                                                • well, recursive approaches at least
                                                  – ASCII-only
                                                  Nov 14 at 9:48










                                                • same with zip
                                                  – ASCII-only
                                                  Nov 14 at 9:50















                                                up vote
                                                5
                                                down vote














                                                Python 2, 84 83 81 70 68 bytes





                                                a=n=''
                                                for b in input():
                                                n+='!';n*=a<b;a=b
                                                if n:print'Excelsior'+n


                                                Try it online!



                                                -2 bytes, thanks to ASCII-only






                                                share|improve this answer























                                                • 68?
                                                  – ASCII-only
                                                  Nov 14 at 9:31










                                                • @ASCII-only Thanks :)
                                                  – TFeld
                                                  Nov 14 at 9:34










                                                • functions are too long :(
                                                  – ASCII-only
                                                  Nov 14 at 9:46










                                                • well, recursive approaches at least
                                                  – ASCII-only
                                                  Nov 14 at 9:48










                                                • same with zip
                                                  – ASCII-only
                                                  Nov 14 at 9:50













                                                up vote
                                                5
                                                down vote










                                                up vote
                                                5
                                                down vote










                                                Python 2, 84 83 81 70 68 bytes





                                                a=n=''
                                                for b in input():
                                                n+='!';n*=a<b;a=b
                                                if n:print'Excelsior'+n


                                                Try it online!



                                                -2 bytes, thanks to ASCII-only






                                                share|improve this answer















                                                Python 2, 84 83 81 70 68 bytes





                                                a=n=''
                                                for b in input():
                                                n+='!';n*=a<b;a=b
                                                if n:print'Excelsior'+n


                                                Try it online!



                                                -2 bytes, thanks to ASCII-only







                                                share|improve this answer














                                                share|improve this answer



                                                share|improve this answer








                                                edited Nov 14 at 9:34

























                                                answered Nov 14 at 7:55









                                                TFeld

                                                13.5k21139




                                                13.5k21139












                                                • 68?
                                                  – ASCII-only
                                                  Nov 14 at 9:31










                                                • @ASCII-only Thanks :)
                                                  – TFeld
                                                  Nov 14 at 9:34










                                                • functions are too long :(
                                                  – ASCII-only
                                                  Nov 14 at 9:46










                                                • well, recursive approaches at least
                                                  – ASCII-only
                                                  Nov 14 at 9:48










                                                • same with zip
                                                  – ASCII-only
                                                  Nov 14 at 9:50


















                                                • 68?
                                                  – ASCII-only
                                                  Nov 14 at 9:31










                                                • @ASCII-only Thanks :)
                                                  – TFeld
                                                  Nov 14 at 9:34










                                                • functions are too long :(
                                                  – ASCII-only
                                                  Nov 14 at 9:46










                                                • well, recursive approaches at least
                                                  – ASCII-only
                                                  Nov 14 at 9:48










                                                • same with zip
                                                  – ASCII-only
                                                  Nov 14 at 9:50
















                                                68?
                                                – ASCII-only
                                                Nov 14 at 9:31




                                                68?
                                                – ASCII-only
                                                Nov 14 at 9:31












                                                @ASCII-only Thanks :)
                                                – TFeld
                                                Nov 14 at 9:34




                                                @ASCII-only Thanks :)
                                                – TFeld
                                                Nov 14 at 9:34












                                                functions are too long :(
                                                – ASCII-only
                                                Nov 14 at 9:46




                                                functions are too long :(
                                                – ASCII-only
                                                Nov 14 at 9:46












                                                well, recursive approaches at least
                                                – ASCII-only
                                                Nov 14 at 9:48




                                                well, recursive approaches at least
                                                – ASCII-only
                                                Nov 14 at 9:48












                                                same with zip
                                                – ASCII-only
                                                Nov 14 at 9:50




                                                same with zip
                                                – ASCII-only
                                                Nov 14 at 9:50










                                                up vote
                                                5
                                                down vote














                                                05AB1E, 26 24 23 bytes



                                                ü‹γvyOE.•1Š¥èò²•™N'!׫,


                                                -2 bytes thanks to @Kroppeb.



                                                Try it online or verify all test cases.



                                                Explanation:





                                                ü                        # Loop over the (implicit) input as pairs
                                                ‹ # And check for each pair [a,b] if a<b is truthy
                                                # i.e. [1,2,1,3,4,1,5,7,20,25,3,17]
                                                # → [1,0,1,1,0,1,1,1,1,0,1]
                                                γ # Split it into chunks of equal elements
                                                # i.e. [1,0,1,1,0,1,1,1,1,0,1]
                                                # → [[1],[0],[1,1],[0],[1,1,1,1],[0],[1]]
                                                vy # Foreach `y` over them
                                                O # Take the sum of that inner list
                                                # i.e. [1,1,1,1] → 4
                                                # i.e. [0] → 0
                                                E # Inner loop `N` in the range [1, length]:
                                                .•1Š¥èò²• # Push string "excelsior"
                                                ™ # Titlecase it: "Excelsior"
                                                N'!׫ '# Append `N` amount of "!"
                                                # i.e. N=3 → "Excelsior!!!"
                                                , # Output with a trailing newline


                                                See this 05AB1E tip of mine (section How to compress strings not part of the dictionary?) to understand why .•1Š¥èò²• is "excelsior".






                                                share|improve this answer



















                                                • 2




                                                  I don't really know 05AB1E but can't you exchange the 0Kg with O?
                                                  – Kroppeb
                                                  2 days ago












                                                • @Kroppeb Ah, completely missed that, but yes, I indeed can. Thanks! :)
                                                  – Kevin Cruijssen
                                                  2 days ago















                                                up vote
                                                5
                                                down vote














                                                05AB1E, 26 24 23 bytes



                                                ü‹γvyOE.•1Š¥èò²•™N'!׫,


                                                -2 bytes thanks to @Kroppeb.



                                                Try it online or verify all test cases.



                                                Explanation:





                                                ü                        # Loop over the (implicit) input as pairs
                                                ‹ # And check for each pair [a,b] if a<b is truthy
                                                # i.e. [1,2,1,3,4,1,5,7,20,25,3,17]
                                                # → [1,0,1,1,0,1,1,1,1,0,1]
                                                γ # Split it into chunks of equal elements
                                                # i.e. [1,0,1,1,0,1,1,1,1,0,1]
                                                # → [[1],[0],[1,1],[0],[1,1,1,1],[0],[1]]
                                                vy # Foreach `y` over them
                                                O # Take the sum of that inner list
                                                # i.e. [1,1,1,1] → 4
                                                # i.e. [0] → 0
                                                E # Inner loop `N` in the range [1, length]:
                                                .•1Š¥èò²• # Push string "excelsior"
                                                ™ # Titlecase it: "Excelsior"
                                                N'!׫ '# Append `N` amount of "!"
                                                # i.e. N=3 → "Excelsior!!!"
                                                , # Output with a trailing newline


                                                See this 05AB1E tip of mine (section How to compress strings not part of the dictionary?) to understand why .•1Š¥èò²• is "excelsior".






                                                share|improve this answer



















                                                • 2




                                                  I don't really know 05AB1E but can't you exchange the 0Kg with O?
                                                  – Kroppeb
                                                  2 days ago












                                                • @Kroppeb Ah, completely missed that, but yes, I indeed can. Thanks! :)
                                                  – Kevin Cruijssen
                                                  2 days ago













                                                up vote
                                                5
                                                down vote










                                                up vote
                                                5
                                                down vote










                                                05AB1E, 26 24 23 bytes



                                                ü‹γvyOE.•1Š¥èò²•™N'!׫,


                                                -2 bytes thanks to @Kroppeb.



                                                Try it online or verify all test cases.



                                                Explanation:





                                                ü                        # Loop over the (implicit) input as pairs
                                                ‹ # And check for each pair [a,b] if a<b is truthy
                                                # i.e. [1,2,1,3,4,1,5,7,20,25,3,17]
                                                # → [1,0,1,1,0,1,1,1,1,0,1]
                                                γ # Split it into chunks of equal elements
                                                # i.e. [1,0,1,1,0,1,1,1,1,0,1]
                                                # → [[1],[0],[1,1],[0],[1,1,1,1],[0],[1]]
                                                vy # Foreach `y` over them
                                                O # Take the sum of that inner list
                                                # i.e. [1,1,1,1] → 4
                                                # i.e. [0] → 0
                                                E # Inner loop `N` in the range [1, length]:
                                                .•1Š¥èò²• # Push string "excelsior"
                                                ™ # Titlecase it: "Excelsior"
                                                N'!׫ '# Append `N` amount of "!"
                                                # i.e. N=3 → "Excelsior!!!"
                                                , # Output with a trailing newline


                                                See this 05AB1E tip of mine (section How to compress strings not part of the dictionary?) to understand why .•1Š¥èò²• is "excelsior".






                                                share|improve this answer















                                                05AB1E, 26 24 23 bytes



                                                ü‹γvyOE.•1Š¥èò²•™N'!׫,


                                                -2 bytes thanks to @Kroppeb.



                                                Try it online or verify all test cases.



                                                Explanation:





                                                ü                        # Loop over the (implicit) input as pairs
                                                ‹ # And check for each pair [a,b] if a<b is truthy
                                                # i.e. [1,2,1,3,4,1,5,7,20,25,3,17]
                                                # → [1,0,1,1,0,1,1,1,1,0,1]
                                                γ # Split it into chunks of equal elements
                                                # i.e. [1,0,1,1,0,1,1,1,1,0,1]
                                                # → [[1],[0],[1,1],[0],[1,1,1,1],[0],[1]]
                                                vy # Foreach `y` over them
                                                O # Take the sum of that inner list
                                                # i.e. [1,1,1,1] → 4
                                                # i.e. [0] → 0
                                                E # Inner loop `N` in the range [1, length]:
                                                .•1Š¥èò²• # Push string "excelsior"
                                                ™ # Titlecase it: "Excelsior"
                                                N'!׫ '# Append `N` amount of "!"
                                                # i.e. N=3 → "Excelsior!!!"
                                                , # Output with a trailing newline


                                                See this 05AB1E tip of mine (section How to compress strings not part of the dictionary?) to understand why .•1Š¥èò²• is "excelsior".







                                                share|improve this answer














                                                share|improve this answer



                                                share|improve this answer








                                                edited 2 days ago

























                                                answered Nov 14 at 8:49









                                                Kevin Cruijssen

                                                34k554181




                                                34k554181








                                                • 2




                                                  I don't really know 05AB1E but can't you exchange the 0Kg with O?
                                                  – Kroppeb
                                                  2 days ago












                                                • @Kroppeb Ah, completely missed that, but yes, I indeed can. Thanks! :)
                                                  – Kevin Cruijssen
                                                  2 days ago














                                                • 2




                                                  I don't really know 05AB1E but can't you exchange the 0Kg with O?
                                                  – Kroppeb
                                                  2 days ago












                                                • @Kroppeb Ah, completely missed that, but yes, I indeed can. Thanks! :)
                                                  – Kevin Cruijssen
                                                  2 days ago








                                                2




                                                2




                                                I don't really know 05AB1E but can't you exchange the 0Kg with O?
                                                – Kroppeb
                                                2 days ago






                                                I don't really know 05AB1E but can't you exchange the 0Kg with O?
                                                – Kroppeb
                                                2 days ago














                                                @Kroppeb Ah, completely missed that, but yes, I indeed can. Thanks! :)
                                                – Kevin Cruijssen
                                                2 days ago




                                                @Kroppeb Ah, completely missed that, but yes, I indeed can. Thanks! :)
                                                – Kevin Cruijssen
                                                2 days ago










                                                up vote
                                                5
                                                down vote














                                                Perl 6, 60 58 57 bytes



                                                -1 byte thanks to nwellnhof





                                                {"Excelsior"X~("!"Xx grep +*,[[&(-+^*×*)]] .skip Z>$_)}


                                                Try it online!



                                                Anonymous code block that returns a list of Excelsiors!






                                                share|improve this answer



























                                                  up vote
                                                  5
                                                  down vote














                                                  Perl 6, 60 58 57 bytes



                                                  -1 byte thanks to nwellnhof





                                                  {"Excelsior"X~("!"Xx grep +*,[[&(-+^*×*)]] .skip Z>$_)}


                                                  Try it online!



                                                  Anonymous code block that returns a list of Excelsiors!






                                                  share|improve this answer

























                                                    up vote
                                                    5
                                                    down vote










                                                    up vote
                                                    5
                                                    down vote










                                                    Perl 6, 60 58 57 bytes



                                                    -1 byte thanks to nwellnhof





                                                    {"Excelsior"X~("!"Xx grep +*,[[&(-+^*×*)]] .skip Z>$_)}


                                                    Try it online!



                                                    Anonymous code block that returns a list of Excelsiors!






                                                    share|improve this answer















                                                    Perl 6, 60 58 57 bytes



                                                    -1 byte thanks to nwellnhof





                                                    {"Excelsior"X~("!"Xx grep +*,[[&(-+^*×*)]] .skip Z>$_)}


                                                    Try it online!



                                                    Anonymous code block that returns a list of Excelsiors!







                                                    share|improve this answer














                                                    share|improve this answer



                                                    share|improve this answer








                                                    edited 2 days ago

























                                                    answered 2 days ago









                                                    Jo King

                                                    19.1k242102




                                                    19.1k242102






















                                                        up vote
                                                        4
                                                        down vote














                                                        Java-8 118 113 Bytes



                                                        n->{String e="";for(int i=0;i<n.length-1;)System.out.print(""==(n[i+1]>n[i++]?e+="!":(e=""))?e:"Excelsior"+e+"n");}


                                                        Easy to read :



                                                        private static void lee(int num) {
                                                        String exclamation = "";
                                                        for (int i = 0; i < num.length - 1;) {
                                                        exclamation = num[i + 1] > num[i++] ? exclamation += "!" : "";
                                                        System.out.print("".equals(exclamation) ? "" : "Excelsior" + exclamation + "n");
                                                        }
                                                        }





                                                        share|improve this answer



















                                                        • 2




                                                          Here some golfs to save 10 bytes: n->{var e="";for(int i=0;i<n.length-1;System.out.print(""==e?e:"Excelsior"+e+"n"))e=n[i++]<n[i]?e+="!":"";}. Try it online (108 bytes). (Java 10+)
                                                          – Kevin Cruijssen
                                                          2 days ago










                                                        • @KevinCruijssen Thanks!
                                                          – coder-croc
                                                          2 days ago






                                                        • 2




                                                          n->{for(int e=0,i=0;i<n.length-1;)if(n[i++]<n[i])System.out.println("Excelsior"+"!".repeat(e++));else e=0;} (107 bytes)
                                                          – Olivier Grégoire
                                                          2 days ago










                                                        • Fixing my issue: ++e instead of e++ so that there is at least one ! to be printed.
                                                          – Olivier Grégoire
                                                          yesterday















                                                        up vote
                                                        4
                                                        down vote














                                                        Java-8 118 113 Bytes



                                                        n->{String e="";for(int i=0;i<n.length-1;)System.out.print(""==(n[i+1]>n[i++]?e+="!":(e=""))?e:"Excelsior"+e+"n");}


                                                        Easy to read :



                                                        private static void lee(int num) {
                                                        String exclamation = "";
                                                        for (int i = 0; i < num.length - 1;) {
                                                        exclamation = num[i + 1] > num[i++] ? exclamation += "!" : "";
                                                        System.out.print("".equals(exclamation) ? "" : "Excelsior" + exclamation + "n");
                                                        }
                                                        }





                                                        share|improve this answer



















                                                        • 2




                                                          Here some golfs to save 10 bytes: n->{var e="";for(int i=0;i<n.length-1;System.out.print(""==e?e:"Excelsior"+e+"n"))e=n[i++]<n[i]?e+="!":"";}. Try it online (108 bytes). (Java 10+)
                                                          – Kevin Cruijssen
                                                          2 days ago










                                                        • @KevinCruijssen Thanks!
                                                          – coder-croc
                                                          2 days ago






                                                        • 2




                                                          n->{for(int e=0,i=0;i<n.length-1;)if(n[i++]<n[i])System.out.println("Excelsior"+"!".repeat(e++));else e=0;} (107 bytes)
                                                          – Olivier Grégoire
                                                          2 days ago










                                                        • Fixing my issue: ++e instead of e++ so that there is at least one ! to be printed.
                                                          – Olivier Grégoire
                                                          yesterday













                                                        up vote
                                                        4
                                                        down vote










                                                        up vote
                                                        4
                                                        down vote










                                                        Java-8 118 113 Bytes



                                                        n->{String e="";for(int i=0;i<n.length-1;)System.out.print(""==(n[i+1]>n[i++]?e+="!":(e=""))?e:"Excelsior"+e+"n");}


                                                        Easy to read :



                                                        private static void lee(int num) {
                                                        String exclamation = "";
                                                        for (int i = 0; i < num.length - 1;) {
                                                        exclamation = num[i + 1] > num[i++] ? exclamation += "!" : "";
                                                        System.out.print("".equals(exclamation) ? "" : "Excelsior" + exclamation + "n");
                                                        }
                                                        }





                                                        share|improve this answer















                                                        Java-8 118 113 Bytes



                                                        n->{String e="";for(int i=0;i<n.length-1;)System.out.print(""==(n[i+1]>n[i++]?e+="!":(e=""))?e:"Excelsior"+e+"n");}


                                                        Easy to read :



                                                        private static void lee(int num) {
                                                        String exclamation = "";
                                                        for (int i = 0; i < num.length - 1;) {
                                                        exclamation = num[i + 1] > num[i++] ? exclamation += "!" : "";
                                                        System.out.print("".equals(exclamation) ? "" : "Excelsior" + exclamation + "n");
                                                        }
                                                        }






                                                        share|improve this answer














                                                        share|improve this answer



                                                        share|improve this answer








                                                        edited 2 days ago

























                                                        answered Nov 14 at 9:57









                                                        coder-croc

                                                        32738




                                                        32738








                                                        • 2




                                                          Here some golfs to save 10 bytes: n->{var e="";for(int i=0;i<n.length-1;System.out.print(""==e?e:"Excelsior"+e+"n"))e=n[i++]<n[i]?e+="!":"";}. Try it online (108 bytes). (Java 10+)
                                                          – Kevin Cruijssen
                                                          2 days ago










                                                        • @KevinCruijssen Thanks!
                                                          – coder-croc
                                                          2 days ago






                                                        • 2




                                                          n->{for(int e=0,i=0;i<n.length-1;)if(n[i++]<n[i])System.out.println("Excelsior"+"!".repeat(e++));else e=0;} (107 bytes)
                                                          – Olivier Grégoire
                                                          2 days ago










                                                        • Fixing my issue: ++e instead of e++ so that there is at least one ! to be printed.
                                                          – Olivier Grégoire
                                                          yesterday














                                                        • 2




                                                          Here some golfs to save 10 bytes: n->{var e="";for(int i=0;i<n.length-1;System.out.print(""==e?e:"Excelsior"+e+"n"))e=n[i++]<n[i]?e+="!":"";}. Try it online (108 bytes). (Java 10+)
                                                          – Kevin Cruijssen
                                                          2 days ago










                                                        • @KevinCruijssen Thanks!
                                                          – coder-croc
                                                          2 days ago






                                                        • 2




                                                          n->{for(int e=0,i=0;i<n.length-1;)if(n[i++]<n[i])System.out.println("Excelsior"+"!".repeat(e++));else e=0;} (107 bytes)
                                                          – Olivier Grégoire
                                                          2 days ago










                                                        • Fixing my issue: ++e instead of e++ so that there is at least one ! to be printed.
                                                          – Olivier Grégoire
                                                          yesterday








                                                        2




                                                        2




                                                        Here some golfs to save 10 bytes: n->{var e="";for(int i=0;i<n.length-1;System.out.print(""==e?e:"Excelsior"+e+"n"))e=n[i++]<n[i]?e+="!":"";}. Try it online (108 bytes). (Java 10+)
                                                        – Kevin Cruijssen
                                                        2 days ago




                                                        Here some golfs to save 10 bytes: n->{var e="";for(int i=0;i<n.length-1;System.out.print(""==e?e:"Excelsior"+e+"n"))e=n[i++]<n[i]?e+="!":"";}. Try it online (108 bytes). (Java 10+)
                                                        – Kevin Cruijssen
                                                        2 days ago












                                                        @KevinCruijssen Thanks!
                                                        – coder-croc
                                                        2 days ago




                                                        @KevinCruijssen Thanks!
                                                        – coder-croc
                                                        2 days ago




                                                        2




                                                        2




                                                        n->{for(int e=0,i=0;i<n.length-1;)if(n[i++]<n[i])System.out.println("Excelsior"+"!".repeat(e++));else e=0;} (107 bytes)
                                                        – Olivier Grégoire
                                                        2 days ago




                                                        n->{for(int e=0,i=0;i<n.length-1;)if(n[i++]<n[i])System.out.println("Excelsior"+"!".repeat(e++));else e=0;} (107 bytes)
                                                        – Olivier Grégoire
                                                        2 days ago












                                                        Fixing my issue: ++e instead of e++ so that there is at least one ! to be printed.
                                                        – Olivier Grégoire
                                                        yesterday




                                                        Fixing my issue: ++e instead of e++ so that there is at least one ! to be printed.
                                                        – Olivier Grégoire
                                                        yesterday










                                                        up vote
                                                        4
                                                        down vote














                                                        R, 86 bytes



                                                        Half of this answer is @Giuseppe's. RIP Stan Lee.





                                                        function(a)for(i in diff(a))"if"(i>0,cat("Excelsior",rep("!",F<-F+1),"
                                                        ",sep=""),F<-0)


                                                        Try it online!






                                                        share|improve this answer

























                                                          up vote
                                                          4
                                                          down vote














                                                          R, 86 bytes



                                                          Half of this answer is @Giuseppe's. RIP Stan Lee.





                                                          function(a)for(i in diff(a))"if"(i>0,cat("Excelsior",rep("!",F<-F+1),"
                                                          ",sep=""),F<-0)


                                                          Try it online!






                                                          share|improve this answer























                                                            up vote
                                                            4
                                                            down vote










                                                            up vote
                                                            4
                                                            down vote










                                                            R, 86 bytes



                                                            Half of this answer is @Giuseppe's. RIP Stan Lee.





                                                            function(a)for(i in diff(a))"if"(i>0,cat("Excelsior",rep("!",F<-F+1),"
                                                            ",sep=""),F<-0)


                                                            Try it online!






                                                            share|improve this answer













                                                            R, 86 bytes



                                                            Half of this answer is @Giuseppe's. RIP Stan Lee.





                                                            function(a)for(i in diff(a))"if"(i>0,cat("Excelsior",rep("!",F<-F+1),"
                                                            ",sep=""),F<-0)


                                                            Try it online!







                                                            share|improve this answer












                                                            share|improve this answer



                                                            share|improve this answer










                                                            answered 2 days ago









                                                            J.Doe

                                                            1,951112




                                                            1,951112






















                                                                up vote
                                                                4
                                                                down vote














                                                                05AB1E, 20 19 bytes



                                                                ü‹0¡€ƶ˜ε'!×”¸Îsiorÿ


                                                                Try it online!



                                                                Explanation



                                                                ü‹                    # pair-wise comparison, less-than
                                                                0¡ # split at zeroes
                                                                €ƶ # lift each, multiplying by its 1-based index
                                                                ˜ # flatten
                                                                ε # apply to each
                                                                '!× # repeat "!" that many times
                                                                ÿ # and interpolate it at the end of
                                                                ”¸Îsior # the compressed word "Excel" followed by the string "sior"





                                                                share|improve this answer



























                                                                  up vote
                                                                  4
                                                                  down vote














                                                                  05AB1E, 20 19 bytes



                                                                  ü‹0¡€ƶ˜ε'!×”¸Îsiorÿ


                                                                  Try it online!



                                                                  Explanation



                                                                  ü‹                    # pair-wise comparison, less-than
                                                                  0¡ # split at zeroes
                                                                  €ƶ # lift each, multiplying by its 1-based index
                                                                  ˜ # flatten
                                                                  ε # apply to each
                                                                  '!× # repeat "!" that many times
                                                                  ÿ # and interpolate it at the end of
                                                                  ”¸Îsior # the compressed word "Excel" followed by the string "sior"





                                                                  share|improve this answer

























                                                                    up vote
                                                                    4
                                                                    down vote










                                                                    up vote
                                                                    4
                                                                    down vote










                                                                    05AB1E, 20 19 bytes



                                                                    ü‹0¡€ƶ˜ε'!×”¸Îsiorÿ


                                                                    Try it online!



                                                                    Explanation



                                                                    ü‹                    # pair-wise comparison, less-than
                                                                    0¡ # split at zeroes
                                                                    €ƶ # lift each, multiplying by its 1-based index
                                                                    ˜ # flatten
                                                                    ε # apply to each
                                                                    '!× # repeat "!" that many times
                                                                    ÿ # and interpolate it at the end of
                                                                    ”¸Îsior # the compressed word "Excel" followed by the string "sior"





                                                                    share|improve this answer















                                                                    05AB1E, 20 19 bytes



                                                                    ü‹0¡€ƶ˜ε'!×”¸Îsiorÿ


                                                                    Try it online!



                                                                    Explanation



                                                                    ü‹                    # pair-wise comparison, less-than
                                                                    0¡ # split at zeroes
                                                                    €ƶ # lift each, multiplying by its 1-based index
                                                                    ˜ # flatten
                                                                    ε # apply to each
                                                                    '!× # repeat "!" that many times
                                                                    ÿ # and interpolate it at the end of
                                                                    ”¸Îsior # the compressed word "Excel" followed by the string "sior"






                                                                    share|improve this answer














                                                                    share|improve this answer



                                                                    share|improve this answer








                                                                    edited 2 days ago

























                                                                    answered 2 days ago









                                                                    Emigna

                                                                    44.8k432136




                                                                    44.8k432136






















                                                                        up vote
                                                                        4
                                                                        down vote













                                                                        C (gcc/clang), 106 99 97 bytes





                                                                        f(a,n)int*a;{int r=0,s[n];for(memset(s,33,n);n-->1;)r*=*a<*++a&&printf("Excelsior%.*sn",++r,s);}


                                                                        Thanks to gastropner for golfing 2 bytes.



                                                                        Try it online here.



                                                                        Ungolfed:



                                                                        f(a, n) // function taking a pointer to the first integer and the length of the array
                                                                        int *a; { // a is of type pointer to int, n is of type int

                                                                        int r = 0, // length of the current run
                                                                        i = 0, // loop variable
                                                                        s[n]; // buffer for exclamation marks; we will never need more than n-1 of those (we are declaring an array of int, but really we will treat it as an array of char)

                                                                        for(memset(s, 33, n); // fill the buffer with n exclamation marks (ASCII code 33)
                                                                        n -- > 1; ) // loop over the array

                                                                        r *= *a < *(++ a) // if the current element is less than the next:
                                                                        && printf("Excelsior%.*sn", // print (on their own line) "Excelsior", followed by ...
                                                                        ++ r, // ... r (incremented) of the ...
                                                                        s) // ... n exclamation marks in the buffer s
                                                                        ; // else r is reset to 0

                                                                        }





                                                                        share|improve this answer























                                                                        • I started making a solution, but ended up so close to yours that posting mine as a separate answer felt a bit silly. Still, the few differences there are can save you a few bytes.
                                                                          – gastropner
                                                                          yesterday










                                                                        • @gastropner Thanks for sharing your version. I have incorporated your improvements and golfed it further to 99 bytes. If only we didn't need to handle the empty array – otherwise it would be 97 bytes, using your style of loop.
                                                                          – O.O.Balance
                                                                          20 hours ago















                                                                        up vote
                                                                        4
                                                                        down vote













                                                                        C (gcc/clang), 106 99 97 bytes





                                                                        f(a,n)int*a;{int r=0,s[n];for(memset(s,33,n);n-->1;)r*=*a<*++a&&printf("Excelsior%.*sn",++r,s);}


                                                                        Thanks to gastropner for golfing 2 bytes.



                                                                        Try it online here.



                                                                        Ungolfed:



                                                                        f(a, n) // function taking a pointer to the first integer and the length of the array
                                                                        int *a; { // a is of type pointer to int, n is of type int

                                                                        int r = 0, // length of the current run
                                                                        i = 0, // loop variable
                                                                        s[n]; // buffer for exclamation marks; we will never need more than n-1 of those (we are declaring an array of int, but really we will treat it as an array of char)

                                                                        for(memset(s, 33, n); // fill the buffer with n exclamation marks (ASCII code 33)
                                                                        n -- > 1; ) // loop over the array

                                                                        r *= *a < *(++ a) // if the current element is less than the next:
                                                                        && printf("Excelsior%.*sn", // print (on their own line) "Excelsior", followed by ...
                                                                        ++ r, // ... r (incremented) of the ...
                                                                        s) // ... n exclamation marks in the buffer s
                                                                        ; // else r is reset to 0

                                                                        }





                                                                        share|improve this answer























                                                                        • I started making a solution, but ended up so close to yours that posting mine as a separate answer felt a bit silly. Still, the few differences there are can save you a few bytes.
                                                                          – gastropner
                                                                          yesterday










                                                                        • @gastropner Thanks for sharing your version. I have incorporated your improvements and golfed it further to 99 bytes. If only we didn't need to handle the empty array – otherwise it would be 97 bytes, using your style of loop.
                                                                          – O.O.Balance
                                                                          20 hours ago













                                                                        up vote
                                                                        4
                                                                        down vote










                                                                        up vote
                                                                        4
                                                                        down vote









                                                                        C (gcc/clang), 106 99 97 bytes





                                                                        f(a,n)int*a;{int r=0,s[n];for(memset(s,33,n);n-->1;)r*=*a<*++a&&printf("Excelsior%.*sn",++r,s);}


                                                                        Thanks to gastropner for golfing 2 bytes.



                                                                        Try it online here.



                                                                        Ungolfed:



                                                                        f(a, n) // function taking a pointer to the first integer and the length of the array
                                                                        int *a; { // a is of type pointer to int, n is of type int

                                                                        int r = 0, // length of the current run
                                                                        i = 0, // loop variable
                                                                        s[n]; // buffer for exclamation marks; we will never need more than n-1 of those (we are declaring an array of int, but really we will treat it as an array of char)

                                                                        for(memset(s, 33, n); // fill the buffer with n exclamation marks (ASCII code 33)
                                                                        n -- > 1; ) // loop over the array

                                                                        r *= *a < *(++ a) // if the current element is less than the next:
                                                                        && printf("Excelsior%.*sn", // print (on their own line) "Excelsior", followed by ...
                                                                        ++ r, // ... r (incremented) of the ...
                                                                        s) // ... n exclamation marks in the buffer s
                                                                        ; // else r is reset to 0

                                                                        }





                                                                        share|improve this answer














                                                                        C (gcc/clang), 106 99 97 bytes





                                                                        f(a,n)int*a;{int r=0,s[n];for(memset(s,33,n);n-->1;)r*=*a<*++a&&printf("Excelsior%.*sn",++r,s);}


                                                                        Thanks to gastropner for golfing 2 bytes.



                                                                        Try it online here.



                                                                        Ungolfed:



                                                                        f(a, n) // function taking a pointer to the first integer and the length of the array
                                                                        int *a; { // a is of type pointer to int, n is of type int

                                                                        int r = 0, // length of the current run
                                                                        i = 0, // loop variable
                                                                        s[n]; // buffer for exclamation marks; we will never need more than n-1 of those (we are declaring an array of int, but really we will treat it as an array of char)

                                                                        for(memset(s, 33, n); // fill the buffer with n exclamation marks (ASCII code 33)
                                                                        n -- > 1; ) // loop over the array

                                                                        r *= *a < *(++ a) // if the current element is less than the next:
                                                                        && printf("Excelsior%.*sn", // print (on their own line) "Excelsior", followed by ...
                                                                        ++ r, // ... r (incremented) of the ...
                                                                        s) // ... n exclamation marks in the buffer s
                                                                        ; // else r is reset to 0

                                                                        }






                                                                        share|improve this answer














                                                                        share|improve this answer



                                                                        share|improve this answer








                                                                        edited 18 hours ago

























                                                                        answered 2 days ago









                                                                        O.O.Balance

                                                                        1,2401318




                                                                        1,2401318












                                                                        • I started making a solution, but ended up so close to yours that posting mine as a separate answer felt a bit silly. Still, the few differences there are can save you a few bytes.
                                                                          – gastropner
                                                                          yesterday










                                                                        • @gastropner Thanks for sharing your version. I have incorporated your improvements and golfed it further to 99 bytes. If only we didn't need to handle the empty array – otherwise it would be 97 bytes, using your style of loop.
                                                                          – O.O.Balance
                                                                          20 hours ago


















                                                                        • I started making a solution, but ended up so close to yours that posting mine as a separate answer felt a bit silly. Still, the few differences there are can save you a few bytes.
                                                                          – gastropner
                                                                          yesterday










                                                                        • @gastropner Thanks for sharing your version. I have incorporated your improvements and golfed it further to 99 bytes. If only we didn't need to handle the empty array – otherwise it would be 97 bytes, using your style of loop.
                                                                          – O.O.Balance
                                                                          20 hours ago
















                                                                        I started making a solution, but ended up so close to yours that posting mine as a separate answer felt a bit silly. Still, the few differences there are can save you a few bytes.
                                                                        – gastropner
                                                                        yesterday




                                                                        I started making a solution, but ended up so close to yours that posting mine as a separate answer felt a bit silly. Still, the few differences there are can save you a few bytes.
                                                                        – gastropner
                                                                        yesterday












                                                                        @gastropner Thanks for sharing your version. I have incorporated your improvements and golfed it further to 99 bytes. If only we didn't need to handle the empty array – otherwise it would be 97 bytes, using your style of loop.
                                                                        – O.O.Balance
                                                                        20 hours ago




                                                                        @gastropner Thanks for sharing your version. I have incorporated your improvements and golfed it further to 99 bytes. If only we didn't need to handle the empty array – otherwise it would be 97 bytes, using your style of loop.
                                                                        – O.O.Balance
                                                                        20 hours ago










                                                                        up vote
                                                                        4
                                                                        down vote













                                                                        Japt -R, 25 22 bytes



                                                                        ò¨ ËÅ£`Ex­lÐâ`ú'!Y+A
                                                                        c


                                                                        Try it



                                                                        3 bytes saved thanks to Kamil



                                                                        ò¨                      :Partition at items that are greater than or equal to the previous item
                                                                        Ë :Map
                                                                        Å : Slice off the first element
                                                                        £ : Map each element at 0-based index Y
                                                                        `Ex­lÐâ` : Compressed string "Excelsior"
                                                                        ú'! : Right pad with exclamation marks
                                                                        Y+A : To length Y+10
                                                                        c :Flatten
                                                                        :Implicitly join with newlines & output





                                                                        share|improve this answer























                                                                        • Another 25 bytes
                                                                          – Luis felipe De jesus Munoz
                                                                          2 days ago










                                                                        • The -R flag isn't actually necessary, the challenge says you can output an array of strings.
                                                                          – Kamil Drakari
                                                                          2 days ago










                                                                        • Nice one, thanks, @KamilDrakari. I tried a solution using slice on my first pass but dismissed it when it worked out too long. Coming back to it now, with your prompting, I guess I should have stuck with it 'cause I got it down to 22 too.
                                                                          – Shaggy
                                                                          17 hours ago















                                                                        up vote
                                                                        4
                                                                        down vote













                                                                        Japt -R, 25 22 bytes



                                                                        ò¨ ËÅ£`Ex­lÐâ`ú'!Y+A
                                                                        c


                                                                        Try it



                                                                        3 bytes saved thanks to Kamil



                                                                        ò¨                      :Partition at items that are greater than or equal to the previous item
                                                                        Ë :Map
                                                                        Å : Slice off the first element
                                                                        £ : Map each element at 0-based index Y
                                                                        `Ex­lÐâ` : Compressed string "Excelsior"
                                                                        ú'! : Right pad with exclamation marks
                                                                        Y+A : To length Y+10
                                                                        c :Flatten
                                                                        :Implicitly join with newlines & output





                                                                        share|improve this answer























                                                                        • Another 25 bytes
                                                                          – Luis felipe De jesus Munoz
                                                                          2 days ago










                                                                        • The -R flag isn't actually necessary, the challenge says you can output an array of strings.
                                                                          – Kamil Drakari
                                                                          2 days ago










                                                                        • Nice one, thanks, @KamilDrakari. I tried a solution using slice on my first pass but dismissed it when it worked out too long. Coming back to it now, with your prompting, I guess I should have stuck with it 'cause I got it down to 22 too.
                                                                          – Shaggy
                                                                          17 hours ago













                                                                        up vote
                                                                        4
                                                                        down vote










                                                                        up vote
                                                                        4
                                                                        down vote









                                                                        Japt -R, 25 22 bytes



                                                                        ò¨ ËÅ£`Ex­lÐâ`ú'!Y+A
                                                                        c


                                                                        Try it



                                                                        3 bytes saved thanks to Kamil



                                                                        ò¨                      :Partition at items that are greater than or equal to the previous item
                                                                        Ë :Map
                                                                        Å : Slice off the first element
                                                                        £ : Map each element at 0-based index Y
                                                                        `Ex­lÐâ` : Compressed string "Excelsior"
                                                                        ú'! : Right pad with exclamation marks
                                                                        Y+A : To length Y+10
                                                                        c :Flatten
                                                                        :Implicitly join with newlines & output





                                                                        share|improve this answer














                                                                        Japt -R, 25 22 bytes



                                                                        ò¨ ËÅ£`Ex­lÐâ`ú'!Y+A
                                                                        c


                                                                        Try it



                                                                        3 bytes saved thanks to Kamil



                                                                        ò¨                      :Partition at items that are greater than or equal to the previous item
                                                                        Ë :Map
                                                                        Å : Slice off the first element
                                                                        £ : Map each element at 0-based index Y
                                                                        `Ex­lÐâ` : Compressed string "Excelsior"
                                                                        ú'! : Right pad with exclamation marks
                                                                        Y+A : To length Y+10
                                                                        c :Flatten
                                                                        :Implicitly join with newlines & output






                                                                        share|improve this answer














                                                                        share|improve this answer



                                                                        share|improve this answer








                                                                        edited 17 hours ago

























                                                                        answered 2 days ago









                                                                        Shaggy

                                                                        18.1k21663




                                                                        18.1k21663












                                                                        • Another 25 bytes
                                                                          – Luis felipe De jesus Munoz
                                                                          2 days ago










                                                                        • The -R flag isn't actually necessary, the challenge says you can output an array of strings.
                                                                          – Kamil Drakari
                                                                          2 days ago










                                                                        • Nice one, thanks, @KamilDrakari. I tried a solution using slice on my first pass but dismissed it when it worked out too long. Coming back to it now, with your prompting, I guess I should have stuck with it 'cause I got it down to 22 too.
                                                                          – Shaggy
                                                                          17 hours ago


















                                                                        • Another 25 bytes
                                                                          – Luis felipe De jesus Munoz
                                                                          2 days ago










                                                                        • The -R flag isn't actually necessary, the challenge says you can output an array of strings.
                                                                          – Kamil Drakari
                                                                          2 days ago










                                                                        • Nice one, thanks, @KamilDrakari. I tried a solution using slice on my first pass but dismissed it when it worked out too long. Coming back to it now, with your prompting, I guess I should have stuck with it 'cause I got it down to 22 too.
                                                                          – Shaggy
                                                                          17 hours ago
















                                                                        Another 25 bytes
                                                                        – Luis felipe De jesus Munoz
                                                                        2 days ago




                                                                        Another 25 bytes
                                                                        – Luis felipe De jesus Munoz
                                                                        2 days ago












                                                                        The -R flag isn't actually necessary, the challenge says you can output an array of strings.
                                                                        – Kamil Drakari
                                                                        2 days ago




                                                                        The -R flag isn't actually necessary, the challenge says you can output an array of strings.
                                                                        – Kamil Drakari
                                                                        2 days ago












                                                                        Nice one, thanks, @KamilDrakari. I tried a solution using slice on my first pass but dismissed it when it worked out too long. Coming back to it now, with your prompting, I guess I should have stuck with it 'cause I got it down to 22 too.
                                                                        – Shaggy
                                                                        17 hours ago




                                                                        Nice one, thanks, @KamilDrakari. I tried a solution using slice on my first pass but dismissed it when it worked out too long. Coming back to it now, with your prompting, I guess I should have stuck with it 'cause I got it down to 22 too.
                                                                        – Shaggy
                                                                        17 hours ago










                                                                        up vote
                                                                        3
                                                                        down vote













                                                                        Common Lisp, 111 bytes



                                                                        (setq i 0)(loop for(a b)on(read)do(incf i(if(and b(> b a))1(- i)))(format(> i 0)"Excelsior~v@{~a~:*~}~%"i #!))


                                                                        Try it online!






                                                                        share|improve this answer

























                                                                          up vote
                                                                          3
                                                                          down vote













                                                                          Common Lisp, 111 bytes



                                                                          (setq i 0)(loop for(a b)on(read)do(incf i(if(and b(> b a))1(- i)))(format(> i 0)"Excelsior~v@{~a~:*~}~%"i #!))


                                                                          Try it online!






                                                                          share|improve this answer























                                                                            up vote
                                                                            3
                                                                            down vote










                                                                            up vote
                                                                            3
                                                                            down vote









                                                                            Common Lisp, 111 bytes



                                                                            (setq i 0)(loop for(a b)on(read)do(incf i(if(and b(> b a))1(- i)))(format(> i 0)"Excelsior~v@{~a~:*~}~%"i #!))


                                                                            Try it online!






                                                                            share|improve this answer












                                                                            Common Lisp, 111 bytes



                                                                            (setq i 0)(loop for(a b)on(read)do(incf i(if(and b(> b a))1(- i)))(format(> i 0)"Excelsior~v@{~a~:*~}~%"i #!))


                                                                            Try it online!







                                                                            share|improve this answer












                                                                            share|improve this answer



                                                                            share|improve this answer










                                                                            answered 2 days ago









                                                                            Renzo

                                                                            1,540516




                                                                            1,540516






















                                                                                up vote
                                                                                3
                                                                                down vote













                                                                                Java 8, 106 bytes





                                                                                n->{String s="",z=s;for(int i=0;i<n.length-1;)z+=n[i++]<n[i]?"Excelsior"+(s+="!")+"n":(s="")+s;return z;}


                                                                                Try it online!



                                                                                (those reassignments of s...yikes)






                                                                                share|improve this answer





















                                                                                • You can golf two more bytes by replacing (s="")+s => (s="")
                                                                                  – O.O.Balance
                                                                                  yesterday






                                                                                • 1




                                                                                  n->{String s="",z=s;for(int i=0;i<n.length-1;)z+=n[i++]>=n[i]?s="":"Excelsior"+(s+="!")+"n";return z;} (103 bytes) Move the s="" to spare bytes.
                                                                                  – Olivier Grégoire
                                                                                  yesterday















                                                                                up vote
                                                                                3
                                                                                down vote













                                                                                Java 8, 106 bytes





                                                                                n->{String s="",z=s;for(int i=0;i<n.length-1;)z+=n[i++]<n[i]?"Excelsior"+(s+="!")+"n":(s="")+s;return z;}


                                                                                Try it online!



                                                                                (those reassignments of s...yikes)






                                                                                share|improve this answer





















                                                                                • You can golf two more bytes by replacing (s="")+s => (s="")
                                                                                  – O.O.Balance
                                                                                  yesterday






                                                                                • 1




                                                                                  n->{String s="",z=s;for(int i=0;i<n.length-1;)z+=n[i++]>=n[i]?s="":"Excelsior"+(s+="!")+"n";return z;} (103 bytes) Move the s="" to spare bytes.
                                                                                  – Olivier Grégoire
                                                                                  yesterday













                                                                                up vote
                                                                                3
                                                                                down vote










                                                                                up vote
                                                                                3
                                                                                down vote









                                                                                Java 8, 106 bytes





                                                                                n->{String s="",z=s;for(int i=0;i<n.length-1;)z+=n[i++]<n[i]?"Excelsior"+(s+="!")+"n":(s="")+s;return z;}


                                                                                Try it online!



                                                                                (those reassignments of s...yikes)






                                                                                share|improve this answer












                                                                                Java 8, 106 bytes





                                                                                n->{String s="",z=s;for(int i=0;i<n.length-1;)z+=n[i++]<n[i]?"Excelsior"+(s+="!")+"n":(s="")+s;return z;}


                                                                                Try it online!



                                                                                (those reassignments of s...yikes)







                                                                                share|improve this answer












                                                                                share|improve this answer



                                                                                share|improve this answer










                                                                                answered 2 days ago









                                                                                NotBaal

                                                                                1216




                                                                                1216












                                                                                • You can golf two more bytes by replacing (s="")+s => (s="")
                                                                                  – O.O.Balance
                                                                                  yesterday






                                                                                • 1




                                                                                  n->{String s="",z=s;for(int i=0;i<n.length-1;)z+=n[i++]>=n[i]?s="":"Excelsior"+(s+="!")+"n";return z;} (103 bytes) Move the s="" to spare bytes.
                                                                                  – Olivier Grégoire
                                                                                  yesterday


















                                                                                • You can golf two more bytes by replacing (s="")+s => (s="")
                                                                                  – O.O.Balance
                                                                                  yesterday






                                                                                • 1




                                                                                  n->{String s="",z=s;for(int i=0;i<n.length-1;)z+=n[i++]>=n[i]?s="":"Excelsior"+(s+="!")+"n";return z;} (103 bytes) Move the s="" to spare bytes.
                                                                                  – Olivier Grégoire
                                                                                  yesterday
















                                                                                You can golf two more bytes by replacing (s="")+s => (s="")
                                                                                – O.O.Balance
                                                                                yesterday




                                                                                You can golf two more bytes by replacing (s="")+s => (s="")
                                                                                – O.O.Balance
                                                                                yesterday




                                                                                1




                                                                                1




                                                                                n->{String s="",z=s;for(int i=0;i<n.length-1;)z+=n[i++]>=n[i]?s="":"Excelsior"+(s+="!")+"n";return z;} (103 bytes) Move the s="" to spare bytes.
                                                                                – Olivier Grégoire
                                                                                yesterday




                                                                                n->{String s="",z=s;for(int i=0;i<n.length-1;)z+=n[i++]>=n[i]?s="":"Excelsior"+(s+="!")+"n";return z;} (103 bytes) Move the s="" to spare bytes.
                                                                                – Olivier Grégoire
                                                                                yesterday










                                                                                up vote
                                                                                3
                                                                                down vote














                                                                                Stax, 17 bytes



                                                                                Θx7├╖&σ '@7g┼┘Ñ«═


                                                                                Run and debug it






                                                                                share|improve this answer

























                                                                                  up vote
                                                                                  3
                                                                                  down vote














                                                                                  Stax, 17 bytes



                                                                                  Θx7├╖&σ '@7g┼┘Ñ«═


                                                                                  Run and debug it






                                                                                  share|improve this answer























                                                                                    up vote
                                                                                    3
                                                                                    down vote










                                                                                    up vote
                                                                                    3
                                                                                    down vote










                                                                                    Stax, 17 bytes



                                                                                    Θx7├╖&σ '@7g┼┘Ñ«═


                                                                                    Run and debug it






                                                                                    share|improve this answer













                                                                                    Stax, 17 bytes



                                                                                    Θx7├╖&σ '@7g┼┘Ñ«═


                                                                                    Run and debug it







                                                                                    share|improve this answer












                                                                                    share|improve this answer



                                                                                    share|improve this answer










                                                                                    answered 2 days ago









                                                                                    recursive

                                                                                    4,9641221




                                                                                    4,9641221






















                                                                                        up vote
                                                                                        3
                                                                                        down vote














                                                                                        R, 111 bytes





                                                                                        function(a,r=rle(sign(diff(a))),v=r$l[r$v>0])write(paste0(rep("Excelsior",sum(v)),strrep("!",sequence(v))),1,1)


                                                                                        Try it online!



                                                                                        A far better R tribute can be found here -- I was too fixated on sequence and rle.






                                                                                        share|improve this answer























                                                                                        • This doesn't give some blank lines, but 86 bytes?
                                                                                          – J.Doe
                                                                                          2 days ago






                                                                                        • 2




                                                                                          @J.Doe dang, that's way better. I'd post that myself if I were you.
                                                                                          – Giuseppe
                                                                                          2 days ago















                                                                                        up vote
                                                                                        3
                                                                                        down vote














                                                                                        R, 111 bytes





                                                                                        function(a,r=rle(sign(diff(a))),v=r$l[r$v>0])write(paste0(rep("Excelsior",sum(v)),strrep("!",sequence(v))),1,1)


                                                                                        Try it online!



                                                                                        A far better R tribute can be found here -- I was too fixated on sequence and rle.






                                                                                        share|improve this answer























                                                                                        • This doesn't give some blank lines, but 86 bytes?
                                                                                          – J.Doe
                                                                                          2 days ago






                                                                                        • 2




                                                                                          @J.Doe dang, that's way better. I'd post that myself if I were you.
                                                                                          – Giuseppe
                                                                                          2 days ago













                                                                                        up vote
                                                                                        3
                                                                                        down vote










                                                                                        up vote
                                                                                        3
                                                                                        down vote










                                                                                        R, 111 bytes





                                                                                        function(a,r=rle(sign(diff(a))),v=r$l[r$v>0])write(paste0(rep("Excelsior",sum(v)),strrep("!",sequence(v))),1,1)


                                                                                        Try it online!



                                                                                        A far better R tribute can be found here -- I was too fixated on sequence and rle.






                                                                                        share|improve this answer















                                                                                        R, 111 bytes





                                                                                        function(a,r=rle(sign(diff(a))),v=r$l[r$v>0])write(paste0(rep("Excelsior",sum(v)),strrep("!",sequence(v))),1,1)


                                                                                        Try it online!



                                                                                        A far better R tribute can be found here -- I was too fixated on sequence and rle.







                                                                                        share|improve this answer














                                                                                        share|improve this answer



                                                                                        share|improve this answer








                                                                                        edited 2 days ago

























                                                                                        answered 2 days ago









                                                                                        Giuseppe

                                                                                        15.9k31052




                                                                                        15.9k31052












                                                                                        • This doesn't give some blank lines, but 86 bytes?
                                                                                          – J.Doe
                                                                                          2 days ago






                                                                                        • 2




                                                                                          @J.Doe dang, that's way better. I'd post that myself if I were you.
                                                                                          – Giuseppe
                                                                                          2 days ago


















                                                                                        • This doesn't give some blank lines, but 86 bytes?
                                                                                          – J.Doe
                                                                                          2 days ago






                                                                                        • 2




                                                                                          @J.Doe dang, that's way better. I'd post that myself if I were you.
                                                                                          – Giuseppe
                                                                                          2 days ago
















                                                                                        This doesn't give some blank lines, but 86 bytes?
                                                                                        – J.Doe
                                                                                        2 days ago




                                                                                        This doesn't give some blank lines, but 86 bytes?
                                                                                        – J.Doe
                                                                                        2 days ago




                                                                                        2




                                                                                        2




                                                                                        @J.Doe dang, that's way better. I'd post that myself if I were you.
                                                                                        – Giuseppe
                                                                                        2 days ago




                                                                                        @J.Doe dang, that's way better. I'd post that myself if I were you.
                                                                                        – Giuseppe
                                                                                        2 days ago










                                                                                        up vote
                                                                                        3
                                                                                        down vote














                                                                                        Jelly, 16 bytes



                                                                                        <Ɲṣ0ÄẎ”!ẋ“Ø6ḥ»;Ɱ


                                                                                        A monadic Link yielding a list of lists of characters.



                                                                                        Try it online! (footer joins with newlines)



                                                                                        How?



                                                                                        <Ɲṣ0ÄẎ”!ẋ“Ø6ḥ»;Ɱ - Link: list of integers     e.g. [1,1,4,2,1,1,3,4]
                                                                                        Ɲ - for each pair of integers: [1,1] [1,4] [4,2] [2,1] [1,1] [1,3] [3,4]
                                                                                        < - less than? [ 0, 1, 0, 0, 0, 1, 1]
                                                                                        ṣ0 - split at zeros [, [1], , , [1, 1]]
                                                                                        Ä - cumulative sums [, [1], , , [1, 2]]
                                                                                        Ẏ - tighten [1,1,2]
                                                                                        ”! - literal '!' character '!'
                                                                                        ẋ - repeat (vectorises) [['!'],['!'],['!','!']]
                                                                                        “Ø6ḥ» - dictionary lookup ['E','x','c','e','l','s','i','o','r']
                                                                                        Ɱ - map with:
                                                                                        ; - concatenate [['E','x','c','e','l','s','i','o','r','!'],['E','x','c','e','l','s','i','o','r','!'],['E','x','c','e','l','s','i','o','r','!','!']]





                                                                                        share|improve this answer

























                                                                                          up vote
                                                                                          3
                                                                                          down vote














                                                                                          Jelly, 16 bytes



                                                                                          <Ɲṣ0ÄẎ”!ẋ“Ø6ḥ»;Ɱ


                                                                                          A monadic Link yielding a list of lists of characters.



                                                                                          Try it online! (footer joins with newlines)



                                                                                          How?



                                                                                          <Ɲṣ0ÄẎ”!ẋ“Ø6ḥ»;Ɱ - Link: list of integers     e.g. [1,1,4,2,1,1,3,4]
                                                                                          Ɲ - for each pair of integers: [1,1] [1,4] [4,2] [2,1] [1,1] [1,3] [3,4]
                                                                                          < - less than? [ 0, 1, 0, 0, 0, 1, 1]
                                                                                          ṣ0 - split at zeros [, [1], , , [1, 1]]
                                                                                          Ä - cumulative sums [, [1], , , [1, 2]]
                                                                                          Ẏ - tighten [1,1,2]
                                                                                          ”! - literal '!' character '!'
                                                                                          ẋ - repeat (vectorises) [['!'],['!'],['!','!']]
                                                                                          “Ø6ḥ» - dictionary lookup ['E','x','c','e','l','s','i','o','r']
                                                                                          Ɱ - map with:
                                                                                          ; - concatenate [['E','x','c','e','l','s','i','o','r','!'],['E','x','c','e','l','s','i','o','r','!'],['E','x','c','e','l','s','i','o','r','!','!']]





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                                                                                            up vote
                                                                                            3
                                                                                            down vote










                                                                                            up vote
                                                                                            3
                                                                                            down vote










                                                                                            Jelly, 16 bytes



                                                                                            <Ɲṣ0ÄẎ”!ẋ“Ø6ḥ»;Ɱ


                                                                                            A monadic Link yielding a list of lists of characters.



                                                                                            Try it online! (footer joins with newlines)



                                                                                            How?



                                                                                            <Ɲṣ0ÄẎ”!ẋ“Ø6ḥ»;Ɱ - Link: list of integers     e.g. [1,1,4,2,1,1,3,4]
                                                                                            Ɲ - for each pair of integers: [1,1] [1,4] [4,2] [2,1] [1,1] [1,3] [3,4]
                                                                                            < - less than? [ 0, 1, 0, 0, 0, 1, 1]
                                                                                            ṣ0 - split at zeros [, [1], , , [1, 1]]
                                                                                            Ä - cumulative sums [, [1], , , [1, 2]]
                                                                                            Ẏ - tighten [1,1,2]
                                                                                            ”! - literal '!' character '!'
                                                                                            ẋ - repeat (vectorises) [['!'],['!'],['!','!']]
                                                                                            “Ø6ḥ» - dictionary lookup ['E','x','c','e','l','s','i','o','r']
                                                                                            Ɱ - map with:
                                                                                            ; - concatenate [['E','x','c','e','l','s','i','o','r','!'],['E','x','c','e','l','s','i','o','r','!'],['E','x','c','e','l','s','i','o','r','!','!']]





                                                                                            share|improve this answer













                                                                                            Jelly, 16 bytes



                                                                                            <Ɲṣ0ÄẎ”!ẋ“Ø6ḥ»;Ɱ


                                                                                            A monadic Link yielding a list of lists of characters.



                                                                                            Try it online! (footer joins with newlines)



                                                                                            How?



                                                                                            <Ɲṣ0ÄẎ”!ẋ“Ø6ḥ»;Ɱ - Link: list of integers     e.g. [1,1,4,2,1,1,3,4]
                                                                                            Ɲ - for each pair of integers: [1,1] [1,4] [4,2] [2,1] [1,1] [1,3] [3,4]
                                                                                            < - less than? [ 0, 1, 0, 0, 0, 1, 1]
                                                                                            ṣ0 - split at zeros [, [1], , , [1, 1]]
                                                                                            Ä - cumulative sums [, [1], , , [1, 2]]
                                                                                            Ẏ - tighten [1,1,2]
                                                                                            ”! - literal '!' character '!'
                                                                                            ẋ - repeat (vectorises) [['!'],['!'],['!','!']]
                                                                                            “Ø6ḥ» - dictionary lookup ['E','x','c','e','l','s','i','o','r']
                                                                                            Ɱ - map with:
                                                                                            ; - concatenate [['E','x','c','e','l','s','i','o','r','!'],['E','x','c','e','l','s','i','o','r','!'],['E','x','c','e','l','s','i','o','r','!','!']]






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                                                                                            share|improve this answer



                                                                                            share|improve this answer










                                                                                            answered 2 days ago









                                                                                            Jonathan Allan

                                                                                            49.9k534163




                                                                                            49.9k534163






















                                                                                                up vote
                                                                                                3
                                                                                                down vote














                                                                                                Perl 5 -n, 41 bytes





                                                                                                $_>$l&&$l?say$c.='!':($c=Excelsior);$l=$_


                                                                                                Try it online!



                                                                                                Takes its input on separate lines.






                                                                                                share|improve this answer

























                                                                                                  up vote
                                                                                                  3
                                                                                                  down vote














                                                                                                  Perl 5 -n, 41 bytes





                                                                                                  $_>$l&&$l?say$c.='!':($c=Excelsior);$l=$_


                                                                                                  Try it online!



                                                                                                  Takes its input on separate lines.






                                                                                                  share|improve this answer























                                                                                                    up vote
                                                                                                    3
                                                                                                    down vote










                                                                                                    up vote
                                                                                                    3
                                                                                                    down vote










                                                                                                    Perl 5 -n, 41 bytes





                                                                                                    $_>$l&&$l?say$c.='!':($c=Excelsior);$l=$_


                                                                                                    Try it online!



                                                                                                    Takes its input on separate lines.






                                                                                                    share|improve this answer













                                                                                                    Perl 5 -n, 41 bytes





                                                                                                    $_>$l&&$l?say$c.='!':($c=Excelsior);$l=$_


                                                                                                    Try it online!



                                                                                                    Takes its input on separate lines.







                                                                                                    share|improve this answer












                                                                                                    share|improve this answer



                                                                                                    share|improve this answer










                                                                                                    answered 2 days ago









                                                                                                    Xcali

                                                                                                    4,990520




                                                                                                    4,990520






















                                                                                                        up vote
                                                                                                        3
                                                                                                        down vote














                                                                                                        Japt, 22 bytes



                                                                                                        ò¨ ®£`Ex­lÐâ`+'!pYÃÅÃc


                                                                                                        Try it online!



                                                                                                        Explanation, with simplified example:



                                                                                                        ò¨                       :Split whenever the sequence does not increase
                                                                                                        e.g. [2,1,1,3] -> [[2],[1],[1,3]]
                                                                                                        ® Ã :For each sub-array:
                                                                                                        £ Ã : For each item in that sub-array:
                                                                                                        `Ex­lÐâ` : Compressed "Excelsior"
                                                                                                        + : Concat with
                                                                                                        '!pY : a number of "!" equal to the index
                                                                                                        e.g. [1,3] -> ["Excelsior","Excelsior!"]
                                                                                                        Å : Remove the first item of each sub-array
                                                                                                        e.g. [[Excelsior],[Excelsior],[Excelsior,Excelsior!]]->[,,[Excelsior!]]
                                                                                                        c :Flatten
                                                                                                        e.g. [,,[Excelsior!]] -> [Excelsior!]





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                                                                                                          up vote
                                                                                                          3
                                                                                                          down vote














                                                                                                          Japt, 22 bytes



                                                                                                          ò¨ ®£`Ex­lÐâ`+'!pYÃÅÃc


                                                                                                          Try it online!



                                                                                                          Explanation, with simplified example:



                                                                                                          ò¨                       :Split whenever the sequence does not increase
                                                                                                          e.g. [2,1,1,3] -> [[2],[1],[1,3]]
                                                                                                          ® Ã :For each sub-array:
                                                                                                          £ Ã : For each item in that sub-array:
                                                                                                          `Ex­lÐâ` : Compressed "Excelsior"
                                                                                                          + : Concat with
                                                                                                          '!pY : a number of "!" equal to the index
                                                                                                          e.g. [1,3] -> ["Excelsior","Excelsior!"]
                                                                                                          Å : Remove the first item of each sub-array
                                                                                                          e.g. [[Excelsior],[Excelsior],[Excelsior,Excelsior!]]->[,,[Excelsior!]]
                                                                                                          c :Flatten
                                                                                                          e.g. [,,[Excelsior!]] -> [Excelsior!]





                                                                                                          share|improve this answer























                                                                                                            up vote
                                                                                                            3
                                                                                                            down vote










                                                                                                            up vote
                                                                                                            3
                                                                                                            down vote










                                                                                                            Japt, 22 bytes



                                                                                                            ò¨ ®£`Ex­lÐâ`+'!pYÃÅÃc


                                                                                                            Try it online!



                                                                                                            Explanation, with simplified example:



                                                                                                            ò¨                       :Split whenever the sequence does not increase
                                                                                                            e.g. [2,1,1,3] -> [[2],[1],[1,3]]
                                                                                                            ® Ã :For each sub-array:
                                                                                                            £ Ã : For each item in that sub-array:
                                                                                                            `Ex­lÐâ` : Compressed "Excelsior"
                                                                                                            + : Concat with
                                                                                                            '!pY : a number of "!" equal to the index
                                                                                                            e.g. [1,3] -> ["Excelsior","Excelsior!"]
                                                                                                            Å : Remove the first item of each sub-array
                                                                                                            e.g. [[Excelsior],[Excelsior],[Excelsior,Excelsior!]]->[,,[Excelsior!]]
                                                                                                            c :Flatten
                                                                                                            e.g. [,,[Excelsior!]] -> [Excelsior!]





                                                                                                            share|improve this answer













                                                                                                            Japt, 22 bytes



                                                                                                            ò¨ ®£`Ex­lÐâ`+'!pYÃÅÃc


                                                                                                            Try it online!



                                                                                                            Explanation, with simplified example:



                                                                                                            ò¨                       :Split whenever the sequence does not increase
                                                                                                            e.g. [2,1,1,3] -> [[2],[1],[1,3]]
                                                                                                            ® Ã :For each sub-array:
                                                                                                            £ Ã : For each item in that sub-array:
                                                                                                            `Ex­lÐâ` : Compressed "Excelsior"
                                                                                                            + : Concat with
                                                                                                            '!pY : a number of "!" equal to the index
                                                                                                            e.g. [1,3] -> ["Excelsior","Excelsior!"]
                                                                                                            Å : Remove the first item of each sub-array
                                                                                                            e.g. [[Excelsior],[Excelsior],[Excelsior,Excelsior!]]->[,,[Excelsior!]]
                                                                                                            c :Flatten
                                                                                                            e.g. [,,[Excelsior!]] -> [Excelsior!]






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                                                                                                            share|improve this answer



                                                                                                            share|improve this answer










                                                                                                            answered yesterday









                                                                                                            Kamil Drakari

                                                                                                            2,541416




                                                                                                            2,541416






















                                                                                                                up vote
                                                                                                                2
                                                                                                                down vote














                                                                                                                Retina, 55 bytes



                                                                                                                d+
                                                                                                                *
                                                                                                                L$rv`(_*,(?<!(?(1)1|2,)))+(_+)b
                                                                                                                Excelsior$#1*!


                                                                                                                Try it online! Link includes test cases. Explanation:



                                                                                                                d+
                                                                                                                *


                                                                                                                Convert to unary.



                                                                                                                rv`(_*,(?<!(?(1)1|2,)))+(_+)b


                                                                                                                Process overlapping matches from right to left (although the matches are then listed from left to right). This means that we can match every number in a run, and the match extends to the start of the run. Each match is further constrained that each additional matched number must be less than the previously matched additional number, or the first number if no additional numbers have been matched yet.



                                                                                                                L$...
                                                                                                                Excelsior$#1*!


                                                                                                                For each match, output Excelsior with the number of additional numbers in the run as desired.






                                                                                                                share|improve this answer

























                                                                                                                  up vote
                                                                                                                  2
                                                                                                                  down vote














                                                                                                                  Retina, 55 bytes



                                                                                                                  d+
                                                                                                                  *
                                                                                                                  L$rv`(_*,(?<!(?(1)1|2,)))+(_+)b
                                                                                                                  Excelsior$#1*!


                                                                                                                  Try it online! Link includes test cases. Explanation:



                                                                                                                  d+
                                                                                                                  *


                                                                                                                  Convert to unary.



                                                                                                                  rv`(_*,(?<!(?(1)1|2,)))+(_+)b


                                                                                                                  Process overlapping matches from right to left (although the matches are then listed from left to right). This means that we can match every number in a run, and the match extends to the start of the run. Each match is further constrained that each additional matched number must be less than the previously matched additional number, or the first number if no additional numbers have been matched yet.



                                                                                                                  L$...
                                                                                                                  Excelsior$#1*!


                                                                                                                  For each match, output Excelsior with the number of additional numbers in the run as desired.






                                                                                                                  share|improve this answer























                                                                                                                    up vote
                                                                                                                    2
                                                                                                                    down vote










                                                                                                                    up vote
                                                                                                                    2
                                                                                                                    down vote










                                                                                                                    Retina, 55 bytes



                                                                                                                    d+
                                                                                                                    *
                                                                                                                    L$rv`(_*,(?<!(?(1)1|2,)))+(_+)b
                                                                                                                    Excelsior$#1*!


                                                                                                                    Try it online! Link includes test cases. Explanation:



                                                                                                                    d+
                                                                                                                    *


                                                                                                                    Convert to unary.



                                                                                                                    rv`(_*,(?<!(?(1)1|2,)))+(_+)b


                                                                                                                    Process overlapping matches from right to left (although the matches are then listed from left to right). This means that we can match every number in a run, and the match extends to the start of the run. Each match is further constrained that each additional matched number must be less than the previously matched additional number, or the first number if no additional numbers have been matched yet.



                                                                                                                    L$...
                                                                                                                    Excelsior$#1*!


                                                                                                                    For each match, output Excelsior with the number of additional numbers in the run as desired.






                                                                                                                    share|improve this answer













                                                                                                                    Retina, 55 bytes



                                                                                                                    d+
                                                                                                                    *
                                                                                                                    L$rv`(_*,(?<!(?(1)1|2,)))+(_+)b
                                                                                                                    Excelsior$#1*!


                                                                                                                    Try it online! Link includes test cases. Explanation:



                                                                                                                    d+
                                                                                                                    *


                                                                                                                    Convert to unary.



                                                                                                                    rv`(_*,(?<!(?(1)1|2,)))+(_+)b


                                                                                                                    Process overlapping matches from right to left (although the matches are then listed from left to right). This means that we can match every number in a run, and the match extends to the start of the run. Each match is further constrained that each additional matched number must be less than the previously matched additional number, or the first number if no additional numbers have been matched yet.



                                                                                                                    L$...
                                                                                                                    Excelsior$#1*!


                                                                                                                    For each match, output Excelsior with the number of additional numbers in the run as desired.







                                                                                                                    share|improve this answer












                                                                                                                    share|improve this answer



                                                                                                                    share|improve this answer










                                                                                                                    answered 2 days ago









                                                                                                                    Neil

                                                                                                                    77.9k744174




                                                                                                                    77.9k744174






















                                                                                                                        up vote
                                                                                                                        2
                                                                                                                        down vote













                                                                                                                        Pyth, 32 bytes



                                                                                                                        j+L"Excelsior"*L!fT.u*hN<0Y.+Q0


                                                                                                                        Try it online here, or verify all the test cases at once here.



                                                                                                                        j+L"Excelsior"*L!fT.u*hN<0Y.+Q0   Implicit: Q=eval(input())
                                                                                                                        .+Q Get forward difference between consecutive elements of Q
                                                                                                                        .u 0 Reduce the above, returning all steps, with current value N starting at 0, next element as Y, using:
                                                                                                                        hN N+1
                                                                                                                        * Multiplied by
                                                                                                                        <0Y 1 if 0<Y, 0 otherwise
                                                                                                                        fT Filter to remove 0s
                                                                                                                        *L! Repeat "!" each element number of times
                                                                                                                        +L"Excelsior" Prepend "Excelsior" to each
                                                                                                                        j Join on newlines, implicit print





                                                                                                                        share|improve this answer

























                                                                                                                          up vote
                                                                                                                          2
                                                                                                                          down vote













                                                                                                                          Pyth, 32 bytes



                                                                                                                          j+L"Excelsior"*L!fT.u*hN<0Y.+Q0


                                                                                                                          Try it online here, or verify all the test cases at once here.



                                                                                                                          j+L"Excelsior"*L!fT.u*hN<0Y.+Q0   Implicit: Q=eval(input())
                                                                                                                          .+Q Get forward difference between consecutive elements of Q
                                                                                                                          .u 0 Reduce the above, returning all steps, with current value N starting at 0, next element as Y, using:
                                                                                                                          hN N+1
                                                                                                                          * Multiplied by
                                                                                                                          <0Y 1 if 0<Y, 0 otherwise
                                                                                                                          fT Filter to remove 0s
                                                                                                                          *L! Repeat "!" each element number of times
                                                                                                                          +L"Excelsior" Prepend "Excelsior" to each
                                                                                                                          j Join on newlines, implicit print





                                                                                                                          share|improve this answer























                                                                                                                            up vote
                                                                                                                            2
                                                                                                                            down vote










                                                                                                                            up vote
                                                                                                                            2
                                                                                                                            down vote









                                                                                                                            Pyth, 32 bytes



                                                                                                                            j+L"Excelsior"*L!fT.u*hN<0Y.+Q0


                                                                                                                            Try it online here, or verify all the test cases at once here.



                                                                                                                            j+L"Excelsior"*L!fT.u*hN<0Y.+Q0   Implicit: Q=eval(input())
                                                                                                                            .+Q Get forward difference between consecutive elements of Q
                                                                                                                            .u 0 Reduce the above, returning all steps, with current value N starting at 0, next element as Y, using:
                                                                                                                            hN N+1
                                                                                                                            * Multiplied by
                                                                                                                            <0Y 1 if 0<Y, 0 otherwise
                                                                                                                            fT Filter to remove 0s
                                                                                                                            *L! Repeat "!" each element number of times
                                                                                                                            +L"Excelsior" Prepend "Excelsior" to each
                                                                                                                            j Join on newlines, implicit print





                                                                                                                            share|improve this answer












                                                                                                                            Pyth, 32 bytes



                                                                                                                            j+L"Excelsior"*L!fT.u*hN<0Y.+Q0


                                                                                                                            Try it online here, or verify all the test cases at once here.



                                                                                                                            j+L"Excelsior"*L!fT.u*hN<0Y.+Q0   Implicit: Q=eval(input())
                                                                                                                            .+Q Get forward difference between consecutive elements of Q
                                                                                                                            .u 0 Reduce the above, returning all steps, with current value N starting at 0, next element as Y, using:
                                                                                                                            hN N+1
                                                                                                                            * Multiplied by
                                                                                                                            <0Y 1 if 0<Y, 0 otherwise
                                                                                                                            fT Filter to remove 0s
                                                                                                                            *L! Repeat "!" each element number of times
                                                                                                                            +L"Excelsior" Prepend "Excelsior" to each
                                                                                                                            j Join on newlines, implicit print






                                                                                                                            share|improve this answer












                                                                                                                            share|improve this answer



                                                                                                                            share|improve this answer










                                                                                                                            answered 2 days ago









                                                                                                                            Sok

                                                                                                                            3,349722




                                                                                                                            3,349722






















                                                                                                                                up vote
                                                                                                                                2
                                                                                                                                down vote














                                                                                                                                Jelly, 18 bytes



                                                                                                                                <Ɲ‘×¥ḟ0”!ẋ“Ø6ḥ»;Ɱ


                                                                                                                                Try it online!



                                                                                                                                Output prettified over TIO.






                                                                                                                                share|improve this answer



























                                                                                                                                  up vote
                                                                                                                                  2
                                                                                                                                  down vote














                                                                                                                                  Jelly, 18 bytes



                                                                                                                                  <Ɲ‘×¥ḟ0”!ẋ“Ø6ḥ»;Ɱ


                                                                                                                                  Try it online!



                                                                                                                                  Output prettified over TIO.






                                                                                                                                  share|improve this answer

























                                                                                                                                    up vote
                                                                                                                                    2
                                                                                                                                    down vote










                                                                                                                                    up vote
                                                                                                                                    2
                                                                                                                                    down vote










                                                                                                                                    Jelly, 18 bytes



                                                                                                                                    <Ɲ‘×¥ḟ0”!ẋ“Ø6ḥ»;Ɱ


                                                                                                                                    Try it online!



                                                                                                                                    Output prettified over TIO.






                                                                                                                                    share|improve this answer















                                                                                                                                    Jelly, 18 bytes



                                                                                                                                    <Ɲ‘×¥ḟ0”!ẋ“Ø6ḥ»;Ɱ


                                                                                                                                    Try it online!



                                                                                                                                    Output prettified over TIO.







                                                                                                                                    share|improve this answer














                                                                                                                                    share|improve this answer



                                                                                                                                    share|improve this answer








                                                                                                                                    edited 2 days ago

























                                                                                                                                    answered 2 days ago









                                                                                                                                    Erik the Outgolfer

                                                                                                                                    30.6k428102




                                                                                                                                    30.6k428102






















                                                                                                                                        up vote
                                                                                                                                        2
                                                                                                                                        down vote














                                                                                                                                        Lua, 88 87 83 82 96 95 113 bytes



                                                                                                                                        Thanks @Kevin Cruijssen for update adhering to spirit of original question.





                                                                                                                                        s=io.read()n=9 e="Excelsior!"f=e
                                                                                                                                        for c in s.gmatch(s,"%S+")do if n<c+0then print(e)e=e..'!'else e=f end n=c+0 end


                                                                                                                                        Try it online!






                                                                                                                                        share|improve this answer



















                                                                                                                                        • 1




                                                                                                                                          Sorry but you need to print the exclamation mark according to the rules (one exclamation mark per length of the current run of increasingly greater numbers).
                                                                                                                                          – Charlie
                                                                                                                                          Nov 14 at 9:49










                                                                                                                                        • No problem. Think I've done as much as I can do here unless someone else sees something...
                                                                                                                                          – ouflak
                                                                                                                                          Nov 14 at 9:56






                                                                                                                                        • 1




                                                                                                                                          I don't know Lua too well, but here is a fix for your code so it runs all test cases correctly Currently you just print an "!" more every time a number is higher than the previous, but you don't reset it back to 1 when that isn't the case. More can probably be golfed, but since I've never golfed in Lua I focused on fixing it with only minor golfs. PS: Not sure if assuming the input are always single digits is correct..
                                                                                                                                          – Kevin Cruijssen
                                                                                                                                          2 days ago








                                                                                                                                        • 2




                                                                                                                                          Since @Charlie mentioned in a comment below the challenge description that it should be possible to take multi-digits numbers as input, here a possible fix by taking a space-delimited input and split on it.
                                                                                                                                          – Kevin Cruijssen
                                                                                                                                          2 days ago












                                                                                                                                        • I decided that Kevin Cruijssen modifications are more inline with the OP's expectation. Thanks!
                                                                                                                                          – ouflak
                                                                                                                                          2 days ago















                                                                                                                                        up vote
                                                                                                                                        2
                                                                                                                                        down vote














                                                                                                                                        Lua, 88 87 83 82 96 95 113 bytes



                                                                                                                                        Thanks @Kevin Cruijssen for update adhering to spirit of original question.





                                                                                                                                        s=io.read()n=9 e="Excelsior!"f=e
                                                                                                                                        for c in s.gmatch(s,"%S+")do if n<c+0then print(e)e=e..'!'else e=f end n=c+0 end


                                                                                                                                        Try it online!






                                                                                                                                        share|improve this answer



















                                                                                                                                        • 1




                                                                                                                                          Sorry but you need to print the exclamation mark according to the rules (one exclamation mark per length of the current run of increasingly greater numbers).
                                                                                                                                          – Charlie
                                                                                                                                          Nov 14 at 9:49










                                                                                                                                        • No problem. Think I've done as much as I can do here unless someone else sees something...
                                                                                                                                          – ouflak
                                                                                                                                          Nov 14 at 9:56






                                                                                                                                        • 1




                                                                                                                                          I don't know Lua too well, but here is a fix for your code so it runs all test cases correctly Currently you just print an "!" more every time a number is higher than the previous, but you don't reset it back to 1 when that isn't the case. More can probably be golfed, but since I've never golfed in Lua I focused on fixing it with only minor golfs. PS: Not sure if assuming the input are always single digits is correct..
                                                                                                                                          – Kevin Cruijssen
                                                                                                                                          2 days ago








                                                                                                                                        • 2




                                                                                                                                          Since @Charlie mentioned in a comment below the challenge description that it should be possible to take multi-digits numbers as input, here a possible fix by taking a space-delimited input and split on it.
                                                                                                                                          – Kevin Cruijssen
                                                                                                                                          2 days ago












                                                                                                                                        • I decided that Kevin Cruijssen modifications are more inline with the OP's expectation. Thanks!
                                                                                                                                          – ouflak
                                                                                                                                          2 days ago













                                                                                                                                        up vote
                                                                                                                                        2
                                                                                                                                        down vote










                                                                                                                                        up vote
                                                                                                                                        2
                                                                                                                                        down vote










                                                                                                                                        Lua, 88 87 83 82 96 95 113 bytes



                                                                                                                                        Thanks @Kevin Cruijssen for update adhering to spirit of original question.





                                                                                                                                        s=io.read()n=9 e="Excelsior!"f=e
                                                                                                                                        for c in s.gmatch(s,"%S+")do if n<c+0then print(e)e=e..'!'else e=f end n=c+0 end


                                                                                                                                        Try it online!






                                                                                                                                        share|improve this answer















                                                                                                                                        Lua, 88 87 83 82 96 95 113 bytes



                                                                                                                                        Thanks @Kevin Cruijssen for update adhering to spirit of original question.





                                                                                                                                        s=io.read()n=9 e="Excelsior!"f=e
                                                                                                                                        for c in s.gmatch(s,"%S+")do if n<c+0then print(e)e=e..'!'else e=f end n=c+0 end


                                                                                                                                        Try it online!







                                                                                                                                        share|improve this answer














                                                                                                                                        share|improve this answer



                                                                                                                                        share|improve this answer








                                                                                                                                        edited 2 days ago









                                                                                                                                        Charlie

                                                                                                                                        7,2812388




                                                                                                                                        7,2812388










                                                                                                                                        answered Nov 14 at 9:29









                                                                                                                                        ouflak

                                                                                                                                        15129




                                                                                                                                        15129








                                                                                                                                        • 1




                                                                                                                                          Sorry but you need to print the exclamation mark according to the rules (one exclamation mark per length of the current run of increasingly greater numbers).
                                                                                                                                          – Charlie
                                                                                                                                          Nov 14 at 9:49










                                                                                                                                        • No problem. Think I've done as much as I can do here unless someone else sees something...
                                                                                                                                          – ouflak
                                                                                                                                          Nov 14 at 9:56






                                                                                                                                        • 1




                                                                                                                                          I don't know Lua too well, but here is a fix for your code so it runs all test cases correctly Currently you just print an "!" more every time a number is higher than the previous, but you don't reset it back to 1 when that isn't the case. More can probably be golfed, but since I've never golfed in Lua I focused on fixing it with only minor golfs. PS: Not sure if assuming the input are always single digits is correct..
                                                                                                                                          – Kevin Cruijssen
                                                                                                                                          2 days ago








                                                                                                                                        • 2




                                                                                                                                          Since @Charlie mentioned in a comment below the challenge description that it should be possible to take multi-digits numbers as input, here a possible fix by taking a space-delimited input and split on it.
                                                                                                                                          – Kevin Cruijssen
                                                                                                                                          2 days ago












                                                                                                                                        • I decided that Kevin Cruijssen modifications are more inline with the OP's expectation. Thanks!
                                                                                                                                          – ouflak
                                                                                                                                          2 days ago














                                                                                                                                        • 1




                                                                                                                                          Sorry but you need to print the exclamation mark according to the rules (one exclamation mark per length of the current run of increasingly greater numbers).
                                                                                                                                          – Charlie
                                                                                                                                          Nov 14 at 9:49










                                                                                                                                        • No problem. Think I've done as much as I can do here unless someone else sees something...
                                                                                                                                          – ouflak
                                                                                                                                          Nov 14 at 9:56






                                                                                                                                        • 1




                                                                                                                                          I don't know Lua too well, but here is a fix for your code so it runs all test cases correctly Currently you just print an "!" more every time a number is higher than the previous, but you don't reset it back to 1 when that isn't the case. More can probably be golfed, but since I've never golfed in Lua I focused on fixing it with only minor golfs. PS: Not sure if assuming the input are always single digits is correct..
                                                                                                                                          – Kevin Cruijssen
                                                                                                                                          2 days ago








                                                                                                                                        • 2




                                                                                                                                          Since @Charlie mentioned in a comment below the challenge description that it should be possible to take multi-digits numbers as input, here a possible fix by taking a space-delimited input and split on it.
                                                                                                                                          – Kevin Cruijssen
                                                                                                                                          2 days ago












                                                                                                                                        • I decided that Kevin Cruijssen modifications are more inline with the OP's expectation. Thanks!
                                                                                                                                          – ouflak
                                                                                                                                          2 days ago








                                                                                                                                        1




                                                                                                                                        1




                                                                                                                                        Sorry but you need to print the exclamation mark according to the rules (one exclamation mark per length of the current run of increasingly greater numbers).
                                                                                                                                        – Charlie
                                                                                                                                        Nov 14 at 9:49




                                                                                                                                        Sorry but you need to print the exclamation mark according to the rules (one exclamation mark per length of the current run of increasingly greater numbers).
                                                                                                                                        – Charlie
                                                                                                                                        Nov 14 at 9:49












                                                                                                                                        No problem. Think I've done as much as I can do here unless someone else sees something...
                                                                                                                                        – ouflak
                                                                                                                                        Nov 14 at 9:56




                                                                                                                                        No problem. Think I've done as much as I can do here unless someone else sees something...
                                                                                                                                        – ouflak
                                                                                                                                        Nov 14 at 9:56




                                                                                                                                        1




                                                                                                                                        1




                                                                                                                                        I don't know Lua too well, but here is a fix for your code so it runs all test cases correctly Currently you just print an "!" more every time a number is higher than the previous, but you don't reset it back to 1 when that isn't the case. More can probably be golfed, but since I've never golfed in Lua I focused on fixing it with only minor golfs. PS: Not sure if assuming the input are always single digits is correct..
                                                                                                                                        – Kevin Cruijssen
                                                                                                                                        2 days ago






                                                                                                                                        I don't know Lua too well, but here is a fix for your code so it runs all test cases correctly Currently you just print an "!" more every time a number is higher than the previous, but you don't reset it back to 1 when that isn't the case. More can probably be golfed, but since I've never golfed in Lua I focused on fixing it with only minor golfs. PS: Not sure if assuming the input are always single digits is correct..
                                                                                                                                        – Kevin Cruijssen
                                                                                                                                        2 days ago






                                                                                                                                        2




                                                                                                                                        2




                                                                                                                                        Since @Charlie mentioned in a comment below the challenge description that it should be possible to take multi-digits numbers as input, here a possible fix by taking a space-delimited input and split on it.
                                                                                                                                        – Kevin Cruijssen
                                                                                                                                        2 days ago






                                                                                                                                        Since @Charlie mentioned in a comment below the challenge description that it should be possible to take multi-digits numbers as input, here a possible fix by taking a space-delimited input and split on it.
                                                                                                                                        – Kevin Cruijssen
                                                                                                                                        2 days ago














                                                                                                                                        I decided that Kevin Cruijssen modifications are more inline with the OP's expectation. Thanks!
                                                                                                                                        – ouflak
                                                                                                                                        2 days ago




                                                                                                                                        I decided that Kevin Cruijssen modifications are more inline with the OP's expectation. Thanks!
                                                                                                                                        – ouflak
                                                                                                                                        2 days ago










                                                                                                                                        up vote
                                                                                                                                        2
                                                                                                                                        down vote













                                                                                                                                        C++ 14 (g++), 123 118 bytes





                                                                                                                                        (auto a){for(int n=0,i=0;++i<a.size();)a[i]>a[i-1]?puts(&("Excelsior"+std::string(++n,33))[0]):n=0;}


                                                                                                                                        Fortunately std::string has a constructor that repeats a char. Try it online here.



                                                                                                                                        Thanks to gastropner for saving 5 bytes.



                                                                                                                                        Ungolfed:



                                                                                                                                         (auto a) { // void lambda taking a std::array of integer

                                                                                                                                        for(int n = 0, // length of the current run
                                                                                                                                        i = 0; // loop variable
                                                                                                                                        ++ i < a.size(); ) // start with the second element and loop to the last
                                                                                                                                        a[i] > a[i - 1] // if the current element is greater than the previous ...
                                                                                                                                        ? puts( // ... print a new line:
                                                                                                                                        &("Excelsior" + // "Excelsior, followed by ...
                                                                                                                                        std::string(++ n, 33)) // ... the appropriate number of exclamation marks (33 is ASCII code for '!'); increment the run length
                                                                                                                                        [0]) // puts() takes a C string
                                                                                                                                        : n = 0; // else reset run length

                                                                                                                                        }





                                                                                                                                        share|improve this answer























                                                                                                                                        • You can shave off another 5 bytes
                                                                                                                                          – gastropner
                                                                                                                                          2 days ago















                                                                                                                                        up vote
                                                                                                                                        2
                                                                                                                                        down vote













                                                                                                                                        C++ 14 (g++), 123 118 bytes





                                                                                                                                        (auto a){for(int n=0,i=0;++i<a.size();)a[i]>a[i-1]?puts(&("Excelsior"+std::string(++n,33))[0]):n=0;}


                                                                                                                                        Fortunately std::string has a constructor that repeats a char. Try it online here.



                                                                                                                                        Thanks to gastropner for saving 5 bytes.



                                                                                                                                        Ungolfed:



                                                                                                                                         (auto a) { // void lambda taking a std::array of integer

                                                                                                                                        for(int n = 0, // length of the current run
                                                                                                                                        i = 0; // loop variable
                                                                                                                                        ++ i < a.size(); ) // start with the second element and loop to the last
                                                                                                                                        a[i] > a[i - 1] // if the current element is greater than the previous ...
                                                                                                                                        ? puts( // ... print a new line:
                                                                                                                                        &("Excelsior" + // "Excelsior, followed by ...
                                                                                                                                        std::string(++ n, 33)) // ... the appropriate number of exclamation marks (33 is ASCII code for '!'); increment the run length
                                                                                                                                        [0]) // puts() takes a C string
                                                                                                                                        : n = 0; // else reset run length

                                                                                                                                        }





                                                                                                                                        share|improve this answer























                                                                                                                                        • You can shave off another 5 bytes
                                                                                                                                          – gastropner
                                                                                                                                          2 days ago













                                                                                                                                        up vote
                                                                                                                                        2
                                                                                                                                        down vote










                                                                                                                                        up vote
                                                                                                                                        2
                                                                                                                                        down vote









                                                                                                                                        C++ 14 (g++), 123 118 bytes





                                                                                                                                        (auto a){for(int n=0,i=0;++i<a.size();)a[i]>a[i-1]?puts(&("Excelsior"+std::string(++n,33))[0]):n=0;}


                                                                                                                                        Fortunately std::string has a constructor that repeats a char. Try it online here.



                                                                                                                                        Thanks to gastropner for saving 5 bytes.



                                                                                                                                        Ungolfed:



                                                                                                                                         (auto a) { // void lambda taking a std::array of integer

                                                                                                                                        for(int n = 0, // length of the current run
                                                                                                                                        i = 0; // loop variable
                                                                                                                                        ++ i < a.size(); ) // start with the second element and loop to the last
                                                                                                                                        a[i] > a[i - 1] // if the current element is greater than the previous ...
                                                                                                                                        ? puts( // ... print a new line:
                                                                                                                                        &("Excelsior" + // "Excelsior, followed by ...
                                                                                                                                        std::string(++ n, 33)) // ... the appropriate number of exclamation marks (33 is ASCII code for '!'); increment the run length
                                                                                                                                        [0]) // puts() takes a C string
                                                                                                                                        : n = 0; // else reset run length

                                                                                                                                        }





                                                                                                                                        share|improve this answer














                                                                                                                                        C++ 14 (g++), 123 118 bytes





                                                                                                                                        (auto a){for(int n=0,i=0;++i<a.size();)a[i]>a[i-1]?puts(&("Excelsior"+std::string(++n,33))[0]):n=0;}


                                                                                                                                        Fortunately std::string has a constructor that repeats a char. Try it online here.



                                                                                                                                        Thanks to gastropner for saving 5 bytes.



                                                                                                                                        Ungolfed:



                                                                                                                                         (auto a) { // void lambda taking a std::array of integer

                                                                                                                                        for(int n = 0, // length of the current run
                                                                                                                                        i = 0; // loop variable
                                                                                                                                        ++ i < a.size(); ) // start with the second element and loop to the last
                                                                                                                                        a[i] > a[i - 1] // if the current element is greater than the previous ...
                                                                                                                                        ? puts( // ... print a new line:
                                                                                                                                        &("Excelsior" + // "Excelsior, followed by ...
                                                                                                                                        std::string(++ n, 33)) // ... the appropriate number of exclamation marks (33 is ASCII code for '!'); increment the run length
                                                                                                                                        [0]) // puts() takes a C string
                                                                                                                                        : n = 0; // else reset run length

                                                                                                                                        }






                                                                                                                                        share|improve this answer














                                                                                                                                        share|improve this answer



                                                                                                                                        share|improve this answer








                                                                                                                                        edited 2 days ago

























                                                                                                                                        answered 2 days ago









                                                                                                                                        O.O.Balance

                                                                                                                                        1,2401318




                                                                                                                                        1,2401318












                                                                                                                                        • You can shave off another 5 bytes
                                                                                                                                          – gastropner
                                                                                                                                          2 days ago


















                                                                                                                                        • You can shave off another 5 bytes
                                                                                                                                          – gastropner
                                                                                                                                          2 days ago
















                                                                                                                                        You can shave off another 5 bytes
                                                                                                                                        – gastropner
                                                                                                                                        2 days ago




                                                                                                                                        You can shave off another 5 bytes
                                                                                                                                        – gastropner
                                                                                                                                        2 days ago










                                                                                                                                        up vote
                                                                                                                                        2
                                                                                                                                        down vote














                                                                                                                                        C# (.NET Core), 115 107 105 bytes





                                                                                                                                        a=>{var b="";for(int i=0;++i<a.Length;)if(a[i]>a[i-1])Console.WriteLine("Excelsior"+(b+="!"));else b="";}


                                                                                                                                        Try it online!



                                                                                                                                        -8 bytes: changed b to a string holding "!"s from an int counter
                                                                                                                                        -2 bytes: set b+="!" as an inline function (thanks to Zac Faragher)



                                                                                                                                        Uses an Action delegate to pull in the input and not require a return.



                                                                                                                                        Ungolfed:



                                                                                                                                        a => {
                                                                                                                                        var b = ""; // initialize the '!' string (b)
                                                                                                                                        for(int i = 0; ++i < a.Length;) // from index 1 until the end of a
                                                                                                                                        if(a[i] > a[i - 1]) // if the current index is greater than the previous index
                                                                                                                                        Console.WriteLine("Excelsior" + // on a new line, print "Excelsior"
                                                                                                                                        (b += "!")); // add a "!" to b, and print the string
                                                                                                                                        else // if the current index is not greater than the previous index
                                                                                                                                        b = ""; // reset b
                                                                                                                                        }





                                                                                                                                        share|improve this answer



















                                                                                                                                        • 1




                                                                                                                                          you can save 2 bytes by making the b+="!" inline with the Excelsior if(a[i]>a[i-1])Console.WriteLine("Excelsior"+(b+="!")); Try it online!
                                                                                                                                          – Zac Faragher
                                                                                                                                          yesterday















                                                                                                                                        up vote
                                                                                                                                        2
                                                                                                                                        down vote














                                                                                                                                        C# (.NET Core), 115 107 105 bytes





                                                                                                                                        a=>{var b="";for(int i=0;++i<a.Length;)if(a[i]>a[i-1])Console.WriteLine("Excelsior"+(b+="!"));else b="";}


                                                                                                                                        Try it online!



                                                                                                                                        -8 bytes: changed b to a string holding "!"s from an int counter
                                                                                                                                        -2 bytes: set b+="!" as an inline function (thanks to Zac Faragher)



                                                                                                                                        Uses an Action delegate to pull in the input and not require a return.



                                                                                                                                        Ungolfed:



                                                                                                                                        a => {
                                                                                                                                        var b = ""; // initialize the '!' string (b)
                                                                                                                                        for(int i = 0; ++i < a.Length;) // from index 1 until the end of a
                                                                                                                                        if(a[i] > a[i - 1]) // if the current index is greater than the previous index
                                                                                                                                        Console.WriteLine("Excelsior" + // on a new line, print "Excelsior"
                                                                                                                                        (b += "!")); // add a "!" to b, and print the string
                                                                                                                                        else // if the current index is not greater than the previous index
                                                                                                                                        b = ""; // reset b
                                                                                                                                        }





                                                                                                                                        share|improve this answer



















                                                                                                                                        • 1




                                                                                                                                          you can save 2 bytes by making the b+="!" inline with the Excelsior if(a[i]>a[i-1])Console.WriteLine("Excelsior"+(b+="!")); Try it online!
                                                                                                                                          – Zac Faragher
                                                                                                                                          yesterday













                                                                                                                                        up vote
                                                                                                                                        2
                                                                                                                                        down vote










                                                                                                                                        up vote
                                                                                                                                        2
                                                                                                                                        down vote










                                                                                                                                        C# (.NET Core), 115 107 105 bytes





                                                                                                                                        a=>{var b="";for(int i=0;++i<a.Length;)if(a[i]>a[i-1])Console.WriteLine("Excelsior"+(b+="!"));else b="";}


                                                                                                                                        Try it online!



                                                                                                                                        -8 bytes: changed b to a string holding "!"s from an int counter
                                                                                                                                        -2 bytes: set b+="!" as an inline function (thanks to Zac Faragher)



                                                                                                                                        Uses an Action delegate to pull in the input and not require a return.



                                                                                                                                        Ungolfed:



                                                                                                                                        a => {
                                                                                                                                        var b = ""; // initialize the '!' string (b)
                                                                                                                                        for(int i = 0; ++i < a.Length;) // from index 1 until the end of a
                                                                                                                                        if(a[i] > a[i - 1]) // if the current index is greater than the previous index
                                                                                                                                        Console.WriteLine("Excelsior" + // on a new line, print "Excelsior"
                                                                                                                                        (b += "!")); // add a "!" to b, and print the string
                                                                                                                                        else // if the current index is not greater than the previous index
                                                                                                                                        b = ""; // reset b
                                                                                                                                        }





                                                                                                                                        share|improve this answer















                                                                                                                                        C# (.NET Core), 115 107 105 bytes





                                                                                                                                        a=>{var b="";for(int i=0;++i<a.Length;)if(a[i]>a[i-1])Console.WriteLine("Excelsior"+(b+="!"));else b="";}


                                                                                                                                        Try it online!



                                                                                                                                        -8 bytes: changed b to a string holding "!"s from an int counter
                                                                                                                                        -2 bytes: set b+="!" as an inline function (thanks to Zac Faragher)



                                                                                                                                        Uses an Action delegate to pull in the input and not require a return.



                                                                                                                                        Ungolfed:



                                                                                                                                        a => {
                                                                                                                                        var b = ""; // initialize the '!' string (b)
                                                                                                                                        for(int i = 0; ++i < a.Length;) // from index 1 until the end of a
                                                                                                                                        if(a[i] > a[i - 1]) // if the current index is greater than the previous index
                                                                                                                                        Console.WriteLine("Excelsior" + // on a new line, print "Excelsior"
                                                                                                                                        (b += "!")); // add a "!" to b, and print the string
                                                                                                                                        else // if the current index is not greater than the previous index
                                                                                                                                        b = ""; // reset b
                                                                                                                                        }






                                                                                                                                        share|improve this answer














                                                                                                                                        share|improve this answer



                                                                                                                                        share|improve this answer








                                                                                                                                        edited 20 hours ago

























                                                                                                                                        answered 2 days ago









                                                                                                                                        Meerkat

                                                                                                                                        2218




                                                                                                                                        2218








                                                                                                                                        • 1




                                                                                                                                          you can save 2 bytes by making the b+="!" inline with the Excelsior if(a[i]>a[i-1])Console.WriteLine("Excelsior"+(b+="!")); Try it online!
                                                                                                                                          – Zac Faragher
                                                                                                                                          yesterday














                                                                                                                                        • 1




                                                                                                                                          you can save 2 bytes by making the b+="!" inline with the Excelsior if(a[i]>a[i-1])Console.WriteLine("Excelsior"+(b+="!")); Try it online!
                                                                                                                                          – Zac Faragher
                                                                                                                                          yesterday








                                                                                                                                        1




                                                                                                                                        1




                                                                                                                                        you can save 2 bytes by making the b+="!" inline with the Excelsior if(a[i]>a[i-1])Console.WriteLine("Excelsior"+(b+="!")); Try it online!
                                                                                                                                        – Zac Faragher
                                                                                                                                        yesterday




                                                                                                                                        you can save 2 bytes by making the b+="!" inline with the Excelsior if(a[i]>a[i-1])Console.WriteLine("Excelsior"+(b+="!")); Try it online!
                                                                                                                                        – Zac Faragher
                                                                                                                                        yesterday










                                                                                                                                        up vote
                                                                                                                                        2
                                                                                                                                        down vote














                                                                                                                                        PHP, 117 109 bytes





                                                                                                                                        <?php do{$i=next($argv);if($p!==null&&$p<$i){$e.='!';echo "
                                                                                                                                        Excelsior$e";}else$e='';$p=$i;}while($i!==false);


                                                                                                                                        Try it online!






                                                                                                                                        share|improve this answer



























                                                                                                                                          up vote
                                                                                                                                          2
                                                                                                                                          down vote














                                                                                                                                          PHP, 117 109 bytes





                                                                                                                                          <?php do{$i=next($argv);if($p!==null&&$p<$i){$e.='!';echo "
                                                                                                                                          Excelsior$e";}else$e='';$p=$i;}while($i!==false);


                                                                                                                                          Try it online!






                                                                                                                                          share|improve this answer

























                                                                                                                                            up vote
                                                                                                                                            2
                                                                                                                                            down vote










                                                                                                                                            up vote
                                                                                                                                            2
                                                                                                                                            down vote










                                                                                                                                            PHP, 117 109 bytes





                                                                                                                                            <?php do{$i=next($argv);if($p!==null&&$p<$i){$e.='!';echo "
                                                                                                                                            Excelsior$e";}else$e='';$p=$i;}while($i!==false);


                                                                                                                                            Try it online!






                                                                                                                                            share|improve this answer















                                                                                                                                            PHP, 117 109 bytes





                                                                                                                                            <?php do{$i=next($argv);if($p!==null&&$p<$i){$e.='!';echo "
                                                                                                                                            Excelsior$e";}else$e='';$p=$i;}while($i!==false);


                                                                                                                                            Try it online!







                                                                                                                                            share|improve this answer














                                                                                                                                            share|improve this answer



                                                                                                                                            share|improve this answer








                                                                                                                                            edited 13 hours ago

























                                                                                                                                            answered 20 hours ago









                                                                                                                                            Scoots

                                                                                                                                            394311




                                                                                                                                            394311






















                                                                                                                                                up vote
                                                                                                                                                2
                                                                                                                                                down vote














                                                                                                                                                PowerShell, 88 87 bytes





                                                                                                                                                param($n)for(;++$i-lt$n.count){if($n[$i]-gt$n[$i-1]){"Excelsior"+"!"*(++$c)}else{$c=0}}


                                                                                                                                                Try it online!



                                                                                                                                                There's probably a restructuring hiding in there, most likely in the if-else, but overall pretty alright. Uses the ol' "Un-instantiated variable defaults to 0" trick for both making the index and the !.






                                                                                                                                                share|improve this answer



























                                                                                                                                                  up vote
                                                                                                                                                  2
                                                                                                                                                  down vote














                                                                                                                                                  PowerShell, 88 87 bytes





                                                                                                                                                  param($n)for(;++$i-lt$n.count){if($n[$i]-gt$n[$i-1]){"Excelsior"+"!"*(++$c)}else{$c=0}}


                                                                                                                                                  Try it online!



                                                                                                                                                  There's probably a restructuring hiding in there, most likely in the if-else, but overall pretty alright. Uses the ol' "Un-instantiated variable defaults to 0" trick for both making the index and the !.






                                                                                                                                                  share|improve this answer

























                                                                                                                                                    up vote
                                                                                                                                                    2
                                                                                                                                                    down vote










                                                                                                                                                    up vote
                                                                                                                                                    2
                                                                                                                                                    down vote










                                                                                                                                                    PowerShell, 88 87 bytes





                                                                                                                                                    param($n)for(;++$i-lt$n.count){if($n[$i]-gt$n[$i-1]){"Excelsior"+"!"*(++$c)}else{$c=0}}


                                                                                                                                                    Try it online!



                                                                                                                                                    There's probably a restructuring hiding in there, most likely in the if-else, but overall pretty alright. Uses the ol' "Un-instantiated variable defaults to 0" trick for both making the index and the !.






                                                                                                                                                    share|improve this answer















                                                                                                                                                    PowerShell, 88 87 bytes





                                                                                                                                                    param($n)for(;++$i-lt$n.count){if($n[$i]-gt$n[$i-1]){"Excelsior"+"!"*(++$c)}else{$c=0}}


                                                                                                                                                    Try it online!



                                                                                                                                                    There's probably a restructuring hiding in there, most likely in the if-else, but overall pretty alright. Uses the ol' "Un-instantiated variable defaults to 0" trick for both making the index and the !.







                                                                                                                                                    share|improve this answer














                                                                                                                                                    share|improve this answer



                                                                                                                                                    share|improve this answer








                                                                                                                                                    edited 5 hours ago

























                                                                                                                                                    answered 6 hours ago









                                                                                                                                                    Veskah

                                                                                                                                                    68311




                                                                                                                                                    68311






















                                                                                                                                                        up vote
                                                                                                                                                        1
                                                                                                                                                        down vote













                                                                                                                                                        Java, 113 bytes



                                                                                                                                                        String i="";for(int a=0;a<s.length-1;a++){if(s[a+1]>s[a]){i+="!";System.out.println("Excelsior"+i);}else{i="";}}





                                                                                                                                                        share|improve this answer










                                                                                                                                                        New contributor




                                                                                                                                                        isaace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                                        Check out our Code of Conduct.






















                                                                                                                                                          up vote
                                                                                                                                                          1
                                                                                                                                                          down vote













                                                                                                                                                          Java, 113 bytes



                                                                                                                                                          String i="";for(int a=0;a<s.length-1;a++){if(s[a+1]>s[a]){i+="!";System.out.println("Excelsior"+i);}else{i="";}}





                                                                                                                                                          share|improve this answer










                                                                                                                                                          New contributor




                                                                                                                                                          isaace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                                          Check out our Code of Conduct.




















                                                                                                                                                            up vote
                                                                                                                                                            1
                                                                                                                                                            down vote










                                                                                                                                                            up vote
                                                                                                                                                            1
                                                                                                                                                            down vote









                                                                                                                                                            Java, 113 bytes



                                                                                                                                                            String i="";for(int a=0;a<s.length-1;a++){if(s[a+1]>s[a]){i+="!";System.out.println("Excelsior"+i);}else{i="";}}





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                                                                                                                                                            Java, 113 bytes



                                                                                                                                                            String i="";for(int a=0;a<s.length-1;a++){if(s[a+1]>s[a]){i+="!";System.out.println("Excelsior"+i);}else{i="";}}






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                                                                                                                                                            New contributor




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                                                                                                                                                            share|improve this answer



                                                                                                                                                            share|improve this answer








                                                                                                                                                            edited 2 days ago





















                                                                                                                                                            New contributor




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                                                                                                                                                            answered 2 days ago









                                                                                                                                                            isaace

                                                                                                                                                            1313




                                                                                                                                                            1313




                                                                                                                                                            New contributor




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                                                                                                                                                            New contributor





                                                                                                                                                            isaace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                                            Check out our Code of Conduct.






                                                                                                                                                            isaace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                                            Check out our Code of Conduct.






















                                                                                                                                                                up vote
                                                                                                                                                                1
                                                                                                                                                                down vote













                                                                                                                                                                VBA, 114 bytes



                                                                                                                                                                For i=0 To UBound(a)-LBound(a)-1 If a(i+1)>a(i)Then s=s&"!" Debug.Print("Excelsior"&s&"") Else s="" End If Next i





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                                                                                                                                                                  up vote
                                                                                                                                                                  1
                                                                                                                                                                  down vote













                                                                                                                                                                  VBA, 114 bytes



                                                                                                                                                                  For i=0 To UBound(a)-LBound(a)-1 If a(i+1)>a(i)Then s=s&"!" Debug.Print("Excelsior"&s&"") Else s="" End If Next i





                                                                                                                                                                  share|improve this answer








                                                                                                                                                                  New contributor




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                                                                                                                                                                    up vote
                                                                                                                                                                    1
                                                                                                                                                                    down vote










                                                                                                                                                                    up vote
                                                                                                                                                                    1
                                                                                                                                                                    down vote









                                                                                                                                                                    VBA, 114 bytes



                                                                                                                                                                    For i=0 To UBound(a)-LBound(a)-1 If a(i+1)>a(i)Then s=s&"!" Debug.Print("Excelsior"&s&"") Else s="" End If Next i





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                                                                                                                                                                    New contributor




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                                                                                                                                                                    VBA, 114 bytes



                                                                                                                                                                    For i=0 To UBound(a)-LBound(a)-1 If a(i+1)>a(i)Then s=s&"!" Debug.Print("Excelsior"&s&"") Else s="" End If Next i






                                                                                                                                                                    share|improve this answer








                                                                                                                                                                    New contributor




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                                                                                                                                                                    share|improve this answer



                                                                                                                                                                    share|improve this answer






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                                                                                                                                                                    answered 2 days ago









                                                                                                                                                                    isaace

                                                                                                                                                                    1313




                                                                                                                                                                    1313




                                                                                                                                                                    New contributor




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                                                                                                                                                                    New contributor





                                                                                                                                                                    isaace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                                                                                                                                                                    isaace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                                                                                                                                                                        up vote
                                                                                                                                                                        1
                                                                                                                                                                        down vote













                                                                                                                                                                        Python 3, 87 bytes



                                                                                                                                                                        c='!'
                                                                                                                                                                        for i in range(1,len(n)):
                                                                                                                                                                        if n[i]>n[i-1]:print('Excelsior'+c);c+='!'
                                                                                                                                                                        else:c='!'


                                                                                                                                                                        Or 97 with the following:



                                                                                                                                                                        c='!';n=input()
                                                                                                                                                                        for i in range(1,len(n)):
                                                                                                                                                                        if n[i]>n[i-1]:print('Excelsior'+c);c+='!'
                                                                                                                                                                        else:c='!'


                                                                                                                                                                        This assumes inputs will be in the format:



                                                                                                                                                                        32105
                                                                                                                                                                        12345
                                                                                                                                                                        <null input>
                                                                                                                                                                        1
                                                                                                                                                                        1213415
                                                                                                                                                                        333343





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                                                                                                                                                                        New contributor




                                                                                                                                                                        Henry T is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                                                                                                                                                                        • Your first program is invalid as it takes input through a predefined variable. The second is invalud as it can't distinguish between numbers with multiple digits. Why not use Python 2 or turn it into a function instead?
                                                                                                                                                                          – Jo King
                                                                                                                                                                          12 hours ago















                                                                                                                                                                        up vote
                                                                                                                                                                        1
                                                                                                                                                                        down vote













                                                                                                                                                                        Python 3, 87 bytes



                                                                                                                                                                        c='!'
                                                                                                                                                                        for i in range(1,len(n)):
                                                                                                                                                                        if n[i]>n[i-1]:print('Excelsior'+c);c+='!'
                                                                                                                                                                        else:c='!'


                                                                                                                                                                        Or 97 with the following:



                                                                                                                                                                        c='!';n=input()
                                                                                                                                                                        for i in range(1,len(n)):
                                                                                                                                                                        if n[i]>n[i-1]:print('Excelsior'+c);c+='!'
                                                                                                                                                                        else:c='!'


                                                                                                                                                                        This assumes inputs will be in the format:



                                                                                                                                                                        32105
                                                                                                                                                                        12345
                                                                                                                                                                        <null input>
                                                                                                                                                                        1
                                                                                                                                                                        1213415
                                                                                                                                                                        333343





                                                                                                                                                                        share|improve this answer










                                                                                                                                                                        New contributor




                                                                                                                                                                        Henry T is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                                                                                                                                                                        • Your first program is invalid as it takes input through a predefined variable. The second is invalud as it can't distinguish between numbers with multiple digits. Why not use Python 2 or turn it into a function instead?
                                                                                                                                                                          – Jo King
                                                                                                                                                                          12 hours ago













                                                                                                                                                                        up vote
                                                                                                                                                                        1
                                                                                                                                                                        down vote










                                                                                                                                                                        up vote
                                                                                                                                                                        1
                                                                                                                                                                        down vote









                                                                                                                                                                        Python 3, 87 bytes



                                                                                                                                                                        c='!'
                                                                                                                                                                        for i in range(1,len(n)):
                                                                                                                                                                        if n[i]>n[i-1]:print('Excelsior'+c);c+='!'
                                                                                                                                                                        else:c='!'


                                                                                                                                                                        Or 97 with the following:



                                                                                                                                                                        c='!';n=input()
                                                                                                                                                                        for i in range(1,len(n)):
                                                                                                                                                                        if n[i]>n[i-1]:print('Excelsior'+c);c+='!'
                                                                                                                                                                        else:c='!'


                                                                                                                                                                        This assumes inputs will be in the format:



                                                                                                                                                                        32105
                                                                                                                                                                        12345
                                                                                                                                                                        <null input>
                                                                                                                                                                        1
                                                                                                                                                                        1213415
                                                                                                                                                                        333343





                                                                                                                                                                        share|improve this answer










                                                                                                                                                                        New contributor




                                                                                                                                                                        Henry T is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                                                        Check out our Code of Conduct.









                                                                                                                                                                        Python 3, 87 bytes



                                                                                                                                                                        c='!'
                                                                                                                                                                        for i in range(1,len(n)):
                                                                                                                                                                        if n[i]>n[i-1]:print('Excelsior'+c);c+='!'
                                                                                                                                                                        else:c='!'


                                                                                                                                                                        Or 97 with the following:



                                                                                                                                                                        c='!';n=input()
                                                                                                                                                                        for i in range(1,len(n)):
                                                                                                                                                                        if n[i]>n[i-1]:print('Excelsior'+c);c+='!'
                                                                                                                                                                        else:c='!'


                                                                                                                                                                        This assumes inputs will be in the format:



                                                                                                                                                                        32105
                                                                                                                                                                        12345
                                                                                                                                                                        <null input>
                                                                                                                                                                        1
                                                                                                                                                                        1213415
                                                                                                                                                                        333343






                                                                                                                                                                        share|improve this answer










                                                                                                                                                                        New contributor




                                                                                                                                                                        Henry T is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                                                                                                                                                                        share|improve this answer



                                                                                                                                                                        share|improve this answer








                                                                                                                                                                        edited 19 hours ago





















                                                                                                                                                                        New contributor




                                                                                                                                                                        Henry T is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                                                        Check out our Code of Conduct.









                                                                                                                                                                        answered 19 hours ago









                                                                                                                                                                        Henry T

                                                                                                                                                                        114




                                                                                                                                                                        114




                                                                                                                                                                        New contributor




                                                                                                                                                                        Henry T is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                                                        Check out our Code of Conduct.





                                                                                                                                                                        New contributor





                                                                                                                                                                        Henry T is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                                                        Check out our Code of Conduct.






                                                                                                                                                                        Henry T is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                                                                                        Check out our Code of Conduct.












                                                                                                                                                                        • Your first program is invalid as it takes input through a predefined variable. The second is invalud as it can't distinguish between numbers with multiple digits. Why not use Python 2 or turn it into a function instead?
                                                                                                                                                                          – Jo King
                                                                                                                                                                          12 hours ago


















                                                                                                                                                                        • Your first program is invalid as it takes input through a predefined variable. The second is invalud as it can't distinguish between numbers with multiple digits. Why not use Python 2 or turn it into a function instead?
                                                                                                                                                                          – Jo King
                                                                                                                                                                          12 hours ago
















                                                                                                                                                                        Your first program is invalid as it takes input through a predefined variable. The second is invalud as it can't distinguish between numbers with multiple digits. Why not use Python 2 or turn it into a function instead?
                                                                                                                                                                        – Jo King
                                                                                                                                                                        12 hours ago




                                                                                                                                                                        Your first program is invalid as it takes input through a predefined variable. The second is invalud as it can't distinguish between numbers with multiple digits. Why not use Python 2 or turn it into a function instead?
                                                                                                                                                                        – Jo King
                                                                                                                                                                        12 hours ago










                                                                                                                                                                        up vote
                                                                                                                                                                        1
                                                                                                                                                                        down vote













                                                                                                                                                                        J, 50 bytes



                                                                                                                                                                        'Excelsior',"1'!'#"0~[:;@(([:<+/);._1)0,2</ ::0]


                                                                                                                                                                        Try it online!



                                                                                                                                                                        ungolfed



                                                                                                                                                                        'Excelsior' ,"1 '!' #"0~ [: ;@(([: < +/);._1) 0 , 2 </ ::0 ]





                                                                                                                                                                        share|improve this answer

























                                                                                                                                                                          up vote
                                                                                                                                                                          1
                                                                                                                                                                          down vote













                                                                                                                                                                          J, 50 bytes



                                                                                                                                                                          'Excelsior',"1'!'#"0~[:;@(([:<+/);._1)0,2</ ::0]


                                                                                                                                                                          Try it online!



                                                                                                                                                                          ungolfed



                                                                                                                                                                          'Excelsior' ,"1 '!' #"0~ [: ;@(([: < +/);._1) 0 , 2 </ ::0 ]





                                                                                                                                                                          share|improve this answer























                                                                                                                                                                            up vote
                                                                                                                                                                            1
                                                                                                                                                                            down vote










                                                                                                                                                                            up vote
                                                                                                                                                                            1
                                                                                                                                                                            down vote









                                                                                                                                                                            J, 50 bytes



                                                                                                                                                                            'Excelsior',"1'!'#"0~[:;@(([:<+/);._1)0,2</ ::0]


                                                                                                                                                                            Try it online!



                                                                                                                                                                            ungolfed



                                                                                                                                                                            'Excelsior' ,"1 '!' #"0~ [: ;@(([: < +/);._1) 0 , 2 </ ::0 ]





                                                                                                                                                                            share|improve this answer












                                                                                                                                                                            J, 50 bytes



                                                                                                                                                                            'Excelsior',"1'!'#"0~[:;@(([:<+/);._1)0,2</ ::0]


                                                                                                                                                                            Try it online!



                                                                                                                                                                            ungolfed



                                                                                                                                                                            'Excelsior' ,"1 '!' #"0~ [: ;@(([: < +/);._1) 0 , 2 </ ::0 ]






                                                                                                                                                                            share|improve this answer












                                                                                                                                                                            share|improve this answer



                                                                                                                                                                            share|improve this answer










                                                                                                                                                                            answered 7 hours ago









                                                                                                                                                                            Jonah

                                                                                                                                                                            1,881816




                                                                                                                                                                            1,881816






















                                                                                                                                                                                up vote
                                                                                                                                                                                1
                                                                                                                                                                                down vote













                                                                                                                                                                                Powershell, 69 bytes





                                                                                                                                                                                $args|%{if($o-ne$e-and$_-gt$o){'Excelsior'+'!'*++$c}else{$c=0}$o=$_}


                                                                                                                                                                                Less golfed test script:



                                                                                                                                                                                $f = {

                                                                                                                                                                                $args|%{
                                                                                                                                                                                if($old-ne$empty-and$_-gt$old){
                                                                                                                                                                                'Excelsior'+'!'*++$c
                                                                                                                                                                                }else{
                                                                                                                                                                                $c=0
                                                                                                                                                                                }
                                                                                                                                                                                $old=$_
                                                                                                                                                                                }

                                                                                                                                                                                }

                                                                                                                                                                                @(
                                                                                                                                                                                ,( (3,2,1,0,5), 'Excelsior!') # Excelsior because 5 > 0

                                                                                                                                                                                ,( (1,2,3,4,5), 'Excelsior!', # Excelsior because 2 > 1
                                                                                                                                                                                'Excelsior!!', # Excelsior because 3 > 2 (run length: 2)
                                                                                                                                                                                'Excelsior!!!', # Excelsior because 4 > 3 (run length: 3)
                                                                                                                                                                                'Excelsior!!!!') # Excelsior because 5 > 4 (run length: 4)

                                                                                                                                                                                ,( $null, '') # <Nothing>

                                                                                                                                                                                ,( (42), '') # <Nothing>

                                                                                                                                                                                ,( (1,2,1,3,4,1,5), 'Excelsior!', # Excelsior because 2 > 1
                                                                                                                                                                                'Excelsior!', # Excelsior because 3 > 1
                                                                                                                                                                                'Excelsior!!', # Excelsior because 4 > 3 (run length: 2)
                                                                                                                                                                                'Excelsior!') # Excelsior because 5 > 1

                                                                                                                                                                                ,( (3,3,3,3,4,3), 'Excelsior!') # Excelsior because 4 > 3
                                                                                                                                                                                ) | % {
                                                                                                                                                                                $a,$expected = $_
                                                                                                                                                                                $result = &$f @a
                                                                                                                                                                                "$result"-eq"$expected"
                                                                                                                                                                                $result
                                                                                                                                                                                }


                                                                                                                                                                                Output:



                                                                                                                                                                                True
                                                                                                                                                                                Excelsior!
                                                                                                                                                                                True
                                                                                                                                                                                Excelsior!
                                                                                                                                                                                Excelsior!!
                                                                                                                                                                                Excelsior!!!
                                                                                                                                                                                Excelsior!!!!
                                                                                                                                                                                True
                                                                                                                                                                                True
                                                                                                                                                                                True
                                                                                                                                                                                Excelsior!
                                                                                                                                                                                Excelsior!
                                                                                                                                                                                Excelsior!!
                                                                                                                                                                                Excelsior!
                                                                                                                                                                                True
                                                                                                                                                                                Excelsior!





                                                                                                                                                                                share|improve this answer

























                                                                                                                                                                                  up vote
                                                                                                                                                                                  1
                                                                                                                                                                                  down vote













                                                                                                                                                                                  Powershell, 69 bytes





                                                                                                                                                                                  $args|%{if($o-ne$e-and$_-gt$o){'Excelsior'+'!'*++$c}else{$c=0}$o=$_}


                                                                                                                                                                                  Less golfed test script:



                                                                                                                                                                                  $f = {

                                                                                                                                                                                  $args|%{
                                                                                                                                                                                  if($old-ne$empty-and$_-gt$old){
                                                                                                                                                                                  'Excelsior'+'!'*++$c
                                                                                                                                                                                  }else{
                                                                                                                                                                                  $c=0
                                                                                                                                                                                  }
                                                                                                                                                                                  $old=$_
                                                                                                                                                                                  }

                                                                                                                                                                                  }

                                                                                                                                                                                  @(
                                                                                                                                                                                  ,( (3,2,1,0,5), 'Excelsior!') # Excelsior because 5 > 0

                                                                                                                                                                                  ,( (1,2,3,4,5), 'Excelsior!', # Excelsior because 2 > 1
                                                                                                                                                                                  'Excelsior!!', # Excelsior because 3 > 2 (run length: 2)
                                                                                                                                                                                  'Excelsior!!!', # Excelsior because 4 > 3 (run length: 3)
                                                                                                                                                                                  'Excelsior!!!!') # Excelsior because 5 > 4 (run length: 4)

                                                                                                                                                                                  ,( $null, '') # <Nothing>

                                                                                                                                                                                  ,( (42), '') # <Nothing>

                                                                                                                                                                                  ,( (1,2,1,3,4,1,5), 'Excelsior!', # Excelsior because 2 > 1
                                                                                                                                                                                  'Excelsior!', # Excelsior because 3 > 1
                                                                                                                                                                                  'Excelsior!!', # Excelsior because 4 > 3 (run length: 2)
                                                                                                                                                                                  'Excelsior!') # Excelsior because 5 > 1

                                                                                                                                                                                  ,( (3,3,3,3,4,3), 'Excelsior!') # Excelsior because 4 > 3
                                                                                                                                                                                  ) | % {
                                                                                                                                                                                  $a,$expected = $_
                                                                                                                                                                                  $result = &$f @a
                                                                                                                                                                                  "$result"-eq"$expected"
                                                                                                                                                                                  $result
                                                                                                                                                                                  }


                                                                                                                                                                                  Output:



                                                                                                                                                                                  True
                                                                                                                                                                                  Excelsior!
                                                                                                                                                                                  True
                                                                                                                                                                                  Excelsior!
                                                                                                                                                                                  Excelsior!!
                                                                                                                                                                                  Excelsior!!!
                                                                                                                                                                                  Excelsior!!!!
                                                                                                                                                                                  True
                                                                                                                                                                                  True
                                                                                                                                                                                  True
                                                                                                                                                                                  Excelsior!
                                                                                                                                                                                  Excelsior!
                                                                                                                                                                                  Excelsior!!
                                                                                                                                                                                  Excelsior!
                                                                                                                                                                                  True
                                                                                                                                                                                  Excelsior!





                                                                                                                                                                                  share|improve this answer























                                                                                                                                                                                    up vote
                                                                                                                                                                                    1
                                                                                                                                                                                    down vote










                                                                                                                                                                                    up vote
                                                                                                                                                                                    1
                                                                                                                                                                                    down vote









                                                                                                                                                                                    Powershell, 69 bytes





                                                                                                                                                                                    $args|%{if($o-ne$e-and$_-gt$o){'Excelsior'+'!'*++$c}else{$c=0}$o=$_}


                                                                                                                                                                                    Less golfed test script:



                                                                                                                                                                                    $f = {

                                                                                                                                                                                    $args|%{
                                                                                                                                                                                    if($old-ne$empty-and$_-gt$old){
                                                                                                                                                                                    'Excelsior'+'!'*++$c
                                                                                                                                                                                    }else{
                                                                                                                                                                                    $c=0
                                                                                                                                                                                    }
                                                                                                                                                                                    $old=$_
                                                                                                                                                                                    }

                                                                                                                                                                                    }

                                                                                                                                                                                    @(
                                                                                                                                                                                    ,( (3,2,1,0,5), 'Excelsior!') # Excelsior because 5 > 0

                                                                                                                                                                                    ,( (1,2,3,4,5), 'Excelsior!', # Excelsior because 2 > 1
                                                                                                                                                                                    'Excelsior!!', # Excelsior because 3 > 2 (run length: 2)
                                                                                                                                                                                    'Excelsior!!!', # Excelsior because 4 > 3 (run length: 3)
                                                                                                                                                                                    'Excelsior!!!!') # Excelsior because 5 > 4 (run length: 4)

                                                                                                                                                                                    ,( $null, '') # <Nothing>

                                                                                                                                                                                    ,( (42), '') # <Nothing>

                                                                                                                                                                                    ,( (1,2,1,3,4,1,5), 'Excelsior!', # Excelsior because 2 > 1
                                                                                                                                                                                    'Excelsior!', # Excelsior because 3 > 1
                                                                                                                                                                                    'Excelsior!!', # Excelsior because 4 > 3 (run length: 2)
                                                                                                                                                                                    'Excelsior!') # Excelsior because 5 > 1

                                                                                                                                                                                    ,( (3,3,3,3,4,3), 'Excelsior!') # Excelsior because 4 > 3
                                                                                                                                                                                    ) | % {
                                                                                                                                                                                    $a,$expected = $_
                                                                                                                                                                                    $result = &$f @a
                                                                                                                                                                                    "$result"-eq"$expected"
                                                                                                                                                                                    $result
                                                                                                                                                                                    }


                                                                                                                                                                                    Output:



                                                                                                                                                                                    True
                                                                                                                                                                                    Excelsior!
                                                                                                                                                                                    True
                                                                                                                                                                                    Excelsior!
                                                                                                                                                                                    Excelsior!!
                                                                                                                                                                                    Excelsior!!!
                                                                                                                                                                                    Excelsior!!!!
                                                                                                                                                                                    True
                                                                                                                                                                                    True
                                                                                                                                                                                    True
                                                                                                                                                                                    Excelsior!
                                                                                                                                                                                    Excelsior!
                                                                                                                                                                                    Excelsior!!
                                                                                                                                                                                    Excelsior!
                                                                                                                                                                                    True
                                                                                                                                                                                    Excelsior!





                                                                                                                                                                                    share|improve this answer












                                                                                                                                                                                    Powershell, 69 bytes





                                                                                                                                                                                    $args|%{if($o-ne$e-and$_-gt$o){'Excelsior'+'!'*++$c}else{$c=0}$o=$_}


                                                                                                                                                                                    Less golfed test script:



                                                                                                                                                                                    $f = {

                                                                                                                                                                                    $args|%{
                                                                                                                                                                                    if($old-ne$empty-and$_-gt$old){
                                                                                                                                                                                    'Excelsior'+'!'*++$c
                                                                                                                                                                                    }else{
                                                                                                                                                                                    $c=0
                                                                                                                                                                                    }
                                                                                                                                                                                    $old=$_
                                                                                                                                                                                    }

                                                                                                                                                                                    }

                                                                                                                                                                                    @(
                                                                                                                                                                                    ,( (3,2,1,0,5), 'Excelsior!') # Excelsior because 5 > 0

                                                                                                                                                                                    ,( (1,2,3,4,5), 'Excelsior!', # Excelsior because 2 > 1
                                                                                                                                                                                    'Excelsior!!', # Excelsior because 3 > 2 (run length: 2)
                                                                                                                                                                                    'Excelsior!!!', # Excelsior because 4 > 3 (run length: 3)
                                                                                                                                                                                    'Excelsior!!!!') # Excelsior because 5 > 4 (run length: 4)

                                                                                                                                                                                    ,( $null, '') # <Nothing>

                                                                                                                                                                                    ,( (42), '') # <Nothing>

                                                                                                                                                                                    ,( (1,2,1,3,4,1,5), 'Excelsior!', # Excelsior because 2 > 1
                                                                                                                                                                                    'Excelsior!', # Excelsior because 3 > 1
                                                                                                                                                                                    'Excelsior!!', # Excelsior because 4 > 3 (run length: 2)
                                                                                                                                                                                    'Excelsior!') # Excelsior because 5 > 1

                                                                                                                                                                                    ,( (3,3,3,3,4,3), 'Excelsior!') # Excelsior because 4 > 3
                                                                                                                                                                                    ) | % {
                                                                                                                                                                                    $a,$expected = $_
                                                                                                                                                                                    $result = &$f @a
                                                                                                                                                                                    "$result"-eq"$expected"
                                                                                                                                                                                    $result
                                                                                                                                                                                    }


                                                                                                                                                                                    Output:



                                                                                                                                                                                    True
                                                                                                                                                                                    Excelsior!
                                                                                                                                                                                    True
                                                                                                                                                                                    Excelsior!
                                                                                                                                                                                    Excelsior!!
                                                                                                                                                                                    Excelsior!!!
                                                                                                                                                                                    Excelsior!!!!
                                                                                                                                                                                    True
                                                                                                                                                                                    True
                                                                                                                                                                                    True
                                                                                                                                                                                    Excelsior!
                                                                                                                                                                                    Excelsior!
                                                                                                                                                                                    Excelsior!!
                                                                                                                                                                                    Excelsior!
                                                                                                                                                                                    True
                                                                                                                                                                                    Excelsior!






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                                                                                                                                                                                    answered 23 mins ago









                                                                                                                                                                                    mazzy

                                                                                                                                                                                    1,725312




                                                                                                                                                                                    1,725312






















                                                                                                                                                                                        up vote
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                                                                                                                                                                                        Japt, 25 bytes



                                                                                                                                                                                        ä< ®?`Ex­lÐâ`+'!p°T:T=0
                                                                                                                                                                                        f


                                                                                                                                                                                        Try it online!






                                                                                                                                                                                        share|improve this answer

























                                                                                                                                                                                          up vote
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                                                                                                                                                                                          Japt, 25 bytes



                                                                                                                                                                                          ä< ®?`Ex­lÐâ`+'!p°T:T=0
                                                                                                                                                                                          f


                                                                                                                                                                                          Try it online!






                                                                                                                                                                                          share|improve this answer























                                                                                                                                                                                            up vote
                                                                                                                                                                                            0
                                                                                                                                                                                            down vote










                                                                                                                                                                                            up vote
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                                                                                                                                                                                            down vote










                                                                                                                                                                                            Japt, 25 bytes



                                                                                                                                                                                            ä< ®?`Ex­lÐâ`+'!p°T:T=0
                                                                                                                                                                                            f


                                                                                                                                                                                            Try it online!






                                                                                                                                                                                            share|improve this answer













                                                                                                                                                                                            Japt, 25 bytes



                                                                                                                                                                                            ä< ®?`Ex­lÐâ`+'!p°T:T=0
                                                                                                                                                                                            f


                                                                                                                                                                                            Try it online!







                                                                                                                                                                                            share|improve this answer












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                                                                                                                                                                                            answered 18 hours ago









                                                                                                                                                                                            Oliver

                                                                                                                                                                                            4,4801828




                                                                                                                                                                                            4,4801828






















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