How to find two functions are measuarable or not?











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Let $E$ be a non measurable subset of $(0,1)$. Define two functions as follows:



$f_1(x)=1/x$ if $x∈E$ and $0$ if $x∉E$ and



$f_2(x)=0$ if $x∈E $ and $f(x)=1/x$ if $x∉E$



then are $f_1$ and $f_2$ measurable ?










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  • Please learn to use MathJax here. It makes it much easier to read your problem.
    – Landuros
    Sep 22 '17 at 9:30












  • I have changed the awful mess you had given into a readable text. Next time, to begin with, enclose mathematical formulas between dollar signs and learn MathJax.
    – Jean Marie
    Sep 22 '17 at 9:34










  • You should give your own attempt on the problem, before you can expect us to help you. To start: what is the definition of measurable function? What happens when you try to apply it to $f_1$?
    – GEdgar
    Sep 22 '17 at 10:45










  • By definition, an extended real valued function f is said to be Lebesgue measurable if its domain is measurable and for each real α the set {x: f(x) < α } is measurable.
    – rohi
    Sep 22 '17 at 11:03















up vote
0
down vote

favorite
1












Let $E$ be a non measurable subset of $(0,1)$. Define two functions as follows:



$f_1(x)=1/x$ if $x∈E$ and $0$ if $x∉E$ and



$f_2(x)=0$ if $x∈E $ and $f(x)=1/x$ if $x∉E$



then are $f_1$ and $f_2$ measurable ?










share|cite|improve this question
























  • Please learn to use MathJax here. It makes it much easier to read your problem.
    – Landuros
    Sep 22 '17 at 9:30












  • I have changed the awful mess you had given into a readable text. Next time, to begin with, enclose mathematical formulas between dollar signs and learn MathJax.
    – Jean Marie
    Sep 22 '17 at 9:34










  • You should give your own attempt on the problem, before you can expect us to help you. To start: what is the definition of measurable function? What happens when you try to apply it to $f_1$?
    – GEdgar
    Sep 22 '17 at 10:45










  • By definition, an extended real valued function f is said to be Lebesgue measurable if its domain is measurable and for each real α the set {x: f(x) < α } is measurable.
    – rohi
    Sep 22 '17 at 11:03













up vote
0
down vote

favorite
1









up vote
0
down vote

favorite
1






1





Let $E$ be a non measurable subset of $(0,1)$. Define two functions as follows:



$f_1(x)=1/x$ if $x∈E$ and $0$ if $x∉E$ and



$f_2(x)=0$ if $x∈E $ and $f(x)=1/x$ if $x∉E$



then are $f_1$ and $f_2$ measurable ?










share|cite|improve this question















Let $E$ be a non measurable subset of $(0,1)$. Define two functions as follows:



$f_1(x)=1/x$ if $x∈E$ and $0$ if $x∉E$ and



$f_2(x)=0$ if $x∈E $ and $f(x)=1/x$ if $x∉E$



then are $f_1$ and $f_2$ measurable ?







measure-theory






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share|cite|improve this question













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edited Sep 22 '17 at 11:10

























asked Sep 22 '17 at 9:27









rohi

214




214












  • Please learn to use MathJax here. It makes it much easier to read your problem.
    – Landuros
    Sep 22 '17 at 9:30












  • I have changed the awful mess you had given into a readable text. Next time, to begin with, enclose mathematical formulas between dollar signs and learn MathJax.
    – Jean Marie
    Sep 22 '17 at 9:34










  • You should give your own attempt on the problem, before you can expect us to help you. To start: what is the definition of measurable function? What happens when you try to apply it to $f_1$?
    – GEdgar
    Sep 22 '17 at 10:45










  • By definition, an extended real valued function f is said to be Lebesgue measurable if its domain is measurable and for each real α the set {x: f(x) < α } is measurable.
    – rohi
    Sep 22 '17 at 11:03


















  • Please learn to use MathJax here. It makes it much easier to read your problem.
    – Landuros
    Sep 22 '17 at 9:30












  • I have changed the awful mess you had given into a readable text. Next time, to begin with, enclose mathematical formulas between dollar signs and learn MathJax.
    – Jean Marie
    Sep 22 '17 at 9:34










  • You should give your own attempt on the problem, before you can expect us to help you. To start: what is the definition of measurable function? What happens when you try to apply it to $f_1$?
    – GEdgar
    Sep 22 '17 at 10:45










  • By definition, an extended real valued function f is said to be Lebesgue measurable if its domain is measurable and for each real α the set {x: f(x) < α } is measurable.
    – rohi
    Sep 22 '17 at 11:03
















Please learn to use MathJax here. It makes it much easier to read your problem.
– Landuros
Sep 22 '17 at 9:30






Please learn to use MathJax here. It makes it much easier to read your problem.
– Landuros
Sep 22 '17 at 9:30














I have changed the awful mess you had given into a readable text. Next time, to begin with, enclose mathematical formulas between dollar signs and learn MathJax.
– Jean Marie
Sep 22 '17 at 9:34




I have changed the awful mess you had given into a readable text. Next time, to begin with, enclose mathematical formulas between dollar signs and learn MathJax.
– Jean Marie
Sep 22 '17 at 9:34












You should give your own attempt on the problem, before you can expect us to help you. To start: what is the definition of measurable function? What happens when you try to apply it to $f_1$?
– GEdgar
Sep 22 '17 at 10:45




You should give your own attempt on the problem, before you can expect us to help you. To start: what is the definition of measurable function? What happens when you try to apply it to $f_1$?
– GEdgar
Sep 22 '17 at 10:45












By definition, an extended real valued function f is said to be Lebesgue measurable if its domain is measurable and for each real α the set {x: f(x) < α } is measurable.
– rohi
Sep 22 '17 at 11:03




By definition, an extended real valued function f is said to be Lebesgue measurable if its domain is measurable and for each real α the set {x: f(x) < α } is measurable.
– rohi
Sep 22 '17 at 11:03










1 Answer
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Hint



What about the sets ${xin(0,1)colon f_1(x)>0}$ and ${xin(0,1)colon f_2(x)=0}$? Read about equivalent conditions of measurability.



Another, more theoretical approach: $f_1(x)=frac{1}{x}chi_E(x)$. The set is measurable iff its characteristic function is measurable. Similar argument could be applied for $f_2$.






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    up vote
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    Hint



    What about the sets ${xin(0,1)colon f_1(x)>0}$ and ${xin(0,1)colon f_2(x)=0}$? Read about equivalent conditions of measurability.



    Another, more theoretical approach: $f_1(x)=frac{1}{x}chi_E(x)$. The set is measurable iff its characteristic function is measurable. Similar argument could be applied for $f_2$.






    share|cite|improve this answer

























      up vote
      0
      down vote













      Hint



      What about the sets ${xin(0,1)colon f_1(x)>0}$ and ${xin(0,1)colon f_2(x)=0}$? Read about equivalent conditions of measurability.



      Another, more theoretical approach: $f_1(x)=frac{1}{x}chi_E(x)$. The set is measurable iff its characteristic function is measurable. Similar argument could be applied for $f_2$.






      share|cite|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        Hint



        What about the sets ${xin(0,1)colon f_1(x)>0}$ and ${xin(0,1)colon f_2(x)=0}$? Read about equivalent conditions of measurability.



        Another, more theoretical approach: $f_1(x)=frac{1}{x}chi_E(x)$. The set is measurable iff its characteristic function is measurable. Similar argument could be applied for $f_2$.






        share|cite|improve this answer












        Hint



        What about the sets ${xin(0,1)colon f_1(x)>0}$ and ${xin(0,1)colon f_2(x)=0}$? Read about equivalent conditions of measurability.



        Another, more theoretical approach: $f_1(x)=frac{1}{x}chi_E(x)$. The set is measurable iff its characteristic function is measurable. Similar argument could be applied for $f_2$.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Sep 22 '17 at 11:28









        szw1710

        6,3801123




        6,3801123






























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