Powershell: compare and match specific part of filename
up vote
0
down vote
favorite
I have something want to use Powershell to write. Could anyone know it? Thanks.
I use powershell to create a list.
e.g.
$SUID = @("0011", "0012", "0013", "0014", "0015")
I have a folder containing log files:
0010Log201811151440.log
0012Log201811151440.log
0013Log201811151440.log
0017Log201811151440.log
0015Log201811151440.log
I want to use Powershell to determine SUID and files matching. Such as:
0011 = file is missing
0012 = 0012Log201811151440.log
0013 = 0013Log201811151440.log
0014 = file is missing
0015 = 0015Log201811151440.log
powershell script
edited Nov 22 at 7:06
Aulis Ronkainen
6051614
asked Nov 22 at 6:35
user966127
31
add a comment |
up vote
0
down vote
favorite
I have something want to use Powershell to write. Could anyone know it? Thanks.
I use powershell to create a list.
e.g.
$SUID = @("0011", "0012", "0013", "0014", "0015")
I have a folder containing log files:
0010Log201811151440.log
0012Log201811151440.log
0013Log201811151440.log
0017Log201811151440.log
0015Log201811151440.log
I want to use Powershell to determine SUID and files matching. Such as:
0011 = file is missing
0012 = 0012Log201811151440.log
0013 = 0013Log201811151440.log
0014 = file is missing
0015 = 0015Log201811151440.log
powershell script
edited Nov 22 at 7:06
Aulis Ronkainen
6051614
asked Nov 22 at 6:35
user966127
31
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have something want to use Powershell to write. Could anyone know it? Thanks.
I use powershell to create a list.
e.g.
$SUID = @("0011", "0012", "0013", "0014", "0015")
I have a folder containing log files:
0010Log201811151440.log
0012Log201811151440.log
0013Log201811151440.log
0017Log201811151440.log
0015Log201811151440.log
I want to use Powershell to determine SUID and files matching. Such as:
0011 = file is missing
0012 = 0012Log201811151440.log
0013 = 0013Log201811151440.log
0014 = file is missing
0015 = 0015Log201811151440.log
powershell script
edited Nov 22 at 7:06
Aulis Ronkainen
6051614
asked Nov 22 at 6:35
user966127
31
I have something want to use Powershell to write. Could anyone know it? Thanks.
I use powershell to create a list.
e.g.
$SUID = @("0011", "0012", "0013", "0014", "0015")
I have a folder containing log files:
0010Log201811151440.log
0012Log201811151440.log
0013Log201811151440.log
0017Log201811151440.log
0015Log201811151440.log
I want to use Powershell to determine SUID and files matching. Such as:
0011 = file is missing
0012 = 0012Log201811151440.log
0013 = 0013Log201811151440.log
0014 = file is missing
0015 = 0015Log201811151440.log
powershell script
powershell script
edited Nov 22 at 7:06
Aulis Ronkainen
6051614
asked Nov 22 at 6:35
user966127
31
edited Nov 22 at 7:06
Aulis Ronkainen
6051614
asked Nov 22 at 6:35
user966127
31
edited Nov 22 at 7:06
Aulis Ronkainen
6051614
edited Nov 22 at 7:06
Aulis Ronkainen
6051614
edited Nov 22 at 7:06
Aulis Ronkainen
6051614
6051614
asked Nov 22 at 6:35
user966127
31
asked Nov 22 at 6:35
user966127
31
asked Nov 22 at 6:35
user966127
31
31
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
accepted
You can use a split method to get the first part of the name:
$filename = "0010Log201811151440.log"
$separator = "Log"
$first = ($filename -split $separator)[0]
$first
answered Nov 22 at 10:03
Xaero Walk
16
Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
– user966127
Nov 23 at 3:30
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
You can use a split method to get the first part of the name:
$filename = "0010Log201811151440.log"
$separator = "Log"
$first = ($filename -split $separator)[0]
$first
answered Nov 22 at 10:03
Xaero Walk
16
Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
– user966127
Nov 23 at 3:30
add a comment |
up vote
0
down vote
accepted
You can use a split method to get the first part of the name:
$filename = "0010Log201811151440.log"
$separator = "Log"
$first = ($filename -split $separator)[0]
$first
answered Nov 22 at 10:03
Xaero Walk
16
Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
– user966127
Nov 23 at 3:30
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
You can use a split method to get the first part of the name:
$filename = "0010Log201811151440.log"
$separator = "Log"
$first = ($filename -split $separator)[0]
$first
answered Nov 22 at 10:03
Xaero Walk
16
You can use a split method to get the first part of the name:
$filename = "0010Log201811151440.log"
$separator = "Log"
$first = ($filename -split $separator)[0]
$first
answered Nov 22 at 10:03
Xaero Walk
16
answered Nov 22 at 10:03
Xaero Walk
16
answered Nov 22 at 10:03
Xaero Walk
16
answered Nov 22 at 10:03
Xaero Walk
16
16
Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
– user966127
Nov 23 at 3:30
add a comment |
Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
– user966127
Nov 23 at 3:30
Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
– user966127
Nov 23 at 3:30
Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
– user966127
Nov 23 at 3:30
add a comment |
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