Are there any examples where the transverse doppler effect is applied in astronomy?
up vote
5
down vote
favorite
Are there any astronomical examples where the transverse doppler effect(Horizontal doppler effect) is applied (Derives a meaningful result)?
light special-relativity doppler-effect
asked Nov 18 at 10:00
YYJ
517
add a comment |
up vote
5
down vote
favorite
Are there any astronomical examples where the transverse doppler effect(Horizontal doppler effect) is applied (Derives a meaningful result)?
light special-relativity doppler-effect
asked Nov 18 at 10:00
YYJ
517
add a comment |
up vote
5
down vote
favorite
up vote
5
down vote
favorite
Are there any astronomical examples where the transverse doppler effect(Horizontal doppler effect) is applied (Derives a meaningful result)?
light special-relativity doppler-effect
asked Nov 18 at 10:00
YYJ
517
Are there any astronomical examples where the transverse doppler effect(Horizontal doppler effect) is applied (Derives a meaningful result)?
light special-relativity doppler-effect
light special-relativity doppler-effect
asked Nov 18 at 10:00
YYJ
517
asked Nov 18 at 10:00
YYJ
517
edited Nov 18 at 10:25
asked Nov 18 at 10:00
YYJ
517
asked Nov 18 at 10:00
YYJ
517
asked Nov 18 at 10:00
YYJ
517
517
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
7
down vote
accepted
Accounting for the transverse Doppler effect (and other relativistic effects) is essential in modelling the X-ray spectral emission lines from the accretion discs around black holes (e.g. Cadaz & Calvani 2005). In this case the transverse Doppler effect is "mixed up" with gravitational redshift and it is treated holistically in the Schwarzschild or Kerr metrics.
The transverse Doppler effect is also essential in interpreting the signals from binary pulsars and even in single pulsars because of the rotation of the Earth and its motion around the Sun.
answered Nov 18 at 11:36
Rob Jeffries
50.7k4101155
One key is that your examples deal with orbiting bodies, so that there is some other source of information about the motion besides the Doppler effect. For a body moving in free space, there is no way to take one input number (Doppler shift) and get two outputs (radial and transverse velocity). Also, the transverse Doppler shift is of order $(v/c)^2$, whereas the radial Doppler shift is of order $v/c$, so to get the transverse effect to be big enough not to be lost in the radial effect, you want big velocities. Hence your examples, which are highly relativistic systems.
– Ben Crowell
Nov 18 at 15:19
1
@BenCrowell - All true, except there are now possibilities with precisely measured proper motions and parallaxes to have an independent measure of transverse velocity.
– Rob Jeffries
Nov 18 at 16:35
Can you check my understanding that about 25km/s or more is enough to measure the transverse velocity with the transverse doppler effect? (Source: lm.facebook.com/…)
– KYHSGeekCode
Nov 20 at 1:28
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
7
down vote
accepted
Accounting for the transverse Doppler effect (and other relativistic effects) is essential in modelling the X-ray spectral emission lines from the accretion discs around black holes (e.g. Cadaz & Calvani 2005). In this case the transverse Doppler effect is "mixed up" with gravitational redshift and it is treated holistically in the Schwarzschild or Kerr metrics.
The transverse Doppler effect is also essential in interpreting the signals from binary pulsars and even in single pulsars because of the rotation of the Earth and its motion around the Sun.
answered Nov 18 at 11:36
Rob Jeffries
50.7k4101155
One key is that your examples deal with orbiting bodies, so that there is some other source of information about the motion besides the Doppler effect. For a body moving in free space, there is no way to take one input number (Doppler shift) and get two outputs (radial and transverse velocity). Also, the transverse Doppler shift is of order $(v/c)^2$, whereas the radial Doppler shift is of order $v/c$, so to get the transverse effect to be big enough not to be lost in the radial effect, you want big velocities. Hence your examples, which are highly relativistic systems.
– Ben Crowell
Nov 18 at 15:19
1
@BenCrowell - All true, except there are now possibilities with precisely measured proper motions and parallaxes to have an independent measure of transverse velocity.
– Rob Jeffries
Nov 18 at 16:35
Can you check my understanding that about 25km/s or more is enough to measure the transverse velocity with the transverse doppler effect? (Source: lm.facebook.com/…)
– KYHSGeekCode
Nov 20 at 1:28
add a comment |
up vote
7
down vote
accepted
Accounting for the transverse Doppler effect (and other relativistic effects) is essential in modelling the X-ray spectral emission lines from the accretion discs around black holes (e.g. Cadaz & Calvani 2005). In this case the transverse Doppler effect is "mixed up" with gravitational redshift and it is treated holistically in the Schwarzschild or Kerr metrics.
The transverse Doppler effect is also essential in interpreting the signals from binary pulsars and even in single pulsars because of the rotation of the Earth and its motion around the Sun.
answered Nov 18 at 11:36
Rob Jeffries
50.7k4101155
One key is that your examples deal with orbiting bodies, so that there is some other source of information about the motion besides the Doppler effect. For a body moving in free space, there is no way to take one input number (Doppler shift) and get two outputs (radial and transverse velocity). Also, the transverse Doppler shift is of order $(v/c)^2$, whereas the radial Doppler shift is of order $v/c$, so to get the transverse effect to be big enough not to be lost in the radial effect, you want big velocities. Hence your examples, which are highly relativistic systems.
– Ben Crowell
Nov 18 at 15:19
1
@BenCrowell - All true, except there are now possibilities with precisely measured proper motions and parallaxes to have an independent measure of transverse velocity.
– Rob Jeffries
Nov 18 at 16:35
Can you check my understanding that about 25km/s or more is enough to measure the transverse velocity with the transverse doppler effect? (Source: lm.facebook.com/…)
– KYHSGeekCode
Nov 20 at 1:28
add a comment |
up vote
7
down vote
accepted
up vote
7
down vote
accepted
Accounting for the transverse Doppler effect (and other relativistic effects) is essential in modelling the X-ray spectral emission lines from the accretion discs around black holes (e.g. Cadaz & Calvani 2005). In this case the transverse Doppler effect is "mixed up" with gravitational redshift and it is treated holistically in the Schwarzschild or Kerr metrics.
The transverse Doppler effect is also essential in interpreting the signals from binary pulsars and even in single pulsars because of the rotation of the Earth and its motion around the Sun.
answered Nov 18 at 11:36
Rob Jeffries
50.7k4101155
Accounting for the transverse Doppler effect (and other relativistic effects) is essential in modelling the X-ray spectral emission lines from the accretion discs around black holes (e.g. Cadaz & Calvani 2005). In this case the transverse Doppler effect is "mixed up" with gravitational redshift and it is treated holistically in the Schwarzschild or Kerr metrics.
The transverse Doppler effect is also essential in interpreting the signals from binary pulsars and even in single pulsars because of the rotation of the Earth and its motion around the Sun.
answered Nov 18 at 11:36
Rob Jeffries
50.7k4101155
answered Nov 18 at 11:36
Rob Jeffries
50.7k4101155
answered Nov 18 at 11:36
Rob Jeffries
50.7k4101155
answered Nov 18 at 11:36
Rob Jeffries
50.7k4101155
50.7k4101155
One key is that your examples deal with orbiting bodies, so that there is some other source of information about the motion besides the Doppler effect. For a body moving in free space, there is no way to take one input number (Doppler shift) and get two outputs (radial and transverse velocity). Also, the transverse Doppler shift is of order $(v/c)^2$, whereas the radial Doppler shift is of order $v/c$, so to get the transverse effect to be big enough not to be lost in the radial effect, you want big velocities. Hence your examples, which are highly relativistic systems.
– Ben Crowell
Nov 18 at 15:19
1
@BenCrowell - All true, except there are now possibilities with precisely measured proper motions and parallaxes to have an independent measure of transverse velocity.
– Rob Jeffries
Nov 18 at 16:35
Can you check my understanding that about 25km/s or more is enough to measure the transverse velocity with the transverse doppler effect? (Source: lm.facebook.com/…)
– KYHSGeekCode
Nov 20 at 1:28
add a comment |
One key is that your examples deal with orbiting bodies, so that there is some other source of information about the motion besides the Doppler effect. For a body moving in free space, there is no way to take one input number (Doppler shift) and get two outputs (radial and transverse velocity). Also, the transverse Doppler shift is of order $(v/c)^2$, whereas the radial Doppler shift is of order $v/c$, so to get the transverse effect to be big enough not to be lost in the radial effect, you want big velocities. Hence your examples, which are highly relativistic systems.
– Ben Crowell
Nov 18 at 15:19
1
@BenCrowell - All true, except there are now possibilities with precisely measured proper motions and parallaxes to have an independent measure of transverse velocity.
– Rob Jeffries
Nov 18 at 16:35
Can you check my understanding that about 25km/s or more is enough to measure the transverse velocity with the transverse doppler effect? (Source: lm.facebook.com/…)
– KYHSGeekCode
Nov 20 at 1:28
One key is that your examples deal with orbiting bodies, so that there is some other source of information about the motion besides the Doppler effect. For a body moving in free space, there is no way to take one input number (Doppler shift) and get two outputs (radial and transverse velocity). Also, the transverse Doppler shift is of order $(v/c)^2$, whereas the radial Doppler shift is of order $v/c$, so to get the transverse effect to be big enough not to be lost in the radial effect, you want big velocities. Hence your examples, which are highly relativistic systems.
– Ben Crowell
Nov 18 at 15:19
One key is that your examples deal with orbiting bodies, so that there is some other source of information about the motion besides the Doppler effect. For a body moving in free space, there is no way to take one input number (Doppler shift) and get two outputs (radial and transverse velocity). Also, the transverse Doppler shift is of order $(v/c)^2$, whereas the radial Doppler shift is of order $v/c$, so to get the transverse effect to be big enough not to be lost in the radial effect, you want big velocities. Hence your examples, which are highly relativistic systems.
– Ben Crowell
Nov 18 at 15:19
1
1
@BenCrowell - All true, except there are now possibilities with precisely measured proper motions and parallaxes to have an independent measure of transverse velocity.
– Rob Jeffries
Nov 18 at 16:35
@BenCrowell - All true, except there are now possibilities with precisely measured proper motions and parallaxes to have an independent measure of transverse velocity.
– Rob Jeffries
Nov 18 at 16:35
Can you check my understanding that about 25km/s or more is enough to measure the transverse velocity with the transverse doppler effect? (Source: lm.facebook.com/…)
– KYHSGeekCode
Nov 20 at 1:28
Can you check my understanding that about 25km/s or more is enough to measure the transverse velocity with the transverse doppler effect? (Source: lm.facebook.com/…)
– KYHSGeekCode
Nov 20 at 1:28
add a comment |
Thanks for contributing an answer to Astronomy Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fastronomy.stackexchange.com%2fquestions%2f28429%2fare-there-any-examples-where-the-transverse-doppler-effect-is-applied-in-astrono%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
