If $M$ has a largest proper submodule, then $ M$ is directly indecomposable
up vote
0
down vote
favorite
How to prove ;
"Every module $M$, which has a largest proper submodule or, in the set of non-zero submodules, a smallest submodule, is directly indecomposable?"
direct-sum
asked Nov 13 at 8:08
Fatih
12
add a comment |
up vote
0
down vote
favorite
How to prove ;
"Every module $M$, which has a largest proper submodule or, in the set of non-zero submodules, a smallest submodule, is directly indecomposable?"
direct-sum
asked Nov 13 at 8:08
Fatih
12
Yes, I can. Can you?
– Tobias Kildetoft
Nov 13 at 8:43
I will be pleasure if you write the proof, i couldnt proof it
– Fatih
Nov 13 at 9:30
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
How to prove ;
"Every module $M$, which has a largest proper submodule or, in the set of non-zero submodules, a smallest submodule, is directly indecomposable?"
direct-sum
asked Nov 13 at 8:08
Fatih
12
How to prove ;
"Every module $M$, which has a largest proper submodule or, in the set of non-zero submodules, a smallest submodule, is directly indecomposable?"
direct-sum
direct-sum
asked Nov 13 at 8:08
Fatih
12
asked Nov 13 at 8:08
Fatih
12
edited Nov 16 at 10:54
asked Nov 13 at 8:08
Fatih
12
asked Nov 13 at 8:08
Fatih
12
asked Nov 13 at 8:08
Fatih
12
12
Yes, I can. Can you?
– Tobias Kildetoft
Nov 13 at 8:43
I will be pleasure if you write the proof, i couldnt proof it
– Fatih
Nov 13 at 9:30
add a comment |
Yes, I can. Can you?
– Tobias Kildetoft
Nov 13 at 8:43
I will be pleasure if you write the proof, i couldnt proof it
– Fatih
Nov 13 at 9:30
Yes, I can. Can you?
– Tobias Kildetoft
Nov 13 at 8:43
Yes, I can. Can you?
– Tobias Kildetoft
Nov 13 at 8:43
I will be pleasure if you write the proof, i couldnt proof it
– Fatih
Nov 13 at 9:30
I will be pleasure if you write the proof, i couldnt proof it
– Fatih
Nov 13 at 9:30
add a comment |
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2996470%2fif-m-has-a-largest-proper-submodule-then-m-is-directly-indecomposable%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Yes, I can. Can you?
– Tobias Kildetoft
Nov 13 at 8:43
I will be pleasure if you write the proof, i couldnt proof it
– Fatih
Nov 13 at 9:30