Find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent
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If $f :mathbb{R} rightarrow mathbb{R}$ be a strictly increasing continuous function and ${a_n}$ is a sequence in $[0,1]$ , then find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent?
I take $f(x) = e^x$ but this is not bounded . Again I take $f(x)= e^{-x}$ but this is not strictly increasing.
I'm not able to find a counterexample which satisfied the given statement.
Any hints/solution. Thanks.
real-analysis
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up vote
1
down vote
favorite
If $f :mathbb{R} rightarrow mathbb{R}$ be a strictly increasing continuous function and ${a_n}$ is a sequence in $[0,1]$ , then find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent?
I take $f(x) = e^x$ but this is not bounded . Again I take $f(x)= e^{-x}$ but this is not strictly increasing.
I'm not able to find a counterexample which satisfied the given statement.
Any hints/solution. Thanks.
real-analysis
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
If $f :mathbb{R} rightarrow mathbb{R}$ be a strictly increasing continuous function and ${a_n}$ is a sequence in $[0,1]$ , then find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent?
I take $f(x) = e^x$ but this is not bounded . Again I take $f(x)= e^{-x}$ but this is not strictly increasing.
I'm not able to find a counterexample which satisfied the given statement.
Any hints/solution. Thanks.
real-analysis
If $f :mathbb{R} rightarrow mathbb{R}$ be a strictly increasing continuous function and ${a_n}$ is a sequence in $[0,1]$ , then find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent?
I take $f(x) = e^x$ but this is not bounded . Again I take $f(x)= e^{-x}$ but this is not strictly increasing.
I'm not able to find a counterexample which satisfied the given statement.
Any hints/solution. Thanks.
real-analysis
real-analysis
edited Nov 17 at 11:35
Robert Z
91.1k1058129
91.1k1058129
asked Nov 17 at 11:28
Messi fifa
50111
50111
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2 Answers
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3
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Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.
1
... or in fact any function $f$ with $f(0)ne f(1)$
– Hagen von Eitzen
Nov 17 at 11:38
@HagenvonEitzen I agree. Thanks for pointing out.
– Robert Z
Nov 17 at 11:40
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up vote
3
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Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.
1
... or in fact any function $f$ with $f(0)ne f(1)$
– Hagen von Eitzen
Nov 17 at 11:38
@HagenvonEitzen I agree. Thanks for pointing out.
– Robert Z
Nov 17 at 11:40
add a comment |
up vote
3
down vote
accepted
Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.
1
... or in fact any function $f$ with $f(0)ne f(1)$
– Hagen von Eitzen
Nov 17 at 11:38
@HagenvonEitzen I agree. Thanks for pointing out.
– Robert Z
Nov 17 at 11:40
add a comment |
up vote
3
down vote
accepted
up vote
3
down vote
accepted
Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.
Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.
answered Nov 17 at 11:33
Robert Z
91.1k1058129
91.1k1058129
1
... or in fact any function $f$ with $f(0)ne f(1)$
– Hagen von Eitzen
Nov 17 at 11:38
@HagenvonEitzen I agree. Thanks for pointing out.
– Robert Z
Nov 17 at 11:40
add a comment |
1
... or in fact any function $f$ with $f(0)ne f(1)$
– Hagen von Eitzen
Nov 17 at 11:38
@HagenvonEitzen I agree. Thanks for pointing out.
– Robert Z
Nov 17 at 11:40
1
1
... or in fact any function $f$ with $f(0)ne f(1)$
– Hagen von Eitzen
Nov 17 at 11:38
... or in fact any function $f$ with $f(0)ne f(1)$
– Hagen von Eitzen
Nov 17 at 11:38
@HagenvonEitzen I agree. Thanks for pointing out.
– Robert Z
Nov 17 at 11:40
@HagenvonEitzen I agree. Thanks for pointing out.
– Robert Z
Nov 17 at 11:40
add a comment |
up vote
3
down vote
Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.
add a comment |
up vote
3
down vote
Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.
add a comment |
up vote
3
down vote
up vote
3
down vote
Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.
Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.
answered Nov 17 at 11:33
drhab
94.9k543125
94.9k543125
add a comment |
add a comment |
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