Find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent











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If $f :mathbb{R} rightarrow mathbb{R}$ be a strictly increasing continuous function and ${a_n}$ is a sequence in $[0,1]$ , then find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent?



I take $f(x) = e^x$ but this is not bounded . Again I take $f(x)= e^{-x}$ but this is not strictly increasing.



I'm not able to find a counterexample which satisfied the given statement.



Any hints/solution. Thanks.










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    up vote
    1
    down vote

    favorite












    If $f :mathbb{R} rightarrow mathbb{R}$ be a strictly increasing continuous function and ${a_n}$ is a sequence in $[0,1]$ , then find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent?



    I take $f(x) = e^x$ but this is not bounded . Again I take $f(x)= e^{-x}$ but this is not strictly increasing.



    I'm not able to find a counterexample which satisfied the given statement.



    Any hints/solution. Thanks.










    share|cite|improve this question


























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      If $f :mathbb{R} rightarrow mathbb{R}$ be a strictly increasing continuous function and ${a_n}$ is a sequence in $[0,1]$ , then find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent?



      I take $f(x) = e^x$ but this is not bounded . Again I take $f(x)= e^{-x}$ but this is not strictly increasing.



      I'm not able to find a counterexample which satisfied the given statement.



      Any hints/solution. Thanks.










      share|cite|improve this question















      If $f :mathbb{R} rightarrow mathbb{R}$ be a strictly increasing continuous function and ${a_n}$ is a sequence in $[0,1]$ , then find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent?



      I take $f(x) = e^x$ but this is not bounded . Again I take $f(x)= e^{-x}$ but this is not strictly increasing.



      I'm not able to find a counterexample which satisfied the given statement.



      Any hints/solution. Thanks.







      real-analysis






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      edited Nov 17 at 11:35









      Robert Z

      91.1k1058129




      91.1k1058129










      asked Nov 17 at 11:28









      Messi fifa

      50111




      50111






















          2 Answers
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          Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.






          share|cite|improve this answer

















          • 1




            ... or in fact any function $f$ with $f(0)ne f(1)$
            – Hagen von Eitzen
            Nov 17 at 11:38










          • @HagenvonEitzen I agree. Thanks for pointing out.
            – Robert Z
            Nov 17 at 11:40


















          up vote
          3
          down vote













          Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.






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            2 Answers
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            active

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            2 Answers
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            active

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            active

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            up vote
            3
            down vote



            accepted










            Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.






            share|cite|improve this answer

















            • 1




              ... or in fact any function $f$ with $f(0)ne f(1)$
              – Hagen von Eitzen
              Nov 17 at 11:38










            • @HagenvonEitzen I agree. Thanks for pointing out.
              – Robert Z
              Nov 17 at 11:40















            up vote
            3
            down vote



            accepted










            Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.






            share|cite|improve this answer

















            • 1




              ... or in fact any function $f$ with $f(0)ne f(1)$
              – Hagen von Eitzen
              Nov 17 at 11:38










            • @HagenvonEitzen I agree. Thanks for pointing out.
              – Robert Z
              Nov 17 at 11:40













            up vote
            3
            down vote



            accepted







            up vote
            3
            down vote



            accepted






            Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.






            share|cite|improve this answer












            Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered Nov 17 at 11:33









            Robert Z

            91.1k1058129




            91.1k1058129








            • 1




              ... or in fact any function $f$ with $f(0)ne f(1)$
              – Hagen von Eitzen
              Nov 17 at 11:38










            • @HagenvonEitzen I agree. Thanks for pointing out.
              – Robert Z
              Nov 17 at 11:40














            • 1




              ... or in fact any function $f$ with $f(0)ne f(1)$
              – Hagen von Eitzen
              Nov 17 at 11:38










            • @HagenvonEitzen I agree. Thanks for pointing out.
              – Robert Z
              Nov 17 at 11:40








            1




            1




            ... or in fact any function $f$ with $f(0)ne f(1)$
            – Hagen von Eitzen
            Nov 17 at 11:38




            ... or in fact any function $f$ with $f(0)ne f(1)$
            – Hagen von Eitzen
            Nov 17 at 11:38












            @HagenvonEitzen I agree. Thanks for pointing out.
            – Robert Z
            Nov 17 at 11:40




            @HagenvonEitzen I agree. Thanks for pointing out.
            – Robert Z
            Nov 17 at 11:40










            up vote
            3
            down vote













            Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.






            share|cite|improve this answer

























              up vote
              3
              down vote













              Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.






              share|cite|improve this answer























                up vote
                3
                down vote










                up vote
                3
                down vote









                Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.






                share|cite|improve this answer












                Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Nov 17 at 11:33









                drhab

                94.9k543125




                94.9k543125






























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