Find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent











up vote
1
down vote

favorite












If $f :mathbb{R} rightarrow mathbb{R}$ be a strictly increasing continuous function and ${a_n}$ is a sequence in $[0,1]$ , then find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent?



I take $f(x) = e^x$ but this is not bounded . Again I take $f(x)= e^{-x}$ but this is not strictly increasing.



I'm not able to find a counterexample which satisfied the given statement.



Any hints/solution. Thanks.










share|cite|improve this question




























    up vote
    1
    down vote

    favorite












    If $f :mathbb{R} rightarrow mathbb{R}$ be a strictly increasing continuous function and ${a_n}$ is a sequence in $[0,1]$ , then find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent?



    I take $f(x) = e^x$ but this is not bounded . Again I take $f(x)= e^{-x}$ but this is not strictly increasing.



    I'm not able to find a counterexample which satisfied the given statement.



    Any hints/solution. Thanks.










    share|cite|improve this question


























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      If $f :mathbb{R} rightarrow mathbb{R}$ be a strictly increasing continuous function and ${a_n}$ is a sequence in $[0,1]$ , then find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent?



      I take $f(x) = e^x$ but this is not bounded . Again I take $f(x)= e^{-x}$ but this is not strictly increasing.



      I'm not able to find a counterexample which satisfied the given statement.



      Any hints/solution. Thanks.










      share|cite|improve this question















      If $f :mathbb{R} rightarrow mathbb{R}$ be a strictly increasing continuous function and ${a_n}$ is a sequence in $[0,1]$ , then find a counterexample that the sequence ${f(a_n)}_n$ is bounded but not convergent?



      I take $f(x) = e^x$ but this is not bounded . Again I take $f(x)= e^{-x}$ but this is not strictly increasing.



      I'm not able to find a counterexample which satisfied the given statement.



      Any hints/solution. Thanks.







      real-analysis






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Nov 17 at 11:35









      Robert Z

      91.1k1058129




      91.1k1058129










      asked Nov 17 at 11:28









      Messi fifa

      50111




      50111






















          2 Answers
          2






          active

          oldest

          votes

















          up vote
          3
          down vote



          accepted










          Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.






          share|cite|improve this answer

















          • 1




            ... or in fact any function $f$ with $f(0)ne f(1)$
            – Hagen von Eitzen
            Nov 17 at 11:38










          • @HagenvonEitzen I agree. Thanks for pointing out.
            – Robert Z
            Nov 17 at 11:40


















          up vote
          3
          down vote













          Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.






          share|cite|improve this answer





















            Your Answer





            StackExchange.ifUsing("editor", function () {
            return StackExchange.using("mathjaxEditing", function () {
            StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
            StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
            });
            });
            }, "mathjax-editing");

            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "69"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            convertImagesToLinks: true,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            noCode: true, onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });














            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3002240%2ffind-a-counterexample-that-the-sequence-fa-n-n-is-bounded-but-not-conver%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            3
            down vote



            accepted










            Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.






            share|cite|improve this answer

















            • 1




              ... or in fact any function $f$ with $f(0)ne f(1)$
              – Hagen von Eitzen
              Nov 17 at 11:38










            • @HagenvonEitzen I agree. Thanks for pointing out.
              – Robert Z
              Nov 17 at 11:40















            up vote
            3
            down vote



            accepted










            Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.






            share|cite|improve this answer

















            • 1




              ... or in fact any function $f$ with $f(0)ne f(1)$
              – Hagen von Eitzen
              Nov 17 at 11:38










            • @HagenvonEitzen I agree. Thanks for pointing out.
              – Robert Z
              Nov 17 at 11:40













            up vote
            3
            down vote



            accepted







            up vote
            3
            down vote



            accepted






            Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.






            share|cite|improve this answer












            Take $a_n:=frac{1+(-1)^n}{2}$ and any strictly increasing function $f$ in $[0,1]$.







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered Nov 17 at 11:33









            Robert Z

            91.1k1058129




            91.1k1058129








            • 1




              ... or in fact any function $f$ with $f(0)ne f(1)$
              – Hagen von Eitzen
              Nov 17 at 11:38










            • @HagenvonEitzen I agree. Thanks for pointing out.
              – Robert Z
              Nov 17 at 11:40














            • 1




              ... or in fact any function $f$ with $f(0)ne f(1)$
              – Hagen von Eitzen
              Nov 17 at 11:38










            • @HagenvonEitzen I agree. Thanks for pointing out.
              – Robert Z
              Nov 17 at 11:40








            1




            1




            ... or in fact any function $f$ with $f(0)ne f(1)$
            – Hagen von Eitzen
            Nov 17 at 11:38




            ... or in fact any function $f$ with $f(0)ne f(1)$
            – Hagen von Eitzen
            Nov 17 at 11:38












            @HagenvonEitzen I agree. Thanks for pointing out.
            – Robert Z
            Nov 17 at 11:40




            @HagenvonEitzen I agree. Thanks for pointing out.
            – Robert Z
            Nov 17 at 11:40










            up vote
            3
            down vote













            Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.






            share|cite|improve this answer

























              up vote
              3
              down vote













              Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.






              share|cite|improve this answer























                up vote
                3
                down vote










                up vote
                3
                down vote









                Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.






                share|cite|improve this answer












                Define $a_n=1$ if $n$ is even and $a_n=0$ if $n$ is odd.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Nov 17 at 11:33









                drhab

                94.9k543125




                94.9k543125






























                    draft saved

                    draft discarded




















































                    Thanks for contributing an answer to Mathematics Stack Exchange!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    Use MathJax to format equations. MathJax reference.


                    To learn more, see our tips on writing great answers.





                    Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


                    Please pay close attention to the following guidance:


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3002240%2ffind-a-counterexample-that-the-sequence-fa-n-n-is-bounded-but-not-conver%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    QoS: MAC-Priority for clients behind a repeater

                    Ивакино (Тотемский район)

                    Can't locate Autom4te/ChannelDefs.pm in @INC (when it definitely is there)