$f(x)$ is differentiable or not on the interval?
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-2
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The question is to use the graph of $f$ to find is f differentiable or not on the given interval?
$f(x)=sqrt{4-x}$ following are the intervals $[0,4]$ and $[-5,0]$ and I have done this question as following
$f$ is differentiable:
functions derivatives
edited Nov 17 at 14:37
mrtaurho
2,5941827
asked Nov 17 at 14:35
Muhammad Usama
11
add a comment |
up vote
-2
down vote
favorite
The question is to use the graph of $f$ to find is f differentiable or not on the given interval?
$f(x)=sqrt{4-x}$ following are the intervals $[0,4]$ and $[-5,0]$ and I have done this question as following
$f$ is differentiable:
functions derivatives
edited Nov 17 at 14:37
mrtaurho
2,5941827
asked Nov 17 at 14:35
Muhammad Usama
11
You missed a sign using ( or not using (?)) the chain rule, what did You think You proved and how is differentiability defined e.g. in the point $x=-4$ ( which is no interior point)....(Please use MathJax)
– Peter Melech
Nov 17 at 14:48
As the left hand limit is equal to right hand limit which proves that f exists so it can be stated that f is differentiable
– Muhammad Usama
Nov 17 at 14:50
$f$ exists, sure, but You didn't prove that, You proved that it is differentiable at $x=0$, though You missed a sign (Please use MathJax)
– Peter Melech
Nov 17 at 14:52
add a comment |
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
The question is to use the graph of $f$ to find is f differentiable or not on the given interval?
$f(x)=sqrt{4-x}$ following are the intervals $[0,4]$ and $[-5,0]$ and I have done this question as following
$f$ is differentiable:
functions derivatives
edited Nov 17 at 14:37
mrtaurho
2,5941827
asked Nov 17 at 14:35
Muhammad Usama
11
The question is to use the graph of $f$ to find is f differentiable or not on the given interval?
$f(x)=sqrt{4-x}$ following are the intervals $[0,4]$ and $[-5,0]$ and I have done this question as following
$f$ is differentiable:
functions derivatives
functions derivatives
edited Nov 17 at 14:37
mrtaurho
2,5941827
asked Nov 17 at 14:35
Muhammad Usama
11
edited Nov 17 at 14:37
mrtaurho
2,5941827
asked Nov 17 at 14:35
Muhammad Usama
11
edited Nov 17 at 14:37
mrtaurho
2,5941827
edited Nov 17 at 14:37
mrtaurho
2,5941827
edited Nov 17 at 14:37
mrtaurho
2,5941827
2,5941827
asked Nov 17 at 14:35
Muhammad Usama
11
asked Nov 17 at 14:35
Muhammad Usama
11
asked Nov 17 at 14:35
Muhammad Usama
11
11
You missed a sign using ( or not using (?)) the chain rule, what did You think You proved and how is differentiability defined e.g. in the point $x=-4$ ( which is no interior point)....(Please use MathJax)
– Peter Melech
Nov 17 at 14:48
As the left hand limit is equal to right hand limit which proves that f exists so it can be stated that f is differentiable
– Muhammad Usama
Nov 17 at 14:50
$f$ exists, sure, but You didn't prove that, You proved that it is differentiable at $x=0$, though You missed a sign (Please use MathJax)
– Peter Melech
Nov 17 at 14:52
add a comment |
You missed a sign using ( or not using (?)) the chain rule, what did You think You proved and how is differentiability defined e.g. in the point $x=-4$ ( which is no interior point)....(Please use MathJax)
– Peter Melech
Nov 17 at 14:48
As the left hand limit is equal to right hand limit which proves that f exists so it can be stated that f is differentiable
– Muhammad Usama
Nov 17 at 14:50
$f$ exists, sure, but You didn't prove that, You proved that it is differentiable at $x=0$, though You missed a sign (Please use MathJax)
– Peter Melech
Nov 17 at 14:52
You missed a sign using ( or not using (?)) the chain rule, what did You think You proved and how is differentiability defined e.g. in the point $x=-4$ ( which is no interior point)....(Please use MathJax)
– Peter Melech
Nov 17 at 14:48
You missed a sign using ( or not using (?)) the chain rule, what did You think You proved and how is differentiability defined e.g. in the point $x=-4$ ( which is no interior point)....(Please use MathJax)
– Peter Melech
Nov 17 at 14:48
As the left hand limit is equal to right hand limit which proves that f exists so it can be stated that f is differentiable
– Muhammad Usama
Nov 17 at 14:50
As the left hand limit is equal to right hand limit which proves that f exists so it can be stated that f is differentiable
– Muhammad Usama
Nov 17 at 14:50
$f$ exists, sure, but You didn't prove that, You proved that it is differentiable at $x=0$, though You missed a sign (Please use MathJax)
– Peter Melech
Nov 17 at 14:52
$f$ exists, sure, but You didn't prove that, You proved that it is differentiable at $x=0$, though You missed a sign (Please use MathJax)
– Peter Melech
Nov 17 at 14:52
add a comment |
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You missed a sign using ( or not using (?)) the chain rule, what did You think You proved and how is differentiability defined e.g. in the point $x=-4$ ( which is no interior point)....(Please use MathJax)
– Peter Melech
Nov 17 at 14:48
As the left hand limit is equal to right hand limit which proves that f exists so it can be stated that f is differentiable
– Muhammad Usama
Nov 17 at 14:50
$f$ exists, sure, but You didn't prove that, You proved that it is differentiable at $x=0$, though You missed a sign (Please use MathJax)
– Peter Melech
Nov 17 at 14:52