How to evaluate this integral with exponent of an exponent?
I have the following integral which I need to evaluate but don't even know where to begin other than knowing I need to use u-substitution:
$$int_1^sqrt{3}2x^{x^{2}}$$
So far I know that $u=x^{2}$ and $du=2x$ but how do I evaluate this?
calculus integration indefinite-integrals
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I have the following integral which I need to evaluate but don't even know where to begin other than knowing I need to use u-substitution:
$$int_1^sqrt{3}2x^{x^{2}}$$
So far I know that $u=x^{2}$ and $du=2x$ but how do I evaluate this?
calculus integration indefinite-integrals
1
You might consider writing $x^{x^2} = exp(log(x^{x^2}))$ and simplifying things a bit. Then try a substitution.
– Xander Henderson
Nov 18 at 16:17
maybe a parameterization so that you could differentiate under the integral sign?
– clathratus
Nov 18 at 21:38
@XanderHenderson what does it mean to write exp(log(x^x^2))? I might be a little slow now but not sure what that exp does...
– blizz
Nov 20 at 1:11
$exp(t) = mathrm{e}^t$.
– Xander Henderson
Nov 20 at 1:42
add a comment |
I have the following integral which I need to evaluate but don't even know where to begin other than knowing I need to use u-substitution:
$$int_1^sqrt{3}2x^{x^{2}}$$
So far I know that $u=x^{2}$ and $du=2x$ but how do I evaluate this?
calculus integration indefinite-integrals
I have the following integral which I need to evaluate but don't even know where to begin other than knowing I need to use u-substitution:
$$int_1^sqrt{3}2x^{x^{2}}$$
So far I know that $u=x^{2}$ and $du=2x$ but how do I evaluate this?
calculus integration indefinite-integrals
calculus integration indefinite-integrals
asked Nov 18 at 16:11
blizz
1345
1345
1
You might consider writing $x^{x^2} = exp(log(x^{x^2}))$ and simplifying things a bit. Then try a substitution.
– Xander Henderson
Nov 18 at 16:17
maybe a parameterization so that you could differentiate under the integral sign?
– clathratus
Nov 18 at 21:38
@XanderHenderson what does it mean to write exp(log(x^x^2))? I might be a little slow now but not sure what that exp does...
– blizz
Nov 20 at 1:11
$exp(t) = mathrm{e}^t$.
– Xander Henderson
Nov 20 at 1:42
add a comment |
1
You might consider writing $x^{x^2} = exp(log(x^{x^2}))$ and simplifying things a bit. Then try a substitution.
– Xander Henderson
Nov 18 at 16:17
maybe a parameterization so that you could differentiate under the integral sign?
– clathratus
Nov 18 at 21:38
@XanderHenderson what does it mean to write exp(log(x^x^2))? I might be a little slow now but not sure what that exp does...
– blizz
Nov 20 at 1:11
$exp(t) = mathrm{e}^t$.
– Xander Henderson
Nov 20 at 1:42
1
1
You might consider writing $x^{x^2} = exp(log(x^{x^2}))$ and simplifying things a bit. Then try a substitution.
– Xander Henderson
Nov 18 at 16:17
You might consider writing $x^{x^2} = exp(log(x^{x^2}))$ and simplifying things a bit. Then try a substitution.
– Xander Henderson
Nov 18 at 16:17
maybe a parameterization so that you could differentiate under the integral sign?
– clathratus
Nov 18 at 21:38
maybe a parameterization so that you could differentiate under the integral sign?
– clathratus
Nov 18 at 21:38
@XanderHenderson what does it mean to write exp(log(x^x^2))? I might be a little slow now but not sure what that exp does...
– blizz
Nov 20 at 1:11
@XanderHenderson what does it mean to write exp(log(x^x^2))? I might be a little slow now but not sure what that exp does...
– blizz
Nov 20 at 1:11
$exp(t) = mathrm{e}^t$.
– Xander Henderson
Nov 20 at 1:42
$exp(t) = mathrm{e}^t$.
– Xander Henderson
Nov 20 at 1:42
add a comment |
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1
You might consider writing $x^{x^2} = exp(log(x^{x^2}))$ and simplifying things a bit. Then try a substitution.
– Xander Henderson
Nov 18 at 16:17
maybe a parameterization so that you could differentiate under the integral sign?
– clathratus
Nov 18 at 21:38
@XanderHenderson what does it mean to write exp(log(x^x^2))? I might be a little slow now but not sure what that exp does...
– blizz
Nov 20 at 1:11
$exp(t) = mathrm{e}^t$.
– Xander Henderson
Nov 20 at 1:42