Central alignment of text or numbers in `Table` Environment











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I want to know how to centre-align a text or a number while using multicolumn in Table environment. I need to prepare a table as shown in the image below. Table for my paper



The MWE for the above table is as follows:



documentclass{article}

%%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
usepackage{multirow}
usepackage{calc}
usepackage{array}
newcolumntype{L}[1]{>
{raggedrightletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{C}[1]{>
{centeringletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{R}[1]{>
{raggedleftletnewline\arraybackslashhspace{0pt}}m{#1}}
newcommand{mc}[3]{multicolumn{#1}{#2}{#3}}
newcommand{mr}[3]{multirow{#1}{#2}{#3}}
usepackage{booktabs}
begin{document}

begin{table}[ht!]
begin{center}
begin{tabular}{cccccccccccccc}hline
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{C{3cm}|}{1} & mc{3}{C{3cm}|}{2} & mc{3}{C{3cm}|}{3}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is bounded } & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is unbounded } & mc{3}{C{3cm}|}{$T_{alpha}^{-1}$ does not exists}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|L{0.75cm}|}{$I$} & mc{3}{C{2.5cm}|}{$R(T-alpha I)=X$} & mc{3}{p{3cm}|}{$alpha in rho (T,X)$} & mc{3}{C{3cm}|}{$-$} & mc{3}{p{3cm}|}{centering$alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$}\ hline
end{tabular}
end{center}
end{table}
%
end{document}


The output of the MWE looks similar to the one in the image. The only issue is the alignment of the text or numbers.



Please help or provide suggestions?










share|improve this question






















  • What you want is not entirely clear. Must text or numbers be horizontally or vertically be centred (or both) in its cell?
    – Bernard
    Nov 23 at 21:41










  • @Bernard The text or numbers should be centred vertically. I think they are horizontally centred in the cell.
    – Tanvir
    Nov 23 at 23:39










  • The solutions provided below solved the problem I had with the alignment.
    – Tanvir
    Nov 24 at 0:43















up vote
4
down vote

favorite












I want to know how to centre-align a text or a number while using multicolumn in Table environment. I need to prepare a table as shown in the image below. Table for my paper



The MWE for the above table is as follows:



documentclass{article}

%%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
usepackage{multirow}
usepackage{calc}
usepackage{array}
newcolumntype{L}[1]{>
{raggedrightletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{C}[1]{>
{centeringletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{R}[1]{>
{raggedleftletnewline\arraybackslashhspace{0pt}}m{#1}}
newcommand{mc}[3]{multicolumn{#1}{#2}{#3}}
newcommand{mr}[3]{multirow{#1}{#2}{#3}}
usepackage{booktabs}
begin{document}

begin{table}[ht!]
begin{center}
begin{tabular}{cccccccccccccc}hline
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{C{3cm}|}{1} & mc{3}{C{3cm}|}{2} & mc{3}{C{3cm}|}{3}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is bounded } & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is unbounded } & mc{3}{C{3cm}|}{$T_{alpha}^{-1}$ does not exists}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|L{0.75cm}|}{$I$} & mc{3}{C{2.5cm}|}{$R(T-alpha I)=X$} & mc{3}{p{3cm}|}{$alpha in rho (T,X)$} & mc{3}{C{3cm}|}{$-$} & mc{3}{p{3cm}|}{centering$alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$}\ hline
end{tabular}
end{center}
end{table}
%
end{document}


The output of the MWE looks similar to the one in the image. The only issue is the alignment of the text or numbers.



Please help or provide suggestions?










share|improve this question






















  • What you want is not entirely clear. Must text or numbers be horizontally or vertically be centred (or both) in its cell?
    – Bernard
    Nov 23 at 21:41










  • @Bernard The text or numbers should be centred vertically. I think they are horizontally centred in the cell.
    – Tanvir
    Nov 23 at 23:39










  • The solutions provided below solved the problem I had with the alignment.
    – Tanvir
    Nov 24 at 0:43













up vote
4
down vote

favorite









up vote
4
down vote

favorite











I want to know how to centre-align a text or a number while using multicolumn in Table environment. I need to prepare a table as shown in the image below. Table for my paper



The MWE for the above table is as follows:



documentclass{article}

%%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
usepackage{multirow}
usepackage{calc}
usepackage{array}
newcolumntype{L}[1]{>
{raggedrightletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{C}[1]{>
{centeringletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{R}[1]{>
{raggedleftletnewline\arraybackslashhspace{0pt}}m{#1}}
newcommand{mc}[3]{multicolumn{#1}{#2}{#3}}
newcommand{mr}[3]{multirow{#1}{#2}{#3}}
usepackage{booktabs}
begin{document}

begin{table}[ht!]
begin{center}
begin{tabular}{cccccccccccccc}hline
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{C{3cm}|}{1} & mc{3}{C{3cm}|}{2} & mc{3}{C{3cm}|}{3}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is bounded } & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is unbounded } & mc{3}{C{3cm}|}{$T_{alpha}^{-1}$ does not exists}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|L{0.75cm}|}{$I$} & mc{3}{C{2.5cm}|}{$R(T-alpha I)=X$} & mc{3}{p{3cm}|}{$alpha in rho (T,X)$} & mc{3}{C{3cm}|}{$-$} & mc{3}{p{3cm}|}{centering$alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$}\ hline
end{tabular}
end{center}
end{table}
%
end{document}


The output of the MWE looks similar to the one in the image. The only issue is the alignment of the text or numbers.



Please help or provide suggestions?










share|improve this question













I want to know how to centre-align a text or a number while using multicolumn in Table environment. I need to prepare a table as shown in the image below. Table for my paper



The MWE for the above table is as follows:



documentclass{article}

%%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
usepackage{multirow}
usepackage{calc}
usepackage{array}
newcolumntype{L}[1]{>
{raggedrightletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{C}[1]{>
{centeringletnewline\arraybackslashhspace{0pt}}m{#1}}
newcolumntype{R}[1]{>
{raggedleftletnewline\arraybackslashhspace{0pt}}m{#1}}
newcommand{mc}[3]{multicolumn{#1}{#2}{#3}}
newcommand{mr}[3]{multirow{#1}{#2}{#3}}
usepackage{booktabs}
begin{document}

begin{table}[ht!]
begin{center}
begin{tabular}{cccccccccccccc}hline
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{C{3cm}|}{1} & mc{3}{C{3cm}|}{2} & mc{3}{C{3cm}|}{3}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|C{0.75cm}|}{} & mc{3}{C{2cm}|}{} & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is bounded } & mc{3}{p{3cm}|}{centering $T_{alpha}^{-1}$ exists and \ is unbounded } & mc{3}{C{3cm}|}{$T_{alpha}^{-1}$ does not exists}\ hline
%-----------------------------------------------------------------------------------------------------------------------
mc{2}{|L{0.75cm}|}{$I$} & mc{3}{C{2.5cm}|}{$R(T-alpha I)=X$} & mc{3}{p{3cm}|}{$alpha in rho (T,X)$} & mc{3}{C{3cm}|}{$-$} & mc{3}{p{3cm}|}{centering$alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$}\ hline
end{tabular}
end{center}
end{table}
%
end{document}


The output of the MWE looks similar to the one in the image. The only issue is the alignment of the text or numbers.



Please help or provide suggestions?







tables multicolumn






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 23 at 20:45









Tanvir

178214




178214












  • What you want is not entirely clear. Must text or numbers be horizontally or vertically be centred (or both) in its cell?
    – Bernard
    Nov 23 at 21:41










  • @Bernard The text or numbers should be centred vertically. I think they are horizontally centred in the cell.
    – Tanvir
    Nov 23 at 23:39










  • The solutions provided below solved the problem I had with the alignment.
    – Tanvir
    Nov 24 at 0:43


















  • What you want is not entirely clear. Must text or numbers be horizontally or vertically be centred (or both) in its cell?
    – Bernard
    Nov 23 at 21:41










  • @Bernard The text or numbers should be centred vertically. I think they are horizontally centred in the cell.
    – Tanvir
    Nov 23 at 23:39










  • The solutions provided below solved the problem I had with the alignment.
    – Tanvir
    Nov 24 at 0:43
















What you want is not entirely clear. Must text or numbers be horizontally or vertically be centred (or both) in its cell?
– Bernard
Nov 23 at 21:41




What you want is not entirely clear. Must text or numbers be horizontally or vertically be centred (or both) in its cell?
– Bernard
Nov 23 at 21:41












@Bernard The text or numbers should be centred vertically. I think they are horizontally centred in the cell.
– Tanvir
Nov 23 at 23:39




@Bernard The text or numbers should be centred vertically. I think they are horizontally centred in the cell.
– Tanvir
Nov 23 at 23:39












The solutions provided below solved the problem I had with the alignment.
– Tanvir
Nov 24 at 0:43




The solutions provided below solved the problem I had with the alignment.
– Tanvir
Nov 24 at 0:43










3 Answers
3






active

oldest

votes

















up vote
3
down vote



accepted










I think you were almost there.



documentclass{article}
usepackage{array}
usepackage{amsmath}
usepackage{bbm}
begin{document}

newcolumntype{C}{>{centeringarraybackslash}p{3cm}}

begin{table}
renewcommand{arraystretch}{1.3}
begin{tabular}{|l|l|C|C|C|}
hline
& & 1 &2 & multicolumn{1}{c|}{3} \ hline
& & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exist \ hline
$mathbbm{1}$ & $R(T-alpha mathbbm{1})=X$ & $alpha in rho (T,X)$ & - &
$begin{array}{r@{}l}
alpha& in sigma_{p} (T,X)\ alpha& in sigma_{ap} (T,X)
end{array}$ \ hline
end{tabular}
end{table}
end{document}


enter image description here






share|improve this answer




























    up vote
    2
    down vote













    Using tabularx gives you more flexibility for line wrapping and total page width table. To center a cell use multicolumn{1}{c|}{..} and you can increase vertical space for rows by renewcommand{arraystretch}{1.3} for more readability. Cells of the last row can be vertically centered by using multirow but this will not make much difference.



    documentclass{article}
    usepackage{array,tabularx}
    begin{document}

    newcolumntype{L}{>{raggedrightarraybackslash}X}

    begin{table}
    renewcommand{arraystretch}{1.3}
    begin{tabularx}{textwidth}{|l|l|L|L|L|}
    hline
    & & multicolumn{1}{c|}{1} & multicolumn{1}{c|}{2} & multicolumn{1}{c|}{3} \ hline
    & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \ hline
    $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ hline
    end{tabularx}
    end{table}

    end{document}


    enter image description here



    You may also want to improve the whole design using booktabs as follows:



    documentclass{article}
    usepackage{array,tabularx,booktabs}
    begin{document}

    newcolumntype{L}{>{raggedrightarraybackslash}X}

    begin{table}
    %renewcommand{arraystretch}{1.3}
    begin{tabularx}{textwidth}{@{}llLLL@{}}
    toprule
    & & multicolumn{1}{c}{1} & multicolumn{1}{c}{2} & multicolumn{1}{c}{3} \ midrule
    & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \
    textit{$I$} & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ bottomrule
    end{tabularx}
    end{table}

    end{document}


    enter image description here






    share|improve this answer























    • +1. Please replace textit{$I$} with $I$, though.
      – Mico
      Nov 23 at 22:20










    • The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
      – Tanvir
      Nov 24 at 0:39


















    up vote
    2
    down vote













    Avoid jailed tables:



    documentclass{article}

    %%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
    usepackage{array}
    usepackage{booktabs}
    usepackage{tabularx}

    newcolumntype{C}{>{centering}X}

    begin{document}

    begin{table}[ht!]
    centering
    renewcommand{tabularxcolumn}{m}

    begin{tabularx}{textwidth}{@{}ccCCC@{}}
    toprule
    && 1 & 2 & 3 tabularnewline
    cmidrule(lr){3-3} cmidrule(lr){4-4} cmidrule(l){5-5}
    && $T_{alpha}^{-1}$ exists and \ is bounded &
    $T_{alpha}^{-1}$ exists and \ is unbounded &
    $T_{alpha}^{-1}$ does not exist tabularnewline
    midrule
    $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
    $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
    bottomrule
    end{tabularx}

    end{table}

    end{document}


    Define only the columns you need. Here two centered columns at their natural width, then three equalized columns. For all columns, both vertical and horizontal centering.



    Since you want to specify the line breaks, I don't state arraybackslash and use tabularnewline for ending rows.



    enter image description here



    It's easy to make it jailed, though.



    begin{tabularx}{textwidth}{|c|c|C|C|C|}
    hline
    && 1 & 2 & 3 tabularnewline
    hline
    && $T_{alpha}^{-1}$ exists and \ is bounded &
    $T_{alpha}^{-1}$ exists and \ is unbounded &
    $T_{alpha}^{-1}$ does not exist tabularnewline
    hline
    $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
    $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
    hline
    end{tabularx}


    enter image description here






    share|improve this answer





















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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      3
      down vote



      accepted










      I think you were almost there.



      documentclass{article}
      usepackage{array}
      usepackage{amsmath}
      usepackage{bbm}
      begin{document}

      newcolumntype{C}{>{centeringarraybackslash}p{3cm}}

      begin{table}
      renewcommand{arraystretch}{1.3}
      begin{tabular}{|l|l|C|C|C|}
      hline
      & & 1 &2 & multicolumn{1}{c|}{3} \ hline
      & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exist \ hline
      $mathbbm{1}$ & $R(T-alpha mathbbm{1})=X$ & $alpha in rho (T,X)$ & - &
      $begin{array}{r@{}l}
      alpha& in sigma_{p} (T,X)\ alpha& in sigma_{ap} (T,X)
      end{array}$ \ hline
      end{tabular}
      end{table}
      end{document}


      enter image description here






      share|improve this answer

























        up vote
        3
        down vote



        accepted










        I think you were almost there.



        documentclass{article}
        usepackage{array}
        usepackage{amsmath}
        usepackage{bbm}
        begin{document}

        newcolumntype{C}{>{centeringarraybackslash}p{3cm}}

        begin{table}
        renewcommand{arraystretch}{1.3}
        begin{tabular}{|l|l|C|C|C|}
        hline
        & & 1 &2 & multicolumn{1}{c|}{3} \ hline
        & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exist \ hline
        $mathbbm{1}$ & $R(T-alpha mathbbm{1})=X$ & $alpha in rho (T,X)$ & - &
        $begin{array}{r@{}l}
        alpha& in sigma_{p} (T,X)\ alpha& in sigma_{ap} (T,X)
        end{array}$ \ hline
        end{tabular}
        end{table}
        end{document}


        enter image description here






        share|improve this answer























          up vote
          3
          down vote



          accepted







          up vote
          3
          down vote



          accepted






          I think you were almost there.



          documentclass{article}
          usepackage{array}
          usepackage{amsmath}
          usepackage{bbm}
          begin{document}

          newcolumntype{C}{>{centeringarraybackslash}p{3cm}}

          begin{table}
          renewcommand{arraystretch}{1.3}
          begin{tabular}{|l|l|C|C|C|}
          hline
          & & 1 &2 & multicolumn{1}{c|}{3} \ hline
          & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exist \ hline
          $mathbbm{1}$ & $R(T-alpha mathbbm{1})=X$ & $alpha in rho (T,X)$ & - &
          $begin{array}{r@{}l}
          alpha& in sigma_{p} (T,X)\ alpha& in sigma_{ap} (T,X)
          end{array}$ \ hline
          end{tabular}
          end{table}
          end{document}


          enter image description here






          share|improve this answer












          I think you were almost there.



          documentclass{article}
          usepackage{array}
          usepackage{amsmath}
          usepackage{bbm}
          begin{document}

          newcolumntype{C}{>{centeringarraybackslash}p{3cm}}

          begin{table}
          renewcommand{arraystretch}{1.3}
          begin{tabular}{|l|l|C|C|C|}
          hline
          & & 1 &2 & multicolumn{1}{c|}{3} \ hline
          & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exist \ hline
          $mathbbm{1}$ & $R(T-alpha mathbbm{1})=X$ & $alpha in rho (T,X)$ & - &
          $begin{array}{r@{}l}
          alpha& in sigma_{p} (T,X)\ alpha& in sigma_{ap} (T,X)
          end{array}$ \ hline
          end{tabular}
          end{table}
          end{document}


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 23 at 22:29









          marmot

          78.7k487166




          78.7k487166






















              up vote
              2
              down vote













              Using tabularx gives you more flexibility for line wrapping and total page width table. To center a cell use multicolumn{1}{c|}{..} and you can increase vertical space for rows by renewcommand{arraystretch}{1.3} for more readability. Cells of the last row can be vertically centered by using multirow but this will not make much difference.



              documentclass{article}
              usepackage{array,tabularx}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{|l|l|L|L|L|}
              hline
              & & multicolumn{1}{c|}{1} & multicolumn{1}{c|}{2} & multicolumn{1}{c|}{3} \ hline
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \ hline
              $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ hline
              end{tabularx}
              end{table}

              end{document}


              enter image description here



              You may also want to improve the whole design using booktabs as follows:



              documentclass{article}
              usepackage{array,tabularx,booktabs}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              %renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{@{}llLLL@{}}
              toprule
              & & multicolumn{1}{c}{1} & multicolumn{1}{c}{2} & multicolumn{1}{c}{3} \ midrule
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \
              textit{$I$} & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ bottomrule
              end{tabularx}
              end{table}

              end{document}


              enter image description here






              share|improve this answer























              • +1. Please replace textit{$I$} with $I$, though.
                – Mico
                Nov 23 at 22:20










              • The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
                – Tanvir
                Nov 24 at 0:39















              up vote
              2
              down vote













              Using tabularx gives you more flexibility for line wrapping and total page width table. To center a cell use multicolumn{1}{c|}{..} and you can increase vertical space for rows by renewcommand{arraystretch}{1.3} for more readability. Cells of the last row can be vertically centered by using multirow but this will not make much difference.



              documentclass{article}
              usepackage{array,tabularx}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{|l|l|L|L|L|}
              hline
              & & multicolumn{1}{c|}{1} & multicolumn{1}{c|}{2} & multicolumn{1}{c|}{3} \ hline
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \ hline
              $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ hline
              end{tabularx}
              end{table}

              end{document}


              enter image description here



              You may also want to improve the whole design using booktabs as follows:



              documentclass{article}
              usepackage{array,tabularx,booktabs}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              %renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{@{}llLLL@{}}
              toprule
              & & multicolumn{1}{c}{1} & multicolumn{1}{c}{2} & multicolumn{1}{c}{3} \ midrule
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \
              textit{$I$} & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ bottomrule
              end{tabularx}
              end{table}

              end{document}


              enter image description here






              share|improve this answer























              • +1. Please replace textit{$I$} with $I$, though.
                – Mico
                Nov 23 at 22:20










              • The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
                – Tanvir
                Nov 24 at 0:39













              up vote
              2
              down vote










              up vote
              2
              down vote









              Using tabularx gives you more flexibility for line wrapping and total page width table. To center a cell use multicolumn{1}{c|}{..} and you can increase vertical space for rows by renewcommand{arraystretch}{1.3} for more readability. Cells of the last row can be vertically centered by using multirow but this will not make much difference.



              documentclass{article}
              usepackage{array,tabularx}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{|l|l|L|L|L|}
              hline
              & & multicolumn{1}{c|}{1} & multicolumn{1}{c|}{2} & multicolumn{1}{c|}{3} \ hline
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \ hline
              $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ hline
              end{tabularx}
              end{table}

              end{document}


              enter image description here



              You may also want to improve the whole design using booktabs as follows:



              documentclass{article}
              usepackage{array,tabularx,booktabs}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              %renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{@{}llLLL@{}}
              toprule
              & & multicolumn{1}{c}{1} & multicolumn{1}{c}{2} & multicolumn{1}{c}{3} \ midrule
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \
              textit{$I$} & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ bottomrule
              end{tabularx}
              end{table}

              end{document}


              enter image description here






              share|improve this answer














              Using tabularx gives you more flexibility for line wrapping and total page width table. To center a cell use multicolumn{1}{c|}{..} and you can increase vertical space for rows by renewcommand{arraystretch}{1.3} for more readability. Cells of the last row can be vertically centered by using multirow but this will not make much difference.



              documentclass{article}
              usepackage{array,tabularx}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{|l|l|L|L|L|}
              hline
              & & multicolumn{1}{c|}{1} & multicolumn{1}{c|}{2} & multicolumn{1}{c|}{3} \ hline
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \ hline
              $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ hline
              end{tabularx}
              end{table}

              end{document}


              enter image description here



              You may also want to improve the whole design using booktabs as follows:



              documentclass{article}
              usepackage{array,tabularx,booktabs}
              begin{document}

              newcolumntype{L}{>{raggedrightarraybackslash}X}

              begin{table}
              %renewcommand{arraystretch}{1.3}
              begin{tabularx}{textwidth}{@{}llLLL@{}}
              toprule
              & & multicolumn{1}{c}{1} & multicolumn{1}{c}{2} & multicolumn{1}{c}{3} \ midrule
              & & $T_alpha^{-1}$ exists and is bounded & $T_alpha^{-1}$ exists and is unbounded & $T_alpha^{-1}$ does not exists \
              textit{$I$} & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & - & $alpha in sigma_{p} (T,X)$ newline $alpha in sigma_{ap} (T,X)$ \ bottomrule
              end{tabularx}
              end{table}

              end{document}


              enter image description here







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Nov 23 at 23:11

























              answered Nov 23 at 21:06









              AboAmmar

              31.4k22781




              31.4k22781












              • +1. Please replace textit{$I$} with $I$, though.
                – Mico
                Nov 23 at 22:20










              • The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
                – Tanvir
                Nov 24 at 0:39


















              • +1. Please replace textit{$I$} with $I$, though.
                – Mico
                Nov 23 at 22:20










              • The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
                – Tanvir
                Nov 24 at 0:39
















              +1. Please replace textit{$I$} with $I$, though.
              – Mico
              Nov 23 at 22:20




              +1. Please replace textit{$I$} with $I$, though.
              – Mico
              Nov 23 at 22:20












              The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
              – Tanvir
              Nov 24 at 0:39




              The solution provided worked like charm. Also learnt a new thing -- using booktabs. This made the final table looked nice.
              – Tanvir
              Nov 24 at 0:39










              up vote
              2
              down vote













              Avoid jailed tables:



              documentclass{article}

              %%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
              usepackage{array}
              usepackage{booktabs}
              usepackage{tabularx}

              newcolumntype{C}{>{centering}X}

              begin{document}

              begin{table}[ht!]
              centering
              renewcommand{tabularxcolumn}{m}

              begin{tabularx}{textwidth}{@{}ccCCC@{}}
              toprule
              && 1 & 2 & 3 tabularnewline
              cmidrule(lr){3-3} cmidrule(lr){4-4} cmidrule(l){5-5}
              && $T_{alpha}^{-1}$ exists and \ is bounded &
              $T_{alpha}^{-1}$ exists and \ is unbounded &
              $T_{alpha}^{-1}$ does not exist tabularnewline
              midrule
              $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
              $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
              bottomrule
              end{tabularx}

              end{table}

              end{document}


              Define only the columns you need. Here two centered columns at their natural width, then three equalized columns. For all columns, both vertical and horizontal centering.



              Since you want to specify the line breaks, I don't state arraybackslash and use tabularnewline for ending rows.



              enter image description here



              It's easy to make it jailed, though.



              begin{tabularx}{textwidth}{|c|c|C|C|C|}
              hline
              && 1 & 2 & 3 tabularnewline
              hline
              && $T_{alpha}^{-1}$ exists and \ is bounded &
              $T_{alpha}^{-1}$ exists and \ is unbounded &
              $T_{alpha}^{-1}$ does not exist tabularnewline
              hline
              $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
              $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
              hline
              end{tabularx}


              enter image description here






              share|improve this answer

























                up vote
                2
                down vote













                Avoid jailed tables:



                documentclass{article}

                %%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
                usepackage{array}
                usepackage{booktabs}
                usepackage{tabularx}

                newcolumntype{C}{>{centering}X}

                begin{document}

                begin{table}[ht!]
                centering
                renewcommand{tabularxcolumn}{m}

                begin{tabularx}{textwidth}{@{}ccCCC@{}}
                toprule
                && 1 & 2 & 3 tabularnewline
                cmidrule(lr){3-3} cmidrule(lr){4-4} cmidrule(l){5-5}
                && $T_{alpha}^{-1}$ exists and \ is bounded &
                $T_{alpha}^{-1}$ exists and \ is unbounded &
                $T_{alpha}^{-1}$ does not exist tabularnewline
                midrule
                $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
                $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
                bottomrule
                end{tabularx}

                end{table}

                end{document}


                Define only the columns you need. Here two centered columns at their natural width, then three equalized columns. For all columns, both vertical and horizontal centering.



                Since you want to specify the line breaks, I don't state arraybackslash and use tabularnewline for ending rows.



                enter image description here



                It's easy to make it jailed, though.



                begin{tabularx}{textwidth}{|c|c|C|C|C|}
                hline
                && 1 & 2 & 3 tabularnewline
                hline
                && $T_{alpha}^{-1}$ exists and \ is bounded &
                $T_{alpha}^{-1}$ exists and \ is unbounded &
                $T_{alpha}^{-1}$ does not exist tabularnewline
                hline
                $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
                $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
                hline
                end{tabularx}


                enter image description here






                share|improve this answer























                  up vote
                  2
                  down vote










                  up vote
                  2
                  down vote









                  Avoid jailed tables:



                  documentclass{article}

                  %%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
                  usepackage{array}
                  usepackage{booktabs}
                  usepackage{tabularx}

                  newcolumntype{C}{>{centering}X}

                  begin{document}

                  begin{table}[ht!]
                  centering
                  renewcommand{tabularxcolumn}{m}

                  begin{tabularx}{textwidth}{@{}ccCCC@{}}
                  toprule
                  && 1 & 2 & 3 tabularnewline
                  cmidrule(lr){3-3} cmidrule(lr){4-4} cmidrule(l){5-5}
                  && $T_{alpha}^{-1}$ exists and \ is bounded &
                  $T_{alpha}^{-1}$ exists and \ is unbounded &
                  $T_{alpha}^{-1}$ does not exist tabularnewline
                  midrule
                  $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
                  $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
                  bottomrule
                  end{tabularx}

                  end{table}

                  end{document}


                  Define only the columns you need. Here two centered columns at their natural width, then three equalized columns. For all columns, both vertical and horizontal centering.



                  Since you want to specify the line breaks, I don't state arraybackslash and use tabularnewline for ending rows.



                  enter image description here



                  It's easy to make it jailed, though.



                  begin{tabularx}{textwidth}{|c|c|C|C|C|}
                  hline
                  && 1 & 2 & 3 tabularnewline
                  hline
                  && $T_{alpha}^{-1}$ exists and \ is bounded &
                  $T_{alpha}^{-1}$ exists and \ is unbounded &
                  $T_{alpha}^{-1}$ does not exist tabularnewline
                  hline
                  $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
                  $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
                  hline
                  end{tabularx}


                  enter image description here






                  share|improve this answer












                  Avoid jailed tables:



                  documentclass{article}

                  %%%%%%%%%% PACKAGES %%%%%%%%%%%%%%%%%%%%%%
                  usepackage{array}
                  usepackage{booktabs}
                  usepackage{tabularx}

                  newcolumntype{C}{>{centering}X}

                  begin{document}

                  begin{table}[ht!]
                  centering
                  renewcommand{tabularxcolumn}{m}

                  begin{tabularx}{textwidth}{@{}ccCCC@{}}
                  toprule
                  && 1 & 2 & 3 tabularnewline
                  cmidrule(lr){3-3} cmidrule(lr){4-4} cmidrule(l){5-5}
                  && $T_{alpha}^{-1}$ exists and \ is bounded &
                  $T_{alpha}^{-1}$ exists and \ is unbounded &
                  $T_{alpha}^{-1}$ does not exist tabularnewline
                  midrule
                  $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
                  $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
                  bottomrule
                  end{tabularx}

                  end{table}

                  end{document}


                  Define only the columns you need. Here two centered columns at their natural width, then three equalized columns. For all columns, both vertical and horizontal centering.



                  Since you want to specify the line breaks, I don't state arraybackslash and use tabularnewline for ending rows.



                  enter image description here



                  It's easy to make it jailed, though.



                  begin{tabularx}{textwidth}{|c|c|C|C|C|}
                  hline
                  && 1 & 2 & 3 tabularnewline
                  hline
                  && $T_{alpha}^{-1}$ exists and \ is bounded &
                  $T_{alpha}^{-1}$ exists and \ is unbounded &
                  $T_{alpha}^{-1}$ does not exist tabularnewline
                  hline
                  $I$ & $R(T-alpha I)=X$ & $alpha in rho (T,X)$ & --- &
                  $alpha in sigma_{p} (T,X)$ \ $alpha in sigma_{ap} (T,X)$ tabularnewline
                  hline
                  end{tabularx}


                  enter image description here







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 24 at 0:52









                  egreg

                  700k8518633138




                  700k8518633138






























                       

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