Microsoft excel nested IF Menu - where is the logical error?











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I have a problem with the nested menu.



On one hand, I have the count of sold items. From 0 to more than 50 000 item.
From the other hand, with the increase of the count, the price drops down.



A is the line of quantity, B is the line of price. 



A20 1000    0.90 B20



A21 2000    0.80 B21



A22 5000    0.70 B22



A23 10000   0.60 B23



A24 20000   0.50 B24



A25 30000   0.40 B25



A26 50000   0.30 B26


And the cell where the end result should be illustrated is B13



I put the following formula:



IF(B13<A2,B13*B20,IF(B13>A21<A22,B13*B21,IF(B13>A22<A23,B13*B22,IF(B13>A23<A24,B13*B23,IF(B13>A24<A25,B13*B24,IF(B13>A25<A26,B13*B25,IF(B13>A26,B13*B26,"0")))))))


But already after the threshold 2000 (e.g. 2001) I get the result 0 (which is my false value).



Where is my mistake?






microsoft-excel







share|improve this question




















  • 1




    Shouldn't the first condition not be B13<A20 (A20 instead of A2)? You may also want to look into VLOOKUP and/or INDEX/MATCH
    – cybernetic.nomad
    Nov 19 at 15:05






  • 1




    If(B13>A21<A22..., that's not the proper construction. You need AND(): IF(AND(B13>A21,A21<A22),... You can test this by putting 1 in A1, and in B1, put =IF(1>A1>2,"Yes","No"), will always return Yes no matter what value you put in A1.
    – BruceWayne
    Nov 19 at 17:57












  • Thanks I decided to use the Vlookup function at the end. Later I fixed the problem, but there was again a logical error.
    – Provangelist
    Nov 20 at 15:33










  • Note that the pricing system you describe doesn't make much sense in the real world (e.g. 999 items would cost 999 * 0.9 = 889.1, while 1000 items would only cost 1000 * 0.8 = 800). The more usual system is to say that the first 1000 items cost 0.9 each and the next 1000 items cost 0.8 etc.)
    – Blackwood
    Nov 20 at 17:17

















up vote
0
down vote

favorite












I have a problem with the nested menu.



On one hand, I have the count of sold items. From 0 to more than 50 000 item.
From the other hand, with the increase of the count, the price drops down.



A is the line of quantity, B is the line of price. 



A20 1000    0.90 B20



A21 2000    0.80 B21



A22 5000    0.70 B22



A23 10000   0.60 B23



A24 20000   0.50 B24



A25 30000   0.40 B25



A26 50000   0.30 B26


And the cell where the end result should be illustrated is B13



I put the following formula:



IF(B13<A2,B13*B20,IF(B13>A21<A22,B13*B21,IF(B13>A22<A23,B13*B22,IF(B13>A23<A24,B13*B23,IF(B13>A24<A25,B13*B24,IF(B13>A25<A26,B13*B25,IF(B13>A26,B13*B26,"0")))))))


But already after the threshold 2000 (e.g. 2001) I get the result 0 (which is my false value).



Where is my mistake?






microsoft-excel







share|improve this question




















  • 1




    Shouldn't the first condition not be B13<A20 (A20 instead of A2)? You may also want to look into VLOOKUP and/or INDEX/MATCH
    – cybernetic.nomad
    Nov 19 at 15:05






  • 1




    If(B13>A21<A22..., that's not the proper construction. You need AND(): IF(AND(B13>A21,A21<A22),... You can test this by putting 1 in A1, and in B1, put =IF(1>A1>2,"Yes","No"), will always return Yes no matter what value you put in A1.
    – BruceWayne
    Nov 19 at 17:57












  • Thanks I decided to use the Vlookup function at the end. Later I fixed the problem, but there was again a logical error.
    – Provangelist
    Nov 20 at 15:33










  • Note that the pricing system you describe doesn't make much sense in the real world (e.g. 999 items would cost 999 * 0.9 = 889.1, while 1000 items would only cost 1000 * 0.8 = 800). The more usual system is to say that the first 1000 items cost 0.9 each and the next 1000 items cost 0.8 etc.)
    – Blackwood
    Nov 20 at 17:17















up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have a problem with the nested menu.



On one hand, I have the count of sold items. From 0 to more than 50 000 item.
From the other hand, with the increase of the count, the price drops down.



A is the line of quantity, B is the line of price. 



A20 1000    0.90 B20



A21 2000    0.80 B21



A22 5000    0.70 B22



A23 10000   0.60 B23



A24 20000   0.50 B24



A25 30000   0.40 B25



A26 50000   0.30 B26


And the cell where the end result should be illustrated is B13



I put the following formula:



IF(B13<A2,B13*B20,IF(B13>A21<A22,B13*B21,IF(B13>A22<A23,B13*B22,IF(B13>A23<A24,B13*B23,IF(B13>A24<A25,B13*B24,IF(B13>A25<A26,B13*B25,IF(B13>A26,B13*B26,"0")))))))


But already after the threshold 2000 (e.g. 2001) I get the result 0 (which is my false value).



Where is my mistake?






microsoft-excel







share|improve this question















I have a problem with the nested menu.



On one hand, I have the count of sold items. From 0 to more than 50 000 item.
From the other hand, with the increase of the count, the price drops down.



A is the line of quantity, B is the line of price. 



A20 1000    0.90 B20



A21 2000    0.80 B21



A22 5000    0.70 B22



A23 10000   0.60 B23



A24 20000   0.50 B24



A25 30000   0.40 B25



A26 50000   0.30 B26


And the cell where the end result should be illustrated is B13



I put the following formula:



IF(B13<A2,B13*B20,IF(B13>A21<A22,B13*B21,IF(B13>A22<A23,B13*B22,IF(B13>A23<A24,B13*B23,IF(B13>A24<A25,B13*B24,IF(B13>A25<A26,B13*B25,IF(B13>A26,B13*B26,"0")))))))


But already after the threshold 2000 (e.g. 2001) I get the result 0 (which is my false value).



Where is my mistake?






microsoft-excel




microsoft-excel






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 19 at 14:24









bummi

1,50731421




1,50731421










asked Nov 19 at 13:40









Provangelist

11




11








  • 1




    Shouldn't the first condition not be B13<A20 (A20 instead of A2)? You may also want to look into VLOOKUP and/or INDEX/MATCH
    – cybernetic.nomad
    Nov 19 at 15:05






  • 1




    If(B13>A21<A22..., that's not the proper construction. You need AND(): IF(AND(B13>A21,A21<A22),... You can test this by putting 1 in A1, and in B1, put =IF(1>A1>2,"Yes","No"), will always return Yes no matter what value you put in A1.
    – BruceWayne
    Nov 19 at 17:57












  • Thanks I decided to use the Vlookup function at the end. Later I fixed the problem, but there was again a logical error.
    – Provangelist
    Nov 20 at 15:33










  • Note that the pricing system you describe doesn't make much sense in the real world (e.g. 999 items would cost 999 * 0.9 = 889.1, while 1000 items would only cost 1000 * 0.8 = 800). The more usual system is to say that the first 1000 items cost 0.9 each and the next 1000 items cost 0.8 etc.)
    – Blackwood
    Nov 20 at 17:17
















  • 1




    Shouldn't the first condition not be B13<A20 (A20 instead of A2)? You may also want to look into VLOOKUP and/or INDEX/MATCH
    – cybernetic.nomad
    Nov 19 at 15:05






  • 1




    If(B13>A21<A22..., that's not the proper construction. You need AND(): IF(AND(B13>A21,A21<A22),... You can test this by putting 1 in A1, and in B1, put =IF(1>A1>2,"Yes","No"), will always return Yes no matter what value you put in A1.
    – BruceWayne
    Nov 19 at 17:57












  • Thanks I decided to use the Vlookup function at the end. Later I fixed the problem, but there was again a logical error.
    – Provangelist
    Nov 20 at 15:33










  • Note that the pricing system you describe doesn't make much sense in the real world (e.g. 999 items would cost 999 * 0.9 = 889.1, while 1000 items would only cost 1000 * 0.8 = 800). The more usual system is to say that the first 1000 items cost 0.9 each and the next 1000 items cost 0.8 etc.)
    – Blackwood
    Nov 20 at 17:17










1




1




Shouldn't the first condition not be B13<A20 (A20 instead of A2)? You may also want to look into VLOOKUP and/or INDEX/MATCH
– cybernetic.nomad
Nov 19 at 15:05




Shouldn't the first condition not be B13<A20 (A20 instead of A2)? You may also want to look into VLOOKUP and/or INDEX/MATCH
– cybernetic.nomad
Nov 19 at 15:05




1




1




If(B13>A21<A22..., that's not the proper construction. You need AND(): IF(AND(B13>A21,A21<A22),... You can test this by putting 1 in A1, and in B1, put =IF(1>A1>2,"Yes","No"), will always return Yes no matter what value you put in A1.
– BruceWayne
Nov 19 at 17:57






If(B13>A21<A22..., that's not the proper construction. You need AND(): IF(AND(B13>A21,A21<A22),... You can test this by putting 1 in A1, and in B1, put =IF(1>A1>2,"Yes","No"), will always return Yes no matter what value you put in A1.
– BruceWayne
Nov 19 at 17:57














Thanks I decided to use the Vlookup function at the end. Later I fixed the problem, but there was again a logical error.
– Provangelist
Nov 20 at 15:33




Thanks I decided to use the Vlookup function at the end. Later I fixed the problem, but there was again a logical error.
– Provangelist
Nov 20 at 15:33












Note that the pricing system you describe doesn't make much sense in the real world (e.g. 999 items would cost 999 * 0.9 = 889.1, while 1000 items would only cost 1000 * 0.8 = 800). The more usual system is to say that the first 1000 items cost 0.9 each and the next 1000 items cost 0.8 etc.)
– Blackwood
Nov 20 at 17:17






Note that the pricing system you describe doesn't make much sense in the real world (e.g. 999 items would cost 999 * 0.9 = 889.1, while 1000 items would only cost 1000 * 0.8 = 800). The more usual system is to say that the first 1000 items cost 0.9 each and the next 1000 items cost 0.8 etc.)
– Blackwood
Nov 20 at 17:17

















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