Solution to constrained quadratic optimization problem











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Is there a closed form solution to this constrained quadratic optimization problem?



$$
mathrm{argmax}_X mathrm{Tr}(AX)mathrm{Tr}(BX)\
0preceq Xpreceq I
$$



Where $A$ and $B$ are hermitian positive matrices and $Apreceq I$, $Bpreceq I$.



EDIT: The inequalities are with respect to the eigenvalues










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  • 1




    By $leq$, do you mean element wise inequality or conic inequality with respect to the semidefinite cone?
    – Brian Borchers
    Nov 16 at 16:23










  • Thank you for the question, see edit.
    – Ziofil
    Nov 16 at 16:25










  • The notation $succeq$ is normally used for this kind of conic inequality.
    – Brian Borchers
    Nov 16 at 16:26










  • Fixed. Thank you.
    – Ziofil
    Nov 16 at 16:28















up vote
0
down vote

favorite












Is there a closed form solution to this constrained quadratic optimization problem?



$$
mathrm{argmax}_X mathrm{Tr}(AX)mathrm{Tr}(BX)\
0preceq Xpreceq I
$$



Where $A$ and $B$ are hermitian positive matrices and $Apreceq I$, $Bpreceq I$.



EDIT: The inequalities are with respect to the eigenvalues










share|cite|improve this question




















  • 1




    By $leq$, do you mean element wise inequality or conic inequality with respect to the semidefinite cone?
    – Brian Borchers
    Nov 16 at 16:23










  • Thank you for the question, see edit.
    – Ziofil
    Nov 16 at 16:25










  • The notation $succeq$ is normally used for this kind of conic inequality.
    – Brian Borchers
    Nov 16 at 16:26










  • Fixed. Thank you.
    – Ziofil
    Nov 16 at 16:28













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Is there a closed form solution to this constrained quadratic optimization problem?



$$
mathrm{argmax}_X mathrm{Tr}(AX)mathrm{Tr}(BX)\
0preceq Xpreceq I
$$



Where $A$ and $B$ are hermitian positive matrices and $Apreceq I$, $Bpreceq I$.



EDIT: The inequalities are with respect to the eigenvalues










share|cite|improve this question















Is there a closed form solution to this constrained quadratic optimization problem?



$$
mathrm{argmax}_X mathrm{Tr}(AX)mathrm{Tr}(BX)\
0preceq Xpreceq I
$$



Where $A$ and $B$ are hermitian positive matrices and $Apreceq I$, $Bpreceq I$.



EDIT: The inequalities are with respect to the eigenvalues







convex-optimization






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 16 at 16:30









Brian Borchers

5,51611119




5,51611119










asked Nov 16 at 16:17









Ziofil

571416




571416








  • 1




    By $leq$, do you mean element wise inequality or conic inequality with respect to the semidefinite cone?
    – Brian Borchers
    Nov 16 at 16:23










  • Thank you for the question, see edit.
    – Ziofil
    Nov 16 at 16:25










  • The notation $succeq$ is normally used for this kind of conic inequality.
    – Brian Borchers
    Nov 16 at 16:26










  • Fixed. Thank you.
    – Ziofil
    Nov 16 at 16:28














  • 1




    By $leq$, do you mean element wise inequality or conic inequality with respect to the semidefinite cone?
    – Brian Borchers
    Nov 16 at 16:23










  • Thank you for the question, see edit.
    – Ziofil
    Nov 16 at 16:25










  • The notation $succeq$ is normally used for this kind of conic inequality.
    – Brian Borchers
    Nov 16 at 16:26










  • Fixed. Thank you.
    – Ziofil
    Nov 16 at 16:28








1




1




By $leq$, do you mean element wise inequality or conic inequality with respect to the semidefinite cone?
– Brian Borchers
Nov 16 at 16:23




By $leq$, do you mean element wise inequality or conic inequality with respect to the semidefinite cone?
– Brian Borchers
Nov 16 at 16:23












Thank you for the question, see edit.
– Ziofil
Nov 16 at 16:25




Thank you for the question, see edit.
– Ziofil
Nov 16 at 16:25












The notation $succeq$ is normally used for this kind of conic inequality.
– Brian Borchers
Nov 16 at 16:26




The notation $succeq$ is normally used for this kind of conic inequality.
– Brian Borchers
Nov 16 at 16:26












Fixed. Thank you.
– Ziofil
Nov 16 at 16:28




Fixed. Thank you.
– Ziofil
Nov 16 at 16:28















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