Are continuous mappings on a compact metric space Lipschitz?











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Continuous mapping on a compact metric space is uniformly continuous is a standard result in real analysis. Lipschitz functions are uniformly continuous. Can the aforementioned result be generalized to Lipschitz? i.e. are all continuous functions on compact metric spaces Lipschitz?



Can we require anything more so that all continuous functions are Lipschitz?










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    Continuous mapping on a compact metric space is uniformly continuous is a standard result in real analysis. Lipschitz functions are uniformly continuous. Can the aforementioned result be generalized to Lipschitz? i.e. are all continuous functions on compact metric spaces Lipschitz?



    Can we require anything more so that all continuous functions are Lipschitz?










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      up vote
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      favorite











      Continuous mapping on a compact metric space is uniformly continuous is a standard result in real analysis. Lipschitz functions are uniformly continuous. Can the aforementioned result be generalized to Lipschitz? i.e. are all continuous functions on compact metric spaces Lipschitz?



      Can we require anything more so that all continuous functions are Lipschitz?










      share|cite|improve this question













      Continuous mapping on a compact metric space is uniformly continuous is a standard result in real analysis. Lipschitz functions are uniformly continuous. Can the aforementioned result be generalized to Lipschitz? i.e. are all continuous functions on compact metric spaces Lipschitz?



      Can we require anything more so that all continuous functions are Lipschitz?







      real-analysis metric-spaces






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      asked Nov 15 at 15:19









      Baran Zadeoglu

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          First question: No. For example, $f(x) = sqrt{x}$ on the compact interval $[0,1]$ isn't Lipschitz.






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            See $sqrt X $on [0,1] is satisfies given condition but not Lipschitz






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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              2
              down vote



              accepted










              First question: No. For example, $f(x) = sqrt{x}$ on the compact interval $[0,1]$ isn't Lipschitz.






              share|cite|improve this answer

























                up vote
                2
                down vote



                accepted










                First question: No. For example, $f(x) = sqrt{x}$ on the compact interval $[0,1]$ isn't Lipschitz.






                share|cite|improve this answer























                  up vote
                  2
                  down vote



                  accepted







                  up vote
                  2
                  down vote



                  accepted






                  First question: No. For example, $f(x) = sqrt{x}$ on the compact interval $[0,1]$ isn't Lipschitz.






                  share|cite|improve this answer












                  First question: No. For example, $f(x) = sqrt{x}$ on the compact interval $[0,1]$ isn't Lipschitz.







                  share|cite|improve this answer












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                  answered Nov 15 at 15:24









                  Hans Lundmark

                  34.5k564110




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                      See $sqrt X $on [0,1] is satisfies given condition but not Lipschitz






                      share|cite|improve this answer

























                        up vote
                        1
                        down vote













                        See $sqrt X $on [0,1] is satisfies given condition but not Lipschitz






                        share|cite|improve this answer























                          up vote
                          1
                          down vote










                          up vote
                          1
                          down vote









                          See $sqrt X $on [0,1] is satisfies given condition but not Lipschitz






                          share|cite|improve this answer












                          See $sqrt X $on [0,1] is satisfies given condition but not Lipschitz







                          share|cite|improve this answer












                          share|cite|improve this answer



                          share|cite|improve this answer










                          answered Nov 15 at 15:27









                          Shubham

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