Can anyone help me maximizing profit











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Hi guys i have a problem that i cant solve. its asking me to compute the optimum number of units that would maximize profit; if no more than 80 units can be built; and the resulting maximum profit.
The function is as follows:
$$
C(x)= frac{x^3}{3} - frac{55x^2}{2} + 200x + 20000
$$

i have used the quadratic formula to find 2 x values (51 and 4) and if done right i got a relative maximum at x=4
F'(x)= {x^2} - {55x} + 200
F(4)=20381.33










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  • 1




    what have you tried in solving the problem? include them in the question statement if possible.
    – Siong Thye Goh
    Nov 16 at 4:47












  • my tutor recommended using principles of derivatives and so i took the first deriv. and got 2 x values:(51 and 4) plugged those in and found the concavity but i just dont know if im on the right track. i found the relative max and plugged it into the original function and got an answer but i know its not what im looking for
    – Francisco Armendariz
    Nov 16 at 4:50










  • you are encouraged to include your attempt in your original post.
    – Siong Thye Goh
    Nov 16 at 4:53










  • Sorry, im so desperate i forgot to. after computing the deriv. of the first equation, i plugged in X=4 which i assume would be the number of units that maximizes profit. my attempt was ((4^3)/3) - ((55(4^2)/2) + 200(4) + 20000 which gave me an answer of $20381.33 i computed a number of units and the resulting profit from it but dont know if i used the right functions or values
    – Francisco Armendariz
    Nov 16 at 5:08










  • You are receiving $3$ negative votes for not including your attempts (none by me). There is an edit button that you can click on and edit your post. here is a reference for typsetting maths on this site. I don't think $4$ or $51$ are the exact roots.
    – Siong Thye Goh
    Nov 16 at 5:14















up vote
-3
down vote

favorite












Hi guys i have a problem that i cant solve. its asking me to compute the optimum number of units that would maximize profit; if no more than 80 units can be built; and the resulting maximum profit.
The function is as follows:
$$
C(x)= frac{x^3}{3} - frac{55x^2}{2} + 200x + 20000
$$

i have used the quadratic formula to find 2 x values (51 and 4) and if done right i got a relative maximum at x=4
F'(x)= {x^2} - {55x} + 200
F(4)=20381.33










share|cite|improve this question




















  • 1




    what have you tried in solving the problem? include them in the question statement if possible.
    – Siong Thye Goh
    Nov 16 at 4:47












  • my tutor recommended using principles of derivatives and so i took the first deriv. and got 2 x values:(51 and 4) plugged those in and found the concavity but i just dont know if im on the right track. i found the relative max and plugged it into the original function and got an answer but i know its not what im looking for
    – Francisco Armendariz
    Nov 16 at 4:50










  • you are encouraged to include your attempt in your original post.
    – Siong Thye Goh
    Nov 16 at 4:53










  • Sorry, im so desperate i forgot to. after computing the deriv. of the first equation, i plugged in X=4 which i assume would be the number of units that maximizes profit. my attempt was ((4^3)/3) - ((55(4^2)/2) + 200(4) + 20000 which gave me an answer of $20381.33 i computed a number of units and the resulting profit from it but dont know if i used the right functions or values
    – Francisco Armendariz
    Nov 16 at 5:08










  • You are receiving $3$ negative votes for not including your attempts (none by me). There is an edit button that you can click on and edit your post. here is a reference for typsetting maths on this site. I don't think $4$ or $51$ are the exact roots.
    – Siong Thye Goh
    Nov 16 at 5:14













up vote
-3
down vote

favorite









up vote
-3
down vote

favorite











Hi guys i have a problem that i cant solve. its asking me to compute the optimum number of units that would maximize profit; if no more than 80 units can be built; and the resulting maximum profit.
The function is as follows:
$$
C(x)= frac{x^3}{3} - frac{55x^2}{2} + 200x + 20000
$$

i have used the quadratic formula to find 2 x values (51 and 4) and if done right i got a relative maximum at x=4
F'(x)= {x^2} - {55x} + 200
F(4)=20381.33










share|cite|improve this question















Hi guys i have a problem that i cant solve. its asking me to compute the optimum number of units that would maximize profit; if no more than 80 units can be built; and the resulting maximum profit.
The function is as follows:
$$
C(x)= frac{x^3}{3} - frac{55x^2}{2} + 200x + 20000
$$

i have used the quadratic formula to find 2 x values (51 and 4) and if done right i got a relative maximum at x=4
F'(x)= {x^2} - {55x} + 200
F(4)=20381.33







calculus optimization






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 16 at 5:26

























asked Nov 16 at 4:44









Francisco Armendariz

11




11








  • 1




    what have you tried in solving the problem? include them in the question statement if possible.
    – Siong Thye Goh
    Nov 16 at 4:47












  • my tutor recommended using principles of derivatives and so i took the first deriv. and got 2 x values:(51 and 4) plugged those in and found the concavity but i just dont know if im on the right track. i found the relative max and plugged it into the original function and got an answer but i know its not what im looking for
    – Francisco Armendariz
    Nov 16 at 4:50










  • you are encouraged to include your attempt in your original post.
    – Siong Thye Goh
    Nov 16 at 4:53










  • Sorry, im so desperate i forgot to. after computing the deriv. of the first equation, i plugged in X=4 which i assume would be the number of units that maximizes profit. my attempt was ((4^3)/3) - ((55(4^2)/2) + 200(4) + 20000 which gave me an answer of $20381.33 i computed a number of units and the resulting profit from it but dont know if i used the right functions or values
    – Francisco Armendariz
    Nov 16 at 5:08










  • You are receiving $3$ negative votes for not including your attempts (none by me). There is an edit button that you can click on and edit your post. here is a reference for typsetting maths on this site. I don't think $4$ or $51$ are the exact roots.
    – Siong Thye Goh
    Nov 16 at 5:14














  • 1




    what have you tried in solving the problem? include them in the question statement if possible.
    – Siong Thye Goh
    Nov 16 at 4:47












  • my tutor recommended using principles of derivatives and so i took the first deriv. and got 2 x values:(51 and 4) plugged those in and found the concavity but i just dont know if im on the right track. i found the relative max and plugged it into the original function and got an answer but i know its not what im looking for
    – Francisco Armendariz
    Nov 16 at 4:50










  • you are encouraged to include your attempt in your original post.
    – Siong Thye Goh
    Nov 16 at 4:53










  • Sorry, im so desperate i forgot to. after computing the deriv. of the first equation, i plugged in X=4 which i assume would be the number of units that maximizes profit. my attempt was ((4^3)/3) - ((55(4^2)/2) + 200(4) + 20000 which gave me an answer of $20381.33 i computed a number of units and the resulting profit from it but dont know if i used the right functions or values
    – Francisco Armendariz
    Nov 16 at 5:08










  • You are receiving $3$ negative votes for not including your attempts (none by me). There is an edit button that you can click on and edit your post. here is a reference for typsetting maths on this site. I don't think $4$ or $51$ are the exact roots.
    – Siong Thye Goh
    Nov 16 at 5:14








1




1




what have you tried in solving the problem? include them in the question statement if possible.
– Siong Thye Goh
Nov 16 at 4:47






what have you tried in solving the problem? include them in the question statement if possible.
– Siong Thye Goh
Nov 16 at 4:47














my tutor recommended using principles of derivatives and so i took the first deriv. and got 2 x values:(51 and 4) plugged those in and found the concavity but i just dont know if im on the right track. i found the relative max and plugged it into the original function and got an answer but i know its not what im looking for
– Francisco Armendariz
Nov 16 at 4:50




my tutor recommended using principles of derivatives and so i took the first deriv. and got 2 x values:(51 and 4) plugged those in and found the concavity but i just dont know if im on the right track. i found the relative max and plugged it into the original function and got an answer but i know its not what im looking for
– Francisco Armendariz
Nov 16 at 4:50












you are encouraged to include your attempt in your original post.
– Siong Thye Goh
Nov 16 at 4:53




you are encouraged to include your attempt in your original post.
– Siong Thye Goh
Nov 16 at 4:53












Sorry, im so desperate i forgot to. after computing the deriv. of the first equation, i plugged in X=4 which i assume would be the number of units that maximizes profit. my attempt was ((4^3)/3) - ((55(4^2)/2) + 200(4) + 20000 which gave me an answer of $20381.33 i computed a number of units and the resulting profit from it but dont know if i used the right functions or values
– Francisco Armendariz
Nov 16 at 5:08




Sorry, im so desperate i forgot to. after computing the deriv. of the first equation, i plugged in X=4 which i assume would be the number of units that maximizes profit. my attempt was ((4^3)/3) - ((55(4^2)/2) + 200(4) + 20000 which gave me an answer of $20381.33 i computed a number of units and the resulting profit from it but dont know if i used the right functions or values
– Francisco Armendariz
Nov 16 at 5:08












You are receiving $3$ negative votes for not including your attempts (none by me). There is an edit button that you can click on and edit your post. here is a reference for typsetting maths on this site. I don't think $4$ or $51$ are the exact roots.
– Siong Thye Goh
Nov 16 at 5:14




You are receiving $3$ negative votes for not including your attempts (none by me). There is an edit button that you can click on and edit your post. here is a reference for typsetting maths on this site. I don't think $4$ or $51$ are the exact roots.
– Siong Thye Goh
Nov 16 at 5:14










2 Answers
2






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Guide:



$$C'(x) = x^2-55x+200$$



Use quadratic formula to solve for the root. Evaluate the $C$ value at those locations.



Also, evaluate $C$ at $x=0$ and $x=80$. Big hint: This step is very important.



Here is a related picture where I have plotted $frac{C}{10^3}.$



enter image description here






share|cite|improve this answer






























    up vote
    0
    down vote













    Calculus could be used to solve for this. First derivative will tell us the maximum/maximize value.



    So:
    d/dx yeilds:



    x^2 - 55x +200 =0



    So now use Quadratic equation you get



    (55 +/- sqrt(89))/2



    So either 3.91 (4) or 51.08 or 51. Hence 4 is the correct answer. You can verify this by plugging values back into C(X) and see which is higher.






    share|cite|improve this answer





















      Your Answer





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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

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      active

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      active

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      up vote
      0
      down vote













      Guide:



      $$C'(x) = x^2-55x+200$$



      Use quadratic formula to solve for the root. Evaluate the $C$ value at those locations.



      Also, evaluate $C$ at $x=0$ and $x=80$. Big hint: This step is very important.



      Here is a related picture where I have plotted $frac{C}{10^3}.$



      enter image description here






      share|cite|improve this answer



























        up vote
        0
        down vote













        Guide:



        $$C'(x) = x^2-55x+200$$



        Use quadratic formula to solve for the root. Evaluate the $C$ value at those locations.



        Also, evaluate $C$ at $x=0$ and $x=80$. Big hint: This step is very important.



        Here is a related picture where I have plotted $frac{C}{10^3}.$



        enter image description here






        share|cite|improve this answer

























          up vote
          0
          down vote










          up vote
          0
          down vote









          Guide:



          $$C'(x) = x^2-55x+200$$



          Use quadratic formula to solve for the root. Evaluate the $C$ value at those locations.



          Also, evaluate $C$ at $x=0$ and $x=80$. Big hint: This step is very important.



          Here is a related picture where I have plotted $frac{C}{10^3}.$



          enter image description here






          share|cite|improve this answer














          Guide:



          $$C'(x) = x^2-55x+200$$



          Use quadratic formula to solve for the root. Evaluate the $C$ value at those locations.



          Also, evaluate $C$ at $x=0$ and $x=80$. Big hint: This step is very important.



          Here is a related picture where I have plotted $frac{C}{10^3}.$



          enter image description here







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited Nov 16 at 5:15

























          answered Nov 16 at 5:06









          Siong Thye Goh

          93.8k1462114




          93.8k1462114






















              up vote
              0
              down vote













              Calculus could be used to solve for this. First derivative will tell us the maximum/maximize value.



              So:
              d/dx yeilds:



              x^2 - 55x +200 =0



              So now use Quadratic equation you get



              (55 +/- sqrt(89))/2



              So either 3.91 (4) or 51.08 or 51. Hence 4 is the correct answer. You can verify this by plugging values back into C(X) and see which is higher.






              share|cite|improve this answer

























                up vote
                0
                down vote













                Calculus could be used to solve for this. First derivative will tell us the maximum/maximize value.



                So:
                d/dx yeilds:



                x^2 - 55x +200 =0



                So now use Quadratic equation you get



                (55 +/- sqrt(89))/2



                So either 3.91 (4) or 51.08 or 51. Hence 4 is the correct answer. You can verify this by plugging values back into C(X) and see which is higher.






                share|cite|improve this answer























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  Calculus could be used to solve for this. First derivative will tell us the maximum/maximize value.



                  So:
                  d/dx yeilds:



                  x^2 - 55x +200 =0



                  So now use Quadratic equation you get



                  (55 +/- sqrt(89))/2



                  So either 3.91 (4) or 51.08 or 51. Hence 4 is the correct answer. You can verify this by plugging values back into C(X) and see which is higher.






                  share|cite|improve this answer












                  Calculus could be used to solve for this. First derivative will tell us the maximum/maximize value.



                  So:
                  d/dx yeilds:



                  x^2 - 55x +200 =0



                  So now use Quadratic equation you get



                  (55 +/- sqrt(89))/2



                  So either 3.91 (4) or 51.08 or 51. Hence 4 is the correct answer. You can verify this by plugging values back into C(X) and see which is higher.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Nov 16 at 6:06









                  CooperH

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